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Using https as standard with django project

I am learning django and trying to complete my first webapp.
I am using shopify api & boilder plate (starter code) and am having an issue with the final step of auth.
Specifically, the redirect URL -- it's using HTTP:// when it should NOT and I don't know how to change it..
#in my view
def authenticate(request):
shop = request.GET.get('shop')
print('shop:', shop)
if shop:
scope = settings.SHOPIFY_API_SCOPE
redirect_uri = request.build_absolute_uri(reverse('shopify_app_finalize')) #try this with new store url?
print('redirect url', redirect_uri) # this equals http://myherokuapp.com/login/finalize/
permission_url = shopify.Session(shop.strip()).create_permission_url(scope, redirect_uri)
return redirect(permission_url)
return redirect(_return_address(request))
Which is a problem because my app uses the Embedded Shopify SDK which causes this error to occur at the point of this request
Refused to frame 'http://my.herokuapp.com/' because it violates the following Content Security Policy directive: "child-src 'self' https://* shopify-pos://*". Note that 'frame-src' was not explicitly set, so 'child-src' is used as a fallback.
How do i change the URL to use HTTPS?
Thank you so much in advance. Please let me know if I can share any other details but my code is practically identical to that starter code

This is what the Django doc says about build_absolute_uri:
Mixing HTTP and HTTPS on the same site is discouraged, therefore
build_absolute_uri() will always generate an absolute URI with the
same scheme the current request has. If you need to redirect users to
HTTPS, it’s best to let your Web server redirect all HTTP traffic to
HTTPS.
So you can do two things:
Make sure your site runs entirely on HTTPS (preferred option): Setup your web server to use HTTPS, see the Heroku documentation on how to do this. Django will automatically use HTTPS for request.build_absolute_uri if the incoming request is on HTTPS.
I'm not sure what gets passed in the shop parameter but if it contains personal data I'd suggest to use HTTPS anyway.
Create the URL yourself:
url = "https://{host}{path}".format(
host = request.get_host(),
path = reverse('shopify_app_finalize'))
But you will still need to configure your server to accept incoming HTTPS requests.

Airplay Remote control HTTP request

I use Airplay with a Raspberry Pi, so I installed Sharply-sync.
It work perfectly but I want to control the music of my iPhone which is emitting music with airplay.
I saw this page to do this: http://nto.github.io/AirPlay.html#audio-remotecontrol
So I have to make an HTTP request to control the music, but I don't know how to use this: GET /ctrl-int/1/pause HTTP/1.1
Host: starlight.local.
Active-Remote: 1986535575
How can I make a request ( why not in Python :) ) with that ?
My raspberry informations: IP: 192.168.X.XX
The Port: 5000
Active-Remote: 1075873687 (It's an example because it change every Time)
I know the first part of the url which I have to make the request, I think it's: http://192.168.X.XX:5000//ctrl-int/1/pause but I don't know how to put the rest...
How can I do that PLEASE ?
Thank for your answers and I'm so sorry for my bad English..

Just use requests module. Check sample code below.
import requests
headers = {'Host': 'starlight.local.' , 'Active-Remote': 1986535575}
url = "http://192.168.x.xx:5000//ctrl-int/1/pause"
requests.get(url, headers=headers)
For more details please check the documentation for the module at http://docs.python-requests.org/en/master/.

Using Python requests to GET not working - web client and browser works

I have my web app API running.
If I go to http://127.0.0.1:5000/ via any browser I get the right response.
If I use the Advanced REST Client Chrome app and send a GET request to my app at that address I get the right response.
However this gives me a 503:
import requests
response = requests.get('http://127.0.0.1:5000/')
I read to try this for some reason:
s = requests.Session()
response = s.get('http://127.0.0.1:5000/')
But I still get a 503 response.
Other things I've tried: Not prefixing with http://, not using a port in the URL, running on a different port, trying a different API call like Post, etc.
Thanks.

Is http://127.0.0.1:5000/ your localhost? If so, try 'http://localhost:5000' instead

Just in case someone is struggling with this as well, what finally worked was running the application on my local network ip.
I.e., I just opened up the web app and changed the app.run(debug=True) line to app.run(host="my.ip.address", debug = True).
I'm guessing the requests library perhaps was trying to protect me from a localhost attack? Or our corporate proxy or firewall was preventing communication from unknown apps to the 127 address. I had set NO_PROXY to include the 127.0.0.1 address, so I don't think that was the problem. In the end I'm not really sure why it is working now, but I'm glad that it is.

How to read JSON from URL in Python?

I am trying to use Python to get a JSON file from the Web. If I open the URL in my browser (Mozilla or Chromium) I do see the JSON. But when I do the following with the Python:
response = urllib2.urlopen(url)
data = json.loads(response.read())
I get an error message that tells me the following (after translation in English): Errno 10060, a connection troughs an error, since the server after a certain time period did not react, or the connection was erroneous, or the host did not react.
ADDED
It looks like there are many people who faced the described problem. There are also some answers to the similar (or the same) question. For example here we can see the following solution:
import requests
r = requests.get("http://www.google.com", proxies={"http": "http://61.233.25.166:80"})
print(r.text)
It is already a step forward for me (I think that it is very likely that the proxy is the reason of the problem). However, I still did not get it done since I do not know URL of my proxy and I probably will need user name and password. Howe can I find them? How did it happen that my browsers have them I do not?
ADDED 2
I think I am now one step further. I have used this site to find out what my proxy is: http://www.whatismyproxy.com/
Then I have used the following code:
proxies = {'http':'my_proxy.blabla.com/'}
r = requests.get(url, proxies = proxies)
print r
As a result I get
<Response [404]>
Looks not so good, but at least I think that my proxy is correct, because when I randomly change the address of the proxy I get another error:
Cannot connect to proxy
So, I can connect to proxy but something is not found.

I think there might be something wrong, when you're trying to get the json from the online source(URL). Just to make things clear, here is a small code snippet
#!/usr/bin/env python
try:
# For Python 3+
from urllib.request import urlopen
except ImportError:
# For Python 2
from urllib2 import urlopen
import json
def get_jsonparsed_data(url):
response = urlopen(url)
data = str(response.read())
return json.loads(data)
If you still get a connection error, You can try a couple of steps:
Try to urlopen() a random site from the Interpreter (Interactive Mode). If you are able to grab the source code you're good. If not check internet conditions or try the request module. Check here
Check and see if the json in the URL is in the correct syntax. For sample json syntax check here
Try the simplejson module.
Edit 1:
if you want to access websites using a system wide proxy you will have to use a proxy handler to use loopback(local host) to connect to that proxy.. A sample code is shown below.
proxy = urllib2.ProxyHandler({
'http': '127.0.0.1',
'https': '127.0.0.1'
})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
# this way you can send both http and https request using proxies
urllib2.urlopen('http://www.google.com')
urllib2.urlopen('https://www.google.com')
I have not not worked a lot with ProxyHandler. I just know the theory and code. I am sure there are better ways to access websites through proxies; One which does not involve installing the opener everytime you run the program. But hopefully it will point you in the right direction.

Does urllib2 in Python 2.6.1 support proxy via https

Does urllib2 in Python 2.6.1 support proxy via https?
I've found the following at http://www.voidspace.org.uk/python/articles/urllib2.shtml:
NOTE
Currently urllib2 does not support
fetching of https locations through a
proxy. This can be a problem.
I'm trying automate login in to web site and downloading document, I have valid username/password.
proxy_info = {
'host':"axxx", # commented out the real data
'port':"1234" # commented out the real data
}
proxy_handler = urllib2.ProxyHandler(
{"http" : "http://%(host)s:%(port)s" % proxy_info})
opener = urllib2.build_opener(proxy_handler,
urllib2.HTTPHandler(debuglevel=1),urllib2.HTTPCookieProcessor())
urllib2.install_opener(opener)
fullurl = 'https://correct.url.to.login.page.com/user=a&pswd=b' # example
req1 = urllib2.Request(url=fullurl, headers=headers)
response = urllib2.urlopen(req1)
I've had it working for similar pages but not using HTTPS and I suspect it does not get through proxy - it just gets stuck in the same way as when I did not specify proxy. I need to go out through proxy.
I need to authenticate but not using basic authentication, will urllib2 figure out authentication when going via https site (I supply username/password to site via url)?
EDIT:
Nope, I tested with
proxies = {
"http" : "http://%(host)s:%(port)s" % proxy_info,
"https" : "https://%(host)s:%(port)s" % proxy_info
}
proxy_handler = urllib2.ProxyHandler(proxies)
And I get error:
urllib2.URLError: urlopen error
[Errno 8] _ssl.c:480: EOF occurred in
violation of protocol

Fixed in Python 2.6.3 and several other branches:
_bugs.python.org/issue1424152 (replace _ with http...)
http://www.python.org/download/releases/2.6.3/NEWS.txt
Issue #1424152: Fix for httplib, urllib2 to support SSL while working through
proxy. Original patch by Christopher Li, changes made by Senthil Kumaran.

I'm not sure Michael Foord's article, that you quote, is updated to Python 2.6.1 -- why not give it a try? Instead of telling ProxyHandler that the proxy is only good for http, as you're doing now, register it for https, too (of course you should format it into a variable just once before you call ProxyHandler and just repeatedly use that variable in the dict): that may or may not work, but, you're not even trying, and that's sure not to work!-)

Incase anyone else have this issue in the future I'd like to point out that it does support https proxying now, make sure the proxy supports it too or you risk running into a bug that puts the python library into an infinite loop (this happened to me).
See the unittest in the python source that is testing https proxying support for further information:
http://svn.python.org/view/python/branches/release26-maint/Lib/test/test_urllib2.py?r1=74203&r2=74202&pathrev=74203