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Prompt toolkit write multiline input to file and close the prompt

I would like to make some form of terminal editor for text-based files.
When started, it prints the current content of the file and makes it possible for user to edit in (multiline input). On press of CTRL + E, it should write that multiline input into specific file and close the prompt.
I have tried using this code, but it doesn't seem to work.
from prompt_toolkit import prompt, PromptSession
from prompt_toolkit.lexers import PygmentsLexer
from pygments.lexers.python import PythonLexer
from prompt_toolkit.formatted_text import HTML
from prompt_toolkit.key_binding import KeyBindings
file_path = 'output.txt'
file = open(file_path, 'r')
content = file.read()
new_content = None
session = PromptSession()
bindings = KeyBindings()
#bindings.add('c-e')
def _(event):
global new_content
global file_path
file = open(file_path, 'w')
file.write(new_content)
session.app.exit()
def show_prompt():
global new_content
global session
bottom_toolbar = HTML('<b><style background-color="white" color="green">Input</style></b>')
lexer = PygmentsLexer(PythonLexer)
new_content = session.prompt('\n',
default=content,
lexer=lexer,
multiline=True,
bottom_toolbar=bottom_toolbar,
key_bindings=bindings)
# Start of the program
if __name__ == '__main__':
show_prompt()

Delete a temporal file when it is closed in Python

I have a function similar to this:
def open_tmp():
tmp = mktemp()
copy('file.txt', tmp)
return open(tmp, 'rt')
And I would like to remove automatically the created temporal file when the file will close, for example:
file = open_tmp()
# Do something with file
file.close() # I want to remove the temporal file here
Is it possible? I thought to create a subclass of BaseIO and rewrite the close() function, but I think it is too much work because I would have to rewrite all the BaseIO methods.

You can try this code snippet. As per security concern I recommended to use tempfile instead of your code.
import os
import tempfile
new_file, file_path = tempfile.mkstemp()
try:
with os.fdopen(new_file, 'w') as temp_file:
# Do something with file
temp_file.write('write some dumy text in file')
finally:
os.remove(file_path)

I've found the solution:
import os
import tempfile
def open_tmp():
tmp = tempfile.mkstemp()
copy('file.txt', tmp) # This copy the file.txt to tmp
file = open(tmp, 'rt')
old_close = file.close
def close():
old_close()
os.remove(tmp)
file.close = close
return file

Creating a python script that returns the size of a new file

I'm trying to create_python_script function that creates a new python script in the current working directory, adds the line of comments to it declared by the 'comments' variable, and returns the size of the new file. The output I get is 0 but should be 31. Not sure what I'm doing wrong.
import os
def create_python_script(filename):
comments = "# Start of a new Python program"
with open("program.py", "w") as file:
filesize = os.path.getsize("/home/program.py")
return(filesize)
print(create_python_script("program.py"))

You forgot to actually write to the file, so it won't contain anything. Another important thing to keep in mind, is that the file is closed automatically after the with statement. In other words: nothing is written to the file until the with statement ends, so the file size is still zero in your program.
This should work:
import os
def create_python_script(filename):
comments = "# Start of a new Python program"
with open(filename, "w") as f:
f.write(comments)
filesize = os.path.getsize(filename)
return(filesize)
print(create_python_script("program.py"))
Note that the input argument was unused previously and has now been changed.

def create_python_script(filename):
comments = "# Start of a new Python program"
with open(filename, 'w') as file:
filesize = file.write(comments)
return(filesize)
print(create_python_script("program.py"))

There is a rogue indent in the exercise:
import os
def create_python_script(filename):
comments = "# Start of a new Python program"
with open(filename, "a") as newprogram:
newprogram.write(comments)
filesize = os.path.getsize(filename)
return(filesize)
print(create_python_script("program.py"))
It should be:
import os
def create_python_script(filename):
comments = "# Start of a new Python program"
with open(filename, "a") as newprogram:
newprogram.write(comments)
filesize = os.path.getsize(filename) #Error over here
return(filesize)
print(create_python_script("program.py"))
I just finished myself.

Reading a text document and converting it to a string

I'm trying to make a basic script that reads a specified text document, asks for a string of characters to replace and what to replace it, then saves it:
from tkinter import Tk, filedialog
from tkinter.filedialog import askopenfilename
Tk().withdraw()
def OpenFile():
fileName = askopenfilename(initialdir="C:/Users", filetypes = (("Text File", "*.txt"),("All Files","*.*")), title = "Open a document.")
with open(fileName, 'r') as f:
textFile = f.read()
OpenFile()
print(textFile)
There's an error when running the script and selecting a file
Traceback (most recent call last):
File "C:\Users\****\Documents\Python\Find and Replace\replace.py", line 11, in <module>
print(textFile)
NameError: name 'textFile' is not defined

Game on: find what's different:
from tkinter import Tk, filedialog
from tkinter.filedialog import askopenfilename
Tk().withdraw()
def OpenFile():
fileName = askopenfilename(initialdir="C:/Users", filetypes = (("Text File", "*.txt"),("All Files","*.*")), title = "Open a document.")
with open(fileName, 'r') as f:
textFile = f.read()
return textFile # RETURN THE FILE CONTENT HERE SO IT IS VISIBLE TO THE MAIN FUNCTION
textFile = OpenFile() # GET YOUR OUTPUT HERE SO YOU CAN PRINT IT ON THE NEXT LINE
print(textFile)

Python CSV.Writer changing saving path

I would like to have my tkinter program prompt the user to select the path the want to save the file which will be produced by the program.
My code looks like this. At this stage the program only saves to one file (the one I defined to test the program)
What code would I use to have 'test_write.csv' changed to any file the user chooses?
##Writing to .cvs file
with open('test_write.csv', 'w') as fp:
a = csv.writer(fp)
# write row of header names
a.writerow(n)
Thank you

Here's an example using tkFileDialog:
import Tkinter
import tkFileDialog
import csv
formats = [('Comma Separated values', '*.csv'), ]
root = Tkinter.Tk()
file_name = tkFileDialog.asksaveasfilename(parent=root, filetypes=formats, title="Save as...")
if file_name:
with open(file_name, 'w') as fp:
a = csv.writer(fp)
# write row of header names
a.writerow(n)

Use the tkFileDialog module.
Example:
import tkFileDialog
with open(tkFileDialog.asksaveasfilename(), "w") as fp:
...

Solution for python3.xxx
import tkinter
from tkinter.filedialog import asksaveasfilename
with open(asksaveasfilename(), 'w') as fp: