i have tried but can't seem to find my mistake in my code.
My code is suppose to switch all the alphabetic characters (like a/aa/A/AA) and do nothing with the rest but when i run the code it doesn't give an error yet do what i want.
Could anyone tell me what i have done wrong or have forgotten?
letter = input("type something")
shift = int(input("type how many shifts"))
if letter in ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']:
a = ord(letter) + shift
b = chr(a)
print(b)
else:
print(letter)
EDIT: thanks for the == replacement for in! Does someone know why using more than one character in letter gives the same print?(Desired output: when i put in abc and 1 i want it to print bcd)
I suppose you want to shift the letters so if the input letter is 'a' and shift is 3, then the output should be 'd'.
In that case replace
if letter == ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']:
with
if letter in ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']:
Or better yet as Tempux suggested you can use
if letter.isalpha()
If you want to shift multple letters you need to loop across each character. Try the following code for multiple letters
letter = input("type something")
shift = int(input("type how many shifts"))
s = ""
for l in letter:
if l.isalpha():
a = ord(l) + shift
s += chr(a)
else:
s += l
print(s)
You compare letter with list, but i think you want to check for contain letter in list, so you should just replace == to in
From the looks of it, I'd say you're more after something like this:
import string
text = input("type something> ")
shift = int(input("enter number of shifts> "))
for letter in text:
index = ord(letter) - ord('a') + shift
print(string.ascii_letters[index % len(string.ascii_letters)])
Related
I simply want to reprint what the user enters for -Wordinput-, what I have now works fine but is there an easier way in which I can do this? Please help!
list = ['a', 'b', 'c', 'd', 'e', 'f', 'g',
'h', 'i', 'j', 'k', 'l', 'm', 'n',
'o', 'p', 'q', 'r', 's', 't', 'u',
'v', 'w', 'x', 'y', 'z']
wordInput = input('Print your word: ')
for i in range(len(wordInput)):
indivLetter = wordInput[i].lower()
finalWord = [match for match in list if indivLetter in match]
print(*finalWord, end='')
Essentially I am trying to create a program that can go through all possible passwords one can create with aaaa-zzzz. I have the code down where it can count the number of passcodes and what they are such as 'abcd' or 'xkyz'. However when I try to implement the checking part of the code to pretty much tell it to stop and that the answer has been found, the program negates it and will go all the way down to 'zzzz' even if the given password is 'aaaa'.
import random
import sys
my_password = "aaaa"
guess_num = 0
done = False
while not done: #setup for the loop
my_password = "aaaa"
prime = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',]
prime2 = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',]
prime3 = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',]
prime4 = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',]
for a in prime:
for b in prime2:
for c in prime3:
for d in prime4:
first = (a + b + c + d) #loop that goes through all aaaa-zzzz
guess = str(first)
if guess == my_password:
print("found it after ", str(guess_num), " tries")
done = True
elif guess != my_password:
guess_num = guess_num + 1
print(guess, guess_num)
print(guess)
You should use itertools.product and string.ascii_lowercase to generate your password guesses. Then you can simplify your code to a simple loop:
import itertools
import string
guess_num = 1
my_password ='abcd'
prime = string.ascii_lowercase # abc...xyz
for guess in itertools.product(prime, repeat=4):
if ''.join(guess) == my_password:
print(f"found it after {guess_num} tries")
break
guess_num += 1
every time a user inputs a message rotorI.append(rotorI.pop(0)) executes on the edited list, i want it to execute on the original list.
rotorI = ['E', 'K', 'M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T','O', 'W','Y','H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J']
while True:
msg = input("Enter a msg: ")
for i in range(len(msg)):
rotorI.append(rotorI.pop(0))
print(rotorI)
I want the output to be:
Enter a msg: hi
['M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y', 'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K']
Enter a msg: hi
['M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y', 'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K']
however this the output i receive:
Enter a msg: hi
['M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y', 'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K']
Enter a msg: hi
['L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y', 'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K', 'M', 'F']
Use copy of your list with using copy()function:
your_main_list = ['E', 'K', 'M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T','O', 'W','Y','H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J']
while True:
msg = input("Enter a msg: ")
list_for_edit = your_main_list.copy()
for i in range(len(msg)):
list_for_edit.append(list_for_edit.pop(0))
print(list_for_edit)
Output is gonna be :
Enter a msg: hi
['M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y',
'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K']
Enter a msg: hi
['M', 'F', 'L', 'G', 'D', 'Q', 'V', 'Z', 'N', 'T', 'O', 'W', 'Y',
'H', 'X', 'U', 'S', 'P', 'A', 'I', 'B', 'R', 'C', 'J', 'E', 'K']
Enter a msg:
Make a copy of the list at each iteration
while True:
msg = input("Enter a msg: ")
newRotor = list(rotorI)
for i in range(len(msg)):
newRotor.append(newRotor.pop(0))
print(newRotor)
Using collections.deque and string for displaying
from collections import deque
rotorI = "EKMFLGDQVZNTOWYHXUSPAIBRCJ"
while True:
msg = input("Enter a msg: ")
newRotor = deque(rotorI)
newRotor.rotate(-len(msg))
print("".join(newRotor))
Enter a msg: hi
MFLGDQVZNTOWYHXUSPAIBRCJEK
Enter a msg: hih
FLGDQVZNTOWYHXUSPAIBRCJEKM
Enter a msg: hihi
LGDQVZNTOWYHXUSPAIBRCJEKMF
Enter a msg: hi
MFLGDQVZNTOWYHXUSPAIBRCJEK
I am trying to make a small program that will jumble up the letters of the alphabet(In simple terms)
I have tried to use things like list.pop() or list.remove(), But those did nothing
import random
def rand_let():
i = 26
alphabet = str('')
for a in range(1, 26):
key = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
print(len(key))
print(key)
letter = random.randint(1, i)
print(key[letter])
letters = key[letter]
alphabet += str(letters)
key.remove(letter)
i -= 1
rand_let()
I want it to jumble up the alphabet,
it is, but the way it is doing it will make letters repeat(I don't want it to repeat)
The shuffle function from random will save you many lines, and does what you're looking for:
import random
alphabet = ['A', 'B', 'C']
random.shuffle(alphabet)
print(alphabet)
#Ex: ['C', 'A', 'B']
The reason you are getting duplicates is that although you have code to remove the letter from the key list, the line that declares the key list is within the loop as well. Try moving the line
key = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
above the for loop. Or, as suggested in other answers, use a library to do this for you.
import random
import string
alphabet = [letter for letter in string.ascii_uppercase]
random.shuffle(alphabet)
print(alphabet)
This will just shuffle the list and then print the elements of the list one by one for each iteration of the for loop.
import random
key = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
random.shuffle(key)
def choice(x):
for letter in key:
print()
choice(key)
I was trying a sample exercise on regexes. To find all the letters of the alphabets. Sort the array, and finally eliminate all repetitions.
>>> letterRegex = re.compile(r'[a-z]')
>>> alphabets = letterRegex.findall("The quick brown fox jumped over the lazy dog")
>>> alphabets.sort()
>>> alphabets
['a', 'b', 'c', 'd', 'd', 'e', 'e', 'e', 'e', 'f', 'g', 'h', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'o', 'o', 'o', 'p', 'q', 'r', 'r', 't', 'u', 'u', 'v', 'w', 'x', 'y', 'z']
After doing the sort I tried to make a loop that'll eliminate all repetitions in the array.
e.g [...'e', 'e'...]
So I did this
>>> i, j = -1,0
>>> for items in range(len(alphabets)):
if alphabets[i+1] == alphabets[j+1]:
alphabets.remove(alphabets[j])
However it didn't work. How can I remove repetitons?
Here's a much easier way of removing co-occurrences:
import itertools
L = ['a', 'b', 'c', 'd', 'd', 'e', 'e', 'e', 'e', 'f', 'g', 'h', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'o', 'o', 'o', 'p', 'q', 'r', 'r', 't', 'u', 'u', 'v', 'w', 'x', 'y', 'z']
answer = []
for k,_group in itertools.groupby(L):
answer.append(k)
Or simpler still:
answer = [k for k,_g in itertools.groupby(L)]
Both yield this:
In [42]: print(answer)
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 't', 'u', 'v', 'w', 'x', 'y', 'z']