How to convert suds object to xml string - python

This is a duplicate to this question:
How to convert suds object to xml
But the question has not been answered: "totxt" is not an attribute on the Client class.
Unfortunately I lack of reputation to add comments. So I ask again:
Is there a way to convert a suds object to its xml?
I ask this because I already have a system that consumes wsdl files and sends data to a webservice. But now the customers want to alternatively store the XML as files (to import them later manually). So all I need are 2 methods for writing data: One writes to a webservice (implemented and tested), the other (not implemented yet) writes to files.
If only I could make something like this:
xml_as_string = My_suds_object.to_xml()
The following code is just an example and does not run. And it's not elegant. Doesn't matter. I hope you get the idea what I want to achieve:
I have the function "write_customer_obj_webservice" that works. Now I want to write the function "write_customer_obj_xml_file".
import suds
def get_customer_obj():
wsdl_url = r'file:C:/somepathhere/Customer.wsdl'
service_url = r'http://someiphere/Customer'
c = suds.client.Client(wsdl_url, location=service_url)
customer = c.factory.create("ns0:CustomerType")
return customer
def write_customer_obj_webservice(customer):
wsdl_url = r'file:C:/somepathhere/Customer.wsdl'
service_url = r'http://someiphere/Customer'
c = suds.client.Client(wsdl_url, location=service_url)
response = c.service.save(someparameters, None, None, customer)
return response
def write_customer_obj_xml_file(customer):
output_filename = r'C\temp\testxml'
# The following line is the problem. "to_xml" does not exist and I can't find a way to do it.
xml = customer.to_xml()
fo = open(output_filename, 'a')
try:
fo.write(xml)
except:
raise
else:
response = 'All ok'
finally:
fo.close()
return response
# Get the customer object always from the wsdl.
customer = get_customer_obj()
# Since customer is an object, setting it's attributes is very easy. There are very complex objects in this system.
customer.name = "Doe J."
customer.age = 42
# Write the new customer to a webservice or store it in a file for later proccessing
if later_processing:
response = write_customer_obj_xml_file(customer)
else:
response = write_customer_obj_webservice(customer)

I found a way that works for me. The trick is to create the Client with the option "nosend=True".
In the documentation it says:
nosend - Create the soap envelope but don't send. When specified, method invocation returns a RequestContext instead of sending it.
The RequestContext object has the attribute envelope. This is the XML as string.
Some pseudo code to illustrate:
c = suds.client.Client(url, nosend=True)
customer = c.factory.create("ns0:CustomerType")
customer.name = "Doe J."
customer.age = 42
response = c.service.save(someparameters, None, None, customer)
print response.envelope # This prints the XML string that would have been sent.

You have some issues in write_customer_obj_xml_file function:
Fix bad path:
output_filename = r'C:\temp\test.xml'
The following line is the problem. "to_xml" does not exist and I can't find a way to do it.
What's the type of customer? type(customer)?
xml = customer.to_xml() # to be continued...
Why mode='a'? ('a' => append, 'w' => create + write)
Use a with statement (file context manager).
with open(output_filename, 'w') as fo:
fo.write(xml)
Don't need to return a response string: use an exception manager. The exception to catch can be EnvironmentError.
Analyse
The following call:
customer = c.factory.create("ns0:CustomerType")
Construct a CustomerType on the fly, and return a CustomerType instance customer.
I think you can introspect your customer object, try the following:
vars(customer) # display the object attributes
help(customer) # display an extensive help about your instance
Another way is to try the WSDL URLs by hands, and see the XML results.
You may obtain the full description of your CustomerType object.
And then?
Then, with the attributes list, you can create your own XML. Use an XML template and fill it with the object attributes.
You may also found the magic function (to_xml) which do the job for you. But, not sure the XML format matches your need.

client = Client(url)
client.factory.create('somename')
# The last XML request by client
client.last_sent()
# The last XML response from Web Service
client.last_received()

Related

Getting specific value from dict

I have a view for getting a soap response (using suds)
The output I get is formatted like this:
('birthdate', None)('updated', datetime.date(2014, 7, 11))('connected_to', Test1,Test2)
My view code is like this:
def view_webservice(request):
#Url to WSDL file
url = 'https://www.domain.com/webservices.nsf/MemberService?WSDL'
imp = Import('http://schemas.xmlsoap.org/soap/encoding/')
doctor = ImportDoctor(imp)
client = Client(url, username='****', password='****', doctor=doctor)
user_id='000001'
result = client.service.readMember(userId=user_id)
return HttpResponse(result) #Output: ('birthdate', None)('updated', datetime.date(2014, 7, 11))('connected_to', Test1,Test2)
I have tried getting a value like this:
birthdate = result.get('birthdate') (error: MemberRead instance has no attribute 'get') birthdate = result('birthdate') (error: MemberRead instance has no call method)
What is the correct way of getting the value?
Edit:
My traceback of result is:
(MedlemRead){
birthdate = None
updated = 2014-07-11
connected_to = "Test1,Test2"
}
Edit 2:
The answer was doing: result.birthdate
SOAP is Simple Object Access Protocol, so the things you get back are objects. That's why the WSDL has such strict definitions of types of values to be sent and what to expect back.
Luckily, suds and other SOAP libraries take care of the mundane details for you and return to you a fully animated object of the correct type.
To access any values, you need to treat the response as an object; which means in your case the answer is result.birthdate.
Keep in mind that the returned object will have the correct types of data as well. So if you are expecting a custom nested object, you'll have to access it correctly.

Updating DataStore JSON values using endpoints (Python)

I am trying to use endpoints to update some JSON values in my datastore. I have the following Datastore in GAE...
class UsersList(ndb.Model):
UserID = ndb.StringProperty(required=True)
ArticlesRead = ndb.JsonProperty()
ArticlesPush = ndb.JsonProperty()
In general what I am trying to do with the API is have the method take in a UserID and a list of articles read (with an article being represented by a dictionary holding an ID and a boolean field saying whether or not the user liked the article). My messages (centered on this logic) are the following...
class UserID(messages.Message):
id = messages.StringField(1, required=True)
class Articles(messages.Message):
id = messages.StringField(1, required=True)
userLiked = messages.BooleanField(2, required=True)
class UserIDAndArticles(messages.Message):
id = messages.StringField(1, required=True)
items = messages.MessageField(Articles, 2, repeated=True)
class ArticleList(messages.Message):
items = messages.MessageField(Articles, 1, repeated=True)
And my API/Endpoint method that is trying to do this update is the following...
#endpoints.method(UserIDAndArticles, ArticleList,
name='user.update',
path='update',
http_method='GET')
def get_update(self, request):
userID = request.id
articleList = request.items
queryResult = UsersList.query(UsersList.UserID == userID)
currentList = []
#This query always returns only one result back, and this for loop is the only way
# I could figure out how to access the query results.
for thing in queryResult:
currentList = json.loads(thing.ArticlesRead)
for item in articleList:
currentList.append(item)
for blah in queryResult:
blah.ArticlesRead = json.dumps(currentList)
blah.put()
for thisThing in queryResult:
pushList = json.loads(thisThing.ArticlesPush)
return ArticleList(items = pushList)
I am having two problems with this code. The first is that I can't seem to figure out (using the localhost Google APIs Explorer) how to send a list of articles to the endpoints method using my UserIDAndArticles class. Is it possible to have a messages.MessageField() as an input to an endpoint method?
The other problem is that I am getting an error on the 'blah.ArticlesRead = json.dumps(currentList)' line. When I try to run this method with some random inputs, I get the following error...
TypeError: <Articles
id: u'hi'
userLiked: False> is not JSON serializable
I know that I have to make my own JSON encoder to get around this, but I'm not sure what the format of the incoming request.items is like and how I should encode it.
I am new to GAE and endpoints (as well as this kind of server side programming in general), so please bear with me. And thanks so much in advance for the help.
A couple things:
http_method should definitely be POST, or better yet PATCH because you're not overwriting all existing values but only modifying a list, i.e. patching.
you don't need json.loads and json.dumps, NDB does it automatically for you.
you're mixing Endpoints messages and NDB model properties.
Here's the method body I came up with:
# get UsersList entity and raise an exception if none found.
uid = request.id
userlist = UsersList.query(UsersList.UserID == uid).get()
if userlist is None:
raise endpoints.NotFoundException('List for user ID %s not found' % uid)
# update user's read articles list, which is actually a dict.
for item in request.items:
userslist.ArticlesRead[item.id] = item.userLiked
userslist.put()
# assuming userlist.ArticlesPush is actually a list of article IDs.
pushItems = [Article(id=id) for id in userlist.ArticlesPush]
return ArticleList(items=pushItems)
Also, you should probably wrap this method in a transaction.

open('file_path').read() - save contents back to file

I need to upload a file to the server using urllib2. Since I cannot use any external libraries (like requests and others) because I am using OpenOffice python, I needed a simple way to post file data.
So I came with:
post_url = "http://localhost:8000/admin/oo_file_uploader?user_id=%s&file_id=%s" % (user_id, file_id)
file_path = doc.Location.replace('file://', '')
data = urllib.urlencode({"file": open(file_path).read()})
urllib2.urlopen(post_url, data)
which posts something to the server.
I wonder if it is possible to save posted contents back to the file using python/django?
This expands somewhat on #zero323's answer. You will want to make sure that you implement some sort of security to prevent random files being uploaded by unauthorized users, which is what the #file_upload_security decorator is implied to handle.
#file_upload_security
def oo_file_uploader(user_id=None, file_id=None):
if request.method == 'POST':
# Exception handling skipped if get() fails.
user = User.objects.get(id=user_id)
save_to_file = MyFiles.objects.get(id=file_id)
# You will probably want to ensure 'file' is in post data.
file_contents = save_to_file.parse_post_to_content(request.POST['file'])
with open(save_to_file.path_to_file, 'w') as fw:
fw.write(file_contents)

How do I handle file upload via PUT request in Django?

I'm implementing a REST-style interface and would like to be able to create (via upload) files via a HTTP PUT request. I would like to create either a TemporaryUploadedFile or a InMemoryUploadedFile which I can then pass to my existing FileField and .save() on the object that is part of the model, thereby storing the file.
I'm not quite sure about how to handle the file upload part. Specifically, this being a put request, I do not have access to request.FILES since it does not exist in a PUT request.
So, some questions:
Can I leverage existing functionality in the HttpRequest class, specifically the part that handles file uploads? I know a direct PUT is not a multipart MIME request, so I don't think so, but it is worth asking.
How can I deduce the mime type of what is being sent? If I've got it right, a PUT body is simply the file without prelude. Do I therefore require that the user specify the mime type in their headers?
How do I extend this to large amounts of data? I don't want to read it all into memory since that is highly inefficient. Ideally I'd do what TemporaryUploadFile and related code does - write it part at a time?
I've taken a look at this code sample which tricks Django into handling PUT as a POST request. If I've got it right though, it'll only handle form encoded data. This is REST, so the best solution would be to not assume form encoded data will exist. However, I'm happy to hear appropriate advice on using mime (not multipart) somehow (but the upload should only contain a single file).
Django 1.3 is acceptable. So I can either do something with request.raw_post_data or request.read() (or alternatively some other better method of access). Any ideas?
Django 1.3 is acceptable. So I can
either do something with
request.raw_post_data or
request.read() (or alternatively some
other better method of access). Any
ideas?
You don't want to be touching request.raw_post_data - that implies reading the entire request body into memory, which if you're talking about file uploads might be a very large amount, so request.read() is the way to go. You can do this with Django <= 1.2 as well, but it means digging around in HttpRequest to figure out the the right way to use the private interfaces, and it's a real drag to then ensure your code will also be compatible with Django >= 1.3.
I'd suggest that what you want to do is to replicate the existing file upload behaviour parts of the MultiPartParser class:
Retrieve the upload handers from request.upload_handlers (Which by default will be MemoryFileUploadHandler & TemporaryFileUploadHandler)
Determine the request's content length (Search of Content-Length in HttpRequest or MultiPartParser to see the right way to do this.)
Determine the uploaded file's filename, either by letting the client specify this using the last path part of the url, or by letting the client specify it in the "filename=" part of the Content-Disposition header.
For each handler, call handler.new_file with the relevant args (mocking up a field name)
Read the request body in chunks using request.read() and calling handler.receive_data_chunk() for each chunk.
For each handler call handler.file_complete(), and if it returns a value, that's the uploaded file.
How can I deduce the mime type of what
is being sent? If I've got it right, a
PUT body is simply the file without
prelude. Do I therefore require that
the user specify the mime type in
their headers?
Either let the client specify it in the Content-Type header, or use python's mimetype module to guess the media type.
I'd be interested to find out how you get on with this - it's something I've been meaning to look into myself, be great if you could comment to let me know how it goes!
Edit by Ninefingers as requested, this is what I did and is based entirely on the above and the django source.
upload_handlers = request.upload_handlers
content_type = str(request.META.get('CONTENT_TYPE', ""))
content_length = int(request.META.get('CONTENT_LENGTH', 0))
if content_type == "":
return HttpResponse(status=400)
if content_length == 0:
# both returned 0
return HttpResponse(status=400)
content_type = content_type.split(";")[0].strip()
try:
charset = content_type.split(";")[1].strip()
except IndexError:
charset = ""
# we can get the file name via the path, we don't actually
file_name = path.split("/")[-1:][0]
field_name = file_name
Since I'm defining the API here, cross browser support isn't a concern. As far as my protocol is concerned, not supplying the correct information is a broken request. I'm in two minds as to whether I want say image/jpeg; charset=binary or if I'm going to allow non-existent charsets. In any case, I'm putting setting Content-Type validly as a client-side responsibility.
Similarly, for my protocol, the file name is passed in. I'm not sure what the field_name parameter is for and the source didn't give many clues.
What happens below is actually much simpler than it looks. You ask each handler if it will handle the raw input. As the author of the above states, you've got MemoryFileUploadHandler & TemporaryFileUploadHandler by default. Well, it turns out MemoryFileUploadHandler will when asked to create a new_file decide whether it will or not handle the file (based on various settings). If it decides it's going to, it throws an exception, otherwise it won't create the file and lets another handler take over.
I'm not sure what the purpose of counters was, but I've kept it from the source. The rest should be straightforward.
counters = [0]*len(upload_handlers)
for handler in upload_handlers:
result = handler.handle_raw_input("",request.META,content_length,"","")
for handler in upload_handlers:
try:
handler.new_file(field_name, file_name,
content_type, content_length, charset)
except StopFutureHandlers:
break
for i, handler in enumerate(upload_handlers):
while True:
chunk = request.read(handler.chunk_size)
if chunk:
handler.receive_data_chunk(chunk, counters[i])
counters[i] += len(chunk)
else:
# no chunk
break
for i, handler in enumerate(upload_handlers):
file_obj = handler.file_complete(counters[i])
if not file_obj:
# some indication this didn't work?
return HttpResponse(status=500)
else:
# handle file obj!
Newer Django versions allow for handling this a lot easier thanks to https://gist.github.com/g00fy-/1161423
I modified the given solution like this:
if request.content_type.startswith('multipart'):
put, files = request.parse_file_upload(request.META, request)
request.FILES.update(files)
request.PUT = put.dict()
else:
request.PUT = QueryDict(request.body).dict()
to be able to access files and other data like in POST. You can remove the calls to .dict() if you want your data to be read-only.
I hit this problem while working with Django 2.2, and was looking for something that just worked for uploading a file via PUT request.
from django.http import QueryDict
from django.http.multipartparser import MultiValueDict
from django.core.files.uploadhandler import (
SkipFile,
StopFutureHandlers,
StopUpload,
)
class PutUploadMiddleware(object):
def __init__(self, get_response):
self.get_response = get_response
def __call__(self, request):
method = request.META.get("REQUEST_METHOD", "").upper()
if method == "PUT":
self.handle_PUT(request)
return self.get_response(request)
def handle_PUT(self, request):
content_type = str(request.META.get("CONTENT_TYPE", ""))
content_length = int(request.META.get("CONTENT_LENGTH", 0))
file_name = request.path.split("/")[-1:][0]
field_name = file_name
content_type_extra = None
if content_type == "":
return HttpResponse(status=400)
if content_length == 0:
# both returned 0
return HttpResponse(status=400)
content_type = content_type.split(";")[0].strip()
try:
charset = content_type.split(";")[1].strip()
except IndexError:
charset = ""
upload_handlers = request.upload_handlers
for handler in upload_handlers:
result = handler.handle_raw_input(
request.body,
request.META,
content_length,
boundary=None,
encoding=None,
)
counters = [0] * len(upload_handlers)
for handler in upload_handlers:
try:
handler.new_file(
field_name,
file_name,
content_type,
content_length,
charset,
content_type_extra,
)
except StopFutureHandlers:
break
for chunk in request:
for i, handler in enumerate(upload_handlers):
chunk_length = len(chunk)
chunk = handler.receive_data_chunk(chunk, counters[i])
counters[i] += chunk_length
if chunk is None:
# Don't continue if the chunk received by
# the handler is None.
break
for i, handler in enumerate(upload_handlers):
file_obj = handler.file_complete(counters[i])
if file_obj:
# If it returns a file object, then set the files dict.
request.FILES.appendlist(file_name, file_obj)
break
any(handler.upload_complete() for handler in upload_handlers)

SUDS - programmatic access to methods and types

I'm investigating SUDS as a SOAP client for python. I want to inspect the methods available from a specified service, and the types required by a specified method.
The aim is to generate a user interface, allowing users to select a method, then fill in values in a dynamically generated form.
I can get some information on a particular method, but am unsure how to parse it:
client = Client(url)
method = client.sd.service.methods['MyMethod']
I am unable to programmaticaly figure out what object type I need to create to be able to call the service
obj = client.factory.create('?')
res = client.service.MyMethod(obj, soapheaders=authen)
Does anyone have some sample code?
Okay, so SUDS does quite a bit of magic.
A suds.client.Client, is built from a WSDL file:
client = suds.client.Client("http://mssoapinterop.org/asmx/simple.asmx?WSDL")
It downloads the WSDL and creates a definition in client.wsdl. When you call a method using SUDS via client.service.<method> it's actually doing a whole lot of recursive resolve magic behind the scenes against that interpreted WSDL. To discover the parameters and types for methods you'll need to introspect this object.
For example:
for method in client.wsdl.services[0].ports[0].methods.values():
print '%s(%s)' % (method.name, ', '.join('%s: %s' % (part.type, part.name) for part in method.soap.input.body.parts))
This should print something like:
echoInteger((u'int', http://www.w3.org/2001/XMLSchema): inputInteger)
echoFloatArray((u'ArrayOfFloat', http://soapinterop.org/): inputFloatArray)
echoVoid()
echoDecimal((u'decimal', http://www.w3.org/2001/XMLSchema): inputDecimal)
echoStructArray((u'ArrayOfSOAPStruct', http://soapinterop.org/xsd): inputStructArray)
echoIntegerArray((u'ArrayOfInt', http://soapinterop.org/): inputIntegerArray)
echoBase64((u'base64Binary', http://www.w3.org/2001/XMLSchema): inputBase64)
echoHexBinary((u'hexBinary', http://www.w3.org/2001/XMLSchema): inputHexBinary)
echoBoolean((u'boolean', http://www.w3.org/2001/XMLSchema): inputBoolean)
echoStringArray((u'ArrayOfString', http://soapinterop.org/): inputStringArray)
echoStruct((u'SOAPStruct', http://soapinterop.org/xsd): inputStruct)
echoDate((u'dateTime', http://www.w3.org/2001/XMLSchema): inputDate)
echoFloat((u'float', http://www.w3.org/2001/XMLSchema): inputFloat)
echoString((u'string', http://www.w3.org/2001/XMLSchema): inputString)
So the first element of the part's type tuple is probably what you're after:
>>> client.factory.create(u'ArrayOfInt')
(ArrayOfInt){
_arrayType = ""
_offset = ""
_id = ""
_href = ""
_arrayType = ""
}
Update:
For the Weather service it appears that the "parameters" are a part with an element not a type:
>>> client = suds.client.Client('http://www.webservicex.net/WeatherForecast.asmx?WSDL')
>>> client.wsdl.services[0].ports[0].methods.values()[0].soap.input.body.parts[0].element
(u'GetWeatherByZipCode', http://www.webservicex.net)
>>> client.factory.create(u'GetWeatherByZipCode')
(GetWeatherByZipCode){
ZipCode = None
}
But this is magic'd into the parameters of the method call (a la client.service.GetWeatherByZipCode("12345"). IIRC this is SOAP RPC binding style? I think there's enough information here to get you started. Hint: the Python command line interface is your friend!
According to suds documentation, you can inspect service object with __str()__. So the following gets a list of methods and complex types:
from suds.client import Client;
url = 'http://www.webservicex.net/WeatherForecast.asmx?WSDL'
client = Client(url)
temp = str(client);
The code above produces following result (contents of temp):
Suds ( https://fedorahosted.org/suds/ ) version: 0.3.4 (beta) build: R418-20081208
Service ( WeatherForecast ) tns="http://www.webservicex.net"
Prefixes (1)
ns0 = "http://www.webservicex.net"
Ports (2):
(WeatherForecastSoap)
Methods (2):
GetWeatherByPlaceName(xs:string PlaceName, )
GetWeatherByZipCode(xs:string ZipCode, )
Types (3):
ArrayOfWeatherData
WeatherData
WeatherForecasts
(WeatherForecastSoap12)
Methods (2):
GetWeatherByPlaceName(xs:string PlaceName, )
GetWeatherByZipCode(xs:string ZipCode, )
Types (3):
ArrayOfWeatherData
WeatherData
WeatherForecasts
This would be much easier to parse. Also every method is listed with their parameters along with their types. You could, probably, even use just regular expression to extract information you need.
Here's a quick script I wrote based on the above information to list the input methods suds reports as available on a WSDL. Pass in the WSDL URL. Works for the project I'm currently on, I can't guarantee it for yours.
import suds
def list_all(url):
client = suds.client.Client(url)
for service in client.wsdl.services:
for port in service.ports:
methods = port.methods.values()
for method in methods:
print(method.name)
for part in method.soap.input.body.parts:
part_type = part.type
if(not part_type):
part_type = part.element[0]
print(' ' + str(part.name) + ': ' + str(part_type))
o = client.factory.create(part_type)
print(' ' + str(o))
You can access suds's ServiceDefinition object. Here's a quick sample:
from suds.client import Client
c = Client('http://some/wsdl/link')
types = c.sd[0].types
Now, if you want to know the prefixed name of a type, it's also quite easy:
c.sd[0].xlate(c.sd[0].types[0][0])
This double bracket notation is because the types are a list (hence a first [0]) and then in each item on this list there may be two items. However, suds's internal implementation of __unicode__ does exactly that (i.e. takes only the first item on the list):
s.append('Types (%d):' % len(self.types))
for t in self.types:
s.append(indent(4))
s.append(self.xlate(t[0]))
Happy coding ;)
Once you created WSDL method object you can get information about it from it's __metadata__, including list of it's arguments' names.
Given the argument's name, you can access it's actual instance in the method created. That instance also contains it's information in __metadata__, there you can get it's type name
# creating method object
method = client.factory.create('YourMethod')
# getting list of arguments' names
arg_names = method.__metadata__.ordering
# getting types of those arguments
types = [method.__getitem__(arg).__metadata__.sxtype.name for arg in arg_names]
Disclaimer: this only works with complex WSDL types. Simple types, like strings and numbers, are defaulted to None
from suds.client import Client
url = 'http://localhost:1234/sami/2009/08/reporting?wsdl'
client = Client(url)
functions = [m for m in client.wsdl.services[0].ports[0].methods]
count = 0
for function_name in functions:
print (function_name)
count+=1
print ("\nNumber of services exposed : " ,count)
i needed an example of using suds with objects.
beside the answers found here, i found a very good article
that answered my question even further.
here is a short summary:
first, print the client to see an overview of it's content.
from suds.client import Client client =
Client("https://wsvc.cdiscount.com/MarketplaceAPIService.svc?wsdl")
print client
second, create an instance of a type (using it's name including it's prefix ns*.), and print it, to see it's member data.
HeaderMessage = client.factory.create('ns0:HeaderMessage')
print HeaderMessage
to fill your object's data members, either assign them a scalar value for scalar members, or a dict, to object members.
HeaderMessage.Context = {
"CatalogID": "XXXXX"
"CustomerID": 'XXXXX'
"SiteID": 123
}
members whose type name start with ArrayOf expect a list of objects of the type mentioned in the rest of the type name.
ArrayOfDomainRights = client.factory.create('ns0:ArrayOfDomainRights')
ArrayOfDomainRights.DomainRights = [XXXXXXXXXXXXX, XXXXXXXXXXXX]
i needed an example of using suds with objects.
beside the answers found here, i found a very good article
that answered my question even further.
here is a short summary:
first, print the client to see an overview of it's content.
from suds.client import Client client =
Client("https://wsvc.cdiscount.com/MarketplaceAPIService.svc?wsdl")
print client
second, create an instance of a type (using it's name including it's prefix ns*.), and print it, to see it's member data.
HeaderMessage = client.factory.create('ns0:HeaderMessage')
print HeaderMessage
to fill your object's data members, either assign them a scalar value for scalar members, or a dict, to object members.
HeaderMessage.Context = {
"CatalogID": "XXXXX"
"CustomerID": 'XXXXX'
"SiteID": 123
}
members whose type name start with ArrayOf expect a list of objects of the type mentioned in the rest of the type name.
ArrayOfDomainRights = client.factory.create('ns0:ArrayOfDomainRights')
ArrayOfDomainRights.DomainRights = [XXXXXXXXXXXXX, XXXXXXXXXXXX]

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