This question already has answers here:
Correct code to remove the vowels from a string in Python
(13 answers)
Closed 6 years ago.
I wrote this function in Python which takes string as an input and the outputs the same string with all chars in lower case, with vowels removed. It's not working as expected, why is that?
def removingVowels(string):
string.lower()
vowels = ['a','e','i','o','u']
for char in string:
if char in vowels:
del string[char]
return string
print (removingVowels("HadEEl"))
Strings are immutable in Python, so you cannot delete a character from them. You need to create a new string.
You would do something like this:
>>> def removingVowels(string):
... string=string.lower()
... return ''.join([c for c in string if c not in 'aeiou'])
...
>>> removingVowels("HadEEl")
'hdl'
How it works:
string=string.lower() You need to assign the result of the string.lower() back to string. It is a common error in Python not to do that.
We then have a list comprehension that interates over the string character by character. The list comprehension builds a list of each character unless it is a member of the string 'aeiou'
The list needs to be joined character by character to form a new string. That is then retuned.
Related
This question already has answers here:
Find common characters between two strings
(5 answers)
Closed 2 months ago.
I have a string of text
hfHrpphHBppfTvmzgMmbLbgf
I have separated this string into two half's
hfHrpphHBppf,TvmzgMmbLbgf
I'd like to check if any of the characters in the first string, also appear in the second string, and would like to class lowercase and uppercase characters as separate (so if string 1 had a and string 2 had A this would not be a match).
and the above would return:
f
split_text = ['hfHrpphHBppf', 'TvmzgMmbLbgf']
for char in split_text[0]:
if char in split_text[1]:
print(char)
There is probably a better way to do it, but this a quick and simple way to do what you want.
Edit:
split_text = ['hfHrpphHBppf', 'TvmzgMmbLbgf']
found_chars = []
for char in split_text[0]:
if char in split_text[1] and char not in found_chars:
found_chars.append(char)
print(char)
There is almost certainly a better way of doing this, but this is a way of doing it with the answer I already gave
You could use the "in" word.
something like this :
for i in range(len(word1) :
if word1[i] in word2 :
print(word[i])
Not optimal, but it should print you all the letter in common
You can achieve this using set() and intersection
text = "hfHrpphHBppf,TvmzgMmbLbgf"
text = text.split(",")
print(set(text[0]).intersection(set(text[1])))
You can use list comprehension in order to check if letters from string a appears in string b.
a='hfHrpphHBppf'
b='TvmzgMmbLbgf'
c=[x for x in a if x in b]
print(' '.join(set(c)))
then output will be:
f
But you can use for,too. Like:
a='hfHrpphHBppf'
b='TvmzgMmbLbgf'
c=[]
for i in a:
if i in b:
c.append(i)
print(set(c))
This question already has answers here:
Keeping only certain characters in a string using Python?
(3 answers)
Closed 1 year ago.
I'm just a beginner so this might be a stupid question but, I'm trying to remove every character from a string except the ones in a list
for example:
you have a string H][e,l}l.o1;4.I want only letters and numbers in the output.
It should look like this:
Hello14
Does anyone have any idea what needs to come behind the str1 = or any other methods?
This is what I tried so far:
def stringCleaner(s):
# initialize an empty string
str1 = " "
chars = set('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ')
for x in range(len(s)):
if any((c in chars) for c in s):
str1=
return str1
It will be better to simply iterate over your input string and create a list of allowed characters and join() the list into a string again at the end.
def stringCleaner(s):
# initialize an empty list
str1 = []
chars = set('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ')
for c in s:
if c in chars:
str1.append(c)
return ''.join(str1)
And then you should be able to see that its only a few short steps to get even better code such as the answer that #user1740577 has posted.
You can for any char in s check in chars list and .join() all of them if exist in chars list.
Try this:
def stringCleaner(s):
chars = set('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ')
return ''.join(c for c in s if c in chars)
stringCleaner('H][e,l}l.o1;4.I')
# 'Hello14I'
This question already has answers here:
Removing numbers from string [closed]
(8 answers)
Closed 5 years ago.
Im looking to remove every single number in a string. More specifically, i'm looking to remove all numbers in the following codes string
Comp_String = "xxf1,aff242342"
how can one do this. (Obviously inside the code). I have found many answers to questions about removing the actual parts of the code that are letters but not numbers. Please explain aswell what your code is actually doing
You can find the answer here
Removing numbers from string
From this answer:
comp_string = "xxf1,aff242342"
new_string = ''.join([i for i in comp_string if not i.isdigit()])
It creates a new string using .join from a list. That list is created using a list comprehension that iterates through characters in your original string, and excludes all digits.
This will remove any characters that ARE NOT letters, by going through each character and only adding it to the output if it is a letter:
output_string = ""
for char in Comp_String:
if char.isalpha():
output_string = output_string + char
This will remove any characters that ARE numbers, by going through each character and only adding it to the output if it is not a number:
output_string = ""
for char in Comp_String:
if not char.isdigit():
output_string = output_string + char
You can do it with regular expressions using the https://docs.python.org/3.6/library/re.html module. The only regex you need is \d, which notates digits.
from re import sub
comp_string = "xxf1,aff242342"
print(sub(pattern=r"\d", repl=r"", string=comp_string))
This question already has answers here:
How to concatenate (join) items in a list to a single string
(11 answers)
Closed 7 years ago.
I know in python there is a way to turn a word or string into a list using list(), but is there a way of turning it back, I have:
phrase_list = list(phrase)
I have tried to change it back into a string using repr() but it keeps the syntax and only changes the data type.
I am wondering if there is a way to turn a list, e.g. ['H','e','l','l','o'] into: 'Hello'.
Use the str.join() method; call it on a joining string and pass in your list:
''.join(phrase)
Here I used the empty string to join the elements of phrase, effectively concatenating all the characters back together into one string.
Demo:
>>> phrase = ['H','e','l','l','o']
>>> ''.join(phrase)
'Hello'
Using ''.join() is the best approach but you could also you a for loop. (Martijn beat me to it!)
hello = ['H','e','l','l','o']
hello2 = ''
for character in hello:
hello2 += character
This question already has answers here:
python capitalize first letter only
(10 answers)
Closed 9 years ago.
I'd like to capitalize the first letter in a string. The string will be a hash (and therefore mostly numbers), so string.title() won't work, because a string like 85033ba6c would be changed to 85033Ba6C, not 85033Ba6c, because the number seperates words, confusing title(). I'd like to capitalize the first letter of a string, no matter how far into the string the letter is. Is there a function for this?
Using re.sub with count:
>>> strs = '85033ba6c'
>>> re.sub(r'[A-Za-z]',lambda m:m.group(0).upper(),strs,1)
'85033Ba6c'
It is assumed in this answer that there is at least one character in the string where isalpha will return True (otherwise, this raises StopIteration)
i,letter = next(x for x in enumerate(myhash) if x[1].isalpha())
new_string = ''.join((myhash[:i],letter.upper(),myhash[i+1:]))
Here, I pick out the character (and index) of the first alpha character in the string. I turn that character into an uppercase character and I join the rest of the string with it.