ok = 1
while ok==1:
sum = 0
count = 0
a = int(input("Ievadiet, cik skaitļu būs virknē: "))
for i in range( 0, a):
N = int(input("Ievadiet veselu skaitli: "))
if N%2 == 1:
count+= 1
sum += N
if count != 0:
average = sum / count
print("Virknes nepāra skaitļu vidējā artimētiskā vērtība ir: ", average)
else:
print("Nevar aprēķināt nepāra skaitļu vidējo aritmētisko.")
ok = int(input(" Vai turpināt (1) vai beigt (0)?"))
This program should ask to type how many numbers will be in chain and then calculate the existing between these numbers the arithmetic mean of the odd numbers. How to separate "if count != 0" from "if N%2 == 1" so the programm will stop calculating arithmetic mean of every number but will calculated only when all numbers of the chain will be written.
Please check this code and see if that if what you want to reach. I just de-indented the last if...else block so no it first gets all the numbers and then shows the mean.
ok = 1
while ok == 1:
sum = 0
count = 0
a = int(input("Ievadiet, cik skaitļu būs virknē: "))
for i in range(0, a):
N = int(input("Ievadiet veselu skaitli: "))
if N % 2 == 1:
count += 1
sum += N
if count != 0:
average = sum / count
print("Virknes nepāra skaitļu vidējā artimētiskā vērtība ir: ", average)
else:
print("Nevar aprēķināt nepāra skaitļu vidējo aritmētisko.")
ok = int(input(" Vai turpināt (1) vai beigt (0)?"))
Have Fun :)
My task is to:
"Write a program that will keep asking the user for some numbers.
If the user hits enter/return without typing anything, the program stops and prints the average of all the numbers that were given. The average should be given to 2 decimal places.
If at any point a 0 is entered, that should not be included in the calculation of the average"
I've been trying for a while, but I can't figure out how to make the programs act on anything I instruct when the user hits 'enter' or for it to ignore the 0.
This is my current code:
count = 0
sum = 0
number = 1
while number >= 0:
number = int(input())
if number == '\n':
print ('hey')
break
if number > 0:
sum = sum + number
count= count + 1
elif number == 0:
count= count + 1
number += 1
avg = str((sum/count))
print('Average is {:.2f}'.format(avg))
You're very close! Almost all of it is perfect!
Here is some more pythonic code, that works.
I've put comments explaining changes:
count = 0
sum = 0
# no longer need to say number = 1
while True: # no need to check for input number >= 0 here
number = input()
if number = '': # user just hit enter key, input left blank
print('hey')
break
if number != 0:
sum += int(number) # same as sum = sum + number
count += 1 # same as count = count + 1
# if number is 0, we don't do anything!
print(f'Average is {count/sum:.2f}') # same as '... {:.2f} ...'.format(count/sum)
Why your code didn't work:
When a user just presses enter instead of typing a number, the input() function doesn't return '\n', rather it returns ''.
I really hope this helps you learn!
Try this:
amount = 0 # Number of non-zero numbers input
nums = 0 # Sum of numbers input
while True:
number = input()
if not number: # Breaks out if nothing is entered
break
if int(number) != 0: # Only add to the variables if the number input is not 0
nums+=int(number)
amount += 1
print(round(nums/amount,2)) # Print out the average rounded to 2 digits
Input:
1
2
3
4
Output:
2.5
Or you can use numpy:
import numpy as np
n = []
while True:
number = input()
if not number: # Breaks out if nothing is entered
break
if int(number) != 0: # Only add to the variables if the number input is not 0
n.append(int(number))
print(round(np.average(n),2)) # Print out the average rounded to 2 digits
A list can store information of the values, number of values and the order of the values.
Try this:
numbers = []
while True:
num = input('Enter number:')
if num == '':
print('Average is', round(sum(numbers)/len(numbers), 2)) # print
numbers = [] # reset
if num != '0' and num != '': numbers.append(int(num)) # add to list
Benefit of this code, it does not break out and runs continuously.
This is my Task:
Require the user to enter their name, with only a certain name being able to trigger the loop.
Print out the number of tries it took the user before inputting the correct number.
Add a conditional statement that will cause the user to exit the program without giving the average of the numbers entered if they enter a certain input
numbers = []
number = 0
count = 0
total = 0
name = 0
while number >= 0:
number = int(raw_input("Please enter any number: \n"))
if number == -1:
break
numbers.append(number)
avg = float(sum(numbers)) / len(numbers)
print "The average of the numbers you entered is " + str(avg) + "!"
while name >= 0:
name = int(raw_input("Please enter the number of characters your name contains: \n"))
count += 1
total += count
if name == 6:
break
tries = sum(total)
print tries
tries = sum(total)... sum takes an iterable whereas total is an int hence the error.
If total = [ ]
and you can append count values in total that would be fine.
so total.append(count)
would create list then you can use sum(total) on it
but here you can simply use print total or count both are same.
numbers = []
number = 0
count = 0
total = 0
name = 0
while number >= 0:
number = int(raw_input("Please enter any number: \n"))
if number == -1:
break
numbers.append(number)
avg = float(sum(numbers)) / len(numbers)
print "The average of the numbers you entered is " + str(avg) + "!"
while name >= 0:
name = int(raw_input("Please enter the number of characters your name contains: \n"))
count += 1
total += count
if name == 6:
break
tries = total
print tries
and you try to reduce your code.
Write a program which repeatedly reads numbers until the user enters "done". Once "done" is entered, print out the total, count, and average of the numbers. If the user enters anything other than a number, detect their mistake using try and except and print an error message and skip to the next number.
This is what I have.
total = 0
count = 0
average = 0
while True:
number = input("Enter a number:")
if number == "done":
break
try:
total += numbers
count += 1
average = total / len(number)
except:
print ("Invalid input")
continue
print (total, count, average)
When I run this, I always get invalid input for some reason. My except part must be wrong.
EDIT:
This is what I have now and it works. I do need, however, try and except, for non numbers.
total = 0
count = 0
average = 0
while True:
number = input("Enter a number:")
if number == "done":
break
total += float(number)
count += 1
average = total / count
print (total, count, average)
I think I got it?!?!
total = 0
count = 0
average = 0
while True:
number = input("Enter a number:")
try:
if number == "done":
break
total += float(number)
count += 1
average = total / count
except:
print ("Invalid input")
print ("total:", total, "count:", count, "average:", average)
Should I panic if this took me like an hour?
This isn't my first programming language but it's been a while.
I know this is old, but thought I'd throw my 2-cents in there (since I myself many years later am using the same examples to learn). You could try:
values=[]
while True:
A=input('Please type in a number.\n')
if A == 'done':
break
try:
B=int(A)
values.append(B)
except:
print ('Invalid input')
total=sum(values)
average=total/(len(values))
print (total, len(values), average)
I find this a tad cleaner (and personally easier to follow).
The problem is when you try to use your input:
try:
total += numbers
First, there is no value numbers; your variable is singular, not plural. Second, you have to convert the text input to a number. Try this:
try:
total += int(number)
It's because there is no len(number) when number is an int. len is for finding the length of lists/arrays. you can test this for yourself by commenting out the try/except/continue. I think the code below is more what you are after?
total = 0
count = 0
average = 0
while True:
number = input("Enter a number:")
if number == "done":
break
try:
total += number
count += 1
average = total / count
except:
print ("Invalid input")
continue
print (total, count, average)
note there are still some issues. for example you literally have to type "done" in the input box in order to not get an error, but this fixes your initial problem because you had len(number) instead of count in your average. also note that you had total += numbers. when your variable is number not numbers. be careful with your variable names/usage.
A solution...
total = 0
count = 0
average = 0
while True:
number = input("Enter a number:")
if number == "done":
break
else:
try:
total += int(number)
count += 1
average = total / count
except ValueError as ex:
print ("Invalid input")
print('"%s" cannot be converted to an int: %s' % (number, ex))
print (total, count, average)
Problems with your code:
total+=numbers # numbers don't exist; is number
len(number) # number is a string. for the average you need count
if is not done, else process it
Use try ... except ValueError to catch problem when convert the number to int.
Also, you can use try ... except ValueError as ex to get an error message more comprehensible.
So, after several attempts, I got the solution
num = 0
count = 0
total = 0
average = 0
while True:
num = input('Enter a number: ')
if num == "done":
break
try:
float(num)
except:
continue
total = total + float(num)
count = count + 1
average = total / count
print(total, count, average)
Old problem with Update solutions
num = 0
total = 0.0
while True:
number = input("Enter a number")
if number == 'done':
break
try :
num1 = float(number)
except:
print('Invailed Input')
continue
num = num+1
total = total + num1
print ('all done')
print (total,num,total/num)
Write and Run picture
Covers all error and a few more things. Even rounds the results to two decimal places.
count = 0
total = 0
average = 0
print()
print('Enter integers and type "done" when finished.')
print('Results are rounded to two decimals.')
while True:
inp = input("Enter a number: ")
try:
if count >= 2 and inp == 'done': #only breaks if more than two integers are entered
break
count = count + 1
total += float(inp)
average = total / count
except:
if count <=1 and inp == 'done':
print('Enter at least 2 integers.')
else:
print('Bad input')
count = count - 1
print()
print('Done!')
print('Count: ' , count, 'Total: ' , round(total, 2), 'Average: ' , round(average, 2))
How to complete my program which repeatedly reads numbers until the user enters
“done”. Once “done” is entered, print out the total, count, and average of
the numbers. If the user enters anything other than a number, detect their mistake
using try and except and print an error message and skip to the next number.
count = 0
total = 0
while True:
x = raw_input('Enter number')
x=int(x)
total = total + x
count = count + 1
average = total / count
print total, count, average
The following code should be what you want.
count = 0
total = 0
while True:
x = raw_input('Enter number: ')
if(x.lower() == "done"):
break
else:
try:
x=int(x)
total = total + x
count = count + 1
average = total / count
except:
print("That is not an integer. Please try again.")
print total, count, average
or in Python 3
count = 0
total = 0
while True:
x = input('Enter number: ')
if(x.lower() == "done"):
break
else:
try:
x=int(x)
total = total + x
count = count + 1
average = total / count
except:
print("That is not an integer. Please try again.")
print(total, count, average)