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Python print() function not recalculating variables in a while loop

I am attempting to write a program that will calculate the difference in a given time and the actual time then display that delta in a while loop. I have been able to get most of this working, the only issue I have found so far is the time variables in the print statement do not update as the loop runs.
import datetime
import time
from os import system
from sys import platform
clear_screen = lambda: system("cls" if platform == "win32" else "clear")
# print("What is the time and date of your event?")
# year = int(input("Year: "))
# month = int(input("Month: "))
# day = int(input("Day: "))
# hour = int(input("Hour: "))
# minute = int(input("Minute: "))
i = 0
year = 2023
month = 1
day = 27
hour = 12
minute = 0
second = 00
today = datetime.datetime.now()
date_entry = datetime.datetime(year, month, day, hour, minute, second)
print(f"The current date & time: {today}")
print(f"The big day is: {date_entry}")
print()
print()
print(f"Tiff's Big day is going to be here soon:")
print()
event_count = date_entry - today
event_hour = event_count.total_seconds() / 3600
event_min = ((event_hour % 1) * (60 / 100)) * 100
event_sec = ((event_min % 1) * (60 / 100)) * 100
def countdown():
print(f"{event_hour:.0f} Hours, {event_min:.0f} Minutes, {event_sec:.0f} seconds until big mode!!!!!")
while i < 50:
i += 1
countdown()
time.sleep(2)
# clear_screen()`
I have a feeling that the time variables in the print statement are not recalculating... I have tried restructuring the program by moving the variables into the countdown() function. That had the same result.
I am expecting the script to output hours, minutes and seconds until a defined time. This part works great. Then pause for 2 seconds (this works) then print the statement again after it recalculates the time delta. This is were it fails, prints the exact same time as in the first print statement.
You might also notice the clear_screen(). This kinda works, it will clear all of the output. I am looking to make it clear the last line printed in the loop (ie: 40 Hours, 12 Minutes, 56 seconds until big mode!!!!!) This is something I haven't looked at much yet. If you have any suggestions...
Thanks in advance for any suggestions.
Output:
The current date & time: 2023-01-25 19:48:04.383425
The big day is: 2023-01-27 12:00:00
Tiff's Big day is going to be here soon:
40 Hours, 12 Minutes, 56 seconds until big mode!!!!!
40 Hours, 12 Minutes, 56 seconds until big mode!!!!!
40 Hours, 12 Minutes, 56 seconds until big mode!!!!!
40 Hours, 12 Minutes, 56 seconds until big mode!!!!!
40 Hours, 12 Minutes, 56 seconds until big mode!!!!!

Be careful with calling time functions, the time is assigned to a variable only the first time, here is an example in the REPL:
>>> import time
>>> time.time()
1674700748.035392
>>> time.time()
1674700749.2911549
>>> time.time()
1674700750.440412
>>> time.time()
1674700751.571879
>>> x = time.time()
>>> x
1674700755.0605464
>>> x
1674700755.0605464
>>> x
1674700755.0605464
>>> x
1674700755.0605464
>>> for i in range(5): print(time.time())
...
1674700912.1213877
1674700912.1214447
1674700912.1214585
1674700912.1214688
1674700912.1214786
>>> for i in range(5): print(x)
...
1674700755.0605464
1674700755.0605464
1674700755.0605464
1674700755.0605464
1674700755.0605464
As you can see if I call time.time multiple times the time changes, but if I assign it to x, then x always has the same value.

Below is the code I wrote to solve my problem:
import datetime
import time
from os import system
from sys import platform
import cursor
# print("What is the time and date of your event?")
# year = int(input("Year: "))
# month = int(input("Month: "))
# day = int(input("Day: "))
# hour = int(input("Hour: "))
# minute = int(input("Minute: "))
year = 2023
month = 1
day = 27
hour = 12
minute = 0
second = 00
date_entry = datetime.datetime(year, month, day, hour, minute, second)
print(f"The current date & time: {datetime.datetime.now()}")
print(f"The big day is: {date_entry}")
print()
print()
print(f"Tiff's Big day is going to be here soon:")
print()
while True:
event_count = date_entry - datetime.datetime.now()
event_hour = event_count.total_seconds() / 3600
event_min = ((event_hour % 1) * (60 / 100)) * 100
event_sec = ((event_min % 1) * (60 / 100)) * 100
print(f"{event_hour:.0f} Hours, {event_min:.0f} Minutes, {event_sec:.0f} seconds until big time!!!", end = "\r")
cursor.hide()
time.sleep(.5)

Converting seconds to minutes and hours and writing to a CSV file [duplicate]

I have a function that returns information in seconds, but I need to store that information in hours:minutes:seconds.
Is there an easy way to convert the seconds to this format in Python?

You can use datetime.timedelta function:
>>> import datetime
>>> str(datetime.timedelta(seconds=666))
'0:11:06'

By using the divmod() function, which does only a single division to produce both the quotient and the remainder, you can have the result very quickly with only two mathematical operations:
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
And then use string formatting to convert the result into your desired output:
print('{:d}:{:02d}:{:02d}'.format(h, m, s)) # Python 3
print(f'{h:d}:{m:02d}:{s:02d}') # Python 3.6+

I can hardly name that an easy way (at least I can't remember the syntax), but it is possible to use time.strftime, which gives more control over formatting:
from time import strftime
from time import gmtime
strftime("%H:%M:%S", gmtime(666))
'00:11:06'
strftime("%H:%M:%S", gmtime(60*60*24))
'00:00:00'
gmtime is used to convert seconds to special tuple format that strftime() requires.
Note: Truncates after 23:59:59

Using datetime:
With the ':0>8' format:
from datetime import timedelta
"{:0>8}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{:0>8}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{:0>8}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Without the ':0>8' format:
"{}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Using time:
from time import gmtime
from time import strftime
# NOTE: The following resets if it goes over 23:59:59!
strftime("%H:%M:%S", gmtime(125))
# Result: '00:02:05'
strftime("%H:%M:%S", gmtime(60*60*24-1))
# Result: '23:59:59'
strftime("%H:%M:%S", gmtime(60*60*24))
# Result: '00:00:00'
strftime("%H:%M:%S", gmtime(666777))
# Result: '17:12:57'
# Wrong

This is my quick trick:
from humanfriendly import format_timespan
secondsPassed = 1302
format_timespan(secondsPassed)
# '21 minutes and 42 seconds'
For more info Visit:
https://humanfriendly.readthedocs.io/en/latest/api.html#humanfriendly.format_timespan

The following set worked for me.
def sec_to_hours(seconds):
a=str(seconds//3600)
b=str((seconds%3600)//60)
c=str((seconds%3600)%60)
d=["{} hours {} mins {} seconds".format(a, b, c)]
return d
print(sec_to_hours(10000))
# ['2 hours 46 mins 40 seconds']
print(sec_to_hours(60*60*24+105))
# ['24 hours 1 mins 45 seconds']

A bit off topic answer but maybe useful to someone
def time_format(seconds: int) -> str:
if seconds is not None:
seconds = int(seconds)
d = seconds // (3600 * 24)
h = seconds // 3600 % 24
m = seconds % 3600 // 60
s = seconds % 3600 % 60
if d > 0:
return '{:02d}D {:02d}H {:02d}m {:02d}s'.format(d, h, m, s)
elif h > 0:
return '{:02d}H {:02d}m {:02d}s'.format(h, m, s)
elif m > 0:
return '{:02d}m {:02d}s'.format(m, s)
elif s > 0:
return '{:02d}s'.format(s)
return '-'
Results in:
print(time_format(25*60*60 + 125))
>>> 01D 01H 02m 05s
print(time_format(17*60*60 + 35))
>>> 17H 00m 35s
print(time_format(3500))
>>> 58m 20s
print(time_format(21))
>>> 21s

This is how I got it.
def sec2time(sec, n_msec=3):
''' Convert seconds to 'D days, HH:MM:SS.FFF' '''
if hasattr(sec,'__len__'):
return [sec2time(s) for s in sec]
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
d, h = divmod(h, 24)
if n_msec > 0:
pattern = '%%02d:%%02d:%%0%d.%df' % (n_msec+3, n_msec)
else:
pattern = r'%02d:%02d:%02d'
if d == 0:
return pattern % (h, m, s)
return ('%d days, ' + pattern) % (d, h, m, s)
Some examples:
$ sec2time(10, 3)
Out: '00:00:10.000'
$ sec2time(1234567.8910, 0)
Out: '14 days, 06:56:07'
$ sec2time(1234567.8910, 4)
Out: '14 days, 06:56:07.8910'
$ sec2time([12, 345678.9], 3)
Out: ['00:00:12.000', '4 days, 00:01:18.900']

hours (h) calculated by floor division (by //) of seconds by 3600 (60 min/hr * 60 sec/min)
minutes (m) calculated by floor division of remaining seconds (remainder from hour calculation, by %) by 60 (60 sec/min)
similarly, seconds (s) by remainder of hour and minutes calculation.
Rest is just string formatting!
def hms(seconds):
h = seconds // 3600
m = seconds % 3600 // 60
s = seconds % 3600 % 60
return '{:02d}:{:02d}:{:02d}'.format(h, m, s)
print(hms(7500)) # Should print 02h05m00s

If you need to get datetime.time value, you can use this trick:
my_time = (datetime(1970,1,1) + timedelta(seconds=my_seconds)).time()
You cannot add timedelta to time, but can add it to datetime.
UPD: Yet another variation of the same technique:
my_time = (datetime.fromordinal(1) + timedelta(seconds=my_seconds)).time()
Instead of 1 you can use any number greater than 0. Here we use the fact that datetime.fromordinal will always return datetime object with time component being zero.

dateutil.relativedelta is convenient if you need to access hours, minutes and seconds as floats as well. datetime.timedelta does not provide a similar interface.
from dateutil.relativedelta import relativedelta
rt = relativedelta(seconds=5440)
print(rt.seconds)
print('{:02d}:{:02d}:{:02d}'.format(
int(rt.hours), int(rt.minutes), int(rt.seconds)))
Prints
40.0
01:30:40

Here is a way that I always use: (no matter how inefficient it is)
seconds = 19346
def zeroes (num):
if num < 10: num = "0" + num
return num
def return_hms(second, apply_zeroes):
sec = second % 60
min_ = second // 60 % 60
hrs = second // 3600
if apply_zeroes > 0:
sec = zeroes(sec)
min_ = zeroes(min_)
if apply_zeroes > 1:
hrs = zeroes(hrs)
return "{}:{}:{}".format(hrs, min_, sec)
print(return_hms(seconds, 1))
RESULT:
5:22:26
Syntax of return_hms() function
The return_hms() function is used like this:
The first variable (second) is the amount of seconds you want to convert into h:m:s.
The second variable (apply_zeroes) is formatting:
0 or less: Apply no zeroes whatsoever
1: Apply zeroes to minutes and seconds when they're below 10.
2 or more: Apply zeroes to any value (including hours) when they're below 10.

Here is a simple program that reads the current time and converts it to a time of day in hours, minutes, and seconds
import time as tm #import package time
timenow = tm.ctime() #fetch local time in string format
timeinhrs = timenow[11:19]
t=tm.time()#time.time() gives out time in seconds since epoch.
print("Time in HH:MM:SS format is: ",timeinhrs,"\nTime since epoch is : ",t/(3600*24),"days")
The output is
Time in HH:MM:SS format is: 13:32:45
Time since epoch is : 18793.335252338384 days

You can divide seconds by 60 to get the minutes
import time
seconds = time.time()
minutes = seconds / 60
print(minutes)
When you divide it by 60 again, you will get the hours

In my case I wanted to achieve format
"HH:MM:SS.fff".
I solved it like this:
timestamp = 28.97000002861023
str(datetime.fromtimestamp(timestamp)+timedelta(hours=-1)).split(' ')[1][:12]
'00:00:28.970'

The solutions above will work if you're looking to convert a single value for "seconds since midnight" on a date to a datetime object or a string with HH:MM:SS, but I landed on this page because I wanted to do this on a whole dataframe column in pandas. If anyone else is wondering how to do this for more than a single value at a time, what ended up working for me was:
mydate='2015-03-01'
df['datetime'] = datetime.datetime(mydate) + \
pandas.to_timedelta(df['seconds_since_midnight'], 's')

I looked every answers here and still tried my own
def a(t):
print(f"{int(t/3600)}H {int((t/60)%60) if t/3600>0 else int(t/60)}M {int(t%60)}S")
Results:
>>> a(7500)
2H 5M 0S
>>> a(3666)
1H 1M 6S
Python: 3.8.8

division = 3623 // 3600 #to hours
division2 = 600 // 60 #to minutes
print (division) #write hours
print (division2) #write minutes
PS My code is unprofessional

Given Time in minutes, print it in hours and minutes

In Question, Given Time is in minutes that requires to be converted into hours and minutes.
Sample :
Input - 53
Output - 0 53
num = int(input())
if num < 60:
print('0'+" "+str(num))
else:
if num>=60:
time = num*(1/60)
time1 = (format(time, '.2f'))
print(str(time1).replace('.',' '))

The easiest way to do this is using integer division (//) and modulo (%):
def printAsHoursAndMinutes(timeInMinutes):
hours = timeInMinutes // 60
minutes = timeInMinutes % 60
print("{} {}".format(hours, minutes)) #edited to match the requested output format
// will return the integer part of the devision, % returns the rest. With 130 as input, the above code will print "2 10", for 5 as input, it prints "0 5".
[Edit:] This works for any nonegative integer. If you want to support negative integers too, add the following condition just before the print:
if(timeInMinutes < 0):
hours = hours + 1
minutes = 60 - minutes
This allows us to handle inputs like -65 to print "-1 5".
For floating point numbers, things migth get a bit ugly because % is not 100% acurate (e.g. 60.1 results in 1.0 0.10000000000000142). This even happenes when using divmod as mentioned by #CristiFati in the comments to the question, so there is no real way around it and we'd need a more advanced handling or a custom modulo method but that is off-topic here.

As per shown in picture...
You may try this..
def HoursandMinutes(Minutes):
Minutes = Minutes % (24*3600)
Hour = Minutes // 60
Minutes %= 60
print("%d %d" % (Hour, Minutes))
When you call this function
OUTPUT
HoursandMinutes(52)
0 52
HoursandMinutes(70)
1 10
HoursandMinutes(90)
1 30
HoursandMinutes(105)
1 45

Parse a decimal from an integer

My code/project: I'm learning Python and trying to create a pace calculator for some marathon training.
My problem: How do I separate/parse the decimal from the final number calculated?
Example: Using the following input values
#[Minutes, Seconds, Distance in miles]
[17, 37, 3.1]
#17 * 60 = 1020; 1020 + 37 = 1057; 1057/3.1 = 340.96
the entire code would give me an answer of 340.96 seconds. If I divide that by 60 to find out the exact Minutes/seconds; the answer becomes 5.68.
I need to take that ".68" and multiply it by 60 to get actual seconds because it represents 68% of a minute.
recordMinutes = int(input("What is your total minutes? "))
for steps in range(1):
converted = recordMinutes * 60
recordSeconds = int(input("What is your total seconds leftover? "))
for steps in range(1):
combined = converted + recordSeconds
distance = float(input("What is the distance? "))
paceRaw = combined/distance
paceBasic = (paceRaw/60)
#This is where I would multiply the ".68" by 60
pace = (#decimal remainder * 60) + #whole number
print ("You need to run %d per mile " % pace)

Use divmod.
>>> divmod(340.96, 60)
(5.0, 40.95999999999998)

A good practice for you as the beginner would be to do this without any libraries or methods:
>>> s = 5.68
>>> s = s*100
568.0
>>> s = s%100
68.0
>>> s/100
0.68

How do I convert seconds to hours, minutes and seconds?

I have a function that returns information in seconds, but I need to store that information in hours:minutes:seconds.
Is there an easy way to convert the seconds to this format in Python?

You can use datetime.timedelta function:
>>> import datetime
>>> str(datetime.timedelta(seconds=666))
'0:11:06'

By using the divmod() function, which does only a single division to produce both the quotient and the remainder, you can have the result very quickly with only two mathematical operations:
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
And then use string formatting to convert the result into your desired output:
print('{:d}:{:02d}:{:02d}'.format(h, m, s)) # Python 3
print(f'{h:d}:{m:02d}:{s:02d}') # Python 3.6+

I can hardly name that an easy way (at least I can't remember the syntax), but it is possible to use time.strftime, which gives more control over formatting:
from time import strftime
from time import gmtime
strftime("%H:%M:%S", gmtime(666))
'00:11:06'
strftime("%H:%M:%S", gmtime(60*60*24))
'00:00:00'
gmtime is used to convert seconds to special tuple format that strftime() requires.
Note: Truncates after 23:59:59

Using datetime:
With the ':0>8' format:
from datetime import timedelta
"{:0>8}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{:0>8}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{:0>8}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Without the ':0>8' format:
"{}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Using time:
from time import gmtime
from time import strftime
# NOTE: The following resets if it goes over 23:59:59!
strftime("%H:%M:%S", gmtime(125))
# Result: '00:02:05'
strftime("%H:%M:%S", gmtime(60*60*24-1))
# Result: '23:59:59'
strftime("%H:%M:%S", gmtime(60*60*24))
# Result: '00:00:00'
strftime("%H:%M:%S", gmtime(666777))
# Result: '17:12:57'
# Wrong

This is my quick trick:
from humanfriendly import format_timespan
secondsPassed = 1302
format_timespan(secondsPassed)
# '21 minutes and 42 seconds'
For more info Visit:
https://humanfriendly.readthedocs.io/en/latest/api.html#humanfriendly.format_timespan

The following set worked for me.
def sec_to_hours(seconds):
a=str(seconds//3600)
b=str((seconds%3600)//60)
c=str((seconds%3600)%60)
d=["{} hours {} mins {} seconds".format(a, b, c)]
return d
print(sec_to_hours(10000))
# ['2 hours 46 mins 40 seconds']
print(sec_to_hours(60*60*24+105))
# ['24 hours 1 mins 45 seconds']

A bit off topic answer but maybe useful to someone
def time_format(seconds: int) -> str:
if seconds is not None:
seconds = int(seconds)
d = seconds // (3600 * 24)
h = seconds // 3600 % 24
m = seconds % 3600 // 60
s = seconds % 3600 % 60
if d > 0:
return '{:02d}D {:02d}H {:02d}m {:02d}s'.format(d, h, m, s)
elif h > 0:
return '{:02d}H {:02d}m {:02d}s'.format(h, m, s)
elif m > 0:
return '{:02d}m {:02d}s'.format(m, s)
elif s > 0:
return '{:02d}s'.format(s)
return '-'
Results in:
print(time_format(25*60*60 + 125))
>>> 01D 01H 02m 05s
print(time_format(17*60*60 + 35))
>>> 17H 00m 35s
print(time_format(3500))
>>> 58m 20s
print(time_format(21))
>>> 21s

This is how I got it.
def sec2time(sec, n_msec=3):
''' Convert seconds to 'D days, HH:MM:SS.FFF' '''
if hasattr(sec,'__len__'):
return [sec2time(s) for s in sec]
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
d, h = divmod(h, 24)
if n_msec > 0:
pattern = '%%02d:%%02d:%%0%d.%df' % (n_msec+3, n_msec)
else:
pattern = r'%02d:%02d:%02d'
if d == 0:
return pattern % (h, m, s)
return ('%d days, ' + pattern) % (d, h, m, s)
Some examples:
$ sec2time(10, 3)
Out: '00:00:10.000'
$ sec2time(1234567.8910, 0)
Out: '14 days, 06:56:07'
$ sec2time(1234567.8910, 4)
Out: '14 days, 06:56:07.8910'
$ sec2time([12, 345678.9], 3)
Out: ['00:00:12.000', '4 days, 00:01:18.900']

hours (h) calculated by floor division (by //) of seconds by 3600 (60 min/hr * 60 sec/min)
minutes (m) calculated by floor division of remaining seconds (remainder from hour calculation, by %) by 60 (60 sec/min)
similarly, seconds (s) by remainder of hour and minutes calculation.
Rest is just string formatting!
def hms(seconds):
h = seconds // 3600
m = seconds % 3600 // 60
s = seconds % 3600 % 60
return '{:02d}:{:02d}:{:02d}'.format(h, m, s)
print(hms(7500)) # Should print 02h05m00s

If you need to get datetime.time value, you can use this trick:
my_time = (datetime(1970,1,1) + timedelta(seconds=my_seconds)).time()
You cannot add timedelta to time, but can add it to datetime.
UPD: Yet another variation of the same technique:
my_time = (datetime.fromordinal(1) + timedelta(seconds=my_seconds)).time()
Instead of 1 you can use any number greater than 0. Here we use the fact that datetime.fromordinal will always return datetime object with time component being zero.

dateutil.relativedelta is convenient if you need to access hours, minutes and seconds as floats as well. datetime.timedelta does not provide a similar interface.
from dateutil.relativedelta import relativedelta
rt = relativedelta(seconds=5440)
print(rt.seconds)
print('{:02d}:{:02d}:{:02d}'.format(
int(rt.hours), int(rt.minutes), int(rt.seconds)))
Prints
40.0
01:30:40

Here is a way that I always use: (no matter how inefficient it is)
seconds = 19346
def zeroes (num):
if num < 10: num = "0" + num
return num
def return_hms(second, apply_zeroes):
sec = second % 60
min_ = second // 60 % 60
hrs = second // 3600
if apply_zeroes > 0:
sec = zeroes(sec)
min_ = zeroes(min_)
if apply_zeroes > 1:
hrs = zeroes(hrs)
return "{}:{}:{}".format(hrs, min_, sec)
print(return_hms(seconds, 1))
RESULT:
5:22:26
Syntax of return_hms() function
The return_hms() function is used like this:
The first variable (second) is the amount of seconds you want to convert into h:m:s.
The second variable (apply_zeroes) is formatting:
0 or less: Apply no zeroes whatsoever
1: Apply zeroes to minutes and seconds when they're below 10.
2 or more: Apply zeroes to any value (including hours) when they're below 10.

Here is a simple program that reads the current time and converts it to a time of day in hours, minutes, and seconds
import time as tm #import package time
timenow = tm.ctime() #fetch local time in string format
timeinhrs = timenow[11:19]
t=tm.time()#time.time() gives out time in seconds since epoch.
print("Time in HH:MM:SS format is: ",timeinhrs,"\nTime since epoch is : ",t/(3600*24),"days")
The output is
Time in HH:MM:SS format is: 13:32:45
Time since epoch is : 18793.335252338384 days

You can divide seconds by 60 to get the minutes
import time
seconds = time.time()
minutes = seconds / 60
print(minutes)
When you divide it by 60 again, you will get the hours

In my case I wanted to achieve format
"HH:MM:SS.fff".
I solved it like this:
timestamp = 28.97000002861023
str(datetime.fromtimestamp(timestamp)+timedelta(hours=-1)).split(' ')[1][:12]
'00:00:28.970'

The solutions above will work if you're looking to convert a single value for "seconds since midnight" on a date to a datetime object or a string with HH:MM:SS, but I landed on this page because I wanted to do this on a whole dataframe column in pandas. If anyone else is wondering how to do this for more than a single value at a time, what ended up working for me was:
mydate='2015-03-01'
df['datetime'] = datetime.datetime(mydate) + \
pandas.to_timedelta(df['seconds_since_midnight'], 's')

I looked every answers here and still tried my own
def a(t):
print(f"{int(t/3600)}H {int((t/60)%60) if t/3600>0 else int(t/60)}M {int(t%60)}S")
Results:
>>> a(7500)
2H 5M 0S
>>> a(3666)
1H 1M 6S
Python: 3.8.8

division = 3623 // 3600 #to hours
division2 = 600 // 60 #to minutes
print (division) #write hours
print (division2) #write minutes
PS My code is unprofessional