I would like to implement a function that updates quantity in LibraryBook each time the admin adds a book in SingleBook on the admin site. I have been searching for means to do so but to no avail. Any pointers including links to documentation would be very much appreciated.
Here is my code:
#models.py
class LibraryBook(models.Model):
book_title = models.CharField(max_length=100, blank=False)
book_author_id = models.ForeignKey(BookAuthors, on_delete=models.CASCADE)
category = models.ForeignKey(BookCategory, on_delete=models.CASCADE)
quantity = models.IntegerField(blank=False, default=0)
number_borrowed = models.IntegerField(default=0)
def __unicode__(self):
return unicode(self.book_title)
class SingleBook(models.Model):
serial_number = models.CharField(primary_key=True , max_length=150, blank=False)
book_id = models.ForeignKey(LibraryBook, on_delete=models.CASCADE)
is_available_returned = models.BooleanField(default=True)
is_borrowed = models.BooleanField(default=False)
def __unicode__(self):
return unicode(self.book_id)
#admin.py
class SingleBookAdmin(admin.ModelAdmin):
list_display = ('book_id', 'serial_number')
class LibraryBookAdmin(admin.ModelAdmin):
list_display = ('book_title', 'book_author_id', 'quantity')
search_fields = ('book_title', 'book_author_id')
fields = ('book_title', 'book_author_id', 'quantity')
PS: I have omitted the import and admin.site.register code
Django==1.9.8
django-material==0.8.0
django-model-utils==2.5.1
psycopg2==2.6.2
wheel==0.24.0
override save_model
If you only want to make the changes when an admin updates a record, the best way is to override the save_model method in ModelAdmin
The save_model method is given the HttpRequest, a model instance, a
ModelForm instance and a boolean value based on whether it is adding
or changing the object. Here you can do any pre- or post-save
operations.
class SingleBookAdmin(admin.ModelAdmin):
list_display = ('book_id', 'serial_number')
def save_model(self, request, obj, form, change):
admin.ModelAdmin.save_model(self, request, obj, form, change)
if obj.is_borrowed:
do something to obj.book_id.quantity
else:
do something to obj.book_id.quantity
post_save signal
from django.dispatch.dispatcher import receiver
from django.db.models.signals import post_save
#receiver(post_save, sender=SingleBook)
def user_updated(sender,instance, **kwargs):
''' Fired when a SingleBook is updated or saved
we will use the opporunity to change quantity'''
# your logic here
Other pointers
If on the other hand, you wanted to make changes based on all user actions, catching the post_save signal is the way to go. In either case, you might want to override the from_db method in the model to keep track of which fields have changed.
You might also want to change quantity and number_borrowed to IntegerFields (unless you are only using sqlite in which case it doesn't matter)
Also book_author_id should probably be book_author and book_id should probably be book (this is not a rule, just a convention to avoid the ugly book_id_id reference)
Use signals. Just attach post_save signal to SingleBook model and update according LibraryBook in it. post_save signal takes created argument, so you can determine if book is newly created or edited and apply your action based on that.
Also attach post_delete signal to decrease counter when SingleBook is removed.
To avoid race conditions (when 2 admins are adding books at the same time), I'm suggesting use of queryset update method together with F on changing LibraryBook counter, example:
LibraryBook.objects.filter(id=single_book.book_id_id).update(quantity=F('quantity') + 1)
Doing it that way will ensure that actual math operation will be performed on database level.
Related
TL;DR both my model and my form calculate the value of the field number_as_char. Can I avoid the double work, but still check uniqueness when using the model without the form?
I use Python 3 and Django 1.11
My model looks as follows:
class Account(models.Model):
parent_account = models.ForeignKey(
to='self',
on_delete=models.PROTECT,
null=True,
blank=True)
number_suffix = models.PositiveIntegerField()
number_as_char = models.CharField(
max_length=100,
blank=True,
default='',
unique=True)
#classmethod
def get_number_as_char(cls, parent_account, number_suffix):
# iterate over all parents
suffix_list = [str(number_suffix), ]
parent = parent_account
while parent is not None:
suffix_list.insert(0, str(parent.number_suffix))
parent = parent.parent_account
return '-'.join(suffix_list)
def save(self, *args, **kwargs):
self.number_as_char = self.get_number_as_char(
self.parent_account, self.number_suffix)
super().save(*args, **kwargs)
The field number_as_char is not supposed to be set by the user because it is calculated based on the selected parent_account: it is obtained by chaining the values of the field number_suffix of all the parent accounts and the current instance.
Here is an example with three accounts:
ac1 = Account()
ac1.parent_account = None
ac1.number_suffix = 2
ac1.save()
# ac1.number_as_char is '2'
ac2 = Account()
ac2.parent_account = ac1
ac2.number_suffix = 5
ac2.save()
# ac2.number_as_char is '2-5'
ac3 = Account()
ac3.parent_account = ac2
ac3.number_suffix = 1
ac3.save()
# ac3.number_as_char is '2-5-1'
It is NOT an option to drop the field and use a model property instead, because I need to ensure uniqueness and also use that field for sorting querysets with order_by().
My form looks as follows:
class AccountForm(forms.ModelForm):
class Meta:
model = Account
fields = [
'parent_account', 'number_suffix', 'number_as_char',
]
widgets = {
'number_as_char': forms.TextInput(attrs={'readonly': True}),
}
def clean(self):
super().clean()
self.cleaned_data['number_as_char'] = self.instance.get_number_as_char(
self.cleaned_data['parent_account'], self.cleaned_data['number_suffix'])
I included number_as_char in the form with widget attribute readonly and I use the forms clean() method to calculate number_as_char (it has to be calculated before validating uniqueness).
This all works (the model and the form), but after validating the form, the value of number_as_char will be calculated again by the models save() method. Its not a big problem, but is there a way to avoid this double calculation?
If I remove the calculation from the forms clean() method, then the uniqueness will not be validated with the new value (it will only check the old value).
I don't want to remove the calculation entirely from the model because I use the model in other parts without the form.
Do you have any suggestions what could be done differently to avoid double calculation of the field?
I can't see any way around doing this in two places (save() and clean()) given that you need it to work for non-form-based saves as well).
However I can offer two efficiency improvements to your get_number_as_char method:
Make it a cached_property so that the second time it is called, you simply return a cached value and eliminate double-calculation. Obviously you need to be careful that this isn't called before an instance is updated, otherwise the old number_as_char will be cached. This should be fine as long as get_number_as_char() is only called during a save/clean.
Based on the information you've provided above you shouldn't have to iterate over all the ancestors, but can simply take the number_as_char for the parent and append to it.
The following incorporates both:
#cached_property
def get_number_as_char(self, parent_account, number_suffix):
number_as_char = str(number_suffix)
if parent_account is not None:
number_as_char = '{}-{}'.format(parent_account.number_as_char, number_as_char)
return number_as_char
To be sure that the caching doesn't cause problems you could just clear the cached value after you're done saving:
def save(self, *args, **kwargs):
self.number_as_char = self.get_number_as_char(
self.parent_account, self.number_suffix)
super().save(*args, **kwargs)
# Clear the cache, in case something edits this object again.
del self.get_number_as_char
I tinkered with it a bit, and I think I found a better way.
By using the disabled property on the number_as_char field of your model form, you can entirely ignore users input (and make the field disabled in a single step).
Your model already calculates the number_as_char attribute in the save method. However, if the Unique constraint fails, then your admin UI will throw a 500 error. However, you can move your field calculation to the clean() method, leaving the save() method as it is.
So the full example will look similar to this:
The form:
class AccountForm(forms.ModelForm):
class Meta:
model = Account
fields = [
'parent_account', 'number_suffix', 'number_as_char',
]
widgets = {
'number_as_char': forms.TextInput(attrs={'disabled': True}),
}
The model:
class Account(models.Model):
# ...
def clean(self):
self.number_as_char = self.get_number_as_char(
self.parent_account, self.number_suffix
)
super().clean()
That way anything that generates form based on your model will throw a nice validation error (provided that it uses the built-in model validation, which is the case for Model Forms).
The only downside to this is that if you save a model that triggers the validation error, you will see an empty field instead of the value that failed the validation - but I guess there is some nice way to fix this as well - I'll edit my answer if I also find a solution to this.
After reading all the answers and doing some more digging through the docs, I ended up using the following:
#samu suggested using the models clean() method and #Laurent S suggested using unique_together for (parent_account, number_suffix). Since only using unique_together doesn't work for me because parent_account can be null, I opted for combining the two ideas: checking for existing (parent_account, number_suffix) combinations in the models clean() method.
As a consecuence, I removed number_as_char from the form and it is now only calculated in the save() method. By the way: thanks to #solarissmoke for suggesting to calculated it based on the first parent only, not iterating all the way to the top of the chain.
Another consecuence is that I now need to explicitly call the models full_clean() method to validate uniqueness when using the model without the form (otherwise I will get the database IntegrityError), but I can live with that.
So, now my model looks like this:
class Account(models.Model):
parent_account = models.ForeignKey(
to='self',
on_delete=models.PROTECT,
null=True,
blank=True)
number_suffix = models.PositiveIntegerField()
number_as_char = models.CharField(
max_length=100,
default='0',
unique=True)
def save(self, *args, **kwargs):
if self.parent_account is not None:
self.number_as_char = '{}-{}'.format(
self.parent_account.number_as_char,
self.number_suffix)
else:
self.number_as_char = str(self.number_suffix)
super().save(*args, **kwargs)
def clean(self):
qs = self._meta.model.objects.exclude(pk=self.pk)
qs = qs.filter(
parent_account=self.parent_account,
number_suffix=self.number_suffix)
if qs.exists():
raise ValidationError('... some message ...')
And my form ends up like this:
class AccountForm(forms.ModelForm):
class Meta:
model = Account
fields = [
'parent_account', 'number_suffix',
]
EDIT
I'll mark my own answer as accepted, because non of the suggestions fully suited my needs.
However, the bounty goes to #samus answer for pointing me in the right direction with using the clean() method.
Another way - probably not as good though - would be to use Django signals. You could make a pre_save signal that would set the correct value for number_as_char field on the instance that's about to get saved.
That way you don't have to have it done in a save() method of your model, OR in the clean() method of your ModelForm.
Using signals should ensure that any operation that uses the ORM to manipulate your data (which, by extend, should mean all ModelForms as well) will trigger your signal.
The disadvantage to this approach is that it is not clear from the code directly how is this property generated. One has to stumble upon the signal definition in order to discover that it's even there. If you can live with it though, I'd go with signals.
Let's say I have two classes/models: Hand and Finger. Imagine that the fingerprint is a TextField and a Hand has an unknown number of Fingers, in the models.py:
from django.db import models
class Hand(models.Model):
smoothness = models.IntegerField(default=0,
validators=[
MaxValueValidator(5),
MinValueValidator(0)
])
fingers = models.ManyToManyField('Finger')
num_fingers = models.IntegerField(default=0)
has_thumb = models.BooleanField(default=False)
def save(self, *args, **kwargs):
self.num_fingers = check_num_finger() # How do I do that?
if check_has_thumb(): # How do I do that?
self.has_thumb = True
super(Hand, self).save(*args, **kwargs)
class Finger(model.Model):
is_a_thumb = models.BooleanField(default=False)
fingerprint = models.TextField()
The new Hand is added through the admin.py like this:
from django.contrib import admin
from .models import Hand, Finger
#admin.register(Finger)
class FingerAdmin(admin.ModelAdmin):
fieldsets = [('Finger', {'fields': ['is_a_thumb','fingerprint']})]
list_display = ('is_a_thumb', 'fingerprint',)
#admin.register(Hand)
class HandAdmin(admin.ModelAdmin):
fieldsets = [('Hand', {'fields': ['smoothness']},
('Fingers', {'fields': ['fingers']}]
And when saving the Hand, we need to check how many fingers are related to the Hand when initialized. And also access the is_a_thumb field inside the Finger model to populate/relate has_a_thumb from the Hand.
How do I access is_a_thumb from eachFinger such that if there's one Finger that is_a_thumb, it changes the Hand's value of has_a_thumb before saving
How do I access the no. of Fingers assigned to the Hand, so that I can update num_fingers before saving?
I'm not sure if you can do it before your object get saved. And I don't think this is the right way. I believe what you need to do is to listen for a m2m_changed signal and update your hand.
from django.db.models.signals import m2m_changed
def fingers_changed(sender, **kwargs):
#sender Hand.fingers.through (the intermediate m2m class)
#instance hand (the Hand instance being modified)
#action "pre_add" (followed by a separate signal with "post_add")
#reverse False (Hand contains the ManyToManyField, so this call modifies the forward relation)
#model Finger (the class of the objects added to the Hand)
#pk_set finger_ids beign added (when post_add its a set of all, not the new ones only, but all)
#using "default" (since the default router sends writes here)
if kwargs['action'] == 'post_add':
hand = kwargs['instance']
hand.num_fingers = hand.fingers.count() #or len(kwargs['pk_set'])
hand.has_thumb = hand.fingers.filter(is_a_thumb=True).exists()
hand.save()
m2m_changed.connect(fingers_changed, sender=Hand.fingers.through)
Note: Btw i'm not sure if M2M is the right relation here. Yes a hand can have many fingers, but one finger should belong to one hand only? If that's True then mb you need to change the relation to One-to-Many (Finger having a FK to Hand).
This is django documentation about working with ManyToMany fields. And this documentation for m2m_changed signal. I think you should use it here. I never use this signal in practice but as I understand the code should look like this.
from django.db import models
from django.db.models.signals import m2m_changed
class Hand(models.Model):
smoothness = models.IntegerField(default=0,
validators=[
MaxValueValidator(5),
MinValueValidator(0)
])
fingers = models.ManyToManyField('Finger')
num_fingers = models.IntegerField(default=0)
has_thumb = models.BooleanField(default=False)
class Finger(model.Model):
is_a_thumb = models.BooleanField(default=False)
fingerprint = models.TextField()
def fingers_changed(sender, **kwargs):
instance = kwargs.pop('instance', None)
instance.num_fingers = instance.fingers.count()
if instance.fingers.filter(is_a_thumb=True):
instance.has_thumb = True
instance.save()
m2m_changed.connect(fingers_changed, sender=Hand.fingers.through)
By the way, I think you have mistake in your code when calling super inside the save method. In this example you should use Hand instead of Sentence.
You may use hand.fingers.count() in order to know the number of fingers of your object.
I am trying to build a filter by function in django. From what I've learned by googling this is quite hard to achieve.
So here is my code:
class TrackingEventType(models.Model):
name = models.CharField(blank=False, null=False, max_length=255)
class TrackingEvent(models.Model):
datetime = models.DateTimeField(blank=False, null=False, default=datetime.now, verbose_name="Zeitpunkt")
event_type = models.ForeignKey(TrackingEventType, help_text="Art des Events")
tracking = models.ForeignKey('Tracking')
class Meta:
ordering = ['-datetime']
class Tracking(models.Model):
tracking_no = models.CharField(blank=False, null=False, max_length=10, unique=True, verbose_name="Tracking Nummer")
def get_last_event(self):
"""
Todo: return the latest event.
"""
return TrackingEvent.objects.filter(tracking=self.id).first()
get_last_event.short_description = 'Last event'
class Meta:
ordering = ['-tracking_no']
My goal is to make it possible to filter Tracking objects by their last events type name. Displaying the result of the funtion in django admin is easy, but adding a corresponding filter isn't.
My idea was also to try to build a filter something like:
trackingevent__set__first__event_type__name
But yeah, that would be too easy :)
Any inputs are welcome.
As you've discovered it isn't trivial to filter in that manner. If you are accessing that information regularly it is probably also not very efficient either.
I would suggest that you store a reference to the latest tracking event in the Tracking model itself:
class Tracking(models.Model)
# ...
last_event = models.ForeignKey(TrackingEvent, null=True)
You would then use signals to update this reference whenever a new tracking event is created. Something along the lines of:
from django.db.models.signals import post_save
from django.dispatch import receiver
#receiver(post_save, sender=TrackingEvent)
def update_latest_tracking_event(sender, instance, created, **kwargs):
# Is this a new event?
if created:
# If yes, then update the Tracking reference
tracking = instance.tracking
tracking.last_event = instance
tracking.save()
(Please read the documentation on where to put this code).
Once all this is in place it becomes easy to filter based on the last tracking event type:
# I'm just guess what event types you have...
cancellation = TrackingEventType.objects.get(name='cancel')
Tracking.objects.filter(last_event__event_type=cancellation)
Example:
class MyUser(models.Model):
blocked_users = models.ManyToManyField("self", blank=True, null=True)
user = MyUser.object.get(pk=1)
user.blocked_users.add(user)
user.blocked_users.all()[0] == user # (!!!)
Can It be prevented on model/db level? Or we need just do check somewhere in app.
Looking at the Django docs for ManyToManyField arguments, it does not seem possible.
The closest argument to what you want is the limit_choices_to However, that only limits choices on ModelForms and admin (you can still save it like you did in your example), and there is currently no easy way to use it to limit based on another value (pk) in the current model.
If you want to prevent it from happening altogether, you'll have to resort to overriding the save method on the through model--something like:
class MyUser(models.Model):
blocked_users = models.ManyToManyField(..., through="BlockedUser")
class BlockedUser(models.Model):
user = models.ForeignKey(MyUser)
blocked = models.ForeignKey(MyUser)
def save(self, *args, **kwargs):
# Only allow this relationship to be created if
if self.user != self.blocked:
super(BlockedUser, self).save(*args, **kwargs)
You could of course also do this with signals.
class TaskManager(models.Manager):
def get_query_set(self):
return super(TaskManager, self).get_query_set().filter(Owner='jim')
class Task(models.Model):
Name = models.CharField('Title', max_length=200)
Notes = models.TextField('Description',max_length=2000, null=True)
project = models.ForeignKey(Project,null=True, blank=True)
Owner = models.CharField(max_length=100, choices=owner_set)
objects = TaskManager()
def __unicode__(self):
return self.Name
I have two models in my models.py, every Task has a project. But when i enter the Task page, it will list all the task by default. So i want it to list only the current user's Task by default. It is that the Task.Owner=current user.
Who can help me with this, thanks!
I have searched from the net and then get the solution:
I update the code i pasted just now above.
Thanks for all.
Why not do this!
Task.objects.filter(owner = current_user)
Update:
1) If you want to filter in you own custom template add this to your view code
2) If you are trying to customize the admin site do this,
from django.contrib import admin
from models import MyModel
class TaskAdmin(admin.ModelAdmin):
def queryset(self, request):
return super(TaskAdmin, self).queryset(request).filter(owner = request.user)
admin.site.register(Task, TaskAdmin)
In the ModelAdmin class you should add:
class TaskAdmin(...):
def queryset(self, request):
qs = super(TaskAdmin, self).queryset(request)
return qs.filter(Owner=request.user)
This will override the default queryset
more here:
https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.queryset
I just want to modify the default filter of a model, make the model list not all items without the modelAdmin, because the modelAdmin just provide a filter which need manual click, i want to filter the model by default automaticlly