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What causes an "unexpected EOF while parsing" with this try except finally?

I have a web bot that looks at a textbox and gathers information. Depending on what page the textbox is on, the HTML is just slightly different.
This chunk of code repeatedly hits me with the syntax error "unexpected EOF while parsing" as soon as it sees the except block. I've written similar scripts that have worked no problem but this one has been giving me issues.
text_box = '/html/body/div[7]/div[45]/div[37]/div/table[1]/tbody/tr/td[1]/div/div[1]/span'
try:
title = driver.find_element(by = By.XPATH, value = text_box).text.split('\n')[0]
except NoSuchElementException:
text_box = '/html/body/div[8]/div[45]/div[37]/div/table[1]/tbody/tr/td[1]/div/div[1]/span'
finally:
title = driver.find_element(by = By.XPATH, value = text_box).text.split('\n')[0]
content = driver.find_element(by = By.XPATH, value = text_box).text.replace(post_title + "\n" + "\n", "")
Any thoughts are appreciated. Thank you.

How to Continue Loop after exception

from textblob import TextBlob
line = """ अशा किंमतीवर खरोखरच चांगला कुकर आहे ok are you sure how are you आधुनिक तंत्रज्ञानासह हे सुलभ आणि सुरक्षित are you आहे இது அற்புதமான தரம் மற்றும் சூப்பர் தயாரிப்பு."""
def split_line(in_line):
line_sp = line.split(" ")
line_two = [" ".join(line_sp[i:i + 3]) for i in range(0, len(line_sp), 3)]
return line_two
#print(split_line(line))
try:
for i in split_line(line):
blob = TextBlob(i)
print (blob.translate(to = 'en'))
except:
print ("same language found not translated")
This is language Translation code some times text blob throw error so I used try/except block so my code stops when print error message but I want to continue this loop after catching exception

Just put the try except block inside the for (if the error is raised by TextBlob(i)):
for i in split_line(line):
try:
blob = TextBlob(i)
print (blob.translate(to = 'en'))
except:
print ("same language found not translated")
This will make the for run until it ends even if an error has been raised in it.

try-catch in a while-loop (python)

while var == 1:
test_url = 'https://testurl.com'
get_response = requests.get(url=test_url)
parsed_json = json.loads(get_response.text)
test = requests.get('https://api.telegram.org/botid/' + 'sendMessage', params=dict(chat_id=str(0815), text="test"))
ausgabe = json.loads(test.text)
print(ausgabe['result']['text'])
time.sleep(3)
How do i put in a try-catch routine to this code, once per 2 days i get an Error in Line 4 at json.loads() and i cant reproduce it. What i´m trying to do is that the while loop is in a "try:" block and an catch block that only triggers when an error occurs inside the while loop. Additionally it would be great if the while loop doesnt stop on an error. How could i do this. Thank you very much for your help. (I started programming python just a week ago)

If you just want to catch the error in forth line, a "Try except" wrap the forth line will catch what error happened.
while var == 1:
test_url = 'https://testurl.com'
get_response = requests.get(url=test_url)
try:
parsed_json = json.loads(get_response.text)
except Exception as e:
print(str(e))
print('error data is {}',format(get_response.text))
test = requests.get('https://api.telegram.org/botid/' + 'sendMessage', params=dict(chat_id=str(0815), text="test"))
ausgabe = json.loads(test.text)
print(ausgabe['result']['text'])
time.sleep(3)

You can simply
while var == 1:
try:
test_url = 'https://testurl.com'
get_response = requests.get(url=test_url)
parsed_json = json.loads(get_response.text)
test = requests.get('https://api.telegram.org/botid/' + 'sendMessage', params=dict(chat_id=str(0815), text="test"))
ausgabe = json.loads(test.text)
print(ausgabe['result']['text'])
time.sleep(3)
except Exception as e:
print "an exception {} of type {} occurred".format(e, type(e).__name__)

Python custom 404 response error

I wrote a hiscore checker for a game that I play, basically you enter a list of usernames into the .txt file & it outputs the results in found.txt.
However if the page responds a 404 it throws an error instead of returning output as " 0 " & continuing with the list.
Example of script,
#!/usr/bin/python
import urllib2
def get_total(username):
try:
req = urllib2.Request('http://services.runescape.com/m=hiscore/index_lite.ws?player=' + username)
res = urllib2.urlopen(req).read()
parts = res.split(',')
return parts[1]
except urllib2.HTTPError, e:
if e.code == 404:
return "0"
except:
return "err"
filename = "check.txt"
accs = []
handler = open(filename)
for entry in handler.read().split('\n'):
if "No Displayname" not in entry:
accs.append(entry)
handler.close()
for account in accs:
display_name = account.split(':')[len(account.split(':')) - 1]
total = get_total(display_name)
if "err" not in total:
rStr = account + ' - ' + total
handler = open('tried.txt', 'a')
handler.write(rStr + '\n')
handler.close()
if total != "0" and total != "49":
handler = open('found.txt', 'a')
handler.write(rStr + '\n')
handler.close()
print rStr
else:
print "Error searching"
accs.append(account)
print "Done"
HTTPERROR exception that doesn't seem to be working,
except urllib2.HTTPError, e:
if e.code == 404:
return "0"
except:
return "err"
Error response shown below.
Now I understand the error shown doesn't seem to be related to a response of 404, however this only occurs with users that return a 404 response from the request, any other request works fine. So I can assume the issue is within the 404 response exception.
I believe the issue may lay in the fact that the 404 is a custom page which you get redirected too?
so the original page is " example.com/index.php " but the 404 is " example.com/error.php "?
Not sure how to fix.
For testing purposes, format to use is,
ID:USER:DISPLAY
which is placed into check.txt

It seems that total can end up being None. In that case you can't check that it has 'err' in it. To fix the crash, try changing that line to:
if total is not None and "err" not in total:
To be more specific, get_total is returning None, which means that either
parts[1] is None or
except urllib2.HTTPError, e: is executed but e.code is not 404.
In the latter case None is returned as the exception is caught but you're only dealing with the very specific 404 case and ignoring other cases.

Compare lines from streaming API - Python

I am lost here, I have an API that streams prices, I am trying to compare the second to last price with the last price, for instance, if x > y then do something. I cannot figure out how to compare the last to the second to the last price when the prices are streaming. Could someone please shed some light on how this may work? Thanks in advance!
my stream:
def stream_to_queue(self):
response = self.connect_to_stream()
if response.status_code != 200:
return
for line in response.iter_lines(1):
if line:
try:
msg = json.loads(line)
except Exception as e:
print "Caught exception when converting message into json\n" + str(e)
return
if msg.has_key("instrument") or msg.has_key("tick"):
price = msg["tick"]["ask"]
print price
This prints a price like 1.23004 and then continues to loop and print more prices. I have tried to save the current price in a variable outside the loop and then reference it when a new price comes in but it's not working..
my attempt:
def stream_to_queue(self):
response = self.connect_to_stream()
if response.status_code != 200:
return
oldLine = ''
for line in response.iter_lines(1):
if line:
try:
msg = json.loads(line)
except Exception as e:
print "Caught exception when converting message into json\n" + str(e)
return
if msg.has_key("instrument") or msg.has_key("tick"):
price = msg["tick"]["ask"]
oldLine = price
newLine = oldLine
if newLine > oldLine:
print newLine

Couple of things:
1- Your indentation is a bit off as the comparison should be done inside the 'for' loop. In your case, the comparison is only being made when the streaming is complete.
2- You are comparing oldLine with newLine which are equal, so nothing will happen. Instead you should compare newLine with price.
Consider the following code:
for line in response.iter_lines(1):
if line:
try:
msg = json.loads(line)
except Exception as e:
print "Caught exception when converting message into json\n" + str(e)
return
if msg.has_key("instrument") or msg.has_key("tick"):
price = msg["tick"]["ask"]
oldLine = price
newLine = oldLine
if newLine > price:
print newLine