Python Semaphore: I Need Negative Initial Value - python

Python's semaphore doesn't support negative initial values. How, then, do I make a thread wait until 8 other threads have done something? If Semophore supported negative initial values, I could have just set it to -8, and have each thread increment the value by 1, until we have a 0, which unblocks the waiting thread.
I can manually increment a global counter inside a critical section, then use a conditional variable, but I want to see if there are other suggestions.

Surely it's late for an answer, but it can come handy to someone else.
If you want to wait for 8 different threads to do something, you can just wait 8 times.
You initialize a semaphore in 0 with
s = threading.Semaphore(0)
and then
for _ in range(8):
s.acquire()
will do the job.
Full example:
import threading
import time
NUM_THREADS = 4
s = threading.Semaphore(0)
def thread_function(i):
print("start of thread", i)
time.sleep(1)
s.release()
print("end of thread", i)
def main_thread():
print("start of main thread")
threads = [
threading.Thread(target=thread_function, args=(i, ))
for i
in range(NUM_THREADS)
]
[t.start() for t in threads]
[s.acquire() for _ in range(NUM_THREADS)]
print("end of main thread")
main_thread()
Possible output:
start of main thread
start of thread 0
start of thread 1
start of thread 2
start of thread 3
end of thread 0
end of thread 2
end of thread 1
end of thread 3
end of main thread

For any further readers: starting from python3.2 there are Barrier Objects which
provides a simple synchronization primitive for use by a fixed number of threads that need to wait for each other.

Related

Multi threading and single thread is giving same performance in Python

In below code if I comment 'line 6' and uncomment 'line 3,4,5'. Code runs in main thread and time taken is 17 sec.
Now if I uncomment 'line 6' and comment 'line 3,4,5'. And uncomment 'line 1' and comment 'line 2' then code runs in multi thread (3 threads are created) time taken is again 17 sec. So multithreading and single thread is taking same time.
Now if I uncomment 'line 6' and comment 'line 3,4,5'. And comment 'line 1' and uncomment 'line 2' then code runs in multi process (3 process are created) time taken is 9 sec. Multiprocessing is working faster as compared to single and multi treading.
Please let us know why is multi thread performance is same as the single thread ?
import threading
import time
import multiprocessing
import multiprocessing.pool
class xyz:
def __init__(self):
self.data = []
pass
def loopData(self):
item = range(0, 100000000)
for i in item:
self.data.append(i)
def loopDatamulti(self):
num_of_thread = 3
thread_list = []
while True:
t = threading.Thread(target=self.loopData, args=()) #line 1
#t = multiprocessing.Process(target=self.loopData,args=()) #line 2
thread_list.append(t)
num_of_thread_created = len(thread_list)
if num_of_thread_created == num_of_thread:
break
for t in thread_list:
t.start()
for t in thread_list:
t.join()
def main():
print("Start")
start_time = time.time()
xa = xyz()
#xa.loopData() #line 3
#xa.loopData() #line 4
#xa.loopData() #line 5
xa.loopDatamulti() #line 6
end_time = time.time()
strLog = "total time {}".format(end_time - start_time)
print(strLog)
if __name__ == "__main__":
main()
Multi-threading is not well suited to the execution of functions that are purely CPU intensive. If such functions never yield the CPU (e.g. for some kind of I/O) they will just "lock down" a single CPU and you'll gain no benefits. This is where multi-processing comes into play. Even then, you need to be careful because if your function is short-lived then the overhead of creating a separate process may outweigh the advantages that you might otherwise expect. Here's an example of multi-processing. Play with the variables ITERS and PROCS to see how the behaviour changes and you'll get the point. The function (myFunc) just carries out an arbitrary pseudo random calculation and build a list to return.
from datetime import datetime
from multiprocessing import Pool
import math
import random
ITERS = 100_000
PROCS = 100
def myFunc(r):
return [(math.sqrt(random.randint(1, 2000))**2)**(1 / 3) for _ in range(r)]
if __name__ == '__main__':
_start = datetime.now()
with Pool() as pool:
for p in [pool.apply_async(func=myFunc, args=(ITERS,))
for _ in range(PROCS)]:
p.wait()
_end = datetime.now()
print(f'Multi-processing duration={_end-_start}')
_start = datetime.now()
for I in range(PROCS):
myFunc(ITERS)
_end = datetime.now()
print(f'Single-threaded duration={_end-_start}')
On my machine and with the values of ITERS and PROCS as shown in the code, the output is as follows:-
Multi-processing duration=0:00:01.526478
Single-threaded duration=0:00:09.776963
In python there is something called Global Interpreter Lock, which makes sure that only one part of the code is run at the time (e.g. a function locks the interpreter and the other code has to wait on it). The reason for that has to do with how python releases unused variables (by counting the number of references to each variable).
You can read up on it here: https://realpython.com/python-gil/
Multiprocessing solves this issue by creating OS level processes in order to actually parallelize your code. By doing this, you get multiple processes, each with it's own python interpreter and therefore it's own Global Interpreter Lock.

Mulitprocessing queue termination

I have a program i want to split into 10 parts with multiprocessing. Each worker will be searching for the same answer using different variables to look for it (in this case its brute forcing a password). How to I get the processes to communicate their status, and how do I terminate all processes once one process has found the answer. Thank you!
If you are going to split it into 10 parts than either you should have 10 cores or at least your worker function should not be 100% CPU bound.
The following code initializes each process with a multiprocess.Queue instance to which the worker function will write its result. The main process waits for the first entry written to the queue and then terminates all pool processes. For this demo, the worker function is passed arguments 1, 2, 3, ... 10 and then sleeps for that amount of time and returns the argument passed. So we would expect that the worker function that was passed the argument value of 1 to complete first and that the total running time of the program should be slightly more than 1 second (it takes some time to create the 10 processes):
import multiprocessing
import time
def init_pool(q):
global queue
queue = q
def worker(x):
time.sleep(x)
# write result to queue
queue.put_nowait(x)
def main():
queue = multiprocessing.Queue()
pool = multiprocessing.Pool(10, initializer=init_pool, initargs=(queue,))
for i in range(1, 11):
# non-blocking:
pool.apply_async(worker, args=(i,))
# wait for first result
result = queue.get()
pool.terminate() # kill all tasks
print('Result: ', result)
# required for Windows:
if __name__ == '__main__':
t = time.time()
main()
print('total time =', time.time() - t)
Prints:
Result: 1
total time = 1.2548246383666992

How to use Pool.join() in Python multiprocessing module?

Here is the code:
def function(index):
print('start process '+str(index))
time.sleep(1)
print('end process '+str(index))
return str(index)
if __name__ == '__main__':
pool = Pool(processes=3)
for i in range(4):
res = pool.apply_async(function,args=(i,))
print(res.get())
pool.close()
print('done')
and the output:
start process 0
end process 0
0
start process 1
end process 1
1
start process 2
end process 2
2
start process 3
end process 3
3
done
In my opinion, if the I don't use the pool.join(), the code should only print 'done' and that's it, because the function of pool.join() is 'Wait for the worker processes to exit', but now without pool.join(), it get the same result.
I really don't understand.
In your code, the method get() has the same effect as join(). It also waits for the process to finish because you want to get the result of it.
If you remove it from your code, you will see the 'done' being printed first:
done
start process 0
res.get waits for the process to finish (how else would it get the return value?) which means that process 0 must finish before process 1 can start, and so on.
Remove res.get and you won't see the processes finish. Move res.get to a separate loop after the first one and you'll see they all start before any of them finish.
Also check out Pool.map.

How to properly use join(timeout) in Python threading? [duplicate]

This question already has answers here:
Python - Join Multiple Threads With Timeout
(4 answers)
Closed 8 years ago.
How do i properly use the join(timeout) function in the follow example? the timeout didn't seem to have an effect on the main thread execution. From the docs, the main thread is blocked until threads join or timeouts.
import threading,time
class Server(threading.Thread):
def __init__(self, hostname):
super(Server, self).__init__()
self.__hostname = hostname
def run(self):
print self.__hostname+' left'
time.sleep(5)
print self.__hostname+' back'
sem.release()
#init
sem = threading.BoundedSemaphore(4)
threads = []
for x in xrange(1,5):
sem.acquire()
t = Server('thread '+str(x))
threads.append(t)
t.start()
for t in threads:
t.join(2)
print 'why is this line executed by main thread 5 seconds after, not 2?'
You have a for loop that tries to join each of the 4 threads with a 2 second timeout.
The first .join() call takes the full 2 seconds and then times out. The second does the same. The third thread finishes after 5 seconds (1 second after the third .join(2) call), and the 4th is already done when it's joined. 2 + 2 + 1 = 5.

How do I parallelize a simple Python loop?

This is probably a trivial question, but how do I parallelize the following loop in python?
# setup output lists
output1 = list()
output2 = list()
output3 = list()
for j in range(0, 10):
# calc individual parameter value
parameter = j * offset
# call the calculation
out1, out2, out3 = calc_stuff(parameter = parameter)
# put results into correct output list
output1.append(out1)
output2.append(out2)
output3.append(out3)
I know how to start single threads in Python but I don't know how to "collect" the results.
Multiple processes would be fine too - whatever is easiest for this case. I'm using currently Linux but the code should run on Windows and Mac as-well.
What's the easiest way to parallelize this code?
Using multiple threads on CPython won't give you better performance for pure-Python code due to the global interpreter lock (GIL). I suggest using the multiprocessing module instead:
pool = multiprocessing.Pool(4)
out1, out2, out3 = zip(*pool.map(calc_stuff, range(0, 10 * offset, offset)))
Note that this won't work in the interactive interpreter.
To avoid the usual FUD around the GIL: There wouldn't be any advantage to using threads for this example anyway. You want to use processes here, not threads, because they avoid a whole bunch of problems.
from joblib import Parallel, delayed
def process(i):
return i * i
results = Parallel(n_jobs=2)(delayed(process)(i) for i in range(10))
print(results) # prints [0, 1, 4, 9, 16, 25, 36, 49, 64, 81]
The above works beautifully on my machine (Ubuntu, package joblib was pre-installed, but can be installed via pip install joblib).
Taken from https://blog.dominodatalab.com/simple-parallelization/
Edit on Mar 31, 2021: On joblib, multiprocessing, threading and asyncio
joblib in the above code uses import multiprocessing under the hood (and thus multiple processes, which is typically the best way to run CPU work across cores - because of the GIL)
You can let joblib use multiple threads instead of multiple processes, but this (or using import threading directly) is only beneficial if the threads spend considerable time on I/O (e.g. read/write to disk, send an HTTP request). For I/O work, the GIL does not block the execution of another thread
Since Python 3.7, as an alternative to threading, you can parallelise work with asyncio, but the same advice applies like for import threading (though in contrast to latter, only 1 thread will be used; on the plus side, asyncio has a lot of nice features which are helpful for async programming)
Using multiple processes incurs overhead. Think about it: Typically, each process needs to initialise/load everything you need to run your calculation. You need to check yourself if the above code snippet improves your wall time. Here is another one, for which I confirmed that joblib produces better results:
import time
from joblib import Parallel, delayed
def countdown(n):
while n>0:
n -= 1
return n
t = time.time()
for _ in range(20):
print(countdown(10**7), end=" ")
print(time.time() - t)
# takes ~10.5 seconds on medium sized Macbook Pro
t = time.time()
results = Parallel(n_jobs=2)(delayed(countdown)(10**7) for _ in range(20))
print(results)
print(time.time() - t)
# takes ~6.3 seconds on medium sized Macbook Pro
To parallelize a simple for loop, joblib brings a lot of value to raw use of multiprocessing. Not only the short syntax, but also things like transparent bunching of iterations when they are very fast (to remove the overhead) or capturing of the traceback of the child process, to have better error reporting.
Disclaimer: I am the original author of joblib.
This IS the easiest way to do it!
You can use asyncio. (Documentation can be found here). It is used as a foundation for multiple Python asynchronous frameworks that provide high-performance network and web-servers, database connection libraries, distributed task queues, etc. Plus it has both high-level and low-level APIs to accomodate any kind of problem.
import asyncio
def background(f):
def wrapped(*args, **kwargs):
return asyncio.get_event_loop().run_in_executor(None, f, *args, **kwargs)
return wrapped
#background
def your_function(argument):
#code
Now this function will be run in parallel whenever called without putting main program into wait state. You can use it to parallelize for loop as well. When called for a for loop, though loop is sequential but every iteration runs in parallel to the main program as soon as interpreter gets there.
1. Firing loop in parallel to main thread without any waiting
#background
def your_function(argument):
time.sleep(5)
print('function finished for '+str(argument))
for i in range(10):
your_function(i)
print('loop finished')
This produces following output:
loop finished
function finished for 4
function finished for 8
function finished for 0
function finished for 3
function finished for 6
function finished for 2
function finished for 5
function finished for 7
function finished for 9
function finished for 1
Update: May 2022
Although this answers the original question, there are ways where we can wait for loops to finish as requested by upvoted comments. So adding them here as well. Keys to implementations are: asyncio.gather() & run_until_complete(). Consider the following functions:
import asyncio
import time
def background(f):
def wrapped(*args, **kwargs):
return asyncio.get_event_loop().run_in_executor(None, f, *args, **kwargs)
return wrapped
#background
def your_function(argument, other_argument): # Added another argument
time.sleep(5)
print(f"function finished for {argument=} and {other_argument=}")
def code_to_run_before():
print('This runs Before Loop!')
def code_to_run_after():
print('This runs After Loop!')
2. Run in parallel but wait for finish
code_to_run_before() # Anything you want to run before, run here!
loop = asyncio.get_event_loop() # Have a new event loop
looper = asyncio.gather(*[your_function(i, 1) for i in range(1, 5)]) # Run the loop
results = loop.run_until_complete(looper) # Wait until finish
code_to_run_after() # Anything you want to run after, run here!
This produces following output:
This runs Before Loop!
function finished for argument=2 and other_argument=1
function finished for argument=3 and other_argument=1
function finished for argument=1 and other_argument=1
function finished for argument=4 and other_argument=1
This runs After Loop!
3. Run multiple loops in parallel and wait for finish
code_to_run_before() # Anything you want to run before, run here!
loop = asyncio.get_event_loop() # Have a new event loop
group1 = asyncio.gather(*[your_function(i, 1) for i in range(1, 2)]) # Run all the loops you want
group2 = asyncio.gather(*[your_function(i, 2) for i in range(3, 5)]) # Run all the loops you want
group3 = asyncio.gather(*[your_function(i, 3) for i in range(6, 9)]) # Run all the loops you want
all_groups = asyncio.gather(group1, group2, group3) # Gather them all
results = loop.run_until_complete(all_groups) # Wait until finish
code_to_run_after() # Anything you want to run after, run here!
This produces following output:
This runs Before Loop!
function finished for argument=3 and other_argument=2
function finished for argument=1 and other_argument=1
function finished for argument=6 and other_argument=3
function finished for argument=4 and other_argument=2
function finished for argument=7 and other_argument=3
function finished for argument=8 and other_argument=3
This runs After Loop!
4. Loops running sequentially but iterations of each loop running in parallel to one another
code_to_run_before() # Anything you want to run before, run here!
for loop_number in range(3):
loop = asyncio.get_event_loop() # Have a new event loop
looper = asyncio.gather(*[your_function(i, loop_number) for i in range(1, 5)]) # Run the loop
results = loop.run_until_complete(looper) # Wait until finish
print(f"finished for {loop_number=}")
code_to_run_after() # Anything you want to run after, run here!
This produces following output:
This runs Before Loop!
function finished for argument=3 and other_argument=0
function finished for argument=4 and other_argument=0
function finished for argument=1 and other_argument=0
function finished for argument=2 and other_argument=0
finished for loop_number=0
function finished for argument=4 and other_argument=1
function finished for argument=3 and other_argument=1
function finished for argument=2 and other_argument=1
function finished for argument=1 and other_argument=1
finished for loop_number=1
function finished for argument=1 and other_argument=2
function finished for argument=4 and other_argument=2
function finished for argument=3 and other_argument=2
function finished for argument=2 and other_argument=2
finished for loop_number=2
This runs After Loop!
Update: June 2022
This in its current form may not run on some versions of jupyter notebook. Reason being jupyter notebook utilizing event loop. To make it work on such jupyter versions, nest_asyncio (which would nest the event loop as evident from the name) is the way to go. Just import and apply it at the top of the cell as:
import nest_asyncio
nest_asyncio.apply()
And all the functionality discussed above should be accessible in a notebook environment as well.
What's the easiest way to parallelize this code?
Use a PoolExecutor from concurrent.futures. Compare the original code with this, side by side. First, the most concise way to approach this is with executor.map:
...
with ProcessPoolExecutor() as executor:
for out1, out2, out3 in executor.map(calc_stuff, parameters):
...
or broken down by submitting each call individually:
...
with ThreadPoolExecutor() as executor:
futures = []
for parameter in parameters:
futures.append(executor.submit(calc_stuff, parameter))
for future in futures:
out1, out2, out3 = future.result() # this will block
...
Leaving the context signals the executor to free up resources
You can use threads or processes and use the exact same interface.
A working example
Here is working example code, that will demonstrate the value of :
Put this in a file - futuretest.py:
from concurrent.futures import ProcessPoolExecutor, ThreadPoolExecutor
from time import time
from http.client import HTTPSConnection
def processor_intensive(arg):
def fib(n): # recursive, processor intensive calculation (avoid n > 36)
return fib(n-1) + fib(n-2) if n > 1 else n
start = time()
result = fib(arg)
return time() - start, result
def io_bound(arg):
start = time()
con = HTTPSConnection(arg)
con.request('GET', '/')
result = con.getresponse().getcode()
return time() - start, result
def manager(PoolExecutor, calc_stuff):
if calc_stuff is io_bound:
inputs = ('python.org', 'stackoverflow.com', 'stackexchange.com',
'noaa.gov', 'parler.com', 'aaronhall.dev')
else:
inputs = range(25, 32)
timings, results = list(), list()
start = time()
with PoolExecutor() as executor:
for timing, result in executor.map(calc_stuff, inputs):
# put results into correct output list:
timings.append(timing), results.append(result)
finish = time()
print(f'{calc_stuff.__name__}, {PoolExecutor.__name__}')
print(f'wall time to execute: {finish-start}')
print(f'total of timings for each call: {sum(timings)}')
print(f'time saved by parallelizing: {sum(timings) - (finish-start)}')
print(dict(zip(inputs, results)), end = '\n\n')
def main():
for computation in (processor_intensive, io_bound):
for pool_executor in (ProcessPoolExecutor, ThreadPoolExecutor):
manager(pool_executor, calc_stuff=computation)
if __name__ == '__main__':
main()
And here's the output for one run of python -m futuretest:
processor_intensive, ProcessPoolExecutor
wall time to execute: 0.7326343059539795
total of timings for each call: 1.8033506870269775
time saved by parallelizing: 1.070716381072998
{25: 75025, 26: 121393, 27: 196418, 28: 317811, 29: 514229, 30: 832040, 31: 1346269}
processor_intensive, ThreadPoolExecutor
wall time to execute: 1.190223217010498
total of timings for each call: 3.3561410903930664
time saved by parallelizing: 2.1659178733825684
{25: 75025, 26: 121393, 27: 196418, 28: 317811, 29: 514229, 30: 832040, 31: 1346269}
io_bound, ProcessPoolExecutor
wall time to execute: 0.533886194229126
total of timings for each call: 1.2977914810180664
time saved by parallelizing: 0.7639052867889404
{'python.org': 301, 'stackoverflow.com': 200, 'stackexchange.com': 200, 'noaa.gov': 301, 'parler.com': 200, 'aaronhall.dev': 200}
io_bound, ThreadPoolExecutor
wall time to execute: 0.38941240310668945
total of timings for each call: 1.6049387454986572
time saved by parallelizing: 1.2155263423919678
{'python.org': 301, 'stackoverflow.com': 200, 'stackexchange.com': 200, 'noaa.gov': 301, 'parler.com': 200, 'aaronhall.dev': 200}
Processor-intensive analysis
When performing processor intensive calculations in Python, expect the ProcessPoolExecutor to be more performant than the ThreadPoolExecutor.
Due to the Global Interpreter Lock (a.k.a. the GIL), threads cannot use multiple processors, so expect the time for each calculation and the wall time (elapsed real time) to be greater.
IO-bound analysis
On the other hand, when performing IO bound operations, expect ThreadPoolExecutor to be more performant than ProcessPoolExecutor.
Python's threads are real, OS, threads. They can be put to sleep by the operating system and reawakened when their information arrives.
Final thoughts
I suspect that multiprocessing will be slower on Windows, since Windows doesn't support forking so each new process has to take time to launch.
You can nest multiple threads inside multiple processes, but it's recommended to not use multiple threads to spin off multiple processes.
If faced with a heavy processing problem in Python, you can trivially scale with additional processes - but not so much with threading.
There are a number of advantages to using Ray:
You can parallelize over multiple machines in addition to multiple cores (with the same code).
Efficient handling of numerical data through shared memory (and zero-copy serialization).
High task throughput with distributed scheduling.
Fault tolerance.
In your case, you could start Ray and define a remote function
import ray
ray.init()
#ray.remote(num_return_vals=3)
def calc_stuff(parameter=None):
# Do something.
return 1, 2, 3
and then invoke it in parallel
output1, output2, output3 = [], [], []
# Launch the tasks.
for j in range(10):
id1, id2, id3 = calc_stuff.remote(parameter=j)
output1.append(id1)
output2.append(id2)
output3.append(id3)
# Block until the results have finished and get the results.
output1 = ray.get(output1)
output2 = ray.get(output2)
output3 = ray.get(output3)
To run the same example on a cluster, the only line that would change would be the call to ray.init(). The relevant documentation can be found here.
Note that I'm helping to develop Ray.
I found joblib is very useful with me. Please see following example:
from joblib import Parallel, delayed
def yourfunction(k):
s=3.14*k*k
print "Area of a circle with a radius ", k, " is:", s
element_run = Parallel(n_jobs=-1)(delayed(yourfunction)(k) for k in range(1,10))
n_jobs=-1: use all available cores
Dask futures; I'm surprised no one has mentioned it yet . . .
from dask.distributed import Client
client = Client(n_workers=8) # In this example I have 8 cores and processes (can also use threads if desired)
def my_function(i):
output = <code to execute in the for loop here>
return output
futures = []
for i in <whatever you want to loop across here>:
future = client.submit(my_function, i)
futures.append(future)
results = client.gather(futures)
client.close()
why dont you use threads, and one mutex to protect one global list?
import os
import re
import time
import sys
import thread
from threading import Thread
class thread_it(Thread):
def __init__ (self,param):
Thread.__init__(self)
self.param = param
def run(self):
mutex.acquire()
output.append(calc_stuff(self.param))
mutex.release()
threads = []
output = []
mutex = thread.allocate_lock()
for j in range(0, 10):
current = thread_it(j * offset)
threads.append(current)
current.start()
for t in threads:
t.join()
#here you have output list filled with data
keep in mind, you will be as fast as your slowest thread
thanks #iuryxavier
from multiprocessing import Pool
from multiprocessing import cpu_count
def add_1(x):
return x + 1
if __name__ == "__main__":
pool = Pool(cpu_count())
results = pool.map(add_1, range(10**12))
pool.close() # 'TERM'
pool.join() # 'KILL'
The concurrent wrappers by the tqdm library are a nice way to parallelize longer-running code. tqdm provides feedback on the current progress and remaining time through a smart progress meter, which I find very useful for long computations.
Loops can be rewritten to run as concurrent threads through a simple call to thread_map, or as concurrent multi-processes through a simple call to process_map:
from tqdm.contrib.concurrent import thread_map, process_map
def calc_stuff(num, multiplier):
import time
time.sleep(1)
return num, num * multiplier
if __name__ == "__main__":
# let's parallelize this for loop:
# results = [calc_stuff(i, 2) for i in range(64)]
loop_idx = range(64)
multiplier = [2] * len(loop_idx)
# either with threading:
results_threading = thread_map(calc_stuff, loop_idx, multiplier)
# or with multi-processing:
results_processes = process_map(calc_stuff, loop_idx, multiplier)
Let's say we have an async function
async def work_async(self, student_name: str, code: str, loop):
"""
Some async function
"""
# Do some async procesing
That needs to be run on a large array. Some attributes are being passed to the program and some are used from property of dictionary element in the array.
async def process_students(self, student_name: str, loop):
market = sys.argv[2]
subjects = [...] #Some large array
batchsize = 5
for i in range(0, len(subjects), batchsize):
batch = subjects[i:i+batchsize]
await asyncio.gather(*(self.work_async(student_name,
sub['Code'],
loop)
for sub in batch))
This could be useful when implementing multiprocessing and parallel/ distributed computing in Python.
YouTube tutorial on using techila package
Techila is a distributed computing middleware, which integrates directly with Python using the techila package. The peach function in the package can be useful in parallelizing loop structures. (Following code snippet is from the Techila Community Forums)
techila.peach(funcname = 'theheavyalgorithm', # Function that will be called on the compute nodes/ Workers
files = 'theheavyalgorithm.py', # Python-file that will be sourced on Workers
jobs = jobcount # Number of Jobs in the Project
)
Have a look at this;
http://docs.python.org/library/queue.html
This might not be the right way to do it, but I'd do something like;
Actual code;
from multiprocessing import Process, JoinableQueue as Queue
class CustomWorker(Process):
def __init__(self,workQueue, out1,out2,out3):
Process.__init__(self)
self.input=workQueue
self.out1=out1
self.out2=out2
self.out3=out3
def run(self):
while True:
try:
value = self.input.get()
#value modifier
temp1,temp2,temp3 = self.calc_stuff(value)
self.out1.put(temp1)
self.out2.put(temp2)
self.out3.put(temp3)
self.input.task_done()
except Queue.Empty:
return
#Catch things better here
def calc_stuff(self,param):
out1 = param * 2
out2 = param * 4
out3 = param * 8
return out1,out2,out3
def Main():
inputQueue = Queue()
for i in range(10):
inputQueue.put(i)
out1 = Queue()
out2 = Queue()
out3 = Queue()
processes = []
for x in range(2):
p = CustomWorker(inputQueue,out1,out2,out3)
p.daemon = True
p.start()
processes.append(p)
inputQueue.join()
while(not out1.empty()):
print out1.get()
print out2.get()
print out3.get()
if __name__ == '__main__':
Main()
Hope that helps.
very simple example of parallel processing is
from multiprocessing import Process
output1 = list()
output2 = list()
output3 = list()
def yourfunction():
for j in range(0, 10):
# calc individual parameter value
parameter = j * offset
# call the calculation
out1, out2, out3 = calc_stuff(parameter=parameter)
# put results into correct output list
output1.append(out1)
output2.append(out2)
output3.append(out3)
if __name__ == '__main__':
p = Process(target=pa.yourfunction, args=('bob',))
p.start()
p.join()

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