I'm trying to extract a link from a page with python and the beautifulsoup library, but I'm stuck. The link is on the following page, on the sidebar area, directly underneath the h4 subtitle "Original Source:
http://www.eurekalert.org/pub_releases/2016-06/uonc-euc062016.php
I've managed to isolate the link (mostly), but I'm unsure of how to further advance my targeting to actually extract the link. Here's my code so far:
import requests
from bs4 import BeautifulSoup
url = "http://www.eurekalert.org/pub_releases/2016-06/uonc-euc062016.php"
data = requests.get(url)
soup = BeautifulSoup(data.text, 'lxml')
source_url = soup.find('section', class_='widget hidden-print').find('div', class_='widget-content').findAll('a')[-1]
print(source_url)
I am currently getting the full html of the last element in which I've isolated, where I'm trying to simply get the link. Of note, this is the only link on the page I'm trying to get.
You're looking for the link which is the href html attribute. source_url is a bs4.element.Tag which has the get method like:
source_url.get('href')
You almost got it!!
SOLUTION 1:
You just have to run the .text method on the soup you've assigned to source_url.
So instead of:
print(source_url)
You should use:
print(source_url.text)
Output:
http://news.unchealthcare.org/news/2016/june/e-cigarette-use-can-alter-hundreds-of-genes-involved-in-airway-immune-defense
SOLUTION 2:
You should call source_url.get('href') to get only the specific href tag related to your soup.findall element.
print source_url.get('href')
Output:
http://news.unchealthcare.org/news/2016/june/e-cigarette-use-can-alter-hundreds-of-genes-involved-in-airway-immune-defense
Related
The element I'm looking to find looks like this:
<a href="pic:/82eu92e/iwjd/" data-superid="picture-link">
Previously I found all href's in the page, then found the correct href by finding which one had the text pic:, but I can't do this any longer due to some pages having scrolling galleries causing stale elements.
You can filter by attribute:
driver.find_element_by_xpath('//a[#data-superid="picture-link"]')
Regarding the scrolling part, here is a previously asked question that can help you.
You could try beautifulsoup + selenium, like:
from bs4 import BeautifulSoup
text = '''<a href="pic:/82eu92e/iwjd/" data-superid="picture-link">'''
# Under your circumstance, you need to use:
# text = driver.page_source
soup = BeautifulSoup(text, "html.parser")
print(soup.find("a", attrs={"data-superid":"picture-link"}))
Result:
<a data-superid="picture-link" href="pic:/82eu92e/iwjd/"></a>
To Extract the href value using data-superid="picture-link" use following css selector or xpath.
links=driver.find_elements_by_css_selector("a[data-superid='picture-link'][href]")
for link in links:
print(link.get_attribute("href"))
OR
links=driver.find_elements_by_xpath("//a[#data-superid='picture-link'][#href]")
for link in links:
print(link.get_attribute("href"))
I am trying to extract the gallery link of the first result on an imgur search.
theurl = "https://imgur.com/search?q=" +text
thepage = urlopen(theurl)
soup = BeautifulSoup(thepage,"html.parser")
link = soup.findAll('a',{"class":"image-list-link"})[0].decode_contents()
Here is what is being displayed for link:
I am mainly trying to get the href value from only this section (the first result for the search)
Here is what the inspect element looks like:
Actually, it's pretty easy to accomplish what you're trying to do. As shown in the image, the href of first image (or any image for that matter) is located inside the <a> tag with the attribute class="image-list-link". So, you can use the find() function, which returns the first match found. And then, use ['href'] to get the link.
Code:
import requests
from bs4 import BeautifulSoup
r = requests.get('https://imgur.com/search?q=python')
soup = BeautifulSoup(r.text, 'lxml')
first_image_link = soup.find('a', class_='image-list-link')['href']
print(first_image_link)
# /gallery/AxKwQ2c
If you want to get the links for all the images, you can use a list comprehension.
all_image_links = [a['href'] for a in soup.find_all('a', class_='image-list-link')]
I am trying to scrape website, but I encountered a problem. When I try to scrape data, it looks like the html differs from what I see on google inspect and from what I get from python. I get this with http://edition.cnn.com/election/results/states/arizona/house/01 I tried to scrape election results. I used this script to check HTML part of the webpage, and I noticed that they different. There is no classes that I need, like section-wrapper.
page =requests.get('http://edition.cnn.com/election/results/states/arizona/house/01')
soup = BeautifulSoup(page.content, "lxml")
print(soup)
Anyone knows what is the problem ?
http://data.cnn.com/ELECTION/2016/AZ/county/H_d1_county.json
This site use JavaScript fetch data, you can check the url above.
You can find this url in chrome dev-tools, there are many links, check it out
Chrome >>F12>> network tab>>F5(refresh page)>>double click the .josn url>> open new tab
import requests
from bs4 import BeautifulSoup
page=requests.get('http://edition.cnn.com/election/results/states/arizona/house/01')
soup = BeautifulSoup(page.content)
#you can try all sorts of tags here I used class: "ad" and class:"ec-placeholder"
g_data = soup.find_all("div", {"class":"ec-placeholder"})
h_data = soup.find_all("div"),{"class":"ad"}
for item in g_data:print item
#print '\n'
#for item in h_data:print item
I am currently going through the Web Scraping section of AutomateTheBoringStuff and trying to write a script that extracts translated words from Google Translate using BeautifulSoup4.
I inspected the html content of a page where 'Explanation' is the translated word:
<span id="result_box" class="short_text" lang="en">
<span class>Explanation</span>
</span>
Using BeautifulSoup4, I tried different selectors but nothing would return the translated word. Here are a few examples I tried, but they return no results at all:
soup.select('span[id="result_box"] > span')
soup.select('span span')
I even copied the selector directly from the Developer Tools, which gave me #result_box > span. This again returns no results.
Can someone explain to me how to use BeautifulSoup4 for my purpose? This is my first time using BeautifulSoup4 but I think I am using BeautifulSoup more or less correctly because the selector
soup.select('span[id="result_box"]')
gets me the outer span element**
[<span class="short_text" id="result_box"></span>]
**Not sure why the 'leng="en"' part is missing but I am fairly certain I have located the correct element regardless.
Here is the complete code:
import bs4, requests
url = 'https://translate.google.ca/#zh-CN/en/%E6%B2%BB%E5%85%B7'
res = requests.get(url)
res.raise_for_status
soup = bs4.BeautifulSoup(res.text, "html.parser")
translation = soup.select('#result_box span')
print(translation)
EDIT: If I save the Google Translate page as an offline html file and then make a soup object out of that html file, there would be no problem locating the element.
import bs4
file = open("Google Translate.html")
soup = bs4.BeautifulSoup(file, "html.parser")
translation = soup.select('#result_box span')
print(translation)
The result_box div is the correct element but your code only works when you save what you see in your browser as that includes the dynamically generated content, using requests you get only the source itself bar any dynamically generated content. The translation is generated by an ajax call to the url below:
"https://translate.google.ca/translate_a/single?client=t&sl=zh-CN&tl=en&hl=en&dt=at&dt=bd&dt=ex&dt=ld&dt=md&dt=qca&dt=rw&dt=rm&dt=ss&dt=t&ie=UTF-8&oe=UTF-8&source=bh&ssel=0&tsel=0&kc=1&tk=902911.786207&q=%E6%B2%BB%E5%85%B7"
For your requests it returns:
[[["Fixture","治具",,,0],[,,,"Zhì jù"]],,"zh-CN",,,[["治 具",1,[["Fixture",999,true,false],["Fixtures",0,true,false],["Jig",0,true,false],["Jigs",0,true,false],["Governance",0,true,false]],[[0,2]],"治具",0,1]],1,,[["ja"],,[1],["ja"]]]
So you will either have to mimic the request, passing all the necessary parameters or use something that supports dynamic content like selenium
Simply try this :
translation = soup.select('#result_box span')[0].text
print(translation)
You can try this diferent aproach:
if filename.endswith(extension_file):
with open(os.path.join(files_from_folder, filename), encoding='utf-8') as html:
soup = BeautifulSoup('<pre>' + html.read() + '</pre>', 'html.parser')
for title in soup.findAll('title'):
recursively_translate(title)
FOR THE COMPLETE CODE, PLEASE SEE HERE:
https://neculaifantanaru.com/en/python-code-text-google-translate-website-translation-beautifulsoup-library.html
or HERE:
https://neculaifantanaru.com/en/example-google-translate-api-key-python-code-beautifulsoup.html
I am extracting data for a research project and I have sucessfully used findAll('div', attrs={'class':'someClassName'}) in many websites but this particular website,
WebSite Link
doesn't return any values when I used attrs option. But when I don't use the attrs option I get entire html dom.
Here is the simple code that I started with to test it out:
soup = bs(urlopen(url))
for div in soup.findAll('div', attrs={'class':'data'}):
print div
My code is working fine, with requests
import requests
from BeautifulSoup import BeautifulSoup as bs
#grab HTML
r = requests.get(r'http://www.amazon.com/s/ref=sr_pg_1?rh=n:172282,k%3adigital%20camera&keywords=digital%20camera&ie=UTF8&qid=1343600585')
html = r.text
#parse the HTML
soup = bs(html)
results= soup.findAll('div', attrs={'class': 'data'})
print results
If you or anyone reading this question would like to know the reason that the code wasn't able to find the attrs value using the code you've given (copied below):
soup = bs(urlopen(url))
for div in soup.findAll('div', attrs={'class':'data'}):
print div
The issue is when you attempted to create a BeautifulSoup object soup = bs(urlopen(url)) as the value of urlopen(url) is a response object and not the DOM.
I'm sure any issues you had encountered could have been more easily resolved by using bs(urlopen(url).read()) instead.