Hey guys I am having a difficult time writing a code to create a triangle of asterisks and having a reflection of the triangle appear on the same line. The end product is two triangles that have a giant V shape of empty space in the middle. So far I have created the left side triangle but I do not know how to reflect it to appear reversed on the opposite side. Here is my code so far:
for A in range(1,10):
for A1 in range(1,A+1):
print("*", end='')
print()
for A2 in range():
print(" ", end='')
print()
for A3 in range(1,A+1):
print("*", end='')
print()
The end shape should look something like an M made up of triangles with a wider space in the middle. I think I am on the right track but A2 needs to be the code to create the gap of spaces in between but I cannot figure out the numbers to do it.
Any help would be appreciated, thanks!
One solution doesn't even use nested for loops
for A in range(1,10):
print(A*"*" + (18-(2*A))*" " + A*"*")
or
for A in range(1,N):
print(A * "*" + (((N-1)*2)*A)*" " + A * "*")
Related
This program will output a right triangle based on user specified height triangle_height and symbol triangle_char.
(1) The given program outputs a fixed-height triangle using a * character. Modify the given program to output a right triangle that instead uses the user-specified triangle_char character.
(2) Modify the program to use a loop to output a right triangle of height triangle_height. The first line will have one user-specified character, such as % or *. Each subsequent line will have one additional user-specified character until the number in the triangle's base reaches triangle_height. Output a space after each user-specified character, including a line's last user-specified character.
I'm having trouble figuring out how to create a space between my characters. Example input is % and 5. My code is:
triangle_char = input('Enter a character:\n')
triangle_height = int(input('Enter triangle height:\n'))
print('')
for i in range (triangle_height):
print((triangle_char) * (i + 1))
my output is:
%
%%
%%%
%%%%
%%%%%
while expected output is:
%
% %
% % %
% % % %
% % % % %
You need to use join(). This would work:
for i in range(triangle_height):
print(' '.join(triangle_char * (i + 1)))
It is adding spaces between every character because strings are iterable.
This may be optimized a bit by having a list of the characters and appending 1 character in each iteration, rather than constructing triangle_char * (i+1) every time.
This should fix the white space errors:
for i in range(triangle_height):
print(' '.join(triangle_char * (i + 1)) + ' ')
for i in range(triangle_height+1):
print(f'{triangle_char} '*i)
I see the popular way so far is using join, but another way while trying to stay true to the original idea is you simply can add a white space after each character. See below:
triangle_char = input('Enter a character:\n')
triangle_height = int(input('Enter triangle height:\n'))
print('')
for i in range(triangle_height):
print((triangle_char + ' ') * (i + 1))
There are some really good suggestions on here. Another approach is to use an incremented variable in a while loop as shown below:
triangle_char = input("Enter a character:\n")[0]
triangle_height = int(input("Enter triangle height:\n"))
i = 0
while (i <= triangle_height):
print((triangle_char + ' ') * i)
i += 1
With the example above, i iterates until it is equal to triangle_height and uses polymorphism to generate a quantity of (triangle_height + ' ') based on the value of i. This will generate the right triangle this lab requires. The space is used to format the triangle per lab requirements.
Another method is using the .join() feature, and it certainly would work well here, but is not taught until CH7 of this book where you learn about input and CSV files. I am unsure if your professor would approve of using this, and I am only saying this because my professor was strict about using material not covered.
An additional method mentioned already is to use a for loop with the use of the range() feature containing an expression:
triangle_char = input("Enter a character:\n")[0]
triangle_height = int(input("Enter triangle height:\n"))
for i in range((triangle_height + 1)):
print((triangle_char + ' ') * i)
The end point of range() being just triangle_height would not suffice because the value specified as the end point is not included in the sequence. This would make a right triangle with a height of 4 even if triangle_height was 5 Therefore, you must use the expression (triangle_height + 1). From there, the output is set up similarly to my first solution.
Try adding a whitespace in the print statement.
height = int(input())
symbol = (input())
print()
for i in range(height): #Loop for every index in the range 0-height
print((symbol + ' ') * (i + 1)) #Add whitespace to symbol
I have a 2d list [1,2,3,4],[4,3,3,1],[3,2,1,1],[2,2,2,1] and I want to print it out to match the following format.
0123
XXXXXXXX
0*1234*0
1*4331*1
2*3211*2
3*2221*3
XXXXXXXX
0123
It should not be hard coded and the length of the list = n so this list n=4 but if list n=5 there would be 5 digits per row and the number on the sides would go 0,1,2,3,4.
So far all I have is:
for row in board:
for column in row:
print(column, end="")
print("")
Which only outputs the list as:
1234
4331
3211
2221
please help me add all the special stuff.
so I find a solution for what you want to do however I think it can be improved a lot (not program quite a lot in python), but I'll leave it here anyways :)
print(" ", end="")
for x in range(len(board)):
print(x, end="")
print()
for x in range(len(board)+4):
print("X", end="")
print()
for num,row in enumerate(board):
print(f"{num}*", end="")
for column in row:
print(column, end="")
print(f"*{num}", end="")
print("")
for x in range(len(board)+4):
print("X", end="")
print()
print(" ", end="")
for x in range(len(board)):
print(x, end="")
print()
Well for the first line you pretty much print 2 spaces, followed by all the digits between 0 and the number of columns in your board. You can use the "range" function for this. Then you must print the correct amount of 'X'. The correct amount is number of columns + 4, I think you can see why.
You should keep a counter starting from 0. For each row you print, you must print the string value of the counter, followed by an asterisk(*), followed by your row, followed by an asterisk(*) and finally followed by the same counter value. You must increment the counter by one for each row.
The last 2 rows are the same as top 2.
I do not want to share my code because this is such a simple problem, I think solving it on your own will help you in the long run.
Probably an unpopular opinion, but I think these kinds of problems are really fun.
This solution formats the contents correctly, even if you change the number of rows, and even the number of items in each row.
def draw_board(board):
# determining the number of elements in a row,
# this is used for printing the X's
# and printing the spaced ranges (i.e. " 0123 ")
n = len(board[0])
# calculating the total width of the board,
# + 4 is because of the "0*...*0" situation
width = n + 4
# calculating margin of the spaced ranges
# (i.e. calculating how much space on each side)
margin = int(n / 2)
# printing the spaced ranges using the margin
print(" " * margin + "".join(str(num) for num in list(range(n))) + " " * margin)
# printing the XXXX
print("X" * width)
# printing the row index number,
# with the *,
# along with the numbers in the row,
# followed by the * and the row number
for row in range(len(board)):
print(str(row) + "*" + "".join(str(elem) for elem in board[row]) + "*" + str(row))
# printing the XXXX
print("X" * width)
# printing the spaced ranges using the margin
print(" " * margin + "".join(str(num) for num in list(range(n))) + " " * margin)
b = [
[1,2,3,4],
[4,3,3,1],
[3,2,1,1],
[2,2,2,1]
]
draw_board(b)
# OUTPUT:
# 0123
# XXXXXXXX
# 0*1234*0
# 1*4331*1
# 2*3211*2
# 3*2221*3
# XXXXXXXX
# 0123
Edited to remove my own tests and to reflect given problem.
so I'm trying to get my nested loop to display an image like in this picture:
So far, this is the code that I have.
for a in range (1):
print("#""#")
for b in range (0,5,1):
print("#", end=" ")
for c in range(b):
print(" ", end=" ")
print("#")
I'm new to the site, so please excuse my terrible formatting. The output I'm getting seems to have an extra space per line compared to the image given, and I'm not sure how to get rid of the space. I'd appreciate any help!
I'm thinking it's the 'end=' '' statement, but if I try replacing that with just a space, my entire line goes wonky.
Thanks!
end=" " prints an space instead of a newline in the end..
I think its better to concatenate the string in this case instead of manipulating the print's end..
for i in range(5):
print('#' + ' '*i + '#')
output:
##
# #
# #
# #
# #
You need to remove the whitespace in the 2nd end variable
for a in range (1):
print("#""#")
for b in range (0,5,1):
print("#", end=" ")
for c in range(b):
print(" ", end="") #this end variable is what is causing your additional space
print("#")
Like this? Changed the third print
for a in range (1):
print("#""#")
for b in range (0,5,1):
print("#", end=" ")
for c in range(b):
print(end=" ")
print("#")
I am trying to write a simple python program that prints two ##, then # #, and increases the number of spaces in between the #'s each time. Here is the code I tried:
i=0
while (i<=5):
print ("#" (" " * i) "#")
#print (" " * i)
#print ("#" "#")
The multiplication works in the first line of code I tested then commended out, I see it in the shell each time it prints one more space.
Printing two #'s works also.
I can't figure out how to combine it into one statement that works, or any other method of doing this.
Any help would be appreciated, thanks.
i=0
while (i<=5):
print( "#" +(" "*i)+ "#")
i=i+1
You need to add the strings inside the print statement and increment i.
You want to print a string that depends an a variable. There are other methods to build a string but the simplest, most obvious one is adding together some fixed pieces and some computed pieces, in your case a "#", a sequence of spaces and another "#". To add together the pieces you have to use the + operator, like in "#"+" "+"#".
Another problem in your code is the while loop, if you don't increment the variable i its value will be always 0 and the loop will be executed forever!
Eventually you will learn that the idiom to iterate over a sequence of integers, from 0 to n-1 is for i in range(n): ..., but for now the while loop is good enough.
This should do it:
i=0
while (i<=5):
print ('#' + i * ' ' + '#')
i = i + 1
Try this:
def test(self, number: int):
for i in range (number)):
print('#' +i * ''+ '#')
i+=1
return
I'm using Grok Learning and the task it give you is 'to select every third letter out of a sentence (starting from the first letter), and print out those letters with spaces in between them.'
This is my code:
text = input("Message? ")
length = len(text)
for i in range (0, length, 3):
decoded = text[i]
print(decoded, end=" ")
Although I it says it isn't correct, it say this is the desired out-put:
Message? cxohawalkldflghemwnsegfaeap
c h a l l e n g e
And my output is the same expect, in my output, I have a space after the last 'e' in challenge. Can anyone think of a way to fix this?
To have spaces only between the characters, you could use a slice to create the string "challenge" then use str.join to add the spaces:
" ".join(text[::3])
Here's Grok's explanation to your question: "So, this question is asking you to loop over a string, and print out every third letter. The easiest way to do this is to use for and range, letting range do all the heavy lifting and hard work! We know that range creates a list of numbers, - we can use these numbers as indexes for the message!"
So if you are going to include functions like print, len, end, range, input, for and in functions, your code should look somewhat similar to this:
line = input('Message? ')
result = line[0]
for i in range(3, len(line), 3):
result += ' ' + line[i]
print(result)
Or this:
line = input('Message? ')
print(line[0], end='')
for i in range(3, len(line), 3):
print(' ' + line[i], end='')
print()
Or maybe this:
code = input ('Message? ') [0::3]
msg = ""
for i in code: msg += " " + i
print (msg [1:])
All of these should work, and I hope this answers your question.
I think Grok is just really picky about the details. (It's also case sensitive)
Maybe try this for an alternative because this one worked for me:
message = input('Message? ')
last_index = len(message) -1
decoded = ''
for i in range(0, last_index, 3):
decoded += message[i] + ' '
print(decoded.rstrip())
You should take another look at the notes on this page about building up a string, and then printing it out all at once, in this case perhaps using rstrip() or output[:-1] to leave off the space on the far right.
Here's an example printing out the numbers 0 to 9 in the same fashion, using both rstrip and slicing.
output = ""
for i in range(10):
output = output + str(i) + ' '
print(output[:-1])
print(output.rstrip())
If you look through the Grok course, there is one page called ‘Step by step, side by side’ (link here at https://groklearning.com/learn/intro-python-1/repeating-things/8/) where it introduces the rstrip function. If you write print(output.rstrip()) it will get rid of whitespace to the right of the string.