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Cant access login popup window elements using Selenium Python

When the login button is clicked a popup window which shows login with google. I need to access into the sign in with google button of the popup. I've shown some previous example to handle the popup using driver.switch_to_window method and iframe method. But cant access the element in the popup window.
The Below code is showing noSuchElementException
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait as wait
from time import sleep
driver = webdriver.Chrome()
driver.maximize_window()
driver.get("https://shatkora.co/grocery")
main_window=None
while not main_window:
main_window=driver.current_window_handle
join_btn=driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div[1]/div/header/div/button")
join_btn.click()
login_window=None;
while not login_window:
for handle in driver.window_handles:
if(handle!=main_window):
login_window=handle
break
# driver.switch_to(login_window)
driver.switch_to.window(login_window)
login_with_google_button=driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div[6]/div/div/div/div[1]/button")
login_with_google_button.click()

You do not need to switch to any windows, also use absolute xpath with explicit waits.
driver = webdriver.Chrome(driver_path)
driver.maximize_window()
driver.get("https://shatkora.co/grocery")
wait = WebDriverWait(driver, 20)
join_btn = wait.until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Join']")))
join_btn.click()
time.sleep(5)
button = driver.find_element_by_xpath("//h3[text()='Welcome to Shatkora!']/following-sibling::button")
driver.execute_script("arguments[0].click();", button)
after this code you will have to switch to new windows, which can be done via below code :
handles = driver.window_handles
driver.switch_to.window(handles[1])

selenium - wait for scrolldown

I am trying to automate downloads from a webpage using selenium.
So far my strategy is to instantiate a firefox driver that loads the page and clicks the download button. However, to be clickable, the button needs to be visible, i.e. not covered by any banners on the page (at least in my understanding). Therefore I need to scroll down (I use scrollIntoView()). If I run button.click() immediately after scrolling down, the download doesn't start, if I hard code a sufficient timeout in between it works out fine. Can somebody help me to set a timeout conditioned on the scroll down?
Here is my code:
from selenium import webdriver
profilePath = '/path/to/my/firefox/profile'
profile = webdriver.FirefoxProfile(profilePath)
driver = webdriver.Firefox(firefox_profile=profile)
driver.get("https://www.happyscribe.com/public/lex-fridman-podcast-artificial-intelligence-ai/164-andrew-huberman-sleep-dreams-creativity-the-limits-of-the-human-mind")
button = driver.find_element_by_id('btn-download')
target=driver.execute_script("arguments[0].scrollIntoView({block: 'center'});", button)
time.sleep(10)
button.click()
and this is the html code of the button:
<button class="hs-btn-secondary small" id="btn-download" type="button">Download</button>
I would be very thankful for any direct help or suggestions on how to tackle the problem from a different angle.

It sounds like you may need to induce WebDriverWait for the element to by clickable. You could do so like this. It will wait for the element to be both visible and enabled before clicking.
from selenium import webdriver
import time
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
profilePath = '/path/to/my/firefox/profile'
profile = webdriver.FirefoxProfile(profilePath)
driver = webdriver.Firefox(firefox_profile=profile)
driver.get("https://www.happyscribe.com/public/lex-fridman-podcast-artificial-intelligence-ai/164-andrew-huberman-sleep-dreams-creativity-the-limits-of-the-human-mind")
button = driver.find_element_by_id('btn-download')
target=driver.execute_script("arguments[0].scrollIntoView({block: 'center'});", button)
WebDriverWait(driver, 10).until(EC.element_to_be_clickable(button))
button.click()

I'm trying to automate a process on a website. How do I close a pop up window with selenium, when it is not clear when the popup window will appear?

I am trying to close a pop up window with selenium in python, which is not allowing my code to execute further. But I am unable to do that. There is a a pop up window which asks me if i want to sign up but it keeps popping up at inconsistent times. Is there a method to check wether or not the pop-up window is active?
My code so far:
import selenium
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
PATH = "C:\Program Files (x86)\chromedriver.exe";
driver = webdriver.Chrome(PATH);
driver.get("https://www.investing.com/news/")
time.sleep(3)
accept_cookies = driver.find_element_by_xpath('//*[#id="onetrust-accept-btn-handler"]');
accept_cookies.click();

So your problem is that you don't want the signup popup to display.
I was just poking the site's script, I found a really nice way for you to work around it: set user agent to gene. The script to display popup will be disabled if user agent matches some mobile browsers.
import time
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
opts = Options()
opts.add_argument("user-agent=gene")
driver = webdriver.Chrome(options=opts)
# Adds the cookie into current browser context
driver.get("https://www.investing.com/news/")
time.sleep(60) # wait for a minute to see if the popup happens
driver.quit()
Run this code, observe the page, it will not display the signup popup.
Alternative work around:
Use a Chrome profile that already turned off the Signup popup, will also not display the popup
from selenium import webdriver
options = webdriver.ChromeOptions()
options.add_argument("user-data-dir=C:\\Path") #Path to your chrome profile
If you really need to close the popup without these methods, define a check function with try/except. Before doing any actions, call this function to check if there's popup, then close the popup, save the state to some variable (so you don't check it anymore). Since the function has try/except, it will not raise Exception and your code will run.

You can do this with 2 quick methods that I can think of immediately.
1:
You will use this often
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
then when you want to get an element that needs time to load and you want to do actions with it, you implement it with WebDriverWait :
wait = WebDriverWait(driver, 10)
try:
accept_cookies = wait.until(EC.presence_of_element_located((By.XPATH, "'//*
[#id=\"onetrust-accept-btn-handler\"]'")))
catch:
# probably you have a bad locator and the element doesn't exist or it needs more than 10 sec to load.
else:
# logic here is processed after successfully obtaining the pop up
accept_cookies.click()
I would recommend using ActionChains
from selenium.webdriver.common.action_chains import ActionChains
then after you obtain the pop up element make the click like this:
actions = ActionChains(driver)
actions.move_to_element(accept_cookies).click().perform()
This is the equivalent of moving the mouse pointer to the middle of the pop up close btn and clicking it

Python Selenium closing a pop-up window

I'd like to close this window opened up on Amazon web site by using Selenium with Python. I've tried find_element_by_xpath, but it doesn't work. Here's the snippet of the code;
close_to_list = browser.get("/html/body/div[4]/div/div/div[2]/div[2]/div[2]/div[1]/div[2]/div/div/table/tbody/tr[2]")
I get the xpath of that 'X' button but I guess I need to close it as switch_to_alert, but I'm new to this era so I couldn't write it properly.
Here's the image view;
enter image description here

You don't need to use switch_to_alert() as well as get() to close modal window. Just try to close it with below code:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, 'button[aria-label="Close"]'))).click()
This allows you to wait for button appearance and click the button

Frame Switch to click on a Box (Python Selenium)

I have a problem trying to automate my browser with Selenium on Python. It's been several hours that I block, and since I'm a beginner .. :(
I explain my problem:
I have to reach click on a box of Recaptcha. To do this, my bot must click on a button on the site, which then displays the recaptcha that I have to validate.
Here are the source page screenshot:
The popup of the recaptcha, in which the checkbox is located
The location of the checkbox that I have to click
I try this code:
time.sleep(5)
browser.switch_to_frame(browser.find_element_by_tag_name("CaptchaPopup"))
browser.switch_to_frame(browser.find_element_by_tag_name("iframe"))
CheckBox = WebDriverWait(browser, 10).until(
browser.find_element_by_id('recaptcha-anchor').click())
time.sleep(0.7)
CheckBox.click()
But the latter returns me an error :(
selenium.common.exceptions.NoSuchFrameException: Message: no such frame
I use Python 2.7.
Do you have a solution ?
Thank you very much in advance!

Try to use below code to handle required check-box:
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
wait(browser, 10).until(EC.frame_to_be_available_and_switch_to_it(browser.find_element_by_xpath('//iframe[contains(#src, "google.com/recaptcha")]')))
wait(browser, 10).until(EC.element_to_be_clickable((By.ID, 'recaptcha-anchor'))).click()