Scraping site with chineese simbols .
How do i scrap chineese simbolse ??
from urllib.request import urlopen
from urllib.parse import urljoin
from lxml.html import fromstring
URL = 'http://list.suning.com/0-258003-0.html'
ITEM_PATH = '.clearfix .product .border-out .border-in .wrap .res-info .sell-point'
def parse_items():
f = urlopen(URL)
list_html = f.read().decode('utf-8')
list_doc = fromstring(list_html)
for elem in list_doc.cssselect(ITEM_PATH):
a = elem.cssselect('a')[0]
href = a.get('href')
title = a.text
em = elem.cssselect('em')[0]
title2 = em.text
print(href, title, title2)
def main():
parse_items()
if __name__ == '__main__':
main()
Error looks like this.
Error looks like this
Error looks like this
Error looks like this
Error looks like this
http://product.suning.com/0000000000/146422477.html Traceback (most recent call last):
File "parser.py", line 27, in <module>
main()
File "parser.py", line 24, in main
parse_items()
File "parser.py", line 20, in parse_items
print(href, title, title2)
UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-2: ordinal not in range(128)
From the print syntax and the imports, I assume that you use a Python3 version, since it can matter for unicode.
So, we can expect that href, title and title2 are all unicode strings (or Python 3 strings). But the print function will try to convert the strings to an encoding acceptable by the output system - for a reason I cannot know, you system uses by default ASCII, so the error.
How to fix:
the best way would be to make your system accept unicode. On Linux or other unixes, you can declare an UTF8 charset in LANG environment variable (export LANG=en_US.UTF-8), on Windows you can try chcp 65001 but this latter if far from being sure
if it does not work, or does not meet your needs, you can force an explicit encoding, or more exactly filter out offending characters, because Python3 natively uses unicode strings.
I would use:
import sys
def u_filter(s, encoding = sys.stdout.encoding):
return (s.encode(encoding, errors='replace').decode(encoding)
if isinstance(s, str) else s)
That means: if s is a unicode string encode it in the encoding used for stdout, replacing any non convertible character by a replacement char, and decode it back into a now clean string
and next:
def fprint(*args, **kwargs):
fargs = [ u_filter(arg) for arg in args ]
print(*fargs, **kwargs)
means: filter out any offending character from unicode strings and print the remaining unchanged.
With that you can safely replace your print throwing the exception with:
fprint(href, title, title2)
Related
I am writing some code that needs to work with both Py2.7 and Py3.7+.
I need to write text to a file using UTF-8 encoding. My code looks like this:
import six
...
content = ...
if isinstance(content, six.string_types):
content = content.encode(encoding='utf-8', errors='strict')
# write 'content' to file
Above, is it possible for content.encode() to raise UnicodeError from either Py2.7 or Py3.7+? I cannot think of a scenario where this is possible. I am not a Python expert, so I think there there must be an edge case.
Here is my reasoning why I think it will never raise UnicodeError:
six.string_types covers three types: Py2.7 str & unicode, Py3.7+ str
All of these types can always encode as UTF-8.
Yes, it's possible:
import six
content = ''.join(map(chr, range(0x110000)))
if isinstance(content, six.string_types):
content = content.encode(encoding='utf-8', errors='strict')
Result (Try it online!, using Python 3.7.4):
Traceback (most recent call last):
File ".code.tio", line 5, in <module>
content = content.encode(encoding='utf-8', errors='strict')
UnicodeEncodeError: 'utf-8' codec can't encode characters in position 55296-57343: surrogates not allowed
And UnicodeEncodeErrors are UnicodeErrors.
I am getting familiar with Python & am struggling to do the below with BeautifulSoup, Python.
What is expected:
*If the output of the script below contains the string 5378, it should email me with the line the string appears.
#! /usr/bin/env python
from bs4 import BeautifulSoup
from lxml import html
import urllib2,re
import codecs
import sys
streamWriter = codecs.lookup('utf-8')[-1]
sys.stdout = streamWriter(sys.stdout)
BASE_URL = "http://outlet.us.dell.com/ARBOnlineSales/Online/InventorySearch.aspx?c=us&cs=22&l=en&s=dfh&brandid=2201&fid=111162"
webpage = urllib2.urlopen(BASE_URL)
soup = BeautifulSoup(webpage.read(), "lxml")
findcolumn = soup.find("div", {"id": "itemheader-FN"})
name = findcolumn.text.strip()
print name
I tried using findall(5378, name), but it returns to empty braces like this [].
I am struggling with Unicode issues if I am trying to use it along with grep.
$ python dell.py | grep 5378
Traceback (most recent call last):
File "dell.py", line 18, in <module>
print name
UnicodeEncodeError: 'ascii' codec can't encode character u'\u201d' in position 817: ordinal not in range(128)
Can someone tell me what am I doing wrong in both cases?
The function findall (from the re module) expects the first parameter to be a a regular expression, which is a string, but you provided an integer. Try this instead:
re.findall("5378", name)
When printed this will output [u'5378'] when it found something or [] when it didn't.
I suspect you want to retrieve the product name from the number, which means you have to iterate through elements in findcolumn. We can use re.search() here to check for a single match within the element's texts.
for input_element in findcolumn.find_all("div"):
name = unicode(input_element.text.strip())
if re.search("5378", name) != None:
print unicode(name)
As for the unicode error, there are a bunch of solutions, depending on your operating system and configuration: Reconfigure your system locale on Ubuntu or Encode your script output with .encode()/unicode().
I'm trying to read from an ods (Opendocument spreadsheet) document with the odfpy modules. So far I've been able to extract some data but whenever a cell contains non-standard input the script errors out with:
Traceback (most recent call last):
File "python/test.py", line 26, in <module>
print x.firstChild
File "/usr/lib/python2.7/site-packages/odf/element.py", line 247, in __str__
return self.data.encode()
UnicodeEncodeError: 'ascii' codec can't encode character u'\u0105' in position 4: ordinal not in range(128)
I tried to force an encoding on the output but apparently it does not go well with print:
Traceback (most recent call last):
File "python/test.py", line 27, in <module>
print x.firstChild.encode('utf-8', 'ignore')
AttributeError: Text instance has no attribute 'encode'
What is the problem here and how could it be solved without editing the module code (which I'd like to avoid at all cost)? Is there an alternative to running encode on output that could work?
Here is my code:
from odf.opendocument import Spreadsheet
from odf.opendocument import load
from odf.table import Table,TableRow,TableCell
from odf.text import P
import sys,codecs
doc = load(sys.argv[1])
d = doc.spreadsheet
tables = d.getElementsByType(Table)
for table in tables:
tName = table.attributes[(u'urn:oasis:names:tc:opendocument:xmlns:table:1.0', u'name')]
print tName
rows = table.getElementsByType(TableRow)
for row in rows[:2]:
cells = row.getElementsByType(TableCell)
for cell in cells:
tps = cell.getElementsByType(P)
if len(tps)>0:
for x in tps:
#print x.firstChild
print x.firstChild.encode('utf-8', 'ignore')
Maybe you are not using the latest odfpy, in the latest verion, the __str__ method of Text is implemented as:
def __str__(self):
return self.data
Update odfpy to the latest version, and modify your code as:
print x.firstChild.__str__().encode('utf-8', 'ignore')
UPDATE
This is another method for getting the raw unicode data for Text: __unicode__. So if you don't want to update odfpy, modify your code as:
print x.firstChild.__unicode__().encode('utf-8', 'ignore')
Seems like the library itself is calling encode() -
return self.data.encode()
This uses the system default encoding , which in your case seems to be ascii. you can check that by using -
import sys
sys.getdefaultencoding()
From the traceback, seems like the actual data exists in a variable called data.
Try doing the below instead -
print x.firstChild.data
I know many people encountered this error before but I couldn't find the solution to my problem.
I have a URL that I want to normalize:
url = u"http://www.dgzfp.de/Dienste/Fachbeitr%C3%A4ge.aspx?EntryId=267&Page=5"
scheme, host_port, path, query, fragment = urlsplit(url)
path = urllib.unquote(path)
path = urllib.quote(path,safe="%/")
This gives an error message:
/usr/lib64/python2.6/urllib.py:1236: UnicodeWarning: Unicode equal comparison failed to convert both arguments to Unicode - interpreting them as being unequal
res = map(safe_map.__getitem__, s)
Traceback (most recent call last):
File "url_normalization.py", line 246, in <module>
logging.info(get_canonical_url(url))
File "url_normalization.py", line 102, in get_canonical_url
path = urllib.quote(path,safe="%/")
File "/usr/lib64/python2.6/urllib.py", line 1236, in quote
res = map(safe_map.__getitem__, s)
KeyError: u'\xc3'
I tried to remove the unicode indicator "u" from the URL string and I do not get the error message. But How can I get rid of the unicode automatically because I read it directly from a database.
urllib.quote() does not properly parse Unicode. To get around this, you can call the .encode() method on the url when reading it (or on the variable you read from the database). So run url = url.encode('utf-8'). With this you get:
import urllib
import urlparse
from urlparse import urlsplit
url = u"http://www.dgzfp.de/Dienste/Fachbeitr%C3%A4ge.aspx?EntryId=267&Page=5"
url = url.encode('utf-8')
scheme, host_port, path, query, fragment = urlsplit(url)
path = urllib.unquote(path)
path = urllib.quote(path,safe="%/")
and then your output for the path variable will be:
>>> path
'/Dienste/Fachbeitr%C3%A4ge.aspx'
Does this work?
I am writing a program in python 2.7.6 that uses nltk with Stanford named entity tagger in Window 7 professional to tag a text and print the result as follows:
import re
from nltk.tag.stanford import NERTagger
WORD = re.compile(r'\w+')
st = NERTagger("./classifiers/english.all.3class.distsim.crf.ser.gz", "stanford-ner.jar")
text = "title Wienfilm 1896-1976 (1976)"
words = WORD.findall(text )
print words
answer = st.tag(words )
print answer
The last print statement in the program suppose to return a tuple consisting of five lists as:
[(u'title', u'O'), (u'Wienfilm', u'O'), (u'1896', u'O'), (u'1976', u'O'), (u'1976', u'O')]
However when I run the program, it gives me the following error message:
['title', 'Wienfilm', '1896', '1976', '1976']
Traceback (most recent call last):
File "E:\Google Drive\myPyPrgs\testNLP.py", line 27, in <module>
answer = st.tag(words )
File "C:\Python27\lib\site-packages\nltk\tag\stanford.py", line 59, in tag
return self.tag_sents([tokens])[0]
File "C:\Python27\lib\site-packages\nltk\tag\stanford.py", line 82, in tag_sents
stanpos_output = stanpos_output.decode(encoding)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xa0 in position 23: ordinal not in
range(128)
Note that if I remove the number, '-1976' from the text string the program tags and prints the correct answer. But if the number '-1976' is within the text, I always have the above error.
In this forum, somebody suggested to me to change the default encoding in the stanford.py of the nltk. When I changed the default encoding in the stanford.py from ascii to UTF-16 and replaced the the last print statement of the above code with the following looping:
for i, word_pos in enumerate(answer):
word, pos = word_pos
print i , word.encode('utf-16'), pos.encode('utf-16')
I got the following incorrect output:
0 ÿþ ÿþtitle/O Wienfilm/O 1896 1976 1976/O
Please any clues on how to deal with this issue? Thanks in advance.
This worked for me: specify the encoding argument as UTF-8 when you create NERTagger object
st = NERTagger("./classifiers/english.all.3class.distsim.crf.ser.gz", "stanford-ner.jar", encoding='utf-8')
Open terminal(cmd), and write;
chcp
It should return something like;
active code page: 857
Then, write;
chcp 1254
After then, in your .py script, to the top of your script write;
# -*- coding: cp1254 -*-
This should solve your problem.If it's not, copy these codes and paste to the top of your script.
# -*-coding:utf-8-*-
import locale
locale.setlocale(locale.LC_ALL, '')
I had many problems with decoding before, these methods solved.
ASCII can decode only 2^7 = 128 characters, that's why you getting that error.As you see in the error sentence ordinal not in range(128) .
And check this website please.Use arrow keys for switching pages :-) I believe it's going to solve your problem.
At the top of your app add:
import sys
reload(sys)
sys.setdefaultencoding("utf-8")
I was dealing with the same problem and I solved it by adding the encoding options on internals.py in nltk.
You must open internals.py saven on:
%YourPythonFolder%\Lib\site-packages\nltk\internals.py
Then go to the method java and adding this line after #construct the full command string (about line 147)
cmd = cmd + ['-inputEncoding', 'utf-8', '-outputEncoding', 'utf-8']
This section code must look like:
# Construct the full command string.
cmd = list(cmd)
cmd = ['-cp', classpath] + cmd
cmd = [_java_bin] + _java_options + cmd
cmd = cmd + ['-inputEncoding', 'utf-8', '-outputEncoding', 'utf-8']
Hope it helps.