Say I have a 2D Numpy array of values on the range 0 to 1, which represents a grayscale image. How do I then convert this into a PIL Image object? All attempts so far have yielded extremely strange scattered pixels or black images.
for x in range(image.shape[0]):
for y in range(image.shape[1]):
image[y][x] = numpy.uint8(255 * (image[x][y] - min) / (max - min))
#Create a PIL image.
img = Image.fromarray(image, 'L')
In the code above, the numpy array image is normalized by (image[x][y] - min) / (max - min) so every value is on the range 0 to 1. Then it is multiplied by 255 and cast to an 8 bit integer. This should, in theory, process through Image.fromarray with mode L into a grayscale image - but the result is a set of scattered white pixels.
I think the answer is wrong. The Image.fromarray( ____ , 'L') function seems to only work properly with an array of integers between 0 and 255. I use the np.uint8 function for this.
You can see this demonstrated if you try to make a gradient.
import numpy as np
from PIL import Image
# gradient between 0 and 1 for 256*256
array = np.linspace(0,1,256*256)
# reshape to 2d
mat = np.reshape(array,(256,256))
# Creates PIL image
img = Image.fromarray(np.uint8(mat * 255) , 'L')
img.show()
Makes a clean gradient
vs
import numpy as np
from PIL import Image
# gradient between 0 and 1 for 256*256
array = np.linspace(0,1,256*256)
# reshape to 2d
mat = np.reshape(array,(256,256))
# Creates PIL image
img = Image.fromarray( mat , 'L')
img.show()
Has the same kind of artifacting.
If I understood you question, you want to get a grayscale image using PIL.
If this is the case, you do not need to multiply each pixels by 255.
The following worked for me
import numpy as np
from PIL import Image
# Creates a random image 100*100 pixels
mat = np.random.random((100,100))
# Creates PIL image
img = Image.fromarray(mat, 'L')
img.show()
im = Image.fromarray(np.uint8(mat), 'L')
or
im = Image.fromarray(np.uint8(mat))
Apparently it accepts type np.uint8(insert array here), also may be able to remove 'L' for conciseness.
Related
I am finding a point within a numpy array and then want to save this array as an image with a box around the located point.
Below is a simplified code representation showing the issue
from PIL import Image, ImageDraw
import numpy as np
np_img = np.zeros((259,339,3))
pt = (29,118)
np_img[pt] = [255,0,0]
print(np_img[pt])
final_img = Image.fromarray(np_img, 'RGB')
#final_draw = ImageDraw.Draw(final_img)
#final_draw.rectangle([(pt[1]-3, pt[0]+3), (pt[1]+3, pt[0]-3)], outline="blue")
new_np_img = np.asarray(final_img)
print(new_np_img[pt])
new_pt = np.where(new_np_img > 0)
print(new_pt)
final_img.show()
I would expect that if I read the generated PIL image back into a numpy array that the point that I set as [255,0,0] would still be that value but it is not. What is PIL doing to my data so that I can understand how I need to condition my numpy array so that it displays the correct position of my point in the PIL image?
The reason for undesired output is because you didn't explicitly defined the datatype of the numpy array as uint8. In your code, the first array (np_img) was stored as float64 datatype. And the array obtained from PIL (final_img) was of the datatype uint8. Which caused inconsistent results.
from PIL import Image
import numpy as np
np_img = np.zeros((259,339,3), np.uint8)
pt = (29,118)
np_img[pt] = [255,0,0]
print(np_img[pt])
final_img = Image.fromarray(np_img, 'RGB')
new_np_img = np.asarray(final_img)
print(new_np_img[pt])
final_img.show()
Output:-
[255 0 0]
[255 0 0]
Output Image:-
Thank you for reading my question.
I am new to python and became interested in scipy. I am trying to figure out how I can make the image of the Racoon (in scipy misc) to a binary one (black, white). This is not taught in the scipy-lecture tutorial.
This is so far my code:
%matplotlib inline
import matplotlib.pyplot as plt
import numpy as np
from scipy import misc #here is how you get the racoon image
face = misc.face()
image = misc.face(gray=True)
plt.imshow(image, cmap=plt.cm.gray)
print image.shape
def binary_racoon(image, lowerthreshold, upperthreshold):
img = image.copy()
shape = np.shape(img)
for i in range(shape[1]):
for j in range(shape[0]):
if img[i,j] < lowerthreshold and img[i,j] > upperthreshold:
#then assign black to the pixel
else:
#then assign white to the pixel
return img
convertedpicture = binary_racoon(image, 80, 100)
plt.imshow(convertedpicture, cmap=plt.cm.gist_gray)
I have seen other people using OpenCV to make a picture binary, but I am wondering how I can do it in this way by looping over the pixels? I have no idea what value to give to the upper and lower threshold, so I made a guess of 80 and 100. Is there also a way to determine this?
In case anyone else is looking for a quick minimal example to experiment with, here's what I used to binarize an image:
from scipy.misc import imread, imsave
# read in image as 8 bit grayscale
img = imread('cat.jpg', mode='L')
# specify a threshold 0-255
threshold = 150
# make all pixels < threshold black
binarized = 1.0 * (img > threshold)
# save the binarized image
imsave('binarized.jpg', binarized)
Input:
Output:
You're overthinking this:
def to_binary(img, lower, upper):
return (lower < img) & (img < upper)
In numpy, the comparison operators apply over the whole array elementwise. Note that you have to use & instead of and to combine the booleans, since python does not allow numpy to overload and
You don't need to iterate over the x and y positions of the image array. Use the numpy array to check if the array is above of below the threshold of interest. Here is some code that produces a boolean (true/false) array as the black and white image.
# use 4 different thresholds
thresholds = [50,100,150,200]
# create a 2x2 image array
fig, ax_arr = plt.subplots(2,2)
# iterate over the thresholds and image axes
for ax, th in zip(ax_arr.ravel(), thresholds):
# bw is the black and white array with the same size and shape
# as the original array. the color map will interpret the 0.0 to 1.0
# float array as being either black or white.
bw = 1.0*(image > th)
ax.imshow(bw, cmap=plt.cm.gray)
ax.axis('off')
# remove some of the extra white space
fig.tight_layout(h_pad=-1.5, w_pad=-6.5)
I am using OpenCV in Python.
I am trying to create a Mask Matrix variable to be used in this function: cv.minMaxLoc. The Matrix variable should have the same size like my template image, with type = CV_8UC1.
My template image has a alpha channel which consists of only 0% or 100% transparency pixels. How can I extract the alpha channel data from my image and put it into the Mask Matrix with 0 = 100% transparency and 1 = 0% transparency?
import numpy as np
import cv
from PIL import Image
# open the image
img = Image.open('./pic.png', 'r')
r,g,b, alpha_channel = img.split()
mask = np.array(alpha_channel)
# all elements in alpha_channel that have value 0
# are set to 1 in the mask matrix
mask[alpha_channel==0] = 1
# all elements in alpha_channel that have value 100
# are set to 0 in the mask matrix
mask[alpha_channel==100] = 0
credit to other posts:
How to get alpha value of a PNG image with PIL?
Converting numpy array having image data to CvMat
To convert numpy array to cvmat do:
cv_arr = cv.fromarray(mask)
Check the dtype of mask. It should be dtype('uint8')
When I convert it my cv_arr is
cvmat(type=42424000 8UC1 rows=1245 cols=2400 step=2400 )
I am not an expert in opencv, but it seems to me that 8UC1 is automatically selected based on the fact that dtype is uint8 (I am guessing here because I couldn't find the documentation about that).
I have 5 pictures and i want to convert each image to 1d array and put it in a matrix as vector. I want to be able to convert each vector to image again.
img = Image.open('orig.png').convert('RGBA')
a = np.array(img)
I'm not familiar with all the features of numpy and wondered if there other tools I can use.
Thanks.
import numpy as np
from PIL import Image
img = Image.open('orig.png').convert('RGBA')
arr = np.array(img)
# record the original shape
shape = arr.shape
# make a 1-dimensional view of arr
flat_arr = arr.ravel()
# convert it to a matrix
vector = np.matrix(flat_arr)
# do something to the vector
vector[:,::10] = 128
# reform a numpy array of the original shape
arr2 = np.asarray(vector).reshape(shape)
# make a PIL image
img2 = Image.fromarray(arr2, 'RGBA')
img2.show()
import matplotlib.pyplot as plt
img = plt.imread('orig.png')
rows,cols,colors = img.shape # gives dimensions for RGB array
img_size = rows*cols*colors
img_1D_vector = img.reshape(img_size)
# you can recover the orginal image with:
img2 = img_1D_vector.reshape(rows,cols,colors)
Note that img.shape returns a tuple, and multiple assignment to rows,cols,colors as above lets us compute the number of elements needed to convert to and from a 1D vector.
You can show img and img2 to see they are the same with:
plt.imshow(img) # followed by
plt.show() # to show the first image, then
plt.imshow(img2) # followed by
plt.show() # to show you the second image.
Keep in mind in the python terminal you have to close the plt.show() window to come back to the terminal to show the next image.
For me it makes sense and only relies on matplotlib.pyplot. It also works for jpg and tif images, etc. The png I tried it on has float32 dtype and the jpg and tif I tried it on have uint8 dtype (dtype = data type); each seems to work.
I hope this is helpful.
I used to convert 2D to 1D image-array using this code:
import numpy as np
from scipy import misc
from sklearn.decomposition import PCA
import matplotlib.pyplot as plt
face = misc.imread('face1.jpg');
f=misc.face(gray=True)
[width1,height1]=[f.shape[0],f.shape[1]]
f2=f.reshape(width1*height1);
but I don't know yet how to change it back to 2D later in code, Also note that not all the imported libraries are necessary, I hope it helps
Upon doing my homework, I stumbled across a problem concerning Python and image manipulation. I must say, using the Image lib is not an option. So here it is
from scipy.misc import imread,imsave
from numpy import zeros
imga = zeros([100,100,3])
h = len(imga)
w = len(imga[0])
for y in range(h):
for x in range(w):
imga[y,x] = [255,255,255]
imsave("Result.jpg",imga)
I would assume it makes my picture white, but it turns it black, and I have no idea why
It's not about the code (and I know it looks very ugly). Its just about the fact, that it is a black image.
Every color in an image is represented by one byte. So to create an image array, you should set it's dtype to uint8.
And, you don't need for-loop to set every elements to 255, you can use fill() method or slice index:
import numpy as np
img = np.zeros([100,100,3],dtype=np.uint8)
img.fill(255) # or img[:] = 255
Easy!
Check the below Code:
whiteFrame = 255 * np.ones((1000,1000,3), np.uint8)
255 is the color for filling the bytes.
1000, 1000 is the size of the image.
3 is the color channel for the image.
And unit8 is the type
Goodluck
Here's a simple way to create a white image with a python one liner.
$ python3 -c "from PIL import Image;Image.new('RGB', (1900, 1080), color = (255,255,255)).save('Img.jpg')"
This will create a white image with a width of 1900 and hight of 1080.
When creating imga, you need to set the unit type. Specifically, change the following line of code:
imga = zeros([100,100,3], dtype=np.uint8)
And, add the following to your imports:
import numpy as np
That gives a white image on my machine.
The headline is too broad and shows up at Google first. I needed a white image and used PIL and numpy. PILlow actually works well with numpy
import numpy as np
from PIL import Image
img = np.zeros([100,100,3],dtype=np.uint8)
img.fill(255) # numpy array!
im = Image.fromarray(img) #convert numpy array to image
im.save('whh.jpg')
Just regarding the headline of this question, I did need a white image as well as a pillow input. And the solutions presented here did not work for me.
Therefore here a different way to generate white images for other purposes:
from PIL import Image
img = Image.new('RGB', (200, 50), color = (255,255,255))
Size and color may be changed in the 2nd and 3rd parameter of the Image.new()-function.
And if you want to write something on this image or save it, this would be example code for this.
from PIL import ImageFont, ImageDraw
fnt = ImageFont.truetype("Pillow/Tests/fonts/FreeMono.ttf", 30)
ImageDraw.Draw(img).text((0,0), "hello world", font=fnt, fill=(0,0,0))
img.save('test.jpg')
# Create an array with a required colours
# The colours are given in BGR [B, G, R]
# The array is created with values of ones, the size is (H, W, Channels)
# The format of the array is uint8
# This array needs to be converted to an image of type uint8
selectedColor = [75, 19, 77] * np.ones((640, 480, 3), np.uint8)
imgSelectedColor = np.uint8(np.absolute(selectedColor))