We Keep Coding

Python / BeautifulSoup webscraper returning "None"

trying to build a webscraper to return lists of freelance gig postings on different websites into one place. My code is below and it keeps returning "None". I'm a bit stuck at this point, if you can help identify why it keeps doing this that would be great.
import requests
from bs4 import BeautifulSoup
import pprint
res1 = requests.get('https://www.airtasker.com/tasks/?task_states=posted&lat=-33.7918&lon=151.0806&location_name=Eastwood%2C%20NSW&radius=20000000&carl_ids=&task_types=both&max_price=9999&min_price=5&search_term=python&badges=&sort_by=posted_desc') # this is where we will scrape the info from
soup1 = BeautifulSoup(res1.text, 'html.parser') # this tells BS to give us HTML code for the page
links1 = soup1.select('.new-task-list-item new-task-list-item--open') # link of each gig
subtext1 = soup1.select('.new-task-list-item__date at-icon-calendar') # date of each gig
res2 = requests.get('https://www.airtasker.com/tasks/?task_states=posted&lat=-33.7918&lon=151.0806&location_name=Eastwood%2C%20NSW&radius=20000000&carl_ids=&task_types=both&max_price=9999&min_price=5&search_term=web%20developer&badges=&sort_by=posted_desc')
soup2 = BeautifulSoup(res2.text, 'html.parser')
links2 = soup2.select('.new-task-list-item new-task-list-item--open')
subtext2 = soup2.select('.new-task-list-item__date at-icon-calendar')
res3 = requests.get('https://www.upwork.com/freelance-jobs/website/')
soup3 = BeautifulSoup(res3.text, 'html.parser')
links3 = soup3.select('.job-title')
subtext3 = soup3.select('.text-muted')
res4 = requests.get('https://www.upwork.com/freelance-jobs/data-science/')
soup4 = BeautifulSoup(res4.text, 'html.parser')
links4 = soup4.select('.job-title')
subtext4 = soup4.select('.text-muted')
res5 = requests.get('https://www.upwork.com/freelance-jobs/bot-development/')
soup5 = BeautifulSoup(res5.text, 'html.parser')
links5 = soup5.select('.job-title')
subtext5 = soup5.select('.text-muted')
res6 = requests.get('https://www.upwork.com/freelance-jobs/python-script/')
soup6 = BeautifulSoup(res6.text, 'html.parser')
links6 = soup6.select('.job-title')
subtext6 = soup6.select('.text-muted')
mega_links = links1 + links2 + links3 + links4 + links5 + links6
mega_subtext = subtext1 + subtext2 + subtext3 + subtext4 + subtext5 + subtext6
def extract(links, subtexts):
joblist = []
for indx, item in enumerate(links):
title = item.getText()
href = item.get('href')
joblist.append({'title': title, 'link': href})
return joblist
pprint.pprint(extract(mega_links , mega_subtext))

I have no idea what exactly you are trying to extract from the scraped web page requests. Here's what I tried from my end:
Your links variable are null or empty lists since there is no such querySelector present for the web page you're trying to scrape. For example, the console of the first web page that you are scraping (the element you're trying to scrape doesn't exist):
I would recommend you to confirm the element you're trying to scrape and confirm it's class.
Another Point of Consideration:
When you will print your soup variables you will notice that you get CloudFare as the output.

Beautiful soup doesn't load the whole page

I got this project where I'm scraping data on Trulia.com and where I want to get the max number of page (last number) for a specific location (photo below) so I can loop through it and get all the hrefs.
To get that last number, I have my code that run as planned and should return an integer but it doesn't always return the same number. I added the print(comprehension list) to understand what's wrong. Here is the code and the output below. The return is commented but sould return the last number of the output list as an int.
city_link = "https://www.trulia.com/for_rent/San_Francisco,CA/"
def bsoup(url):
resp = r.get(url, headers=req_headers)
soup = bs(resp.content, 'html.parser')
return soup
def max_page(link):
soup = bsoup(link)
page_num = soup.find_all(attrs={"data-testid":"pagination-page-link"})
print([x.get_text() for x in page_num])
# return int(page_num[-1].get_text())
for x in range(10):
max_page(city_link)
I have no clue why sometimes it's returning something wrong. The photo above is the corresponding link.

Okay, now if I understand what you want, you are trying to see how many pages of links there are for a given location for rent. If we can assume the given link is the only required link, this code:
import requests
import bs4
url = "https://www.trulia.com/for_rent/San_Francisco,CA/"
req = requests.get(url)
soup = bs4.BeautifulSoup(req.content, features='lxml')
def get_number_of_pages(soup):
caption_tag = soup.find('div', class_="Text__TextBase-sc-1cait9d-0-
div Text__TextContainerBase-sc-1cait9d-1 RBSGf")
pagination = caption_tag.text
words = pagination.split(" ")
values = []
for word in words:
if not word.isalpha():
values.append(word)
links_per_page = values[0].split('-')[1]
total_links = values[1].replace(',', '')
no_of_pages = round(int(total_links)/int(links_per_page) + 0.5)
return no_of_pages
for i in range(10):
print(get_number_of_pages(soup))
achieves what you're looking for, and has repeatability because it doesn't interact with javascript, but the pagination caption at the bottom of the page.

How to make pandas loop faster: scraping the text from url

I'm trying to scrape the text from articles in my website. I have a 'for' loop, but it works very slow. Are there any faster ways to do that? I've read about Pandas Built-In-Loop, vectorization and and numpy vectorization, but failed to apply it to my code.
def scarp_text(df):
pd.options.mode.chained_assignment = None
session = requests.Session()
for j in range(0, len(df)):
try:
url = df['url'][j] #takes a url of an article in a column 'url'
req = session.get(url)
soup = BeautifulSoup(req.text, 'lxml')
except Exception as e:
print(e)
tags = soup.find_all('p')
if tags == []:
tags = soup.find_all('p', itemprop = 'articleBody')
# Putting together all text from HTML p tags
article = ''
for p in paragraph_tags:
article = article + ' ' + p.get_text()
article = " ".join(article.split())
df['article_text'][j] = article #put collected text to a corresponding cell
return df

You have 2 for loops, the most inner loop is usually the best place to start.
Plus operator is inefficient for string concatenation. Str.join is a better choice, it also takes a generator as input.
article = " ".join(p.get_text() for p in paragraph_tags)
article = " ".join(article.split())

How to go through all items and than save them in a dictionary key

I want to load automatically a code from website.
I have a list with some names and want to go through every item. Go through the first item, make request, open website, copy the code/number from HTML (text in span) and than save this result in dictionary and so on (for all items).
I read from csv all lines and save them into a list.
After this I make request to load HTML from a website, search the company and read the numbers from span.
My code:
with open(test_f, 'r') as file:
rows = csv.reader(file,
delimiter=',',
quotechar='"')
data = [data for data in rows]
print(data)
url_part1 = "http://www.monetas.ch/htm/651/de/Firmen-Suchresultate.htm?Firmensuche="
url_enter_company = [data for data in rows]
url_last_part = "&CompanySearchSubmit=1"
firma_noga = []
for data in firma_noga:
search_noga = url_part1 + url_enter_company + url_last_part
r = requests.get(search_noga)
soup = BeautifulSoup(r.content, 'html.parser')
lii = soup.find_all("span")
# print all numbers that are in a span
numbers = [d.text for d in lii]
print("NOGA Codes: ")
I want to get in dictionary the result, where the key should be the company name (item in a list) and the value should be the number that I read from the span:
dict = {"firma1": "620100", "firma2": "262000, 465101"}
Can some one help me, I am new at web scraping and python, and don't know what I am doing wrong.

Split your string with regex and do your stuff depending on wether it is a number or not:
import re
for partial in re.split('([0-9]+)', myString):
try:
print(int(partial))
except:
print(partial + ' is not a number')
EDIT:
Well, myString is somewhat expected to be a string.
To get the text content of your spans as a string you should be able to use .text something like this:
spans = soup.find_all('span')
for span in spans:
myString = span.text #
for partial in re.split('([0-9]+)', myString):
try:
print(int(partial))
except:
print(partial + ' is not a number')

Abstracting from my requirements in comments I think somethinfg like this should work for you:
firma_noga = ['firma1', 'firma2', 'firma3'] #NOT EMPTY as in your code!
res_dict = {}
for data in firma_noga:
search_noga = url_part1 + url_enter_company + url_last_part
r = requests.get(search_noga)
soup = BeautifulSoup(r.content, 'html.parser')
lii = soup.find_all("span")
for l in lii:
if data not in res_dict:
res_dict[data] = [l]
else:
res_dict[data].append(l)
Obviously this will work obviously if firma-noga won't be empty like in your code; and all the rest (your) parsing logic should be valid as well.

Scraping multiple pages for parsing in Beautiful Soup

I'm trying to scrape multiple pages off of a single website for BeautifulSoup to parse. So far, I've tried using urllib2 to do this, but have been encountering some problems. What I've attempted is:
import urllib2,sys
from BeautifulSoup import BeautifulSoup
for numb in ('85753', '87433'):
address = ('http://www.presidency.ucsb.edu/ws/index.php?pid=' + numb)
html = urllib2.urlopen(address).read()
soup = BeautifulSoup(html)
title = soup.find("span", {"class":"paperstitle"})
date = soup.find("span", {"class":"docdate"})
span = soup.find("span", {"class":"displaytext"}) # span.string gives you the first bit
paras = [x for x in span.findAllNext("p")]
first = title.string
second = date.string
start = span.string
middle = "\n\n".join(["".join(x.findAll(text=True)) for x in paras[:-1]])
last = paras[-1].contents[0]
print "%s\n\n%s\n\n%s\n\n%s\n\n%s" % (first, second, start, middle, last)
This only gives me results for the second number in the numb sequence, i.e. http://www.presidency.ucsb.edu/ws/index.php?pid=87433. I also made some attempts at using mechanize, but had no success. Ideally what I would like to be able to do is have a page, with a list of links, and then automatically select a link, pass the HTML off to BeautifulSoup, and then move to the next link in the list.

You need to put the rest of the code inside the loop. Right now you're iterating over both items in the tuple, but at the end of the iteration only the last item remains assigned to address which subsequently gets parsed outside the loop.

I think you just missed the indentation in the loop :
import urllib2,sys
from BeautifulSoup import BeautifulSoup
for numb in ('85753', '87433'):
address = ('http://www.presidency.ucsb.edu/ws/index.php?pid=' + numb)
html = urllib2.urlopen(address).read()
soup = BeautifulSoup(html)
title = soup.find("span", {"class":"paperstitle"})
date = soup.find("span", {"class":"docdate"})
span = soup.find("span", {"class":"displaytext"}) # span.string gives you the first bit
paras = [x for x in span.findAllNext("p")]
first = title.string
second = date.string
start = span.string
middle = "\n\n".join(["".join(x.findAll(text=True)) for x in paras[:-1]])
last = paras[-1].contents[0]
print "%s\n\n%s\n\n%s\n\n%s\n\n%s" % (first, second, start, middle, last)
I think this should solve the problem..

Here's a tidier solution (using lxml):
import lxml.html as lh
root_url = 'http://www.presidency.ucsb.edu/ws/index.php?pid='
page_ids = ['85753', '87433']
def scrape_page(page_id):
url = root_url + page_id
tree = lh.parse(url)
title = tree.xpath("//span[#class='paperstitle']")[0].text
date = tree.xpath("//span[#class='docdate']")[0].text
text = tree.xpath("//span[#class='displaytext']")[0].text_content()
return title, date, text
if __name__ == '__main__':
for page_id in page_ids:
title, date, text = scrape_page(page_id)