Get primary keys after update in SQLAlchemy Core? - python

I've been using .inserted_primary_key in SQLAlchemy to get primary keys after inserts, for example:
my_id = sql_conn.execute(my_table.insert(my_data_dict)).inserted_primary_key
Is there a way to get the same thing after an update? Like:
my_id = sql_conn.execute(
my_table.update().where(some_cond).values(my_data_dict)).updated_primary_key
I'm on MySQL and I could do this with actual SQL like:
SET #update_id := 0;
UPDATE some_table SET column_name = 'value', id = (SELECT #update_id := id)
WHERE some_other_column = 'blah' LIMIT 1;
SELECT #update_id;
Any way to mimic that, or something like it?

Related

Get table name for field in database result in Python (PostgreSQL)

I'm trying to get table name for field in result set that I got from database (Python, Postgres). There is a function in PHP to get table name for field, I used it and it works so I know it can be done (in PHP). I'm looking for similar function in Python.
pg_field_table() function in PHP gets results and field number and "returns the name of the table that field belongs to". That is exactly what I need, but in Python.
Simple exaple - create tables, insert rows, select data:
CREATE TABLE table_a (
id INT,
name VARCHAR(10)
);
CREATE TABLE table_b (
id INT,
name VARCHAR(10)
);
INSERT INTO table_a (id, name) VALUES (1, 'hello');
INSERT INTO table_b (id, name) VALUES (1, 'world');
When using psycopg2 or sqlalchemy I got right data and right field names but without information about table name.
import psycopg2
query = '''
SELECT *
FROM table_a A
LEFT JOIN table_b B
ON A.id = B.id
'''
con = psycopg2.connect('dbname=testdb user=postgres password=postgres')
cur = con.cursor()
cur.execute(query)
data = cur.fetchall()
print('fields', [desc[0] for desc in cur.description])
print('data', data)
The example above prints field names. The output is:
fields ['id', 'name', 'id', 'name']
data [(1, 'hello', 1, 'world')]
I know that there is cursor.description, but it does not contain table name, just the field name.
What I need - some way to retrieve table names for fields in result set when using raw SQL to query data.
EDIT 1: I need to know if "hello" came from "table_a" or "table_b", both fields are named same ("name"). Without information about table name you can't tell in which table the value is.
EDIT 2: I know that there are some workarounds like SQL aliases: SELECT table_a.name AS name1, table_b.name AS name2 but I'm really asking how to retrieve table name from result set.
EDIT 3: I'm looking for solution that allows me to write any raw SQL query, sometimes SELECT *, sometimes SELECT A.id, B.id ... and after executing that query I will get field names and table names for fields in the result set.
It is necessary to query the pg_attribute catalog for the table qualified column names:
query = '''
select
string_agg(format(
'%%1$s.%%2$s as "%%1$s.%%2$s"',
attrelid::regclass, attname
) , ', ')
from pg_attribute
where attrelid = any (%s::regclass[]) and attnum > 0 and not attisdropped
'''
cursor.execute(query, ([t for t in ('a','b')],))
select_list = cursor.fetchone()[0]
query = '''
select {}
from a left join b on a.id = b.id
'''.format(select_list)
print cursor.mogrify(query)
cursor.execute(query)
print [desc[0] for desc in cursor.description]
Output:
select a.id as "a.id", a.name as "a.name", b.id as "b.id", b.name as "b.name"
from a left join b on a.id = b.id
['a.id', 'a.name', 'b.id', 'b.name']

Retrieving identity of most recent insert in Oracle DB 12c

I'd like to have returned to me (via cx_oracle in python) the value of the Identity that's created for a row that I'm inserting. I think I can figure out the python bit on my own, if someone could please state how to modify my SQL statement to get the ID of the newly-created row.
I have a table that's created with something like the following:
CREATE TABLE hypervisor
(
id NUMBER GENERATED BY DEFAULT AS IDENTITY (
START WITH 1 NOCACHE ORDER ) NOT NULL ,
name VARCHAR2 (50)
)
LOGGING ;
ALTER TABLE hypervisor ADD CONSTRAINT hypervisor_PK PRIMARY KEY ( id ) ;
And I have SQL that's similar to the following:
insert into hypervisor ( name ) values ('my hypervisor')
Is there an easy way to obtain the id of the newly inserted row? I'm happy to modify my SQL statement to have it returned, if that's possible.
Most of the google hits on this issue were for version 11 and below, which don't support automatically-generated identity columns so hopefully someone here can help out.
Taking what user2502422 said above and adding the python bit:
newest_id_wrapper = cursor.var(cx_Oracle.STRING)
sql_params = { "newest_id_sql_param" : newest_id_wrapper }
sql = "insert into hypervisor ( name ) values ('my hypervisor') " + \
"returning id into :python_var"
cursor.execute(sql, sql_params)
newest_id=newest_id_wrapper.getvalue()
This example taken from learncodeshare.net has helped me grasp the correct syntax.
cur = con.cursor()
new_id = cur.var(cx_Oracle.NUMBER)
statement = 'insert into cx_people(name, age, notes) values (:1, :2, :3) returning id into :4'
cur.execute(statement, ('Sandy', 31, 'I like horses', new_id))
sandy_id = new_id.getvalue()
pet_statement = 'insert into cx_pets (name, owner, type) values (:1, :2, :3)'
cur.execute(pet_statement, ('Big Red', sandy_id, 'horse'))
con.commit()
It's only slightly different from ragerdl's answer, but different enough to be added here I believe!
Notice the absence of sql_params = { "newest_id_sql_param" : newest_id_wrapper }
Use the returning clause of the insert statement.
insert into hypervisor (name ) values ('my hypervisor')
returning id into :python_var
You said you could handle the Python bit ? You should be able to "bind" the return parameter in your program.
I liked the answer by Marco Polo, but it is incomplete.
The answer from FelDev is good too but does not address named parameters.
Here is a more complete example from code I wrote with a simplified table (less fields). I have omitted code on how to set up a cursor since that is well documented elsewhere.
import cx_Oracle
INSERT_A_LOG = '''INSERT INTO A_LOG(A_KEY, REGION, DIR_NAME, FILENAME)
VALUES(A_KEY_Sequence.nextval, :REGION, :DIR_NAME, :FILENAME)
RETURNING A_KEY INTO :A_LOG_ID'''
CURSOR = None
class DataProcessor(Process):
# Other code for setting up connection to DB and storing it in CURSOR
def save_log_entry(self, row):
global CURSOR
# Oracle variable to hold value of last insert
log_var = CURSOR.var(cx_Oracle.NUMBER)
row['A_LOG_ID'] = log_var
row['REGION'] = 'R7' # Other entries set elsewhere
try:
# This will fail unless row.keys() =
# ['REGION', 'DIR_NAME', 'FILE_NAME', 'A_LOG_ID']
CURSOR.execute(INSERT_A_LOG, row)
except Exception as e:
row['REJCTN_CD'] = 'InsertFailed'
raise
# Get last inserted ID from Oracle for update
self.last_log_id = log_var.getvalue()
print('Insert id was {}'.format(self.last_log_id))
Agreeing with the older answers. However, depending on your version of cx_Oracle (7.0 and newer), var.getvalue() might return an array instead of a scalar.
This is to support multiple return values as stated in this comment.
Also note, that cx_Oracle is deprecated and has moved to oracledb now.
Example:
newId = cur.var(oracledb.NUMBER, outconverter=int)
sql = """insert into Locations(latitude, longitude) values (:latitude, :longitude) returning locationId into :newId"""
sqlParam = [latitude, longitude, newId]
cur.execute(sql, sqlParam)
newIdValue = newId.getvalue()
newIdValue would return [1] instead of 1

How can I get the youngest objects from SQLAlchemy?

Each row in my table has a date. The date is not unique. The same date is present more than one time.
I want to get all objects with the youngest date.
My solution work but I am not sure if this is a elegent SQLAlchemy way.
query = _session.query(Table._date) \
.order_by(Table._date.desc()) \
.group_by(Table._date)
# this is the younges date (type is date.datetime)
young = query.first()
query = _session.query(Table).filter(Table._date==young)
result = query.all()
Isn't there a way to put all this in one query object or something like that?
You need a having clause, and you need to import the max function
then your query will be:
from sqlalchemy import func
stmt = _session.query(Table) \
.group_by(Table._date) \
.having(Table._date == func.max(Table._date)
This produces a sql statement like the following.
SELECT my_table.*
FROM my_table
GROUP BY my_table._date
HAVING my_table._date = MAX(my_table._date)
If you construct your sql statement with a select, you can examine the sql produced in your case using. *I'm not sure if this would work with statements query
str(stmt)
Two ways of doing this using a sub-query:
# #note: do not need to alias, but do in order to specify `name`
T1 = aliased(MyTable, name="T1")
# version-1:
subquery = (session.query(func.max(T1._date).label("max_date"))
.as_scalar()
)
# version-2:
subquery = (session.query(T1._date.label("max_date"))
.order_by(T1._date.desc())
.limit(1)
.as_scalar()
)
qry = session.query(MyTable).filter(MyTable._date == subquery)
results = qry.all()
The output should be similar to:
# version-1
SELECT my_table.id AS my_table_id, my_table.name AS my_table_name, my_table._date AS my_table__date
FROM my_table
WHERE my_table._date = (
SELECT max("T1"._date) AS max_date
FROM my_table AS "T1")
# version-2
SELECT my_table.id AS my_table_id, my_table.name AS my_table_name, my_table._date AS my_table__date
FROM my_table
WHERE my_table._date = (
SELECT "T1"._date AS max_date
FROM my_table AS "T1"
ORDER BY "T1"._date DESC LIMIT ? OFFSET ?
)

How to correctly use SQL joins/subqueries in Sqlalchemy

Say I have the following SQL code and I want to change it to Sqlalchemy:
SELECT amount FROM table1
JOIN table2
ON table2.id = table1.b_id
JOIN (SELECT id FROM table3 WHERE val1 = %s AND val2 = %s) inst
ON inst.id = table1.i_id
WHERE
val3 = %s
I've tried making a subquery for the SELECT id FROM table3 clause as follows:
subq = session.query(table3.id).filter(and_(table3.val1 == 'value', table3.val2 == 'value')).subquery()
And then putting everything together:
query = session.query(table1).join(table2).filter(table2.id == table1.b_id).\
join(subq).filter(table1.val3 == 'value')
When I ouput query.first().amount, this works for a few examples, but for some queries I'm getting no results when there should be something there, so I must be messing up somewhere. Any ideas where I'm going wrong? Thanks
Query below should produce exactly the SQL you have. It is not much different from your, but removes some unnecessary things.
So if it does not work, then also your original SQL might not work. Therefore, I assume that your issue is not SQL but either data or the parameters for that query. And you can always print out the query itself by engine.echo = True.
val1, val2, val3 = 'value', 'value', 'value' # #NOTE: specify filter values
subq = (session.query(table3.id)
.filter(and_(table3.val1 == val1, table3.val2 == val2))
).subquery(name='inst')
quer = (
session.query(table1.amount) # #NOTE: select only one column
.join(table2) # #NOTE: no need for filter(...)
.join(subq)
.filter(table1.val3 == val3)
).first()
print(quer and quer.amount)

Getting the id of the last record inserted for Postgresql SERIAL KEY with Python

I am using SQLAlchemy without the ORM, i.e. using hand-crafted SQL statements to directly interact with the backend database. I am using PG as my backend database (psycopg2 as DB driver) in this instance - I don't know if that affects the answer.
I have statements like this,for brevity, assume that conn is a valid connection to the database:
conn.execute("INSERT INTO user (name, country_id) VALUES ('Homer', 123)")
Assume also that the user table consists of the columns (id [SERIAL PRIMARY KEY], name, country_id)
How may I obtain the id of the new user, ideally, without hitting the database again?
You might be able to use the RETURNING clause of the INSERT statement like this:
result = conn.execute("INSERT INTO user (name, country_id) VALUES ('Homer', 123)
RETURNING *")
If you only want the resulting id:
result = conn.execute("INSERT INTO user (name, country_id) VALUES ('Homer', 123)
RETURNING id")
[new_id] = result.fetchone()
User lastrowid
result = conn.execute("INSERT INTO user (name, country_id) VALUES ('Homer', 123)")
result.lastrowid
Current SQLAlchemy documentation suggests
result.inserted_primary_key should work!
Python + SQLAlchemy
after commit, you get the primary_key column id (autoincremeted) updated in your object.
db.session.add(new_usr)
db.session.commit() #will insert the new_usr data into database AND retrieve id
idd = new_usr.usrID # usrID is the autoincremented primary_key column.
return jsonify(idd),201 #usrID = 12, correct id from table User in Database.
this question has been asked many times on stackoverflow and no answer I have seen is comprehensive. Googling 'sqlalchemy insert get id of new row' brings up a lot of them.
There are three levels to SQLAlchemy.
Top: the ORM.
Middle: Database abstraction (DBA) with Table classes etc.
Bottom: SQL using the text function.
To an OO programmer the ORM level looks natural, but to a database programmer it looks ugly and the ORM gets in the way. The DBA layer is an OK compromise. The SQL layer looks natural to database programmers and would look alien to an OO-only programmer.
Each level has it own syntax, similar but different enough to be frustrating. On top of this there is almost too much documentation online, very hard to find the answer.
I will describe how to get the inserted id AT THE SQL LAYER for the RDBMS I use.
Table: User(user_id integer primary autoincrement key, user_name string)
conn: Is a Connection obtained within SQLAlchemy to the DBMS you are using.
SQLite
======
insstmt = text(
'''INSERT INTO user (user_name)
VALUES (:usernm) ''' )
# Execute within a transaction (optional)
txn = conn.begin()
result = conn.execute(insstmt, usernm='Jane Doe')
# The id!
recid = result.lastrowid
txn.commit()
MS SQL Server
=============
insstmt = text(
'''INSERT INTO user (user_name)
OUTPUT inserted.record_id
VALUES (:usernm) ''' )
txn = conn.begin()
result = conn.execute(insstmt, usernm='Jane Doe')
# The id!
recid = result.fetchone()[0]
txn.commit()
MariaDB/MySQL
=============
insstmt = text(
'''INSERT INTO user (user_name)
VALUES (:usernm) ''' )
txn = conn.begin()
result = conn.execute(insstmt, usernm='Jane Doe')
# The id!
recid = conn.execute(text('SELECT LAST_INSERT_ID()')).fetchone()[0]
txn.commit()
Postgres
========
insstmt = text(
'''INSERT INTO user (user_name)
VALUES (:usernm)
RETURNING user_id ''' )
txn = conn.begin()
result = conn.execute(insstmt, usernm='Jane Doe')
# The id!
recid = result.fetchone()[0]
txn.commit()
result.inserted_primary_key
Worked for me. The only thing to note is that this returns a list that contains that last_insert_id.
Make sure you use fetchrow/fetch to receive the returning object
insert_stmt = user.insert().values(name="homer", country_id="123").returning(user.c.id)
row_id = await conn.fetchrow(insert_stmt)
For Postgress inserts from python code is simple to use "RETURNING" keyword with the "col_id" (name of the column which you want to get the last inserted row id) in insert statement at end
syntax -
from sqlalchemy import create_engine
conn_string = "postgresql://USERNAME:PSWD#HOSTNAME/DATABASE_NAME"
db = create_engine(conn_string)
conn = db.connect()
INSERT INTO emp_table (col_id, Name ,Age)
VALUES(3,'xyz',30) RETURNING col_id;
or
(if col_id column is auto increment)
insert_sql = (INSERT INTO emp_table (Name ,Age)
VALUES('xyz',30) RETURNING col_id;)
result = conn.execute(insert_sql)
[last_row_id] = result.fetchone()
print(last_row_id)
#output = 3
ex -

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