I am a beginner in python using 2.7.11 and i have made a guessing game. Here is my code so far
def game():
import random
random_number = random.randint(1,100)
tries = 0
low = 0
high = 100
while tries < 8:
if(tries == 0):
guess = input("Guess a random number between {} and {}.".format(low, high))
tries += 1
try:
guess_num = int(guess)
except:
print("That's not a whole number!")
break
if guess_num < low or guess_num > high:
print("That number is not between {} and {}.".format(low, high))
break
elif guess_num == random_number:
print("Congratulations! You are correct!")
print("It took you {} tries.".format(tries))
playAagain = raw_input ("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if playAagain == "y" or "Y":
game()
elif guess_num > random_number:
print("Sorry that number is too high.")
high = guess_num
guess = input("Guess a number between {} and {} .".format(low, high))
elif guess_num < random_number:
print("Sorry that number is too low.")
low = guess_num
guess = input("Guess a number between {} and {} .".format(low, high))
else:
print("Sorry, but my number was {}".format(random_number))
print("You are out of tries. Better luck next time.")
game()
How would i incorporate a system that makes it so Each time the user guesses the correct number it includes feedback giving the fewest number of guesses it took to correctly guess the number. Like a high score on how many guesses it took them and to change it only if it was beaten
you can create a static variable like this :
game.highscore = 10
and you update it each time when the user wins the game (check if tries less than highscore)
You could add a best_score parameter to your game function:
def game(best_score=None):
...
elif guess_num == random_number:
print("Congratulations! You are correct!")
print("It took you {} tries.".format(tries))
# update best score
if best_score is None:
best_score = tries
else:
best_score = min(tries, best_score)
print("Best score so far: {} tries".format(best_score))
play_again = raw_input("Excellent! You guessed the number! Would you like to play again (y or n)? ")
if play_again.lower() == "y":
game(best_score) # launch new game with new best score
...
At the start of your code (before defining the function), add the global variable best_score (or whatever you want to call it), and initialize it as None:
best_score = None
During the check on whether the number is the correct guess, you can check the number of tries against the best_score, and update accordingly:
elif guess_num == random_number:
global best_score
# check if best_score needs to be updated
if best_score == None or tries < best_score:
best_score = tries
print("Congratulations! You are correct!")
print("It took you {} tries.".format(tries))
# print out a message about the best score
print("Your best score is {} tries.".format(best_score))
Related
I am creating a python random counting game. I'm having some difficulties with certain parts. Can anyone here review my code? I'm having difficulty with trying to implement a try/except and a tries function that counts the user's attempts. I also have to verify that the number is a legitimate input and not a variable. So far I've gotten this far and its coming along good. I just need alittle help ironing out a few things. Thanks guys you rock.
Here is the code below:
import random
def main():
start_game()
play_again()
tries()
print("Welcome to the number guessing game")
print("I'm thinking of a number between 1 and 50")
def start_game():
secret_number = random.randint(1,50)
user_attempt_number = 1
user_guess = 0
while user_guess != secret_number and user_attempt_number < 5:
print("---Attempt", user_attempt_number)
user_input_text = input("Guess what number I am thinking of: ")
user_guess = int(user_input_text)
if user_guess > secret_number:
print("Too high")
elif user_guess < secret_number:
print("Too low")
else:
print("Right")
user_attempt_number += 1
if user_guess != secret_number:
print("You ran out of attempts. The correct number was"
+str(secret_number)+ ".")
def play_again():
while True:
play_again = input("Do you want to play again?")
if play_again == 'yes':
main()
if play_again =='no':
print("Thanks for playing")
break
def tries():
found= False
max_attempts=50
secret_number = random.randint(1, 50)
while tries <= max_attempts and not found:
user_input_text = start_game()
user_guess_count=+1
if user_input_text == secret_number:
print("It took you {} tries.".format(user_guess_count))
found = True
main()
Try this method:
def play_game():
print("Enter the upper limit for the range of numbers: ")
limit = int(input())
number = random.randint(1, limit)
print("I'm thinking of a number from 1 to " + str(limit) + "\n")
count = 1 #new line
while True:
guess = int(input("Your guess: "))
if guess < number:
print("Too low.")
elif guess > number:
print("Too high.")
elif guess == number:
print("You guessed it in " + str(count) + " tries.\n")
count = count+
This is the code:
print("Welcome to my guessing game can you get the magic number hint, it's between 1 and 100 ")
import random
Magic_number = random.randrange(1, 100)
print(Magic_number)
guess = int(input("Enter your guess:"))
guess_limit = 5
guess_counter = 1
out_of_guesses = False
print("You have", str(guess_limit - guess_counter), "tries left")
while not out_of_guesses:
guess = int(input("Enter guess: "))
if guess == Magic_number:
print("Well done you got it!!")
exit(0)
elif guess < Magic_number:
print("That number is too small, try again")
elif guess > Magic_number:
print("That number is too high try again")
guess_counter += 1
print("You have", str(guess_limit - guess_counter), "tries left")
# exit clause
if guess_limit == guess_counter:
out_of_guesses = True
print("Game over, sorry")
And even if I get it correct on the first try it does something like this:
Welcome to my guessing game can you get the magic number
hint,
it's between 1 and 100
47
Enter your guess: 47
You have 4 tries left
Enter guess: 47
Well done you got it!!
As you can see even though i was correct on the first try it wasn't counted. Ps.(That is what shows up at the bottom of my screen where the code is executed.)
You do not check if guess == Magic_number after reading input on line 4.
Like this
import random
Magic_number = random.randrange(1, 100)
print(Magic_number)
guess = int(input("Enter your guess:"))
if guess == Magic_number:
print ("You won")
exit(0)
You don't need all those variables, check this.
import random
Magic_number = random.randrange(1, 100)
print(Magic_number)
guess_limit = 5
guess_counter = 0
while True:
guess = int(input("Enter guess: "))
if guess == Magic_number:
print("Well done you got it!!")
exit(0)
elif guess < Magic_number:
print("That number is too small, try again")
elif guess > Magic_number:
print("That number is too high try again")
guess_counter += 1
print(f"You have {guess_limit - guess_counter} tries left")
if guess_counter == guess_limit:
print("Game over, sorry")
exit(0)
Im getting a syntax error for elif option ==2:. I was wondering what I need to do to fix it. I followed the pseudocode my professor gave us but it still won't run. I'm wondering if I shouldn't have used elif or maybe something about the indentation is off.
import random
print("Welcome to the guess my number program")
while True:
print("1. You guess the number")
print("2. You type a number and see if the computer can guess it")
print("3. Exit")
option = int(input("Please enter your number here: "))
if option ==1:
#generates a random number
mynumber = random.randint(1,11)
#number of guesses
count = 1
while True:
try:
guess = int(input("Guess a number between 1 and 10:"))
while guess < 1 or guess > 10:
guess = int(input("Guess a number between 1 and 10:")) # THIS LINE HERE
except:
print("Numbers Only")
continue
#prints if the number you chose is too low and adds 1 to the counter
if guess < mynumber:
print("The number you chose is too low")
count= count+1
#prints if the number you chose is too high and adds 1 to the counter
elif guess > mynumber:
print("The number you choose is too high")
count = count+1
#If the number you chose is correct it will tell you that you guessed the number and how many attempts it took
elif guess == mynumber:
print("You guessed it in " , count , "attempts")
break
elif option == 2:
number = int(input("Please Enter a Number: "))
count = 1
while True:
randomval = random.randint(1,11)
if (number < randomval):
print("Too high")
elif (number > randomval):
print("Too low")
count = count+1
elif (number==randomval):
print("The computer guessed it in" + count + "attempts. The number was" + randomval)
break
else:
break
The problem is simple. There is no continuity between if option == 1 and elif option == 2, because of the in between while loop. What you have to do is remove the el part of elif option == 2 and just write if option == 2.
I haven't tested the whole program myself. But at a glance, this should rectify the problem.
Please comment if otherwise.
I was just wondering if there is a way to limit the amount of times a user can input something on a while loop. This is simply a guess a number 1-100 game. I have the found variable = False.
while not found:
user_guess = int(input("Your guess: "))
if user_guess == random_number:
print("you got it!")
found = True
elif user_guess > random_number:
print("Guess lower")
else:
print("guess higher")
I wanted to see if i could make this code seem more like a game by limiting the amount a user can guess for the input. Ive had some ideas i just cannot wrap my head around it. do i have set a variable value for the input to set the amount of times it can run? Im new to programming so i am struggling a bit.
count = 0
max_guesses_allowed = pick your max here
while not found or count < max_guesses_allowed:
user_guess = int(input("Your guess: "))
if user_guess == random_number:
print("you got it!")
found = True
elif user_guess > random_number:
count += 1
print("Guess lower")
else:
count += 1
print("guess higher")
The standard way would be to count the number of loops, and then exit if they exceed the maximum.
max_allowed = 10
attempt = 0
while not found:
attempt += 1
user_guess = int(input("Your guess: "))
if user_guess == random_number:
print("you got it!")
found = True
elif attempt == max_allowed:
print("You've reached the maximum number of guesses.")
break
elif user_guess > random_number:
print("Guess lower")
else:
print("guess higher")
I'm just starting out on python and I'm wondering exactly why my variable guesses is not defined. I feel as if it's a indentation issue but once I change the indentation I usually come upon a syntax error any help understanding this issue would be greatly appreciated.
import random
def game():
guesses = []
secret_num = random.randint(1, 10)
while len(guesses) < 5:
try:
guess = int(input("Guess a number between 1 and 10 "))
except ValueError:
print("{} isn't a number!".format(guess))
else:
if guess == secret_num:
print("You got it! My number was {}".format(secret_num))
break
elif guess < secret_num:
print("My number is higher than {}".format(guess))
else:
print("My number is lower tha {}".format(guess))
guesses.append(guess)
else:
print("You didn't get it my secret number was {}".format(secret_num))
play_again = input("Do you want to play again? Y/N")
if play_again.lower() != 'n':
game()
else:
print("Bye thanks for playing!")
This doesn't throw any errors on my computer. Note you'll have to call the game() function if you want to actually run the code.
import random
def game():
guesses = []
secret_num = random.randint(1, 10)
while len(guesses) < 5:
try:
guess = int(input("Guess a number between 1 and 10 "))
except ValueError:
print("{} isn't a number!".format(guess))
else:
if guess == secret_num:
print("You got it! My number was {}".format(secret_num))
break
elif guess < secret_num:
print("My number is higher than {}".format(guess))
else:
print("My number is lower tha {}".format(guess))
guesses.append(guess)
else:
print("You didn't get it my secret number was {}".format(secret_num))
play_again = input("Do you want to play again? Y/N")
if play_again.lower() != 'n':
game()
else:
print("Bye thanks for playing!")
game() # to run the code