I have this json data I need to iterate through. The general format of the json data is
{
"Name" : "Bob"
"value" : "1100"
"morestuff" : "otherstuff"
"otherTermResults" : {
"stuff" : "morestuff"
"things" : "thisandthat"
"value" : "1200"
}
"value" : "1300"
....
....
....
} // end
As you can see there are 3 fields named "value". In python i can access the first 2 with
line_object = json.loads(line)
value1 = line_object["value"] //gets me 1000
value2 = line_object["otherTermResults"][0]["value"] // gets me 1200
This reliable gets me the first 2 "value" fields. I dont know how to get the 3rd "value" the one reading 1300. In addition the json data im working with may have an "n" unknown duplicates of "value" not nested in a subfield just for one name, in this case "bob". I read a few things saying you have to access the correct index but that was for jquery. In python
json.loads(line)
only loads in the first field that matches the "value". how do i resolve this issue in python? Do i need to switch to another language?
json.loads takes an object_pairs_hook that you can use to customize behavior. For example, to collect the duplicate values into a list you might do something like:
import json
def find_value(ordered_pairs):
d = {}
for k, v in ordered_pairs:
if k == "value":
d.setdefault(k, []).append(v)
else:
d[k] = v
return d
json.loads(raw_post_data, object_pairs_hook=find_value)
Related
hello i got a problem and i'm not sure how to solve it :
i have a project where i'm recovering a json file via a request and making a list with the keys i need so it look a bit like this:
{
"name":"Lucas White",
"project":{
"key_project":"EB-648",
"name_status":"Open"
}
},
{
"name":"Lisa Booth",
"project":{
"key_project":"EB-647",
"name_status":"Open"
}
}
{
"name":"Lucas White",
"project":{
"key_project":"EB-645",
"name_status":"Development In Progress"
}
},
here is my code in python
entries = []
entries.append({
"name":name ,
"project": {
"key_project":key_project,
"name_status":name_status
}
},)
how do i make it so that Lucas get a list with all his project keys ??
also its my first question i hope it is clear cause english is not my first language
I would suggest the next approach. First, add all data to the map and then transform the map to the list. You can use "name" as a key in the map. Here is out of a head example:
elements = {}
for ...:
...
if name not in elements:
# we check if name is not in our dictionary and create new list for that name
elements[name] = list()
elements[name].append({
"key_project":key_project,
"name_status":name_status
})
# we append the new project to the list
# as a result we get a map with names as keys and a list of projects for that name as values
result_list = [{"name": k, "projects": v} for k, v in elements.items()]
# k - key - and we used "name" as key
# v - value - value is list of all projects
Python Noob here. I saw many similar questions but none of it my exact use case. I have a simple nested json, and I'm trying to access the element name present inside metadata. Below is my sample json.
{
"items": [{
"metadata": {
"name": "myname1"
}
},
{
"metadata": {
"name": "myname1"
}
}
]
}
Below is the code That I have tried so far, but not successfull.
import json
f = open('./myfile.json')
x = f.read()
data = json.loads(x)
for i in data['items']:
for j in i['metadata']:
print (j['name'])
It errors out stating below
File "pythonjson.py", line 8, in
print (j['name']) TypeError: string indices must be integers
When I printed print (type(j)) I received the following o/p <class 'str'>. So I can see that it is a list of strings and not an dictinoary. So now How can I parse through a list of strings? Any official documentation or guide would be much helpful to know the concept of this.
Your json is bad, and the python exception is clear and unambiguous. You have the basic string "name" and you are trying to ... do a lookup on that?
Let's cut out all the json and look at the real issue. You do not know how to iterate over a dict. You're actually iterating over the keys themselves. If you want to see their values too, you're going to need dict.items()
https://docs.python.org/3/tutorial/datastructures.html#looping-techniques
metadata = {"name": "myname1"}
for key, value in metadata.items():
if key == "name":
print ('the name is', value)
But why bother if you already know the key you want to look up?
This is literally why we have dict.
print ('the name is', metadata["name"])
You likely need:
import json
f = open('./myfile.json')
x = f.read()
data = json.loads(x)
for item in data['items']:
print(item["metadata"]["name"]
Your original JSON is not valid (colons missing).
to access contents of name use "i["metadata"].keys()" this will return all keys in "metadata".
Working code to access all values of the dictionary in "metadata".
for i in data['items']:
for j in i["metadata"].keys():
print (i["metadata"][j])
**update:**Working code to access contents of "name" only.
for i in data['items']:
print (i["metadata"]["name"])
Have a JSON file output similar to:
{
"object1": {
"json_data": "{json data information}",
"tables_data": "TABLES_DATA"
},
"object2": {
"json_data": {json data information}",
"tables_data": ""
}
}
Essentially, if there is an empty string for tables_data as shown in object2 (eg. "tables_data": ""), I want the entire object to be removed so that the output would look like:
{
"object1": {
"json_data": "{json data information}",
"tables_data": "TABLES_DATA"
}
}
What is the best way to go about doing this? Each of these objects correspond to a separate index in a list that I've appended called summary[].
To achieve this, you could iterate through the JSON dictionary and test the tables_data values, adding the objectX elements to a new dictionary if their tables_data value passes the test:
new_dict = {k: v for k, v in json_dict.items()
if v.get("tables_data", "") != ""}
If your JSON objectX is stored in a list as you say, these could be processed as follows using a list comprehension:
filtered_summary = [object_dict for object_dict in summary
if object_dict.get("tables_data", "") != ""]
Unless you have compelling reasons to do otherwise, the pythonic way to filter out a list or dict (or any iterable) is not to change it in place but to create a new filtered one. For your case this would look like
raw_data = YOUR_DICT_HERE_WHEREVER_IT_COMES_FROM
# NB : empty string have a false value in a boolean test
cleaned_data = {k:v for k, v in raw_data.items() if not v["table_data"]}
So I have a dictionary called component and a list of dictionaries called allocations.
I want to be able to put the allocations under a component as a nested dictionary. kind of like so:
Allocations[
allocation1 : {
key : value
},
allocation2 {
key : value
}
]
My desired output:
Component1 : {
key:value
allocations : [allocation1 : {
key : value
}
,allocation2 : {
key : value
}
]
}
I came from Java, and i realize there is no append that I can use.
I tried this and obviously didnt work:
#allocate this under the selected component - DIDNT WORK
component["allocations"][] = allocation
How can I create a list of dictionaries in a dictionary?
Simply assign it:
component["allocations"] = some_list
For instance, if you want a new, empty one:
component["allocations"] = []
or:
component["allocations"] = list()
Then, manipulate the list as usual:
component["allocations"].append(some_object)
This is the string I am looking to update.
Koordinatstring =
{
"Koords":"Koordinates",
"TrueCoords":
{
"FirstFind":
{
"X":"134",
"Y":"223",
},
"SecondFind":
{
"X":"721",
"Y":"632",
},
"ThirdFind":
{
"X":"412",
"Y":"344",
},
"FourthFind":
{
"X":"612",
"Y":"532",
}
}
}
I know how to extract only the X or Y value from FourthFind for example. But what I am looking to do at the moment, is to access that value and replace it with a new one that I want to input.
I would like to do something simliar to:
k = json.dumps(koordinatstring)
l = json.loads(k)
Kords1 = l['TrueCoords']['FirstFind']['X']
To overwrite data, but I don't know if that is possible.
Even though the data may have come from a JSON document, once parsed you have ordinary dictionaries referencing other ordinary dictionaries.
You can always assign to a key in a dictionary:
d = {'foo': 'bar'}
d['foo'] = 'spam'
You just have a nested dictionary, so you need to string together a few [...] subscriptions to access the one you want to change:
l['TrueCoords']['FourthFind']['X'] = '42'
This sets the 'X' key to the new value '42', in the dictionary referenced by l['TrueCoords']['FourthFind'].