We Keep Coding

Python Selenium Click button inside span tag using button text

The html text below exits on a page. I am trying to have selenium click the button that this tag is referring to. I can not search this href because the id for given app is unknown and link will always have a different id. I have to click on this button by locating it by text inside button which is "New Database/Server"
<a class="btn btn-primary" data-turbo-frame="modal" href="/repo/servers/new?repo_application_id=280"><svg class="bi flex-shrink-0 me-2" height="24" role="img" width="24"><use href="#icon_database-plus"></use></svg><span class="pe-3">New Database/Server</span></a>
How do I have the driver go to this href link?

Use following xpath to click on the button.
driver.find_element(By.XPATH, "//a[.//span[text()='New Database/Server']]").click()
or use link_text
driver.find_element(By.LINK_TEXT, "New Database/Server").click()

How do I select this dropdown button in Selenium?

I have this html :
<div class="dropdown float-right">
<button class="btn btn-default" type="button" id="export-button" data-toggle="dropdown">
<i class="the-download-export"></i>
Export
</button>
<div class="dropdown-menu dropdown-menu-right"><div class="dropdown-item action-export" data-format="csv" data-store="com" data-reverse-type="single"><i class="text-primary fa fa-upload" aria-hidden="true"></i>Download File</div>
This is a dropdown that has a few options. When the button is clicked, it collapses the dropdown selection and the divs appear(there are more divs for various data formats which i haven't added here for simplicity).
I have tried a few things in order to click the button with the csv data format, but everything has failed. Either not finding it or getting the div only, which is not interactible.
What is the proper way of selecting and clicking this dropdown collapsible button in Python ?

That's very little to work on.
I can recommend either checking whether you can get the data another way (e.g. api call when clicking the button) or something with x-path like
button = getFromXPath(".//button[#id='export-button']")
button.click()

Selecting button without ID in selenium Python

I'm learning with Python Selenium and I'm trying to click a button which doesn't seem to have an id. I get an error that the element could not be scrolled into view.
Could anyone help with how I click the element?
It might be useful to know that the button only appears when you mouse over a section of the page
HTML is:
<div class="btn-group" role="group" aria-label="...">
<button type="button" class="grey-bg btn btn-default btn-expand" title="Expand"></button>
<button type="button" class="grey-bg btn btn-default btn-export" title="Export"></button>
<button type="button" class="grey-bg btn btn-default btn-clone" title="Clone"></button>
<button type="button" class="grey-bg btn btn-default btn-stamp" title="Pin"></button>
<button type="button" class="grey-bg btn btn-default btn-delete" title="Delete"></button>
</div>
I've tried to select by xpath:
driver.find_element_by_xpath('//*[#title="Export"]').click()
Thanks!

As you mentioned, it appears when you mouse hover. Kindly refer to this discussion for mouse hover. And try to look for the button after then click using javascript as this doesn't need to be displayed in order to click.
exportBtn = driver.find_element_by_xpath('//*[#title="Export"]') driver.execute_script("arguments[0].click();", exportBtn)

From the error, it looks like the element hasn't been scrolled into view. In order to scroll to the element, just add this line to ur code:
element = driver.find_element_by_xpath('//*[#title="Export"]')
driver.execute_script("arguments[0].scrollIntoView();", element)
element.click()
Hope that this helps!

How to find and click the button by "onclick" with Selenium and Python?

There are 2 buttons in a page, and the difference between these 2 buttons is "onclick".
<button class="btn btn-primary" style="width: 96px;" type="button" id="YesBtn" onclick="check_security('security_div0')">OK</button>
<button class="btn btn-primary" style="width: 96px;" type="button" id="YesBtn" onclick="check_security('wlan1security_div0')">OK</button>
I was thinking to use xpath:
driver.find_element_by_xpath("//form[#id='update-container-id']/div/div/div/div[2]/div/div[2]/table[1]/tbody/tr[1]/td[8]/div[3]/div/div/div/div[3]/button").click()
But it responses the error as below:
selenium.common.exceptions.ElementNotInteractableException: Message: Element <button id="YesBtn" class="btn btn-primary" type="button"> could not be scrolled into view
Does anyone can help me to click the 2nd button correctly? Thanks a lot.

try with the x-path //button[#onclick="check_security('wlan1security_div0')"]
driver.find_element_by_xpath("//button[#onclick=\"check_security('wlan1security_div0')\"]").click()
Using Action class,
button = driver.find_element_by_xpath("//button[#onclick=\"check_security('wlan1security_div0')\"]")
ActionChains(driver).move_to_element(button).click(button).perform()
using java script executor,
driver.execute_script("javascript:check_security('wlan1security_div0')")

As per the HTML you have provided, to click on the button using the onclick() event you can use the following solution:
First Element(css_selector):
driver.find_element_by_css_selector("button.btn.btn-primary#YesBtn[onclick*='security_div0']").click()
First Element(xpath):
driver.find_element_by_xpath("//button[#class='btn btn-primary' and #id='YesBtn'][#onclick=\"check_security('security_div0')\"]").click()
Second Element(css_selector):
driver.find_element_by_css_selector("button.btn.btn-primary#YesBtn[onclick*='wlan1security_div0']").click()
Second Element(xpath):
driver.find_element_by_xpath("//button[#class='btn btn-primary' and #id='YesBtn'][#onclick=\"check_security('wlan1security_div0')\"]").click()

First and foremost, you are using a really long xpath which will be difficult to maintain. You can narrow it down further.
Now, some xpaths you can try:
1) Get the second button with the id YesBtn (assuming there are only two buttons with that attribute) :
driver.find_element_by_xpath("(//button[#id= 'YesBtn'])[2]");
2) Find by the onclick attribute:
driver.find_element_by_xpath("//button[#onclick= \'check_security(\'wlan1security_div0\')\']");

button1 with HTML :
<button class="btn btn-primary" style="width: 96px;" type="button" id="YesBtn" onclick="check_security('security_div0')">OK</button>
XPATH :
//button[text()='OK' and #onclick="check_security('security_div0')"]
button2 with HTML :
<button class="btn btn-primary" style="width: 96px;" type="button" id="YesBtn" onclick="check_security('wlan1security_div0')">OK</button>
HTML:
//button[text()='OK' and #onclick="check_security('wlan1security_div0')"]

try:
buttonVar = browser.find_element_by_css_selector(cssSel)
ActionChains(browser).move_to_element(buttonVar).click(buttonVar ).perform()
except Exception as ex:
print("button not found)
Firefox gives you several option you can use with selenium find_element or elements;
by pressing f12 to bring up the inspector,
use the "pick an item" icon in the left corner to select the item you want to view.
This will highlight the text for that item in the inspector, which you can then right click on to bring up a menu where you select "copy" where there are at least 2 find_element options, css_selecor & xpath.
I personally don't like xpath.
They are sometimes long & unruly to work with but whatever suits your style. In my case css_selector works fine.

clicking a button on a password protected website in python

I'm trying to write a script that pushes a button that looks like this in HTML code:
<button type="button" class="button save create">
<img src="img/tick-circle.png" title="" alt="">
Create
</button>
I read this post: Python: clicking a button but I can't figure out how to translate it to my problem because the website I am trying to click a button on does not take me to a new page once the button is clicked. Any suggestions?