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bs4 findAll not collecting all of the data from the other pages on the website

I'm trying to scrape a real estate website using BeautifulSoup.
I'm trying to get a list of rental prices for London. This works but only for the first page on the website. There are over 150 of them so I'm missing out on a lot of data. I would like to be able to collect all the prices from all the pages. Here is the code I'm using:
import requests
from bs4 import BeautifulSoup as soup
url = 'https://www.zoopla.co.uk/to-rent/property/central-london/?beds_max=5&price_frequency=per_month&q=Central%20London&results_sort=newest_listings&search_source=home'
response = requests.get(url)
response.status_code
data = soup(response.content, 'lxml')
prices = []
for line in data.findAll('div', {'class': 'css-1e28vvi-PriceContainer e2uk8e7'}):
price = str(line).split('>')[2].split(' ')[0].replace('£', '').replace(',','')
price = int(price)
prices.append(price)
Any idea as to why I can't collect the prices from all the pages using this script?
Extra question : is there a way to access the price using soup, IE with doing any list/string manipulation? When I call data.find('div', {'class': 'css-1e28vvi-PriceContainer e2uk8e7'}) I get a string of the following form <div class="css-1e28vvi-PriceContainer e2uk8e7" data-testid="listing-price"><p class="css-1o565rw-Text eczcs4p0" size="6">£3,012 pcm</p></div>
Any help would be much appreciated!

You can append &pn=<page number> parameter to the URL to get next pages:
import re
import requests
from bs4 import BeautifulSoup as soup
url = "https://www.zoopla.co.uk/to-rent/property/central-london/?beds_max=5&price_frequency=per_month&q=Central%20London&results_sort=newest_listings&search_source=home&pn="
prices = []
for page in range(1, 3): # <-- increase number of pages here
data = soup(requests.get(url + str(page)).content, "lxml")
for line in data.findAll(
"div", {"class": "css-1e28vvi-PriceContainer e2uk8e7"}
):
price = line.get_text(strip=True)
price = int(re.sub(r"[^\d]", "", price))
prices.append(price)
print(price)
print("-" * 80)
print(len(prices))
Prints:
...
1993
1993
--------------------------------------------------------------------------------
50

BeautifulSoup not finding dates

I'm trying to scrape some data from here: https://www.reuters.com/companies/AMPF.MI/financials/income-statement-quarterly.
I'd like to get the dates in the first row (ie. 31-Mar-21 31-Dec-20 30-Sep-20 30-Jun-20 31-Mar-20).
The problem comes when I try to get the date, with bs4 it outputs nothing. I wrote this code:
url = "https://www.reuters.com/companies/AMPF.MI/financials/income-statement-quarterly"
html_content = requests.get(url).text
soup = BeautifulSoup (html_content, "lxml")
a = soup.find('div', attrs = {"class": "tables-container"})
date = a.find("time").text;
When I execute it, it gives me nothing. Printing a, it can be seen that the find () doesn't get the date ... `
<th scope="column"><time class="TextLabel__text-label___3oCVw TextLabel__black___2FN-Z TextLabel__medium___t9PWg"></time>
Thanks.

The data is embedded within the page in JSON form. You can use this example how to parse it:
import json
import requests
from bs4 import BeautifulSoup
url = "https://www.reuters.com/companies/AMPF.MI/financials/income-statement-quarterly"
soup = BeautifulSoup(requests.get(url).content, "html.parser")
data = json.loads(soup.select_one("#__NEXT_DATA__").contents[0])
# uncomment this to print all data:
# print(json.dumps(data, indent=4))
x = data["props"]["initialState"]["markets"]["financials"]["financial_tables"]
headers = x["income_interim_tables"][0]["headers"]
print(*headers, sep="\n")
Prints:
2021-03-31
2020-12-31
2020-09-30
2020-06-30
2020-03-31

As I do not have enough reputation to comment:
The problem is that the scraped HTML does not contain the dates. The time tags are empty.
You need a way to scrape while pre-rendering the JavaScript which fills in the dates. This is a different topic which requires some headless browser or other approaches, e.g. https://www.scrapingbee.com/blog/scrapy-javascript/

What is the proper syntax for .find() in bs4?

I am trying to scrape the bitcoin price off of coinbase and cannot find the proper syntax. When I run the program (without the line with question marks) I get the block of html that I need, but I don't know how to narrow down and retrieve the price itself. Any help appreciated, thanks.
import requests
from bs4 import BeautifulSoup
url = 'https://www.coinbase.com/charts'
data = requests.get(url)
nicedata = data.text
soup = BeautifulSoup(nicedata, 'html.parser')
prettysoup = soup.prettify()
bitcoin = soup.find('h4', {'class':
'Header__StyledHeader-sc-1q6y56a-0 hZxUBM
TextElement__Spacer-sc-18l8wi5-0 hpeTzd'})
price = bitcoin.find('???')
print(price)
The attached image contains the html

To get text from item:
price = bitcoin.text
But this page has many items <h4> with this class but find() gets only first one and it has text Bitcoin, not price from your image. You may need find_all() to get list with all items and then you can use index [index] or slicing [start:end] to get some items, or you can use for-loop to work with every item on list.
import requests
from bs4 import BeautifulSoup
url = 'https://www.coinbase.com/charts'
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
all_h4 = soup.find_all('h4', {'class': 'Header__StyledHeader-sc-1q6y56a-0 hZxUBM TextElement__Spacer-sc-18l8wi5-0 hpeTzd'})
for h4 in all_h4:
print(h4.text)
It can be easier to work with data if you keep it in list of list or array or DataFrame. But to create list of lists it would be easier to find rows <tr> and inside every row search <h4>
import requests
from bs4 import BeautifulSoup
url = 'https://www.coinbase.com/charts'
r = requests.get(url, headers=headers)
soup = BeautifulSoup(r.text, 'html.parser')
all_tr = soup.find_all('tr')
data = []
for tr in all_tr:
row = []
for h4 in tr.find_all('h4'):
row.append(h4.text)
if row: # skip empty row
data.append(row)
for row in data:
print(row)
It doesn't need class to get all h4.
BTW: This page uses JavaScript to append new rows when you scroll page but requests and BeautifulSoup can't run JavaScript - so if you will need all rows then you may need Selenium to control web browser which runs JavaScript

How to skip or truncate character or symbols from text I need. Web-scraping with beautiful soup

I need to get price (61,990) between div tag but how can I get rid of currency symbol?
Same as here, I need to grab rating only (4.7), but I don't need anything after that, such that img src. How can I ignore it? Or skip it?
Code sample:
from bs4 import BeautifulSoup
import requests
price = []
ratings=[]
response = requests.get("https://www.flipkart.com/laptops/~buyback-guarantee-on-laptops-/pr?sid=6bo%2Cb5g&uniq")
soup = BeautifulSoup(response.text, 'html.parser')
for a in soup.findAll('a',href=True, attrs={'class':'_31qSD5'}):
price=a.find('div', attrs={'class':'_1vC4OE _2rQ-NK'})
rating=a.find('div', attrs={'class':'hGSR34'})

Here. You just need to use the .text method and treat it like a normal string. In this case, retain all but the first character.
from bs4 import BeautifulSoup
import requests
price = []
ratings=[]
response = requests.get("https://www.flipkart.com/laptops/~buyback-guarantee-on-laptops-/pr?sid=6bo%2Cb5g&uniq")
soup = BeautifulSoup(response.text, 'html.parser')
for a in soup.findAll('a',href=True, attrs={'class':'_31qSD5'}):
price=a.find('div', attrs={'class':'_1vC4OE _2rQ-NK'}).text[1:]
rating=a.find('div', attrs={'class':'hGSR34'}).text
print(price)
print(rating)
Out[110]: '4.3'
Out[111]: '52,990'

Get a <span> value using python web scrape

I am trying to get a product price using BeautifulSoup in python.
But i keep getting erroes, no matter what I try.
The picture of the site i am trying to web scrape
I want to get the 19,90 value.
I have already done a code to get all the product names, and now need their prices.
import requests
from bs4 import BeautifulSoup
url = 'https://www.zattini.com.br/busca?nsCat=Natural&q=amaro&searchTermCapitalized=Amaro&page=1'
page = requests.get(url)
soup = BeautifulSoup(page.text, 'html.parser')
price = soup.find('span', itemprop_='price')
print(price)

Less ideal is parsing out the JSON containing the prices
import requests
import json
import pandas as pd
from bs4 import BeautifulSoup
url = 'https://www.zattini.com.br/busca?nsCat=Natural&q=amaro&searchTermCapitalized=Amaro&page=1'
page = requests.get(url)
soup = BeautifulSoup(page.content, 'lxml')
scripts = [script.text for script in soup.select('script') if 'var freedom = freedom ||' in script.text]
pricesJson = scripts[0].split('"items":')[1].split(']')[0] + ']'
prices = [item['price'] for item in json.loads(pricesJson)]
names = [name.text for name in soup.select('#item-list [itemprop=name]')]
results = list(zip(names,prices))
df = pd.DataFrame(results)
print(df)
Sample output:

span[itemprop='price'] is generated by javascript. Original value stored in div[data-final-price] with value like 1990 and you can format it to 19,90 with Regex.
import re
...
soup = BeautifulSoup(page.text, 'html.parser')
prices = soup.select('div[data-final-price]')
for price in prices:
price = re.sub(r'(\d\d$)', r',\1', price['data-final-price'])
print(price)
Results:
19,90
134,89
29,90
119,90
104,90
59,90
....