db = sqlite3.connect("SQL database")
cursor = db.cursor()
query = 'DELETE FROM Item WHERE ItemID = {}'.format(self.ID)
cursor.execute(query)
db.commit()
cursor.close()
unsure why this error is coming up as my code seems to be correct.
The error is that whatever value self.ID is the error states that that there is no such column that is that value.
For example self.ID = "hello"
The error would be:
no such column: "hello"
Any help would be appreciated, thanks
Your query looks like:
DELETE FROM Item WHERE ItemID = hello
The error message is helpful in this case.
Instead do:
db = sqlite3.connect("SQL database")
cursor = db.cursor()
query = 'DELETE FROM Item WHERE ItemID = ?'
cursor.execute(query, (self.ID,))
db.commit()
cursor.close()
Notes:
The parameter placeholder for sqlite3 is ?.
The parameter value should be the second argument to .execute()
That parameter should be passed to .execute() as a sequence. A tuple is fine.
Related
I write to see how I can get only one data to show by a print when I make a query in python, when I do the query it should only give me a number but I cannot show or access it.
def run_query(self, query, parameters = ()):
with sqlite3.connect(self.db_name) as conn:
cursor = conn.cursor()
result = cursor.execute(query, parameters)
conn.commit()
return result
def get_horarios(self):
query = 'SELECT hora FROM horarios where horario=1'
db_rows = self.run_query(query)
print(db_rows)
To show the first row in the results of the query:
print(db_rows.fetchone())
To show all of the results of the query:
print(db_rows.fetchall())
or
for row in db_rows.fetchall():
print(row)
The query always return a list. To access the first item, you can do:
print(db_rows[0])
basically, it keeps on giving me that error and honestly I can't figure it out.
code:
#tasks.loop(seconds=60)
async def mutething():
db = sqlite3.connect('mute.db')
cursor = db.cursor()
cursor.execute(f"SELECT timeofmute FROM mutes")
result = cursor.fetchall()
out = [item for t in result for item in t]
out = [i + 60 for i in out]
out = tuple(out)
cursor.executemany("UPDATE mutes SET timeofmute (?)", (out,))
error:
sqlite3.OperationalError: near "(": syntax error
missing equal in your update statement but you need a where clause to pass primary key value , so you need to add your pk value to your tuple as well, so you need to include that in your select statement :
cursor.execute(f"SELECT id, timeofmute FROM mutes")
cursor.execute("UPDATE mutes SET timeofmute= ? WHERE id = ?", (out,))
but you simply could update data using sql without fetching the whole data :
#tasks.loop(seconds=60)
async def mutething():
db = sqlite3.connect('mute.db')
cursor = db.cursor()
cursor.execute(f"UPDATE mutes SET timeofmute = timeofmute + 60")
I am writing a function that will retrieve data from sqlite table based on the parameters user provide. This is the function so far
def database_retrieve(db_file, id):
try:
conn = sqlite3.connect(db_file)
with conn:
sql_command = "SELECT * FROM my_table WHERE id = "+id
cur = conn.cursor()
cur.execute(sql_command)
result = cur.fetchall()
return result
except Exception as e:
print(e)
db_file = 'testdb.db'
print(database_retrieve(db_file, 'subject1'))
This gives me the following error
no such column: subject1
None
When I add subject1, which is an entry under the id column in my_table, directly to the sql command like this
sql_command = "SELECT * FROM my_table WHERE id = 'subject1'"
it works fine and prints all the data.
I am new to sqlite3. Please help. Thanks in advance
These are the links I used to come this far
Python sqlite3 string variable in execute
https://www.dummies.com/programming/databases/how-to-retrieve-data-from-specific-rows-in-mysql-databases/
When you do this
sql_command = "SELECT * FROM my_table WHERE id = "+id
The value of sql_command is
"SELECT * FROM my_table WHERE id = subject1"
As you can see, subject1 is not in quotes. sqlite thinks it is a column, that's why you see that error.
Instead, do this
sql_command = "SELECT * FROM my_table WHERE id = ?"
cur.execute(sql_command, [id])
? acts as a placeholder for the variable id.
The official sqlite3 documentation mentions few others methods
https://docs.python.org/2/library/sqlite3.html
The sql_command string being generated should be something like this (Formatted string):
sql_command = "SELECT * FROM my_table WHERE id = %s AND name = %s" % (212212, 'shashank')
I have a problem with creating SQL query for Oracle database using Python.
I want to bind string variable and it does not work, could you tell me what am I doing wrong?
This is my code:
import cx_Oracle
dokList = []
def LoadDatabase():
conn = None
cursor = None
try:
conn = cx_Oracle.connect("login", "password", "localhost")
cursor = conn.cursor()
query = "SELECT * FROM DOCUMENT WHERE DOC = :param"
for doknumber in dokList:
cursor.execute(query, {'doknr':doknumber})
print(cursor.rowcount)
except cx_Oracle.DatabaseError as err:
print(err)
finally:
if cursor:
cursor.close()
if conn:
conn.close()
def CheckData():
with open('changedNamed.txt') as f:
lines = f.readlines()
for line in lines:
dokList.append(line)
CheckData()
LoadDatabase()
The output of cursor.rowcount is 0 but it should be number greater than 0.
You're using a dictionary ({'doknr' : doknumber}) for your parameter, so it's a named parameter - the :param needs to match the key name. Try this:
query = "SELECT * FROM DOCUMENT WHERE DOC = :doknr"
for doknumber in dokList:
cursor.execute(query, {'doknr':doknumber})
print(cursor.rowcount)
For future troubleshooting, to check whether your parameter is getting passed properly, you can also try changing your query to "select :param from dual".
I am trying to print SQL result through python code, where I an trying to pass different predicates of the where clause from a for loop. But the code only taking the last value from the loop and giving the result.
In the below example I have two distinct id values 'aaa' and 'bbb'. There are 4 records for id value = 'aaa' and 2 records for the id value = 'bbb'.
But the below code only giving me the result for the id value ='bbb' not for id value 'aaa'
Can anyone help to identify what exactly wrong I am doing?
import pymysql
db = pymysql.connect(host="localhost", user="user1", passwd="pass1", db="db1")
cur = db.cursor()
in_lst=['aaa', 'bbb']
for i in in_lst:
Sql = "SELECT id, val, typ FROM test123 Where id='{inpt}'".format(inpt=i)
print(Sql)
cur.execute(Sql)
records = cur.fetchall()
print(records)
db.close()
The result I am getting as below
C:\Python34\python.exe C:/Users/Koushik/PycharmProjects/Test20161204/20170405.py
SELECT id, val, typ FROM test123 Where id='bbb'
(('bbb', 5, '1a'), ('bbb', 17, '1d'))
Process finished with exit code 0
import pymysql
db = pymysql.connect(host="localhost", user="root", passwd="1234", db="sakila")
cur = db.cursor()
in_lst=['1', '2']
for i in in_lst:
Sql = "SELECT * FROM actor Where actor_id='{inpt}'".format(inpt=i)
print(Sql)
cur.execute(Sql)
records = cur.fetchall()
print(records)
db.close()
Indentation is your problem, please update the code according to your needs...
Within your for loop, you're formatting the sql statement to replace "{inpt}" with "aaa". However, before you do anything with that value, you're immediately overwriting it with the "bbb" version.
You would need to either:
Store the results somehow before the next iteration of the loop, then process them outside of the loop.
Process the results within the loop.
Something like the following will give you a list containing both results from the fetchall() calls:
import pymysql
db = pymysql.connect(host="localhost", user="user1", passwd="pass1", db="db1")
cur = db.cursor()
in_lst=['aaa', 'bbb']
records = list()
for i in in_lst:
Sql = "SELECT id, val, typ FROM test123 Where id='{inpt}'".format(inpt=i)
print(Sql)
cur.execute(Sql)
records.append(cur.fetchall())
print(records)
db.close()