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composite two foreign key in sqlalchemy?

I am using SQLALchemy in flask. And I am confused how to define composite key with two foreign keys.
One foreign key from one table and second from another table.
class Store_category_mapping(db.Model):
__tablename__ = 'store_category_mapping'
category_id = db.Column(db.Integer, nullable=False)
store_id = db.Column(db.Integer, nullable=False)
store_name = db.Column(db.String(50), nullable=False)
__table_args__ = (
db.ForeignKeyConstraint(
[category_id, store_id],
[Category_master.category_id, Store_master.store_id]
),
)
It gives this error:
sqlalchemy.exc.ArgumentError: ForeignKeyConstraint on
store_category_mapping(category_id, store_id) refers to multiple
remote tables: category_master and store_master

You can't have a composite foreign key that references more than one remote table. Composite foreign keys are a way to ensure integrity when one remote table has a composite primary key.
If you want to make sure that you only ever have one store_category_mapping entry with a given combination of category_id and store_id you could go for a UniqueConstraint instead.
I'm not familiar with flask, but I assume it would look somewhat like this:
class Store_category_mapping(db.Model):
__tablename__ = 'store_category_mapping'
category_id = db.Column(db.Integer, db.ForeignKey(Category_master.category_id), nullable=False)
store_id = db.Column(db.Integer, db.ForeignKey(Store_master.store_id), nullable=False)
store_name = db.Column(db.String(50), nullable=False)
__table_args__ = (
db.UniqueConstraint('category_id','store_id'),
)

SqlAlchemy can't determine join condition

I have 2 tables defined:
class TCableSet(Base):
__tablename__ = 'tCableSet'
ixCableSet = Column(Integer, primary_key=True)
decCableSetOne = Column(Numeric(8, 2))
decCableSetTwo = Column(Numeric(8, 2))
decCableSetThree = Column(Numeric(8, 2))
class TStepVoltage(Base):
__tablename__ = 'tStepVoltage'
ixStepVoltage = Column(Integer, primary_key=True)
ixSubReport = Column(Integer, ForeignKey('tSubReport.ixSubReport'), nullable=False)
iVoltage = Column(Integer)
ixPhaseA = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
ixPhaseB = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
ixPhaseC = Column(Integer, ForeignKey('tCableSet.ixCableSet'), nullable=False)
sub_report = relationship('TSubReport',
backref=backref('step_voltage'))
I understand why I am getting this error but can't figure out a proper way (yet).
When the table gets saved, I store the values in the tCableSet table and then use the id as a foreign key in my tStepVoltage table. The problem I have is when I go to retrieve the data, I want to be able to get the values(tCableSet row) along with the rest of my tStepVoltage table via a relationship, however I'm not sure how to go about this since I don't have a field in my tCableSet that can directly be linked via relationship to my tStepVoltage. I basically just needed the tCableSet for normalization

Since you have more than one foreign key that points to the same table, you have to tell SQLAlchemy which foreign key to use.
For example:
sub_report_a = relationship('TSubReport',
backref=backref('step_voltage'),
foreign_keys=[ixPhaseA])

SQLAlchemy column_property basics

I have two models:
class Report(Base):
__tablename__ = 'report'
id = Column(Integer, primary_key=True)
class ReportPhoto(Base):
__tablename__ = 'report_photo'
id = Column(Integer, primary_key=True)
report_id = Column(Integer, ForeignKey(Report.id), nullable=False)
report = relationship(Report, uselist=False, backref=backref('report_photo', uselist=True))
And I would like to add column to Report model which indicates is there any records within ReportPhoto. I try to use column_property this way:
class Report(Base):
__tablename__ = 'report'
id = Column(Integer, primary_key=True)
has_photo = column_property(
select(ReportPhoto.any())
)
but get an error NameError: name 'ReportPhoto' is not defined. How I can fix this issue?

something like that should work:
class ReportPhoto(Base):
__tablename__ = 'report_photo'
id = Column(Integer, primary_key=True)
report_id = Column(Integer, ForeignKey('report.id'), nullable=False)
class Report(Base):
__tablename__ = 'report'
id = Column(Integer, primary_key=True)
report_photos = relationship(ReportPhoto, backref='report')
has_photo = column_property(
exists().where(ReportPhoto.report_id==id)
)

I will add to #Vladimir lliev's response with some clarification for anyone else that might not see how to do this.
Place the table that will have the 'foreign table referencing' column_property after that which it references. In this case, it means placing Report after ReportPhoto. This will solve your NameError, however, you would be left with a new error on your ReportPhoto foreign key reference. To solve this, place your foreign key table reference in quotes. You can read more by referencing the declarative documentation (e.g., declarative.py) and looking under "Configuring Relationships" --- specifically, read the portion on quoting your foreign references.
With your code, this would look like:
class ReportPhoto(Base):
# This now goes first
__tablename__ = 'report_photo'
id = Column(Integer, primary_key=True)
# Notice the quotations around Report references here
report_id = Column(Integer, ForeignKey("Report.id"), nullable=False)
# Notice the quotations around Report references here
report = relationship("Report",
uselist=False,
backref=backref("report_photo", uselist=True))
class Report(Base):
# This is now _after_ ReportPhoto
__tablename__ = 'report'
id = Column(Integer, primary_key=True)
# ReportPhoto now exists and we will not trip a NameError exception
has_photo = column_property(
select(ReportPhoto.any())
)

How to build many-to-many relations using SQLAlchemy: a good example

I have read the SQLAlchemy documentation and tutorial about building many-to-many relation but I could not figure out how to do it properly when the association table contains more than the 2 foreign keys.
I have a table of items and every item has many details. Details can be the same on many items, so there is a many-to-many relation between items and details
I have the following:
class Item(Base):
__tablename__ = 'Item'
id = Column(Integer, primary_key=True)
name = Column(String(255))
description = Column(Text)
class Detail(Base):
__tablename__ = 'Detail'
id = Column(Integer, primary_key=True)
name = Column(String)
value = Column(String)
My association table is (It's defined before the other 2 in the code):
class ItemDetail(Base):
__tablename__ = 'ItemDetail'
id = Column(Integer, primary_key=True)
itemId = Column(Integer, ForeignKey('Item.id'))
detailId = Column(Integer, ForeignKey('Detail.id'))
endDate = Column(Date)
In the documentation, it's said that I need to use the "association object". I could not figure out how to use it properly, since it's mixed declarative with mapper forms and the examples seem not to be complete. I added the line:
details = relation(ItemDetail)
as a member of Item class and the line:
itemDetail = relation('Detail')
as a member of the association table, as described in the documentation.
when I do item = session.query(Item).first(), the item.details is not a list of Detail objects, but a list of ItemDetail objects.
How can I get details properly in Item objects, i.e., item.details should be a list of Detail objects?

From the comments I see you've found the answer. But the SQLAlchemy documentation is quite overwhelming for a 'new user' and I was struggling with the same question. So for future reference:
ItemDetail = Table('ItemDetail',
Column('id', Integer, primary_key=True),
Column('itemId', Integer, ForeignKey('Item.id')),
Column('detailId', Integer, ForeignKey('Detail.id')),
Column('endDate', Date))
class Item(Base):
__tablename__ = 'Item'
id = Column(Integer, primary_key=True)
name = Column(String(255))
description = Column(Text)
details = relationship('Detail', secondary=ItemDetail, backref='Item')
class Detail(Base):
__tablename__ = 'Detail'
id = Column(Integer, primary_key=True)
name = Column(String)
value = Column(String)
items = relationship('Item', secondary=ItemDetail, backref='Detail')

Like Miguel, I'm also using a Declarative approach for my junction table. However, I kept running into errors like
sqlalchemy.exc.ArgumentError: secondary argument <class 'main.ProjectUser'> passed to to relationship() User.projects must be a Table object or other FROM clause; can't send a mapped class directly as rows in 'secondary' are persisted independently of a class that is mapped to that same table.
With some fiddling, I was able to come up with the following. (Note my classes are different than OP's but the concept is the same.)
Example
Here's a full working example
from sqlalchemy import create_engine, Column, Integer, String, ForeignKey
from sqlalchemy.orm import declarative_base, relationship, Session
# Make the engine
engine = create_engine("sqlite+pysqlite:///:memory:", future=True, echo=False)
# Make the DeclarativeMeta
Base = declarative_base()
class User(Base):
__tablename__ = "users"
id = Column(Integer, primary_key=True)
name = Column(String)
projects = relationship('Project', secondary='project_users', back_populates='users')
class Project(Base):
__tablename__ = "projects"
id = Column(Integer, primary_key=True)
name = Column(String)
users = relationship('User', secondary='project_users', back_populates='projects')
class ProjectUser(Base):
__tablename__ = "project_users"
id = Column(Integer, primary_key=True)
notes = Column(String, nullable=True)
user_id = Column(Integer, ForeignKey('users.id'))
project_id = Column(Integer, ForeignKey('projects.id'))
# Create the tables in the database
Base.metadata.create_all(engine)
# Test it
with Session(bind=engine) as session:
# add users
usr1 = User(name="bob")
session.add(usr1)
usr2 = User(name="alice")
session.add(usr2)
session.commit()
# add projects
prj1 = Project(name="Project 1")
session.add(prj1)
prj2 = Project(name="Project 2")
session.add(prj2)
session.commit()
# map users to projects
prj1.users = [usr1, usr2]
prj2.users = [usr2]
session.commit()
with Session(bind=engine) as session:
print(session.query(User).where(User.id == 1).one().projects)
print(session.query(Project).where(Project.id == 1).one().users)
Notes
reference the table name in the secondary argument like secondary='project_users' as opposed to secondary=ProjectUser
use back_populates instead of backref
I made a detailed writeup about this here.

Previous Answer worked for me, but I used a Class base approach for the table ItemDetail. This is the Sample code:
class ItemDetail(Base):
__tablename__ = 'ItemDetail'
id = Column(Integer, primary_key=True, index=True)
itemId = Column(Integer, ForeignKey('Item.id'))
detailId = Column(Integer, ForeignKey('Detail.id'))
endDate = Column(Date)
class Item(Base):
__tablename__ = 'Item'
id = Column(Integer, primary_key=True)
name = Column(String(255))
description = Column(Text)
details = relationship('Detail', secondary=ItemDetail.__table__, backref='Item')
class Detail(Base):
__tablename__ = 'Detail'
id = Column(Integer, primary_key=True)
name = Column(String)
value = Column(String)
items = relationship('Item', secondary=ItemDetail.__table__, backref='Detail')

sqlalchemy does not create my foreign key

SqlAlchemy newbie question:
Base = declarative_base()
class A(Base):
__tablename__ = 'as'
id = Column(Integer, primary_key=True)
class B(Base):
__tablename__ = 'bs'
id = Column(Integer, primary_key=True)
a = relation(A)
When I create my database schema, I have two tables, as and bs, which have one column (id) but there is no a column in table bs that points to A.
What can I be doing wrong? My database is mysql, if it matters.

relation() only tells the mapper how are the two tables related. You still need to add a column with the foreign key information. For example:
class B(Base):
__tablename__ = 'bs'
id = Column(Integer, primary_key=True)
a_id = Column(Integer, ForeignKey('as.id'), name="a")
a = relation(A)