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How to click on specific text in a paragraph?

I have a paragraph element as follows:
<p>You have logged in successfully. <em>LOGOUT</em></p>
Clicking on "LOGOUT" will initiate a logout procedure (e.g display a confirmation prompt).
How do I simulate this clicking on "LOGOUT" using Selenium WebDriver?

To find and click the "LOGOUT" text with python, you can use the following code:
logout = driver.find_element_by_xpath("//em[text()='LOGOUT']")
logout.click()

This could help :
Execute button Click with Selenium
As a preach :
You should first, try to analize the general basic components offered for your tool, and the interactions with external systems (selection, executions, listening).
Based on the first link offered as a resource your code should be some like :
package postBlo;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.chromse.ChromeDriver;
public class singleClickButton {
public singleClickButton() {
super();
}
public static void main(String[] args) throws Exception {
System.setProperty("webdriver.chrome.driver", "./exefiles/chromedriver.exe");
WebDriver = new ChromeDriver();
driver.manage().window().maximixe();
driver.get("your-local-site-to-test");
//Referen an input component and set a values
driver.findElement(By.name("id-html-tag")).sendKeys("someValue text");
/* ## Execution of button by using id
You could use both methods to identify the element you need :
By using "xpath" expression wich allows you to navigate between elements by using expressions
By using id-identifier
Chose one of both.
driver.findElement(By.xpath("expression-xpath")).click();
driver.findElement(By.id("id-element")).click();
*/
driver.findElement(By.xpath("/html/body/elemnts-container-button/button\r\n" + "")).click();
driver.findElement(By.id("button-id")).click();
}
}
As a mention I'm not related to Selenium but still the logic it's alike.
Best

How to fix pac file not recognized for python selenium test?

For reasons I am not able to explain here in a short manner, I want to use a pac file for a firefox test (python-selenium) to coordinate the used proxy for various types of requests.
Here is the pac file I am using:
function FindProxyForURL(url, host)
{
console.log("test proxy");
lsjkd fhafh fasdfhsdjkl fhs
if (url.substring(0, 3) === "ws:" || url.substring(0, 4) === "wss:")
{
return "DIRECT";
} else {
return "PROXY 0.0.0.0:8080";
}
}
and here is the complete script for the test:
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
selenium_proxy = webdriver.Proxy()
selenium_proxy.proxy_type = webdriver.common.proxy.ProxyType.PAC
selenium_proxy.proxyAutoconfigUrl = "/path/to/proxy.pac"
profile = webdriver.FirefoxProfile()
profile.set_proxy(selenium_proxy)
driver = webdriver.Firefox(firefox_profile=profile)
driver.get("http://www.python.org")
assert "Python" in driver.title
elem = driver.find_element_by_name("q")
elem.clear()
elem.send_keys("pycon")
elem.send_keys(Keys.RETURN)
assert "No results found." not in driver.page_source
time.sleep(10)
driver.close()
Because the pac file contains an obvious syntax error I expect the test to fail (like UnknownError). However, the page loads without problems and the test succeeds.
Why is the pac file not use inside the firefox driver? Or is it loaded but ignored? Is it possible to log some text from inside the pac file?
I tried to do that like above but (even without the syntax error) I cannot see the console.log anywhere (neither in the browser itself, for which I added the sleep of 10 seconds, so I can press F12 to check the browser's console).
How to be able to use the pac file for firefox?
Addendum:
You can even use the following pac file to see it is not being used at all:
//
// Define the network paths (direct, proxy and deny)
//
// Default connection
var direct = "DIRECT";
// Alternate Proxy Server
var proxy = "PROXY 0.0.0.0:8095";
// Default localhost for denied connections
var deny = "PROXY 0.0.0.0:65535";
//
// Proxy Logic
//
function FindProxyForURL(url, host)
{
return deny;
}
EACH request should be denied - but the test still works and the webpage is correctly requested...

The solution is the definition of the autoconfig URL!
One must not use a path like
selenium_proxy.proxyAutoconfigUrl = "/home/user/proxy.pac"
but a URL form
selenium_proxy.proxyAutoconfigUrl = "file:///home/user/proxy.pac"

how to detect unexpected url change python webdriver selenium?

I am automating a browser process but same credentials are used by all the persons(only one user can access the portal at a time), so whenever somebody else login-in, the current user is automatically kicked out with url change to "http://172.17.3.248:8889/ameyoreports/?acpMode=false#loggedOut".
Is there any way to constantly check for url change while my automatation script is running along and when logout is detected end the script.
I am using python selenium webdriver.

In Java we can take help from EventLister https://seleniumhq.github.io/selenium/docs/api/java/org/openqa/selenium/support/events/WebDriverEventListener.html for example if you implement it
public class Test2 implements WebDriverEventListener{
#Override
public void beforeFindBy(By arg0, WebElement arg1, WebDriver driver) {
if(driver.getCurrentUrl().equals("http://172.17.3.248:8889/ameyoreports/?acpMode=false#loggedOut")==true) {
//do want you want.
}
}
we have to use the same like below to cross check url before doing any action (as per above example, cross check url before finding element)
FirefoxDriver driver = new FirefoxDriver();
EventFiringWebDriver eventDriver = new EventFiringWebDriver(driver);
EventHandler handler = new EventHandler();
eventDriver.register(handler);
eventDriver.get("url");
in Java it helps http://toolsqa.com/selenium-webdriver/event-listener/ for python http://selenium-python.readthedocs.io/api.html#module-selenium.webdriver.support.abstract_event_listener

hey there is current_url attribute associated with the selenium webdriver object, you will be able to fetch the changed url using webdriver.current_url.
Keep a check for that and you can break your script whenever you want.
You can test it with the following code
#using chrome webdriver
from selenium.webdriver.chrome.options import Options
browser = Options()
instance = webdriver.Chrome(webdriver_path, options=browser)
instance.get(url)
instance.current_url <<<<<<< this will give the current url opened in browser
# manually enter another url in the browser then again check
instance.current_url

Until/WebDriverWait throwing NoSuchElementException

Based on every answer and piece of documentation I've seen, the following should wait for the element at xpath path:
delay = some amount of time way longer than I know is needed
driver = webdriver.Firefox()
driver.get(url)
wait = WebDriverWait(driver, delay, ignored_exceptions=NoSuchElementException)
wait.until(EC.presence_of_element_located(driver.find_element_by_xpath(path)))
but no matter what I do it always throws a NoSuchElementException immediately after getting the url. And before anyone marks this as a duplicate or calls me out on it, I am aware of this answer and although the element I'm looking for is in some kind of wrapper, I got the same problem when trying the above looking for that wrapper instead (also it works if I just provide a normal sleep call instead of the Expected Condition stuff which makes me think I don't need to manually enter into the wrapper). What's the point of having a function for waiting for an element to be loaded that doesn't wait until the element is loaded? Any help in solving this problem would be greatly appreciated.

I use this java code for similar situations:
private Wait<WebDriver> staleWait = new FluentWait<>(getDriver())
.withTimeout(WAIT_INTERVAL, TimeUnit.SECONDS)
.pollingEvery(POLLING_INTERVAL, TimeUnit.MILLISECONDS)
.ignoring(NoSuchElementException.class)
.ignoring(StaleElementReferenceException.class);
protected WebElement visibilityOf(WebElement webElement) {
staleWait.until((ExpectedCondition<Boolean>) webDriver -> {
try {
return element(webElement).isDisplayed();
} catch (StaleElementReferenceException e) {
return false;
} catch (NoSuchElementException ne) {
return false;
}
});
return element(webElement);
}

How to browse a whole website using selenium?

Is it possible to go through all the URIs of a given URL (website) using selenium ?
My aim is to launch firefox browser using selenium with a given URL of my choice (I know how to do it thanks to this website), and then let firefox browse all the pages that URL (website) has. I appreciate any hint/help on how to do it in Python.

You can use a recursive method in a class such as the one given below to do this.
public class RecursiveLinkTest {
//list to save visited links
static List<String> linkAlreadyVisited = new ArrayList<String>();
WebDriver driver;
public RecursiveLinkTest(WebDriver driver) {
this.driver = driver;
}
public void linkTest() {
// loop over all the a elements in the page
for(WebElement link : driver.findElements(By.tagName("a")) {
// Check if link is displayed and not previously visited
if (link.isDisplayed()
&& !linkAlreadyVisited.contains(link.getText())) {
// add link to list of links already visited
linkAlreadyVisited.add(link.getText());
System.out.println(link.getText());
// click on the link. This opens a new page
link.click();
// call recursiveLinkTest on the new page
new RecursiveLinkTest(driver).linkTest();
}
}
driver.navigate().back();
}
public static void main(String[] args) throws InterruptedException {
WebDriver driver = new FirefoxDriver();
driver.get("http://newtours.demoaut.com/");
// start recursive linkText
new RecursiveLinkTest(driver).linkTest();
}
}
Hope this helps you.

As Khyati mentions it is possible, however, selenium not a webcrawler or robot. You have to know where/what you are trying to test.
If you really want to go down that path I would recommend that you hit the page, pull all elements back and then loop through to click any elements that would correspond to navigation functionality (i.e. "//a" or hyperlink click).
Although if you go down this path and there is a page that opens another page then has a link back you would want to keep a list of all visited URL's and make sure that you don't duplicate a page like that.
This would work, but would also require a bit of logic in it to make it happen...and you might find yourself in an endless loop if you aren't careful.

I know you asked for a python example, but I was just in the middle of setting up a simple rep o for protractor testings and the task you want to accomplish seems to be very easy to do with protractor (which is just a wrapper around webdriver)
here is the code in javascript:
describe( 'stackoverflow scrapping', function () {
var ptor = protractor.getInstance();
beforeEach(function () {
browser.ignoreSynchronization = true;
} );
afterEach(function () {
} );
it( 'should find the number of links in a given url', function () {
browser.get( 'http://stackoverflow.com/questions/24257802/how-to-browse-a-whole-website-using-selenium' );
var script = function () {
var cb = arguments[ 0 ];
var nodes = document.querySelectorAll( 'a' );
nodes = [].slice.call( nodes ).map(function ( a ) {
return a.href;
} );
cb( nodes );
};
ptor.executeAsyncScript( script ).then(function ( res ) {
var visit = function ( url ) {
console.log( 'visiting url', url );
browser.get( url );
return ptor.sleep( 1000 );
};
var doVisit = function () {
var url = res.pop();
if ( url ) {
visit( url ).then( doVisit );
} else {
console.log( 'done visiting pages' );
}
};
doVisit();
} );
} );
} );
You can clone the repo from here
Note: I know protractor is probably not the best tool for it, but it was so simple to do it with it that I just give it a try.
I tested this with firefox (you can use the firefox-conf branch for it, but it will require that you fire webdriver manually) and chrome. If you're using osx this should work with no problem (assuming you have nodejs installed)

Selenium API provides all the facility via which you can do various operations like type ,click , goto , navigateTo , switch between frames, drag and drop, etc.
What you are aiming to do is just browsing in simple terms, clicking and providing different URls within the website also ,if I understood properly. Ya , you can definitely do it via Selenium webdriver.
And you can make a property file, for better ease and readiness where-in you can pass different properties like URLs , Base URI ,etc and do the automation testing via Selenium Webdriver in different browsers.

This is possible. I have implemented this using Java webdriver and URI. This was mainly created to identify the broken links.
Using "getElements" having tag can be get using webdriver once open and save "href" value.
Check all link status using URL class of java and Put it in stack.
Then pop link from stack and "get" link using Webdriver. Again get all the links from the page remove duplicate links which are present in stack.
Loop this until stack is empty.
You can update it as per your requirements. Such as levels of traversing, excluding other links which are not having domain of the given website etc.
Please comment if you are finding difficulty in implementation.