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I am trying to recursively append to a list while iterating over a nested list. For example, if I have a list [['a',['b',['c','d']]]], I would like a function to return [['a','b','c'],['a','b','d']]. My attempt so far is the following:
def recurse_append(data):
r_list=[]
for elem in data:
if isinstance(elem, list):
r_list.extend(recurse_append(elem))
else:
r_list.append(elem)
return r_list
which for this example returns ['a','b','c','d']. Unlike the example, the nested list that I am writing this for does not contain the same number of elements at each level, so I thought that a recursive function would be the best way to take this into account. Any help towards a solution would be greatly appreciated.
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this is dictionary I don't know how to use sort and reverse.
for some reason don't print the dictionary
disc: {'clave1': ['a','b','c'],
'clave2': ['ship','car','house'],
'clave3': [2,1,3]}
I get that the 'disc' is a variable holding the dictionary.
In this case just sort and reverse the values that are lists.
disc = {'clave1': ['a','b','c'],
'clave2': ['ship','car','house'],
'clave3': [2,1,3]}
for l in disc.values():
l.reverse()
for l in disc.values():
l.sort()
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d = {1:'a', 2:'b'}
#s = '1|a;2|b'
s = ';'.join([str(k)+'|'+d[k] for k in d])
Is there a better way to do this conversion?
I'd only make two small changes:
Use f-strings
Use a generator expression instead of a list comprehension, which would remove the need to hold all the values in memory prior to joining. It's not really a big deal unless you have thousaaaands of key/value pairs, though.
s = ';'.join(f'{k}|{d[k]}' for k in d)
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Below is my list,
['pending/', 'pending/2021-08-01/', 'pending/2021-06-01/', 'pending/2021-06-18/']
And I need to sort the list and filter it to a below format. Please suggest a quicker way to achieve it
['pending/2021-06-01/', 'pending/2021-06-18/', 'pending/2021-08-01/']
When your format is fixed and always starts with "pending" you can use the normal sorted function and count the / in a list comprehension.
>>> values = ['pending/', 'pending/2021-08-01/', 'pending/2021-06-01/', 'pending/2021-06-18/']
>>> sorted(x for x in values if x.count('/') == 2)
['pending/2021-06-01/', 'pending/2021-06-18/', 'pending/2021-08-01/']
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I need to remove a certain element from a list of dictionaries. Unfortunately, the only reference to the object needing removal is a place in another list:
enemy_list[num]
I need to take out enemy_list[num] from everyone.
ii = 0
for i in enemy_list:
print(ii, ':', enemy_list[ii])
ii += 1
num = input("Which of your opponents would you like to eliminate? ")
num = int(num)
del everyone[enemy_list[num]]
I cannot remove it from only enemy_list because it is reset multiple times as everyone in list everyone takes a turn.
I tried this question, but it only worked from removing entire lists from eachother. Is there a way I could change it to work for this case?
Thanks for your time!
everyone.remove(enemy_list[num])
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I'm having trouble understanding a particular list comprehension example. In the sample code below a list comprehension is used for the parameter of the set method. Most examples I've seen usually look like this "x for x in y". I've read documentation but it isn't clearing it up for me. What exactly is [marks for name] doing. Shouldn't it be [marks for marks]?
marksheet = []
for _ in range(0,int(input())):
marksheet.append([input(), float(input())])
second_highest = sorted(list(set([marks for name, marks in marksheet])))[1]
print('\n'.join([a for a,b in sorted(marksheet) if b == second_highest]))
Your code is using Python's list comprehension to create a list from another list based on the condition.
See more about list comprehensions here:
https://www.programiz.com/python-programming/list-comprehension
The [1] is accessing the item at index 1 (2nd item) of your sorted list.
As for .join, each line in the sorted list is being printed out with a newline (\n) between each one.