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Python move pictures from one folder to another ignoring case

I am trying to create a script to move all the picture files from one folder to another. I have found the script that works for this, except it doesn't work if the extensions are in capitals. Is there an easy way around this?
Current code:
import shutil
import os
source = "C:/Users/Tonello/Desktop/"
dest = "C:/Users/Tonello/Desktop/Pictures/"
files = os.listdir(source)
for f in files:
if os.path.splitext(f)[1] in (".jpg", ".gif", ".png"):
shutil.move(source + f, dest)

You could lowercase the extension before checking it:
if os.path.splitext(f)[1].lower() in (".jpg", ".gif", ".png"):
# Here --------------^

Moving all .csv files which match specific text pattern from multiple subfolders to new folder [Python]

I see many answers on here to similar questions but I cannot seem to adapt it quite yet due to my budding Python skill. I'd like to save the time of individually grabbing the data sets that contain what I need for analysis in R, but my scripts either don't run or seem to do what I need.
I need to 1) loop through a sea of subfolders in a parent folder, 2) loop through the bagillion .csv files in those subs and pick out the 1 that matters (matching text below) and 3) copy it over to a new clean folder with only what I want.
What I have tried:
1)
import os, shutil, glob
src_fldr = 'C:/project_folder_withsubfolders';
dst_fldr = 'C:/project_folder_withsubfolders/subfolder_to_dump_into';
try:
os.makedirs(dst_fldr); ## it creates the destination folder
except:
print ("Folder already exist or some error");
for csv_file in glob.glob(src_fldr+'*statistics_Intensity_Sum_Ch=3_Img=1.csv*'):
shutil.copy2(csv_file, dst_fldr);
where the text statistics_Intensity_Sum etc is the exact pattern I need for the file to copy over
this didn't actually copy anything over
Making a function that will do this:
srcDir = 'C:/project_folder_withsubfolders'
dstDir = 'C:/project_folder_withsubfolders/subfolder_to_dump_into'
def moveAllFilesinDir(srcDir, dstDir):
files = os.listdir(srcDir)
for f in files:
if f.find("statistics_Intensity_Sum_Ch=3_Img=1"):
shutil.move(f, dstDir)
else:
shutil.move(f, srcDir)
moveAlllFilesinDir(srcDir, dstDir)
This returned the following error:
File "C:\Users\jbla12\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 806, in move
os.rename(src, real_dst)
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'F1 converted' -> 'C:/Users/jbla12/Desktop/R Analyses/p65_project/sum_files\\F1 converted'
That's because that's a sub-folder I want it to go through! I've tried other methods but don't have record of them in my scripts.

SOLVED:
Special thanks to "Automate the Boring Stuff"
import shutil
import os
dest = 'C:/Users/jbla12/Desktop/R Analyses/p65_project/sum_files/'
src = 'C:/Users/jbla12/Desktop/R Analyses/p65_project/'
txt_ID = 'statistics_Intensity_Sum_Ch=3_Img=1.csv'
def moveSpecFiles(txt_ID, src, dest):
#src is the original file(s) destination
#dest is the destination for the files to end up in
#spec_txt is what the files end with that you want to ID
for foldername, subfolders, filenames in os.walk(src):
for file in filenames:
if file.endswith(txt_ID):
shutil.copy(os.path.join(foldername, file), dest)
print('Your files are ready sir/madam!')
moveSpecFiles(txt_ID, src, dest)

How to move multiple files whith spaces in their names with python?

I want to move multiple files (only files not folders) from the directory source to directory dest. I'm doing like below using a for loop:
import os
import shutil
import glob
source = "r'" + "/This is/the source path/"
dest = "r'" + "/This is/the destination path/"
files = glob.glob(source+'/*.*')
for f in files:
shutil.move(source+f, dest)
>> IOError: [Errno 2] No such file or directory:
But if I do it for a single file like this, it works.
source = "/This is/the source path/"
dest = "/This is/the destination path/"
file_1 = r'This is a file.txt'
shutil.move(source+file_1, dest) ## This works
How can I dot for several files?

The portion of the path defined by source is going to be included in your file paths defined in files. Adding source to f in your loop would create redundancy. Instead try:
shutil.move(f, dest)
Also, I'm not sure why you are adding "r'". Perhaps you mean to define source as raw input such as when you defined file_1? In that case you should execute something like this:
source = r'/some/path/to/file.ext'

But how to print moved files name like if I use print("Moved:" ) will be next argument in print statement

Move pairs of files (.txt & .xml) into their corresponding folder using Python

I have been working this challenge for about a day or so. I've looked at multiple questions and answers asked on SO and tried to 'MacGyver' the code used for my purpose, but still having issues.
I have a directory (lets call it "src\") with hundreds of files (.txt and .xml). Each .txt file has an associated .xml file (let's call it a pair). Example:
src\text-001.txt
src\text-001.xml
src\text-002.txt
src\text-002.xml
src\text-003.txt
src\text-003.xml
Here's an example of how I would like it to turn out so each pair of files are placed into a single unique folder:
src\text-001\text-001.txt
src\text-001\text-001.xml
src\text-002\text-002.txt
src\text-002\text-002.xml
src\text-003\text-003.txt
src\text-003\text-003.xml
What I'd like to do is create an associated folder for each pair and then move each pair of files into its respective folder using Python. I've already tried working from code I found (thanks to a post from Nov '12 by Sethdd, but am having trouble figuring out how to use the move function to grab pairs of files. Here's where I'm at:
import os
import shutil
srcpath = "PATH_TO_SOURCE"
srcfiles = os.listdir(srcpath)
destpath = "PATH_TO_DEST"
# grabs the name of the file before extension and uses as the dest folder name
destdirs = list(set([filename[0:9] for filename in srcfiles]))
def create(dirname, destpath):
full_path = os.path.join(destpath, dirname)
os.mkdir(full_path)
return full_path
def move(filename, dirpath):
shutil.move(os.path.join(srcpath, filename)
,dirpath)
# create destination directories and store their names along with full paths
targets = [
(folder, create(folder, destpath)) for folder in destdirs
]
for dirname, full_path in targets:
for filename in srcfile:
if dirname == filename[0:9]:
move(filename, full_path)
I feel like it should be easy, but Python isn't something I work with everyday and it's been a while since my scripting days... Any help would be greatly appreciated!
Thanks,
WK2EcoD

Use the glob module to interate all of the 'txt' files. From that you can parse and create the folders and copy the files.

The process should be as simple as it appears to you as a human.
for file_name in os.listdir(srcpath):
dir = file_name[:9]
# if dir doesn't exist, create it
# move file_name to dir
You're doing a lot of intermediate work that seems to be confusing you.
Also, insert some simple print statements to track data flow and execution flow. It appears that you have no tracing output so far.

You can do it with os module. For every file in directory check if associated folder exists, create if needed and then move the file. See the code below:
import os
SRC = 'path-to-src'
for fname in os.listdir(SRC):
filename, file_extension = os.path.splitext(fname)
if file_extension not in ['xml', 'txt']:
continue
folder_path = os.path.join(SRC, filename)
if not os.path.exists(folder_path):
os.mkdir(folderpath)
os.rename(
os.path.join(SRC, fname),
os.path.join(folder_path, fname)
)

My approach would be:
Find the pairs that I want to move (do nothing with files without a pair)
Create a directory for every pair
Move the pair to the directory
#! /usr/bin/env python
# -*- coding: utf-8 -*-
import os, shutil
import re
def getPairs(files):
pairs = []
file_re = re.compile(r'^(.*)\.(.*)$')
for f in files:
match = file_re.match(f)
if match:
(name, ext) = match.groups()
if ext == 'txt' and name + '.xml' in files:
pairs.append(name)
return pairs
def movePairsToDir(pairs):
for name in pairs:
os.mkdir(name)
shutil.move(name+'.txt', name)
shutil.move(name+'.xml', name)
files = os.listdir()
pairs = getPairs(files)
movePairsToDir(pairs)
NOTE: This script works when called inside the directory with the pairs.

How do i copy files with shutil in python

im trying to copy a .txt file from one dest to another. This code is running but the file isnt copying. What am i doing wrong?
import shutil
import os
src = "/c:/users/mick/temp"
src2 = "c:/users/mick"
dst = "/c:/users/mick/newfolder1/"
for files in src and src2:
if files.endswith(".txt"):
shutil.copy(files, dst)

Your for loop isn't actually searching through the files of each of your sources. In addition your for loop isn't looping through each of the sources but rather the letters in src and src2 that are present in both. This adjustment should handle what you need.
import os
src = ["c:/users/mick/temp", "c:/users/mick"]
dst = "c:/users/mick/newfolder1/"
for source in src:
for src_file in os.listdir(source):
if src_file.endswith(".txt"):
old_path = os.path.join(source, src_file)
new_path = os.path.join(dst, src_file)
os.rename(old_path, new_path)
You shouldn't need shutil for this situation as it is simply a more powerful os.rename that attempts to handle different scenarios a little better (to my knowledge). However if "newfolder1" isn't already existant than you will want to replace os.rename() with os.renames() as this attempts to create the directories inbetween.

shutils is useful for copying, but to move a file use
os.rename(oldpath, newpath)

I know the question is little older. But Here are the simple way to achieve your task. You may change the file extension as you wish. For copying you may use copy() & for moving yo may change it to move(). Hope this helps.
#To import the modules
import os
import shutil
#File path list atleast source & destination folders must be present not everything.
#*******************************WARNING**********************************************
#Make sure these folders names are already created while using the 'move() / copy()'*
#************************************************************************************
filePath1 = 'C:\\Users\\manimani\\Downloads' #Downloads folder
filePath2 = 'F:\\Projects\\Python\\Examples1' #Downloads folder
filePath3 = 'C:\\Users\\manimani\\python' #Python program files folder
filePath4 = 'F:\\Backup' #Backup folder
filePath5 = 'F:\\PDF_Downloads' #PDF files folder
filePath6 = 'C:\\Users\\manimani\\Videos' #Videos folder
filePath7 = 'F:\\WordFile_Downloads' #WordFiles folder
filePath8 = 'F:\\ExeFiles_Downloads' #ExeFiles folder
filePath9 = 'F:\\Image_Downloads' #JPEG_Files folder
#To change the directory from where the files to look // ***Source Directory***
os.chdir(filePath8)
#To get the list of files in the specific source directory
myFiles = os.listdir()
#To move all the '.docx' files to a different location // ***Destination Directory***
for filename in myFiles:
if filename.endswith('.docx'):
print('Moving the file : ' + filename)
shutil.move(filename, filePath4) #Destination directory name
print('All the files are moved as directed. Thanks')

import os, shutil
src1 = "c:/users/mick/temp/"
src2 = "c:/users/mick/"
dist = "c:/users/mick/newfolder"
if not os.path.isdir(dist) : os.mkdir(dist)
for src in [src1, src2] :
for f in os.listdir(src) :
if f.endswith(".txt") :
#print(src) # For testing purposes
shutil.copy(src, dist)
os.remove(src)
I think the error was that you were trying to copy a directory as a file, but you forgot to go through the files in the directory. You were just doing shutil.copy("c:/users/mick/temp/", c:/users/mick/newfolder/").