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beautifulsoup python doesnt find what i am looking for

So i am trying to extract the text in the grand-final section (the winner team name)
https://i.stack.imgur.com/4QPqI.png
my problem is that the text that im looking to extract isnt found by soup, it only finds up to (class="sgg2h1cC DEPRECATED_bootstrap_container undefined native-scroll dragscroll") but as you can see here:
https://i.imgur.com/Brmv6ba.png there is more.
here is my code, can someone explain how i would get the info im looking for? also im pretty new to webscraping
from bs4 import BeautifulSoup
URL = 'https://smash.gg/tournament/revolve-oceania-2v2-finale/event/revolve-oceania-2v2-finale-event/brackets/841267/1343704'
page = requests.get(URL)
soup = BeautifulSoup(page.content, 'html.parser')
results = soup.find(id="app_feature_canvas")
a = results.find_all('div', class_="regionWrapper-APP_TOURNAMENT_PAGE-FeatureCanvas")
print()
for b in a:
c = b.find('div', class_="page-section page-section-grey")
print(c)

What you see in your inspector is not the same as what you get when you use requests. Instead of using the dev console, view the page source.
Those parts of the page are generated by JavaScript, thus, will not appear when you request the page via requests.
URL = 'https://smash.gg/tournament/revolve-oceania-2v2-finale/event/revolve-oceania-2v2-finale-event/brackets/841267/1343704'
page = requests.get(URL)
print(page.text) # notice this is nothing like what you see in the inspector
To get javascript execution, consider using selenium instead of requests.
from selenium import webdriver
driver = webdriver.Chrome()
driver.get(URL)
html = driver.page_source # DOM with JavaScript execution complete
soup = BeautifulSoup(html)
# ... go from here
Alternatively, there may be enough information in the page source to get what you're looking for. Notice there's a lot of JSON in the page source with various info that, presumably, may be used by the JS to populate those elements.
Alternatively still, you can also copy/paste from the DOM browser in your inspector. (right-click the html element and click "copy outer html")
html = pyperclip.paste() # put contents of the clipboard into a variable
soup = BeautifulSoup(html)
results = soup.find(id="app_feature_canvas")
a = results.find_all('div', class_="regionWrapper-APP_TOURNAMENT_PAGE-FeatureCanvas")
print()
for b in a:
c = b.find('div', class_="page-section page-section-grey")
print(c)
And this works :-)

Using Python to receive specific URLs from a webpage (Multireddit lists)

I'm trying to run some statistical analysis on topic-based multireddits. Rather than collecting each individual subreddit by hand, I have found websites that collect these subreddits (Example, Example 2).
These sites unfortunately do not have the ability to download the list of subreddits into plaintext that can be used in a dictionary. Is there a specific method I could use to scrape these sites to only receive back the URL of each attached hyperlink on the webpage?
Thanks!
Edit: Here's my current code
Here's my current code, which runs, but returns every URL.
import requests
from bs4 import BeautifulSoup
import pandas as pd
url = "https://snoopsnoo.com/subreddits/travel/"
page = requests.get(url)
data = page.text
soup = BeautifulSoup(data)
links = []
for link in soup.find_all('a'):
reddit = link.get('href')
links.append(reddit)
df = pd.DataFrame(links, columns=['string_values'])
df.to_csv('travel.csv')

Yes there is such a method. If you are using Python, a widely used library is Beautifulsoup. This library parses the HTML directly, so no webdriver is necessary or running a webbrowser in the background like with selenium. You can install it with: pip install bs4.
For your first example site:
import urllib
from bs4 import BeautifulSoup
# Load the url
url = "https://snoopsnoo.com/subreddits/travel/"
html = urllib.request.urlopen(url).read()
# Create the parser object
soup = BeautifulSoup(html)
# Find all panel headings
panels = soup.find_all(class_="panel-heading big")
# Find the <a>-elements and exctract the link
links = [elem.find('a')['href'] for elem in panels]
print(links)
Here I checked the contents of the page to locate the panel elements by class and then extracted the <a>-elements and its href-attribute.

This code will grab all of the titles.
from selenium import webdriver
firefox_options = webdriver.FirefoxOptions()
#firefox_options.add_argument('--headless')
driver = webdriver.Firefox(executable_path='geckodriver.exe', firefox_options=firefox_options)
driver.get("https://snoopsnoo.com/subreddits/travel/")
for i in range(3):
wds = driver.find_elements_by_class_name('title')
for wd in wds:
print(wd.text)
driver.find_element_by_xpath('/html/body/div/div[2]/div[1]/ul/li/a').click
print('next page')
driver.close()
Change 3 to how many pages you want in for i in range(3): Uncomment firefox_options.add_argument('--headless') to use headless mode

Scraping with Python. Can't get wanted data

I am trying to scrape website, but I encountered a problem. When I try to scrape data, it looks like the html differs from what I see on google inspect and from what I get from python. I get this with http://edition.cnn.com/election/results/states/arizona/house/01 I tried to scrape election results. I used this script to check HTML part of the webpage, and I noticed that they different. There is no classes that I need, like section-wrapper.
page =requests.get('http://edition.cnn.com/election/results/states/arizona/house/01')
soup = BeautifulSoup(page.content, "lxml")
print(soup)
Anyone knows what is the problem ?

http://data.cnn.com/ELECTION/2016/AZ/county/H_d1_county.json
This site use JavaScript fetch data, you can check the url above.
You can find this url in chrome dev-tools, there are many links, check it out
Chrome >>F12>> network tab>>F5(refresh page)>>double click the .josn url>> open new tab

import requests
from bs4 import BeautifulSoup
page=requests.get('http://edition.cnn.com/election/results/states/arizona/house/01')
soup = BeautifulSoup(page.content)
#you can try all sorts of tags here I used class: "ad" and class:"ec-placeholder"
g_data = soup.find_all("div", {"class":"ec-placeholder"})
h_data = soup.find_all("div"),{"class":"ad"}
for item in g_data:print item
#print '\n'
#for item in h_data:print item

Scraping all links using Python BeautifulSoup/lxml

http://www.snapdeal.com/
I was trying to scrape all links from this site and when I do, I get an unexpected result. I figured out that this is happening because of javascript.
under "See All categories" Tab you will find all major product categories. If you hover the mouse over any category it will expand the categories. I want those links from each major categories.
url = 'http://www.snapdeal.com/'
data = urllib2.urlopen(url)
page = BeautifulSoup(data)
#print data
for link in page.findAll('a'):
l = link.get('href')
print l
But, this gave me a different result than what I expected (I turned off javascript and looked at the page source and output was from this source)
I just want to finds all sub links from each major category. any suggestions will be appreciated.

This is happening just because you are letting BeautifulSoup chose its own best parser , and you might not have installed lxml .
The best option is to use html.parser to parse the url .
from bs4 import BeautifulSoup
import urllib2
url = 'http://www.snapdeal.com/'
data = urllib2.urlopen(url).read()
page = BeautifulSoup(data,'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print l
This worked for me .Make sure to install dependencies .

I thinks you should try another library such as selenium , it provide a web driver for you and this is the advantage of this library ,for my self I couldn't handle javascripts with bs4.

Categories Menu is the url you are looking for. Many websites generate the content dynamically using XHR(XMLHTTPRequest).
In order to examine the components of a website get familiar with Firebug add-on in Firefox or Developer Tools(inbuilt addon) in Chrome. You can check the XHR used in website under the network tab in aforementioned add-ons.

Use a web scraping tool such as scrapy or mechanize
In mechanize, to get all the links in the snapdeal homepage,
br=Browser()
br.open("http://www.snapdeal.com")
for link in browser.links():
print link.name
print link.url

I have been looking into a way to scrape links from webpages that are only rendered in an actual browser but wanted the results to be run using a headless browser.
I was able to achieve this using phantomJS, selenium and beautiful soup
#!/usr/bin/python
import bs4
import requests
from selenium import webdriver
driver = webdriver.PhantomJS('phantomjs')
url = 'http://www.snapdeal.com/'
browser = driver.get(url)
content = driver.page_source
soup = bs4.BeautifulSoup(content)
links = [a.attrs.get('href') for a in soup.find_all('a')]
for paths in links:
print paths
driver.close()

The following examples will work for both HTTP and HTTPS. I'm writing this answer to show how this can be used in both Python 2 and Python 3.
Python 2
This is inspired by this answer.
from bs4 import BeautifulSoup
import urllib2
url = 'https://stackoverflow.com'
data = urllib2.urlopen(url).read()
page = BeautifulSoup(data,'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print l
Python 3
from bs4 import BeautifulSoup
from urllib.request import urlopen
import ssl
# to open up HTTPS URLs
gcontext = ssl.SSLContext()
# You can give any URL here. I have given the Stack Overflow homepage
url = 'https://stackoverflow.com'
data = urlopen(url, context=gcontext).read()
page = BeautifulSoup(data, 'html.parser')
for link in page.findAll('a'):
l = link.get('href')
print(l)
Other Languages
For other languages, please see this answer.

Getting Different Results For Web Scraping

I was trying to do web scraping and was using the following code :
import mechanize
from bs4 import BeautifulSoup
url = "http://www.thehindu.com/archive/web/2010/06/19/"
br = mechanize.Browser()
htmltext = br.open(url).read()
link_dictionary = {}
soup = BeautifulSoup(htmltext)
for tag_li in soup.findAll('li', attrs={"data-section":"Chennai"}):
for link in tag_li.findAll('a'):
link_dictionary[link.string] = link.get('href')
print link_dictionary[link.string]
urlnew = link_dictionary[link.string]
brnew = mechanize.Browser()
htmltextnew = brnew.open(urlnew).read()
articletext = ""
soupnew = BeautifulSoup(htmltextnew)
for tag in soupnew.findAll('p'):
articletext += tag.text
print articletext
I was unable to get any printed values by using this. But on using attrs={"data-section":"Business"} instead of attrs={"data-section":"Chennai"} I was able to get the desired output. Can someone help me?

READ THE TERMS OF SERVICES OF THE WEBSITE BEFORE SCRAPING
If you are using firebug or inspect element in Chrome, you might see some contents that will not be seen if you are using Mechanize or Urllib2.
For example, when you view the source code of the page sent out by you. (Right click view source in Chrome). and search for data-section tag, you won't see any tags which chennai, I am not 100% sure but I will say those contents need to be populated by Javascript ..etc. which requires the functionality of a browser.
If I were you, I will use selenium to open up the page and then get the source page from there, then the HTML collected in that way will be more like what you see in a browser.
Cited here
from selenium import webdriver
from bs4 import BeautifulSoup
import time
driver = webdriver.Firefox()
driver.get("URL GOES HERE")
# I noticed there is an ad here, sleep til page fully loaded.
time.sleep(10)
soup = BeautifulSoup(driver.page_source)
print len(soup.findAll(...}))
# or you can work directly in selenium
...
driver.close()
And the output for me is 8