Accessing class methods inside another class at same scope - python

Trying to get a work around for getting access to a class method in another class while being inside a class. Code below will probably explain my goal.
class Access(object):
def __init__(self):
pass
def select(self, value):
Store.keep(value)
class Store(object):
def __init__(self):
self.store_value = 0
def keep(self, value):
self.store_value = value
x = Access()
y = Store()
x.select(10)
y.store_value
##Want the output of 10

I don't see any way to do what you want without Access having a reference to a Store object.
The closest thing you can do is
class Access(object):
def __init__(self):
pass
def select(self, value):
Store.keep(value)
class Store(object):
#classmethod
def keep(cls, value):
cls.store_value = value
x = Access()
y = Store()
x.select(10)
print y.store_value #will print 10
#but
z = Store()
print z.store_value #will print 10 too
Where store_value is shared by all instances of Store.

You could pass an instance to select also and use Store.keep(inst, value):
class Access(object):
def __init__(self):
pass
def select(self, inst, value):
Store.keep(inst, value)
class Store(object):
def __init__(self):
self.store_value = 0
def keep(self, value):
self.store_value = value
x = Access()
y = Store()
x.select(y, 10)
print(y.store_value)
10

Related

How do I pass the same variable(iterable) between instances of different classes(that inherits from the same parent)

I want to pass a variable(iterable )between instances of different classes. I have a structure similar with the one below.
Each class has its own module(so no globals) and needs to work in python 3 and 2.
class O:
pass
class A(O):
pass
class B(O):
def __init__(self, cache):
self.cache = cache
class B1(B):
def p(self):
self.cache.add_to_cache("32", "something something")
class B2(B):
def p(self):
self.cache.get_from_cache("52", "something else")
For B and its sub-classes I want to create a cache. All instances of this classes(B, B1, B2) to use the same cache.
To keep it simple, let's say that the cache is just a dict.
c = {}
a = A(c)
b1 = B() - needs c
b1.p()
b2 = C() - needs c
b2.p()
print(cache)
Off course the example above, is wrong because the cache is different for each instance.
The chache should be :
{
"32", "something something"
"52": "something else"
}
Another approach to this is using CacheService as an injectable Singleton service, which I consider a better practice.
Read this first for a code/syntax solution to your direct question, or continue reading for a solution with better design.
class O(object):
pass
class CacheService(object):
__instances = {}
#staticmethod
def getinstance(owner_id):
if owner_id not in CacheService.__instances:
CacheService.__instances[owner_id] = CacheService(owner_id)
return CacheService.__instances[owner_id]
def __init__(self, owner_id):
self._owner_id = owner_id
self._owner_query = CacheService.__name__ + self._owner_id
self._cache = {}
def put_in_cache(self, key, value):
self._cache[self._owner_query + str(key)] = value
def get_from_cache(self, key):
return self._cache.get(self._owner_query + str(key), "the_default")
class B(O):
def __init__(self):
self._cache = CacheService.getinstance(B.__name__)
class B1(B):
def __init__(self):
super(B1, self).__init__()
def p(self):
val1 = self._cache.get_from_cache("a")
print(val1)
class B2(B):
def __init__(self):
super(B2, self).__init__()
def p(self):
self._cache.put_in_cache("a", 2)
if __name__ == "__main__":
b1 = B1()
b2 = B2()
b2.p()
b1.p()
out:
2
This still uses a class variable, but hides it from your "everyday code", and moves it to the "infrastructure level".
I see this as cleaner, as now your class hierarchy shouldn't handle its own global variables.
To directly answer the programming question, Use class variables.
As a side note, it would be much better to use some kind of "CacheService" and inject that to the constructor, rather than use inheritance and class variables.
For this, see my other answer.
Code for using class variables follows:
class O(object):
pass
class B(O):
__cache = {} # use your cache class if you want, I am using dict just for show
def __init__(self):
pass
def _get_from_cache(self, key):
return self._cache.get(key, "default1")
def _put_in_cache(self, key, value):
self._cache[key] = value
class B1(B):
def __init__(self):
super(B1, self).__init__()
def p(self):
val1 = self._get_from_cache("a")
print(val1)
class B2(B):
def __init__(self):
super(B2, self).__init__()
def p(self):
self._put_in_cache("a", 2)
if __name__ == "__main__":
b1 = B1()
b2 = B2()
b2.p()
b1.p()
out:
2
Notice _get_from_cache and _put_in_cache are methods, but they can be #staticmethods, as they only ever access class variables, and their self isn't "really" ever being used. __cache could theoretically be accessed directly by children, but the _get_from_cache and _put_in_cache makes __cache private, and gives a protected API to it.

Can we pass the class object inside its own method?

I have a class A object method which uses another class B object's method, which the argument is class A object.
class A():
def calculate(self):
B = B.calculator(A)
class B():
def calculator(self, A):
...do something with A.attributes
It is possible to just pass attributes into the object, but I would see this possibility as the last priority. I am definitely a bit oversimplify my case, but I am wondering if there is a way to pass the entire class
Edit:
Sorry for the confusion. At the end I am trying to call class A object and A.calculate(), which will call class B obj and calculator function.
class A():
def __init__(self, value):
self.value = value
def calculate(self):
Bobj = B()
Bobj.calculator(A)
class B():
def calculator(self, A):
...do something with A.value
def main():
Aobj = A(value)
Aobj.calculate()
Your scenario does not currently indicate that you want to use any information from B when calculating A. There are a few ways of getting the functionality that you want.
Scenario: B stores no information and performs calculation. B should be a function
def B(value):
```do something with value```
return
class A():
def __init__(self, value):
self.value = value
def calculate(self):
return B(self.value)
def main():
Aobj = A(value)
Aobj.calculate()
Scenario: B stores some other information, but internal B information is not needed for the calculation. B should have a static method
class B():
#staticmethod
def calculate(value):
```do something with value```
return
class A():
def __init__(self, value):
self.value = value
def calculate(self):
return B.calculate(self.value)
def main():
Aobj = A(value)
Aobj.calculate()

How to pass value from class to class - Python

I am trying to pass a value from one function in a class to another function in a class. Below is some simplified code of what I'm trying to achieve.
class test:
def __init__(self):
self.differentvalue = 0
def set(self, value):
print(value)
self.differentvalue = value #this is not the same value as defined above - i.e. this is a new variable created in foo class i believe
class foo:
def __init__(self):
test.set(self, 5)
if __name__ == '__main__':
foo()
I do not want __init__ to be called so test().set(5) is not an option.
Cheers,
Sean
You have two options
Option #1, best option if you need to keep a different context for differtvalue for each instance of Test
class Test:
def __init__(self):
self.differentvalue = 0
def set(self, value):
self.differentvalue = value
class foo:
def __init__(self):
test = Test()
test.set(5)
Option #2, best if you need to keep the latest value for differentvalue across all Test classes
class Test:
__DIFFERENTVALUE = 0
def __init__(self):
pass
#staticmethod
def set(value):
Test.__DIFFERENTVALUE = value
class foo:
def __init__(self):
Test.set(5)
You could define a class variable with a value of None, then upon calling the setter for the first time, assign a value to it. Further calls to the setter will not change the value.
In the following example, an __init__ method is not required in Test.
class Test:
differentvalue = None
#classmethod
def set(cls, value):
if value is not None and Test.differentvalue is None:
Test.differentvalue = value
class foo:
def __init__(self):
Test.set(5)
if __name__ == '__main__':
foo()
print(Test.differentvalue)
Test.set(12)
print(Test.differentvalue)
output:
5
5 # the value did not change

Is there a way to have #property "getter/setter" less heavy in python?

I have a simple class (Node) that has an ID and 3 coordinates (X,Y,Z). Its ID must be an integer and its coordinates floats, therefore I have used the following class definition.
I'm new to OO programming, but it seems "heavy" for such a simple class. Is there any way to compact that and make it less repetitive? For instance if I had 10 coordinates this would be a bit heavy.
Anyway it works I'm just wondering if there's a better way to do that.
class Node():
def __init__(self):
self.ID = 0
self.X = 0
self.Y = 0
self.Z = 0
#property
def ID(self):
return self._ID
#ID.setter
def ID(self,value):
self._ID = int(value)
#property
def X(self):
return self._X
#X.setter
def X(self,value):
self._X = float(value)
#property
def Y(self):
return self._Y
#Y.setter
def Y(self,value):
self._Y = float(value)
#property
def Z(self):
return self._Z
#Z.setter
def Z(self,value):
self._Z = float(value)
In Python, if you want to provide read and write access to attributes, you simply make them "public".
Like so:
class Node():
def __init__(self):
self.ID = 0 # No underscores
self.X = 0 # means
self.Y = 0 # public
self.Z = 0 # (by convention)
Now you can use your class like this:
n = Node()
n.Z = 9
This is perfectly fine, because you can still decide later on to adjust the behavior of the read and write operations (using the #property decorator), without braking the interface of your class.
You might also want to look into dataclasses (introducted in Python 3.7):
from dataclasses import dataclass
#dataclass
class Node:
ID = 0
X = 0
Y = 0
Z: float = 0 # type hints are optional
A final note: class attributes are lowercase by convention. Only constants should be written with full uppercase letters.
What you want is a custom descriptor, not property itself.
class Force(object):
def __init__(self, type_, var):
self.type = type_
self.var = "_" + var
def __get__(self, obj, type):
# obj is None when the descriptor is accessed via
# the class, rather than an instance.
# type is the class through which the descriptor is accessed;
# not used here.
if obj is None:
return self
return getattr(obj, self.var)
def __set__(self, obj, value):
setattr(obj, self.var, self.type(value))
class Node:
ID = Force(int, 'ID')
X = Force(float, 'X')
Y = Force(float, 'Y')
Z = Force(float, 'Z')
def __init__(self):
self.ID = 0
self.X = 0
self.Y = 0
self.Z = 0
Python 3.6 added support for a __set_name__ method which is called automatically when the descriptor is instantiated, receiving the name the descriptor is assigned to as an argument.
class Force:
def __init__(self, type_):
self.type = type_
def __set_name__(self, owner, name):
# Owner is the class which contains the descriptor;
# not used here
self.var = "_" + name
def __get__(self, obj, type):
if obj is None:
return self
return getattr(obj, self.var)
def __set__(self, obj, value):
setattr(obj, self.var, self.type(value))
class Node:
ID = Force(int)
X = Force(float)
Y = Force(float)
Z = Force(float)
def __init__(self):
self.ID = 0
self.X = 0
self.Y = 0
self.Z = 0
(I'm certain this can be improved. Force.__init__ could take an initial value for each instance of the descriptor, instead of requiring Node.__init__ to initialize each.)

Python Class Objects Attribute Referencing

I have two classes. a and b.
In one of class a's methods, I created an object of class b. One of class b attributes takes a function. So say I gave it a random function but does this function of class b have access to class a's attribute? even though I didn't pass it in directly as a parameter?
class b:
def __init__(self):
self.attribute_function = None
class a:
def __init__(self):
self.temp = 10
self.counter = 0
def temp(self):
obj = b()
obj.attribute_function = lambda self: self.counter < self.temp
return obj.attribute_function()
if __name__ == "__main__":
#pass
obj = a()
print obj.temp()
In the above example, I tried to provide a really basic example, but if you run it, it doesn't work...
Revised Code, class a should look like this:
class a:
def __init__(self):
self.temp = 10
self.counter = 0
def temp(self):
obj = b()
obj.attribute_function = lambda args: self.counter < self.temp
return obj.attribute_function(1) # i added this 1 to fill in arg
This works:
class b:
def __init__(self):
self.attribute_function = None
class a:
def __init__(self):
self._temp = 10
self.counter = 0
def temp(self):
obj = b()
obj.attribute_function = lambda self=self: self.counter < self._temp
return obj.attribute_function()
if __name__ == "__main__":
obj = a()
print obj.temp()
On problem you had is self.temp = 10 which shadowed your method temp().
Another problem: lambda self: self.counter < self._temp. Your lambda function was expecting an argument. But omitting self is not a good idea lambda : self.counter < self._temp, because if you call obj.attribute_function() somewhere where self is not available or has changed - it will not find self or use another self. self=self fixes that.
But generally such magic is an anti-pattern. Tell us what are your trying to achieve, and there should be a better way to do what you want. Otherwise this kind of code will ensure many headaches.
I think this is a better solution (called strategy pattern):
class B:
def __init__(self, a):
self.a = a
def temp(self):
return self.a.temp()
class A:
def __init__(self):
self._temp = 10
self.counter = 0
def temp(self):
return self.counter < self._temp
if __name__ == "__main__":
obj = B(A())
print obj.temp()
Your example does not work because you have a name collision at temp
You have assigned temp to be both a method:
def temp(self):
and an attribute:
self.temp = 10

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