I was messing around just trying to make a script that deletes items by ".zip" extension.
import sys
import os
from os import listdir
test=os.listdir("/Users/ben/downloads/")
for item in test:
if item.endswith(".zip"):
os.remove(item)
Whenever I run the script I get:
OSError: [Errno 2] No such file or directory: 'cities1000.zip'
cities1000.zip is obviously a file in my downloads folder.
What did I do wrong here? Is the issue that os.remove requires the full path to the file? If this is the issue, than how can I do that in this current script without completely rewriting it.
You can set the path in to a dir_name variable, then use os.path.join for your os.remove.
import os
dir_name = "/Users/ben/downloads/"
test = os.listdir(dir_name)
for item in test:
if item.endswith(".zip"):
os.remove(os.path.join(dir_name, item))
For this operation you need to append the file name on to the file path so the command knows what folder you are looking into.
You can do this correctly and in a portable way in python using the os.path.join command.
For example:
import os
directory = "/Users/ben/downloads/"
test = os.listdir( directory )
for item in test:
if item.endswith(".zip"):
os.remove( os.path.join( directory, item ) )
Alternate approach that avoids join-ing yourself over and over: Use glob module to join once, then let it give you back the paths directly.
import glob
import os
dir = "/Users/ben/downloads/"
for zippath in glob.iglob(os.path.join(dir, '*.zip')):
os.remove(zippath)
I think you could use Pathlib-- a modern way, like the following:
import pathlib
dir = pathlib.Path("/Users/ben/downloads/")
zip_files = dir.glob(dir / "*.zip")
for zf in zip_files:
zf.unlink()
If you want to delete all zip files recursively, just write so:
import pathlib
dir = pathlib.Path("/Users/ben/downloads/")
zip_files = dir.rglob(dir / "*.zip") # recursively
for zf in zip_files:
zf.unlink()
Just leaving my two cents on this issue: if you want to be chic you can use glob or iglob from the glob package, like so:
import glob
import os
files_in_dir = glob.glob('/Users/ben/downloads/*.zip')
# or if you want to be fancy, you can use iglob, which returns an iterator:
files_in_dir = glob.iglob('/Users/ben/downloads/*.zip')
for _file in files_in_dir:
print(_file) # just to be sure, you know how it is...
os.remove(_file)
origfolder = "/Users/ben/downloads/"
test = os.listdir(origfolder)
for item in test:
if item.endswith(".zip"):
os.remove(os.path.join(origfolder, item))
The dirname is not included in the os.listdir output. You have to attach it to reference the file from the list returned by said function.
Prepend the directory to the filename
os.remove("/Users/ben/downloads/" + item)
EDIT: or change the current working directory using os.chdir.
Related
How can I delete the contents of a local folder in Python?
The current project is for Windows, but I would like to see *nix also.
import os, shutil
folder = '/path/to/folder'
for filename in os.listdir(folder):
file_path = os.path.join(folder, filename)
try:
if os.path.isfile(file_path) or os.path.islink(file_path):
os.unlink(file_path)
elif os.path.isdir(file_path):
shutil.rmtree(file_path)
except Exception as e:
print('Failed to delete %s. Reason: %s' % (file_path, e))
You can simply do this:
import os
import glob
files = glob.glob('/YOUR/PATH/*')
for f in files:
os.remove(f)
You can of course use an other filter in you path, for example : /YOU/PATH/*.txt for removing all text files in a directory.
You can delete the folder itself, as well as all its contents, using shutil.rmtree:
import shutil
shutil.rmtree('/path/to/folder')
shutil.rmtree(path, ignore_errors=False, onerror=None)
Delete an entire directory tree; path must point to a directory (but not a symbolic link to a directory). If ignore_errors is true, errors resulting from failed removals will be ignored; if false or omitted, such errors are handled by calling a handler specified by onerror or, if that is omitted, they raise an exception.
Expanding on mhawke's answer this is what I've implemented. It removes all the content of a folder but not the folder itself. Tested on Linux with files, folders and symbolic links, should work on Windows as well.
import os
import shutil
for root, dirs, files in os.walk('/path/to/folder'):
for f in files:
os.unlink(os.path.join(root, f))
for d in dirs:
shutil.rmtree(os.path.join(root, d))
I'm surprised nobody has mentioned the awesome pathlib to do this job.
If you only want to remove files in a directory it can be a oneliner
from pathlib import Path
[f.unlink() for f in Path("/path/to/folder").glob("*") if f.is_file()]
To also recursively remove directories you can write something like this:
from pathlib import Path
from shutil import rmtree
for path in Path("/path/to/folder").glob("**/*"):
if path.is_file():
path.unlink()
elif path.is_dir():
rmtree(path)
Using rmtree and recreating the folder could work, but I have run into errors when deleting and immediately recreating folders on network drives.
The proposed solution using walk does not work as it uses rmtree to remove folders and then may attempt to use os.unlink on the files that were previously in those folders. This causes an error.
The posted glob solution will also attempt to delete non-empty folders, causing errors.
I suggest you use:
folder_path = '/path/to/folder'
for file_object in os.listdir(folder_path):
file_object_path = os.path.join(folder_path, file_object)
if os.path.isfile(file_object_path) or os.path.islink(file_object_path):
os.unlink(file_object_path)
else:
shutil.rmtree(file_object_path)
This:
removes all symbolic links
dead links
links to directories
links to files
removes subdirectories
does not remove the parent directory
Code:
for filename in os.listdir(dirpath):
filepath = os.path.join(dirpath, filename)
try:
shutil.rmtree(filepath)
except OSError:
os.remove(filepath)
As many other answers, this does not try to adjust permissions to enable removal of files/directories.
Using os.scandir and context manager protocol in Python 3.6+:
import os
import shutil
with os.scandir(target_dir) as entries:
for entry in entries:
if entry.is_dir() and not entry.is_symlink():
shutil.rmtree(entry.path)
else:
os.remove(entry.path)
Earlier versions of Python:
import os
import shutil
# Gather directory contents
contents = [os.path.join(target_dir, i) for i in os.listdir(target_dir)]
# Iterate and remove each item in the appropriate manner
[shutil.rmtree(i) if os.path.isdir(i) and not os.path.islink(i) else os.remove(i) for i in contents]
Notes: in case someone down voted my answer, I have something to explain here.
Everyone likes short 'n' simple answers. However, sometimes the reality is not so simple.
Back to my answer. I know shutil.rmtree() could be used to delete a directory tree. I've used it many times in my own projects. But you must realize that the directory itself will also be deleted by shutil.rmtree(). While this might be acceptable for some, it's not a valid answer for deleting the contents of a folder (without side effects).
I'll show you an example of the side effects. Suppose that you have a directory with customized owner and mode bits, where there are a lot of contents. Then you delete it with shutil.rmtree() and rebuild it with os.mkdir(). And you'll get an empty directory with default (inherited) owner and mode bits instead. While you might have the privilege to delete the contents and even the directory, you might not be able to set back the original owner and mode bits on the directory (e.g. you're not a superuser).
Finally, be patient and read the code. It's long and ugly (in sight), but proven to be reliable and efficient (in use).
Here's a long and ugly, but reliable and efficient solution.
It resolves a few problems which are not addressed by the other answerers:
It correctly handles symbolic links, including not calling shutil.rmtree() on a symbolic link (which will pass the os.path.isdir() test if it links to a directory; even the result of os.walk() contains symbolic linked directories as well).
It handles read-only files nicely.
Here's the code (the only useful function is clear_dir()):
import os
import stat
import shutil
# http://stackoverflow.com/questions/1889597/deleting-directory-in-python
def _remove_readonly(fn, path_, excinfo):
# Handle read-only files and directories
if fn is os.rmdir:
os.chmod(path_, stat.S_IWRITE)
os.rmdir(path_)
elif fn is os.remove:
os.lchmod(path_, stat.S_IWRITE)
os.remove(path_)
def force_remove_file_or_symlink(path_):
try:
os.remove(path_)
except OSError:
os.lchmod(path_, stat.S_IWRITE)
os.remove(path_)
# Code from shutil.rmtree()
def is_regular_dir(path_):
try:
mode = os.lstat(path_).st_mode
except os.error:
mode = 0
return stat.S_ISDIR(mode)
def clear_dir(path_):
if is_regular_dir(path_):
# Given path is a directory, clear its content
for name in os.listdir(path_):
fullpath = os.path.join(path_, name)
if is_regular_dir(fullpath):
shutil.rmtree(fullpath, onerror=_remove_readonly)
else:
force_remove_file_or_symlink(fullpath)
else:
# Given path is a file or a symlink.
# Raise an exception here to avoid accidentally clearing the content
# of a symbolic linked directory.
raise OSError("Cannot call clear_dir() on a symbolic link")
As a oneliner:
import os
# Python 2.7
map( os.unlink, (os.path.join( mydir,f) for f in os.listdir(mydir)) )
# Python 3+
list( map( os.unlink, (os.path.join( mydir,f) for f in os.listdir(mydir)) ) )
A more robust solution accounting for files and directories as well would be (2.7):
def rm(f):
if os.path.isdir(f): return os.rmdir(f)
if os.path.isfile(f): return os.unlink(f)
raise TypeError, 'must be either file or directory'
map( rm, (os.path.join( mydir,f) for f in os.listdir(mydir)) )
I used to solve the problem this way:
import shutil
import os
shutil.rmtree(dirpath)
os.mkdir(dirpath)
To delete all files inside a folder a I use:
import os
for i in os.listdir():
os.remove(i)
To delete all the files inside the directory as well as its sub-directories, without removing the folders themselves, simply do this:
import os
mypath = "my_folder" #Enter your path here
for root, dirs, files in os.walk(mypath, topdown=False):
for file in files:
os.remove(os.path.join(root, file))
# Add this block to remove folders
for dir in dirs:
os.rmdir(os.path.join(root, dir))
# Add this line to remove the root folder at the end
os.rmdir(mypath)
You might be better off using os.walk() for this.
os.listdir() doesn't distinguish files from directories and you will quickly get into trouble trying to unlink these. There is a good example of using os.walk() to recursively remove a directory here, and hints on how to adapt it to your circumstances.
If you are using a *nix system, why not leverage the system command?
import os
path = 'folder/to/clean'
os.system('rm -rf %s/*' % path)
I konw it's an old thread but I have found something interesting from the official site of python. Just for sharing another idea for removing of all contents in a directory. Because I have some problems of authorization when using shutil.rmtree() and I don't want to remove the directory and recreate it. The address original is http://docs.python.org/2/library/os.html#os.walk. Hope that could help someone.
def emptydir(top):
if(top == '/' or top == "\\"): return
else:
for root, dirs, files in os.walk(top, topdown=False):
for name in files:
os.remove(os.path.join(root, name))
for name in dirs:
os.rmdir(os.path.join(root, name))
I had to remove files from 3 separate folders inside a single parent directory:
directory
folderA
file1
folderB
file2
folderC
file3
This simple code did the trick for me: (I'm on Unix)
import os
import glob
folders = glob.glob('./path/to/parentdir/*')
for fo in folders:
file = glob.glob(f'{fo}/*')
for f in file:
os.remove(f)
Hope this helps.
Yet Another Solution:
import sh
sh.rm(sh.glob('/path/to/folder/*'))
Well, I think this code is working. It will not delete the folder and you can use this code to delete files having the particular extension.
import os
import glob
files = glob.glob(r'path/*')
for items in files:
os.remove(items)
Pretty intuitive way of doing it:
import shutil, os
def remove_folder_contents(path):
shutil.rmtree(path)
os.makedirs(path)
remove_folder_contents('/path/to/folder')
use this function
import os
import glob
def truncate(path):
files = glob.glob(path+'/*.*')
for f in files:
os.remove(f)
truncate('/my/path')
Use the method bellow to remove the contents of a directory, not the directory itself:
import os
import shutil
def remove_contents(path):
for c in os.listdir(path):
full_path = os.path.join(path, c)
if os.path.isfile(full_path):
os.remove(full_path)
else:
shutil.rmtree(full_path)
Answer for a limited, specific situation:
assuming you want to delete the files while maintainig the subfolders tree, you could use a recursive algorithm:
import os
def recursively_remove_files(f):
if os.path.isfile(f):
os.unlink(f)
elif os.path.isdir(f):
for fi in os.listdir(f):
recursively_remove_files(os.path.join(f, fi))
recursively_remove_files(my_directory)
Maybe slightly off-topic, but I think many would find it useful
I resolved the issue with rmtree makedirs by adding time.sleep() between:
if os.path.isdir(folder_location):
shutil.rmtree(folder_location)
time.sleep(.5)
os.makedirs(folder_location, 0o777)
the easiest way to delete all files in a folder/remove all files
import os
files = os.listdir(yourFilePath)
for f in files:
os.remove(yourFilePath + f)
This should do the trick just using the OS module to list and then remove!
import os
DIR = os.list('Folder')
for i in range(len(DIR)):
os.remove('Folder'+chr(92)+i)
Worked for me, any problems let me know!
I need to iterate through all .asm files inside a given directory and do some actions on them.
How can this be done in a efficient way?
Python 3.6 version of the above answer, using os - assuming that you have the directory path as a str object in a variable called directory_in_str:
import os
directory = os.fsencode(directory_in_str)
for file in os.listdir(directory):
filename = os.fsdecode(file)
if filename.endswith(".asm") or filename.endswith(".py"):
# print(os.path.join(directory, filename))
continue
else:
continue
Or recursively, using pathlib:
from pathlib import Path
pathlist = Path(directory_in_str).glob('**/*.asm')
for path in pathlist:
# because path is object not string
path_in_str = str(path)
# print(path_in_str)
Use rglob to replace glob('**/*.asm') with rglob('*.asm')
This is like calling Path.glob() with '**/' added in front of the given relative pattern:
from pathlib import Path
pathlist = Path(directory_in_str).rglob('*.asm')
for path in pathlist:
# because path is object not string
path_in_str = str(path)
# print(path_in_str)
Original answer:
import os
for filename in os.listdir("/path/to/dir/"):
if filename.endswith(".asm") or filename.endswith(".py"):
# print(os.path.join(directory, filename))
continue
else:
continue
This will iterate over all descendant files, not just the immediate children of the directory:
import os
for subdir, dirs, files in os.walk(rootdir):
for file in files:
#print os.path.join(subdir, file)
filepath = subdir + os.sep + file
if filepath.endswith(".asm"):
print (filepath)
You can try using glob module:
import glob
for filepath in glob.iglob('my_dir/*.asm'):
print(filepath)
and since Python 3.5 you can search subdirectories as well:
glob.glob('**/*.txt', recursive=True) # => ['2.txt', 'sub/3.txt']
From the docs:
The glob module finds all the pathnames matching a specified pattern according to the rules used by the Unix shell, although results are returned in arbitrary order. No tilde expansion is done, but *, ?, and character ranges expressed with [] will be correctly matched.
Since Python 3.5, things are much easier with os.scandir() and 2-20x faster (source):
with os.scandir(path) as it:
for entry in it:
if entry.name.endswith(".asm") and entry.is_file():
print(entry.name, entry.path)
Using scandir() instead of listdir() can significantly increase the
performance of code that also needs file type or file attribute
information, because os.DirEntry objects expose this information if
the operating system provides it when scanning a directory. All
os.DirEntry methods may perform a system call, but is_dir() and
is_file() usually only require a system call for symbolic links;
os.DirEntry.stat() always requires a system call on Unix but only
requires one for symbolic links on Windows.
Python 3.4 and later offer pathlib in the standard library. You could do:
from pathlib import Path
asm_pths = [pth for pth in Path.cwd().iterdir()
if pth.suffix == '.asm']
Or if you don't like list comprehensions:
asm_paths = []
for pth in Path.cwd().iterdir():
if pth.suffix == '.asm':
asm_pths.append(pth)
Path objects can easily be converted to strings.
Here's how I iterate through files in Python:
import os
path = 'the/name/of/your/path'
folder = os.fsencode(path)
filenames = []
for file in os.listdir(folder):
filename = os.fsdecode(file)
if filename.endswith( ('.jpeg', '.png', '.gif') ): # whatever file types you're using...
filenames.append(filename)
filenames.sort() # now you have the filenames and can do something with them
NONE OF THESE TECHNIQUES GUARANTEE ANY ITERATION ORDERING
Yup, super unpredictable. Notice that I sort the filenames, which is important if the order of the files matters, i.e. for video frames or time dependent data collection. Be sure to put indices in your filenames though!
You can use glob for referring the directory and the list :
import glob
import os
#to get the current working directory name
cwd = os.getcwd()
#Load the images from images folder.
for f in glob.glob('images\*.jpg'):
dir_name = get_dir_name(f)
image_file_name = dir_name + '.jpg'
#To print the file name with path (path will be in string)
print (image_file_name)
To get the list of all directory in array you can use os :
os.listdir(directory)
I'm not quite happy with this implementation yet, I wanted to have a custom constructor that does DirectoryIndex._make(next(os.walk(input_path))) such that you can just pass the path you want a file listing for. Edits welcome!
import collections
import os
DirectoryIndex = collections.namedtuple('DirectoryIndex', ['root', 'dirs', 'files'])
for file_name in DirectoryIndex(*next(os.walk('.'))).files:
file_path = os.path.join(path, file_name)
I really like using the scandir directive that is built into the os library. Here is a working example:
import os
i = 0
with os.scandir('/usr/local/bin') as root_dir:
for path in root_dir:
if path.is_file():
i += 1
print(f"Full path is: {path} and just the name is: {path.name}")
print(f"{i} files scanned successfully.")
Get all the .asm files in a directory by doing this.
import os
path = "path_to_file"
file_type = '.asm'
for filename in os.listdir(path=path):
if filename.endswith(file_type):
print(filename)
print(f"{path}/{filename}")
# do something below
I don't understand why some answers are complicated. This is how I would do it with Python 2.7. Replace DIRECTORY_TO_LOOP with the directory you want to use.
import os
DIRECTORY_TO_LOOP = '/var/www/files/'
for root, dirs, files in os.walk(DIRECTORY_TO_LOOP, topdown=False):
for name in files:
print(os.path.join(root, name))
I attended an interview and they asked me to write a script to move from one directory to another and delete only the .html files.
Now I tried to do this at first using os.remove() . Following is the code:
def rm_files():
import os
from os import path
folder='J:\\Test\\'
for files in os.listdir(folder):
file_path=path.join(folder,files)
os.remove(file_path)
The problem I am facing here is that I cannot figure out how to delete only .html files in my directory
Then I tried using glob. Following is the code:
def rm_files1():
import os
import glob
files=glob.glob('J:\\Test\\*.html')
for f in files:
os.remove(f)
Using glob I can delete the .html files but still I cannot figure out how to implement the logic of moving from one directory to another.
And along with that can someone please help me figure out how to delete a specific file type using os.remove() ?
Thank you.
Either of these methods should work. For the first way, you could just string.endswith(suffix) like so:
def rm_files():
import os
from os import path
folder='J:\\Test\\'
for files in os.listdir(folder):
file_path=path.join(folder,files)
if file_path.endswith(".html"):
os.remove(file_path)
Or if you prefer glob, moving directories is fairly straightforward: os.chdir(path) like this:
def rm_files1():
import os
os.chdir('J:\\Test')
import glob
files=glob.glob('J:\\Test\\*.html')
for f in files:
os.remove(f)
Though it seems unnecessary since glob is taking an absolute path anyway.
Your problem can be described in the following steps.
move to specific directory. This can be done using os.chdir()
grab list of all *.html files. Use glob.glob('*.html')
remove the files. use os.remove()
Putting it all together:
import os
import glob
import sys
def remove_html_files(path_name):
# move to desired path, if it exists
if os.path.exists(path_name):
os.chdir(path_name)
else:
print('invalid path')
sys.exit(1)
# grab list of all html files in current directory
file_list = glob.glob('*.html')
#delete files
for f in file_list:
os.remove(f)
#output messaage
print('deleted '+ str(len(file_list))+' files in folder' + path_name)
# call the function
remove_html_files(path_name)
To remove all html files in a directory with os.remove() you can do like this using endswith() function
import sys
import os
from os import listdir
directory = "J:\\Test\\"
test = os.listdir( directory )
for item in test:
if item.endswith(".html"):
os.remove( os.path.join( directory, item ) )
I need to iterate through all .asm files inside a given directory and do some actions on them.
How can this be done in a efficient way?
Python 3.6 version of the above answer, using os - assuming that you have the directory path as a str object in a variable called directory_in_str:
import os
directory = os.fsencode(directory_in_str)
for file in os.listdir(directory):
filename = os.fsdecode(file)
if filename.endswith(".asm") or filename.endswith(".py"):
# print(os.path.join(directory, filename))
continue
else:
continue
Or recursively, using pathlib:
from pathlib import Path
pathlist = Path(directory_in_str).glob('**/*.asm')
for path in pathlist:
# because path is object not string
path_in_str = str(path)
# print(path_in_str)
Use rglob to replace glob('**/*.asm') with rglob('*.asm')
This is like calling Path.glob() with '**/' added in front of the given relative pattern:
from pathlib import Path
pathlist = Path(directory_in_str).rglob('*.asm')
for path in pathlist:
# because path is object not string
path_in_str = str(path)
# print(path_in_str)
Original answer:
import os
for filename in os.listdir("/path/to/dir/"):
if filename.endswith(".asm") or filename.endswith(".py"):
# print(os.path.join(directory, filename))
continue
else:
continue
This will iterate over all descendant files, not just the immediate children of the directory:
import os
for subdir, dirs, files in os.walk(rootdir):
for file in files:
#print os.path.join(subdir, file)
filepath = subdir + os.sep + file
if filepath.endswith(".asm"):
print (filepath)
You can try using glob module:
import glob
for filepath in glob.iglob('my_dir/*.asm'):
print(filepath)
and since Python 3.5 you can search subdirectories as well:
glob.glob('**/*.txt', recursive=True) # => ['2.txt', 'sub/3.txt']
From the docs:
The glob module finds all the pathnames matching a specified pattern according to the rules used by the Unix shell, although results are returned in arbitrary order. No tilde expansion is done, but *, ?, and character ranges expressed with [] will be correctly matched.
Since Python 3.5, things are much easier with os.scandir() and 2-20x faster (source):
with os.scandir(path) as it:
for entry in it:
if entry.name.endswith(".asm") and entry.is_file():
print(entry.name, entry.path)
Using scandir() instead of listdir() can significantly increase the
performance of code that also needs file type or file attribute
information, because os.DirEntry objects expose this information if
the operating system provides it when scanning a directory. All
os.DirEntry methods may perform a system call, but is_dir() and
is_file() usually only require a system call for symbolic links;
os.DirEntry.stat() always requires a system call on Unix but only
requires one for symbolic links on Windows.
Python 3.4 and later offer pathlib in the standard library. You could do:
from pathlib import Path
asm_pths = [pth for pth in Path.cwd().iterdir()
if pth.suffix == '.asm']
Or if you don't like list comprehensions:
asm_paths = []
for pth in Path.cwd().iterdir():
if pth.suffix == '.asm':
asm_pths.append(pth)
Path objects can easily be converted to strings.
Here's how I iterate through files in Python:
import os
path = 'the/name/of/your/path'
folder = os.fsencode(path)
filenames = []
for file in os.listdir(folder):
filename = os.fsdecode(file)
if filename.endswith( ('.jpeg', '.png', '.gif') ): # whatever file types you're using...
filenames.append(filename)
filenames.sort() # now you have the filenames and can do something with them
NONE OF THESE TECHNIQUES GUARANTEE ANY ITERATION ORDERING
Yup, super unpredictable. Notice that I sort the filenames, which is important if the order of the files matters, i.e. for video frames or time dependent data collection. Be sure to put indices in your filenames though!
You can use glob for referring the directory and the list :
import glob
import os
#to get the current working directory name
cwd = os.getcwd()
#Load the images from images folder.
for f in glob.glob('images\*.jpg'):
dir_name = get_dir_name(f)
image_file_name = dir_name + '.jpg'
#To print the file name with path (path will be in string)
print (image_file_name)
To get the list of all directory in array you can use os :
os.listdir(directory)
I'm not quite happy with this implementation yet, I wanted to have a custom constructor that does DirectoryIndex._make(next(os.walk(input_path))) such that you can just pass the path you want a file listing for. Edits welcome!
import collections
import os
DirectoryIndex = collections.namedtuple('DirectoryIndex', ['root', 'dirs', 'files'])
for file_name in DirectoryIndex(*next(os.walk('.'))).files:
file_path = os.path.join(path, file_name)
I really like using the scandir directive that is built into the os library. Here is a working example:
import os
i = 0
with os.scandir('/usr/local/bin') as root_dir:
for path in root_dir:
if path.is_file():
i += 1
print(f"Full path is: {path} and just the name is: {path.name}")
print(f"{i} files scanned successfully.")
Get all the .asm files in a directory by doing this.
import os
path = "path_to_file"
file_type = '.asm'
for filename in os.listdir(path=path):
if filename.endswith(file_type):
print(filename)
print(f"{path}/{filename}")
# do something below
I don't understand why some answers are complicated. This is how I would do it with Python 2.7. Replace DIRECTORY_TO_LOOP with the directory you want to use.
import os
DIRECTORY_TO_LOOP = '/var/www/files/'
for root, dirs, files in os.walk(DIRECTORY_TO_LOOP, topdown=False):
for name in files:
print(os.path.join(root, name))
I have 700 files in a single folder. I need to find files that have "h10v03" as part of the name and copy them to a different folder using python.
Heres an example of one of the files: MOD10A1.A2000121.h10v03.005.2007172062725.hdf
I appreciate any help.
Something like this would do the trick.
import os
import shutil
source_dir = "/some/directory/path"
target_dir = "/some/other/directory/path"
part = "h10v03"
files = [file for file in os.listdir(source_dir)
if os.path.isfile(file) and part in file]
for file in files:
shutil.copy2(os.path.join(source_dir, file), target_dir)
Does it need to be python?
A unix shell does that for you quite fine:
cp ./*h10v03* /other/directory/
In python I would suggest you take a look at os.listdir() and shutil.copy()
EDIT:
some untested code:
import os
import shutil
src_dir = "/some/path/"
target_dir = "/some/other/path/"
searchstring = "h10v03"
for f in os.listdir(src_dir):
if searchstring in f and os.path.isfile(os.path.join(src_dir, f)):
shutil.copy2(os.path.join(src_dir, f), target_dir)
print "COPY", f
with the glob module (untested):
import glob
import os
import shutil
for f in glob.glob("/some/path/*2000*h10v03*"):
print f
shutil.copy2(f, os.path.join("/some/target/dir/", os.path.basename(f)))
Firstly, find all the items in that folder with os.listdir. Then you can use the count() method of string to determine if it has your string. Then you can use shutil to copy the file.