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python while loop in a while loop ignores the print after winning the game

I'm having an issue with my program. I'm working on a program that lets you play a small game of guessing the correct number. The problem is if you guess the correct number it will not print out: "You guessed it correctly". The program will not continue and will stay stuck on the correct number. This only happens if you have to guess multiple times. I've tried changing the else to a break command but it didn't work.
Is there anyone with a suggestion?
This is what I use to test it:
smallest number: 1
biggest number: 10
how many times can u guess: 10
If you try to guess the correct number two or three times (maybe more if u need more guesses) it will not print out you won.
import random
#counts the mistakes
count = 1
#askes to give up a minimum and maximum to guess between
minimum = int(input("what is the smallest number? "))
maximum = int(input("what is the biggest number? "))
#askes how many times u can guess in total
amount = int(input("How many times can you guess? "))
#random number between the 2 variables minimum and maximum
x = random.randrange(minimum, maximum)
guess = int(input("guess the number: "))
#while loop until the guess is the same as the random number
while guess != x:
#this is if u guessed to much u get the error that you've guessed to much
while count < amount:
if guess > x:
print("this is not the correct number, the correct number is lower \n")
guess = int(input("guess the number: "))
count += 1
elif guess < x:
print("this is not the correct number, the correct number is higher \n")
guess = int(input("guess the number: "))
count += 1
else: print("\n \nYou Lost, You've guessed", x, "times\n")
break
#this part is not working, only if you guess it at the first time. it should also print this if you guessed it in 3 times
else: print("You guessed it correctly", x)
test = (input("this is just a test if it continues out of the loop "))
print(test)

The main issue is that once guess == x and count < amount you have a while loop running that will never stop, since you don't take new inputs. At that point, you should break out of the loop, which will also conclude the outer loop

You can do it simply by using one while loop as follows:
import random
#counts the mistakes
count = 1
#askes to give up a minimum and maximum to guess between
minimum = int(input("what is the smallest number? "))
maximum = int(input("what is the biggest number? "))
#askes how many times u can guess in total
amount = int(input("How many times can you guess? "))
#random number between the 2 variables minimum and maximum
x = random.randrange(minimum, maximum)
#this is if u guessed too much u get the error that you've guessed too much
while count <= amount:
guess = int(input("guess the number: "))
if guess > x:
print("this is not the correct number, the correct number is lower \n")
count += 1
elif guess < x:
print("this is not the correct number, the correct number is higher \n")
count += 1
else:
print("You guessed it correctly", x)
break
if guess!=x:
print("\n \nYou Lost, You've guessed", count, "times\n")

As Lukas says, you've kind of created a situation where you get into a loop you can never escape because you don't ask again.
One common pattern you could try is to deliberately make a while loop that will run and run, until you explicitly break out of it (either because the player has guessed too many times, or because they guessed correctly). Also, you can get away with only asking for a guess in one part of your code, inside that while loop, rather than in a few places.
Here's my tweak to your code - one of lots of ways of doing what you want to:
import random
#counts the mistakes
count = 0
#asks to give up a minimum and maximum to guess between
minimum = int(input("what is the smallest number? "))
maximum = int(input("what is the biggest number? "))
#asks how many times u can guess in total
amount = int(input("How many times can you guess? "))
#random number between the 2 variables minimum and maximum
x = random.randrange(minimum, maximum)
#while loop until the guess is the same as the random number
while True:
if count < amount:
guess = int(input("guess the number: "))
#this is if u guessed to much u get the error that you've guessed to much
if guess > x:
print("this is not the correct number, the correct number is lower \n")
count += 1
elif guess < x:
print("this is not the correct number, the correct number is higher \n")
count += 1
else:
print("You guessed it correctly", x)
break
else:
print("\n \nYou Lost, You've guessed", x, "times\n")
PS: You got pretty close to making it work, so nice one for getting as far as you did!

This condition is never checked again when the guessed number is correct so the program hangs:
while guess != x:
How about you check for equality as the first condition and break out of the loop if true:
import random
#counts the mistakes
count = 1
#askes to give up a minimum and maximum to guess between
minimum = int(input("what is the smallest number? "))
maximum = int(input("what is the biggest number? "))
#askes how many times u can guess in total
amount = int(input("How many times can you guess? "))
#random number between the 2 variables minimum and maximum
x = random.randrange(minimum, maximum)
guess = int(input("guess the number: "))
if guess == x:
print("You guessed it correctly", x)
else:
while count < amount:
if guess > x:
print("this is not the correct number, the correct number is lower \n")
guess = int(input("guess the number: "))
count += 1
elif guess < x:
print("this is not the correct number, the correct number is higher \n")
guess = int(input("guess the number: "))
count += 1
else:
print("You guessed it correctly", x)
break
else:
print("You guessed too many times")

Python help (computer guess number)

I'm learning how to program in Python and I found 2 tasks that should be pretty simple, but the second one is very hard for me.
Basically, I need to make a program where computer guesses my number. So I enter a number and then the computer tries to guess it. Everytime it picks a number I need to enter Lower or Higher. I don't know how to do this. Could anyone advise me on how to do it?
For example (number is 5):
computer asks 10?
I write Lower
computer asks 4?
I write Higher
Program:
I already made a program which automatically says Higher or Lower but I want to input Lower or Higher as a user.
from random import randit
number = int(input("Number? "))
attempts = 0
guess = 0
min = 0
max = 100
while guess != number:
guess = randint(min,max)
print(guess,"?")
if guess < number:
print("Higher")
min = guess
elif guess > number:
print("Lower")
max = guess
attemps += 1
print("I needed", attempts, "attemps")

You may want to put in a case for if it doesn't match you input, also I think you need a case for when the guess finally equals the number, you may want to allow an input for "Found it!" or something like that.
from random import randint
number = int(input("Number? "))
attempts = 0
guess = 0
min = 0
max = 100
while guess != number:
guess = randint(min,max)
print(guess,"?")
answer = str(input("Higher/Lower? "))
if answer == 'Higher':
min = guess
elif answer == 'Lower':
max = guess
attempts += 1
print("I needed", attempts, "attempts")

from random import randit
attempts = 0
guess = 0
min = 0
max = 100
while guess != number:
number = int(input("Number? "))
guess = randint(min,max)
print(guess,"?")
if guess < number:
print("Higher")
min = guess
elif guess > number:
print("Lower")
max = guess
attemps += 1
print("I needed", attempts, "attemps")
problem is your using a loop but inputting value once at start of app . just bring input inside the while statement hope this help

from random import randint
print('choos a number in your brain and if guess is true enter y else any key choose time of guess: ')
print("define the range (A,B) :")
A = int(input("A: "))
B = int(input("B: "))
time = int(input("time:"))
while time != 0:
ran = randint(A, B)
inp = input(f"is this {ran} ?")
time -= 1
if inp == "y":
print("bla bla bla computer wins!")
break
print("NOPE!")
if time == 0:
print("computer game over!")
break

from random import *
number = int(input("Number? "))
attempts = 0
guess = 0
min = 0
max = 100
attemps =0
guess = randint(min,max)
while guess != number:
userInput=input(str(guess)+"?")
if userInput.lower()=="lower":
max=guess
elif userInput.lower()=="higher":
min=guess
attemps += 1
guess = randint(min,max)
print("I needed", attemps, "attempts to guess ur number ="+str(guess))
output:
Number? 5
66?lower
63?lower
24?lower
19?lower
18?lower
10?lower
4?higher
9?lower
6?lower
4?higher
I needed 10 attempts to guess ur number =5

How to Separate a Range of Odd and Even Numbers Through Searching the Array While Skipping Numbers

I'd like to challenge myself and develop my programming skills. I would like to create a program that asks for the user to enter a range of numbers where odd and even numbers should be separated (preferably through search) and also separated by a specified jump factor.
Also the user should be allowed to choose whether or not they would like to continue. And if so they can repeat the process of entering a new range.
for example when the program is run a sample input would be:
"Please enter the first number in the range": 11
"Please enter the last number in the range": 20
"Please enter the amount you want to jump by": 3
and the program would output:
"Your odd Numbers are": 11,17
"Your even Numbers are": 14,20
"Would you like to enter more numbers(Y/N)":
So far what I have for code is this but am having trouble putting it together and would appreciate some help.
import sys
print("Hello. Please Proceed to Enter a Range of Numbers")
first = int(input("please enter the first number in the range: "))
last = int(input("please enter the last number in the range: "))
jump = int(input("please enter the amount you want to jump by: "))
def mylist(first,last):
print("your first number is: ",first,"your last number is: ",last,"your jump factor is: ",jump)
def binarySearch (target, mylist):
startIndex = 0
endIndex = len(mylist) – 1
found = False
targetIndex = -1
while (not found and startIndex <= endIndex):
midpoint = (startIndex + endIndex) // 2
if (mylist[midpoint] == target):
found = True
targetIndex = midpoint
else:
if(target<mylist[midpoint]):
endIndex=midpoint-1
else:
startIndex=midpoint+1
return targetIndex
print("your odd Numbers are: ")
print("your even Numbers are: ")
input("Would you like to enter more numbers (Y/N)?")
N = sys.exit()
Y = first = int(input("please enter the first number in the range"))
last = int(input("please enter the last number in the range"))
jump = int(input("please enter the amount you want to jump by: "))

question - "So far what I have for code is this but am having trouble putting it together and would appreciate some help."
answer -
As a start, it seems like a good idea to group your inputs and outputs into functions! Then putting it together is a snap!
def get_inputs():
bar = input('foo')
def process_inputs():
bar = bar + 1
def print_outputs():
print(bar)
if '__name__' == '__main__':
get_inputs()
process_inputs()
print_outputs()
You could even toss in something like if input('more? (Y/N):') == 'Y': in a while loop.

Maybe I'm missing something but couldn't you replace your binary search with the following?
>>> list(filter(lambda x: x%2 == 1, range(11, 20 + 1, 3)))
[11, 17]
>>> list(filter(lambda x: x%2 == 0, range(11, 20 + 1, 3)))
[14, 20]

Python Guessing Game: Prevent Python guessing the same numbers

I am working on a guessing game in python, i think i have everything only, i want to make the program to guess between numbers it already guessed for example, if the users number is 5, and it picks 3 the user input '+' and it knows the number is higher, and if the program guess 6 the user input '-' and it knows the number is lower than 6, but sometimes it guesses a 2, its obvious that if the number is higher than 3 it can't possibly be 2 right, so how do i write that? I am a beginner at this and i would appreciate if you could make it simple, below is my code.
print("Hello,")
print("welcome to the guessing game")
print('I shall guess a number between 1 and 99, and then ask you if am right')
print('I have a maximum of 20 chances\n')
import random
guess = random.randint(1,99)
print("Your number is %f, Am i right?" % guess)
print('If I am, enter =, If the number is higher enter (+), if the number is lower enter (-)')
ans = input('Which is it: ')
print("You chose %s" % ans)
minguess = 1
maxguess = 99
count = 0
while (count < 20):
count = count + 1
if ans == '+':
##I am using these prints to keep track of the numbers and if everything is working correctly
maxguess1 = guess + 1
print('THe maxguess is', maxguess1)
newguess = random.randint(maxguess1, maxguess)
print('The newguess is', newguess)
newguess = int(newguess)
print("Is it %d?" % newguess)
print('If I am, enter =, If the number is higher enter (+), if the number is lower enter (-)')
ans = input('Which is it: ')
elif ans == "-":
maxguess2 = guess - 1
print('The minus maxguess is', maxguess2)
newguess = random.randint(minguess, maxguess2)
print('The minus newguess is', newguess)
newguess1 = int(newguess)
print("Is it %d?" % newguess1)
print('If I am, enter =, If the number is higher enter (+), if the number is lower enter (-)')
ans = input('Which is it: ')
if ans == "=":
print('YAAAAAAS MAN')
i wanted it to change the numbers whenever it guessed a new number
guess = newguess

NOTE: This example is in Python 2.7, NOT Python 3, but the concepts are the same.
Break down the problem into its individual elements:
import random
# Possible Range is [1-99], 1 inclusive to 99 inclusive
min_possible = 1
max_possible = 99
# Number of Guesses
max_guesses = 20
# Process
for i in xrange(max_guesses): # Loops through the process 'max_guesses' times
# Program Takes a Guess
guess = random.randint(min_possible, max_possible)
print 'My guess is ' + str(guess)
# Ask for User Feedback
user_feedback = ''
while not user_feedback in ['+', '-', '=']:
user_feedback = raw_input('Is the number higher (+), lower (-), or equal (=) to my guess?')
# Use the User Feedback
if user_feedback == '+':
min_possible = guess + 1 # B/c low end is inclusive
elif user_feedback == '-':
max_possible = guess - 1 # B/c high end is inclusive
else:
print 'I knew the answer was ' + str(guess)
break

Python numbers game reverse

So I have to make a "game" on python were I think of a number and it tries to guess the number. I have to tell it if it's higher or lower than the number it guessed and continue from there. So far I have it doing what I need but I have no idea how to make python remember what numbers it's guessed. So If I tell it to guess a number between 1 and 10 and it guesses 7, I say it's too high it then guesses 4 and I say it's too low it might then guess and 8. Well I can't have it guess a number higher than 7 since I said it's lower than that already. Is there any way to make it remember that?
Here's my code:
from random import randrange
def lowHigh():
l = input ("Please input the low number range.")
numl = eval(l)
h = input ("Please input the high number range.")
numh = eval(h)
guess = randrange(1,numh + 1)
print (guess)
while True:
ask = input("Is this number correct? y for yes or n for no.")
if ask == 'y':
print("Yay! I guessed right!")
break
else:
lowOrHigh = input ("Is this number too high or low? h for high, l for low.")
if lowOrHigh == 'h':
guess = randrange(numl,guess-1)
print(guess)
else:
guess = randrange(guess+1,numh)
print(guess)

You can use two different numbers to indicate the lowest and highest guesses.
When the computer guesses a number and its higher actual number, you can make the highest = that number.
Same way when the computer guesses a number and its lower than actual number, you can make the lower = that number.
And each time you take random number between these two lowest and highest number only.
The code would look like -
from random import randrange
def lowHigh():
l = input ("Please input the low number range.")
numl = eval(l)
h = input ("Please input the high number range.")
numh = eval(h)
lowest = l
highest = h
while True:
guess = randrange(lowest,highest+1)
print (guess)
ask = input("Is this number correct? y for yes or n for no.")
if ask == 'y':
print("Yay! I guessed right!")
break
else:
lowOrHigh = input ("Is this number too high or low? h for high, l for low.")
if lowOrHigh == 'h':
highest = guess - 1
else:
lowest = guess

You can save the numbers it guessed in a list and then you check if a new guess is already in the list or not.
initialise an empty list like so:
guessed=[]
and then you can append guesses made by your program into the list
guessed.append(guess)

Demo:
from random import randrange
import time
def guessNumber(min_no, max_no):
""" Select number from the range. """
try:
return randrange(min_no, max_no)
except ValueError:
return min_no
def userNoInput(msg):
""" Get Number into from the user. """
while 1:
try:
return int(raw_input(msg))
except ValueError:
print "Enter Only Number string."
continue
def findMe():
"""
1. Get Lower and Upeer Value number from the User.
2. time sleep to guess number for user in between range.
3. While infinite loop.
4. Get guess number from the Computer.
5. User can check guess number and tell computer that guess number if correct ror not.
6. If Correct then print msg and break While loop.
7. If not Correct then
Ask Computer will User that guess number is Greate or Lower then Actual number.
7.1. If Greater then Set Max limit as guess number.
7.2. If Not Greater then Set Min limit as guess number.
7.3. Continue While loop
"""
min_no = userNoInput("Please input the low number range:")
max_no = userNoInput("Please input the high number range:")
print "Guess any number between %d and %d."%(min_no, max_no)
max_no += 1
time.sleep(2)
while True:
guess = guessNumber(min_no, max_no)
print "Computer guess Number:-", guess
ask = raw_input("Is this number correct? y for Yes or n for No:")
if ask.lower() == 'y':
print("Yay! I guessed right!")
break
else:
lowOrHigh = raw_input("Is this number too high or low? h for high, l for low.")
if lowOrHigh.lower() == 'h':
#- As guess number is higher then set max number to guess number.
max_no = guess
else:
#- As guess number is lower then set min number to guess number.
min_no = guess
findMe()
Output:
Please input the low number range:10
Please input the high number range:20
Guess any number between 10 and 20.
Computer guess Number:- 14
Is this number correct? y for Yes or n for No:n
Is this number too high or low? h for high, l for low.l
Computer guess Number:- 19
Is this number correct? y for Yes or n for No:n
Is this number too high or low? h for high, l for low.h
Computer guess Number:- 17
Is this number correct? y for Yes or n for No:n
Is this number too high or low? h for high, l for low.h
Computer guess Number:- 16
Is this number correct? y for Yes or n for No:n
Is this number too high or low? h for high, l for low.h
Computer guess Number:- 15
Is this number correct? y for Yes or n for No:y
Yay! I guessed right!
Note:
Python 2.7 : raw_input() method, print is statement.
Python 3.X : input() method, print is function.

Its very similar to a Binary Search Algorithm
Its just that the usual mid value in such algorithms can be replaced by randrange(Low,High)
I'm not sure if this is a working code but I suggest you do it recursively:
items= range(l,h)
def random_search(ask, items, l, h):
"""
Random search function.
Assumes 'items' is a sorted list.
The search range is [low, high)
"""
ask = input("Is this number correct? y for yes or n for no.")
lowOrHigh = input ("Is this number too high or low? h for high, l for low.")
elem = randrange(l,h)
if ask == 'y':
return elem
elif h == l:
return False
elif lowOrHigh == 'h':
items= range(l,elem)
return random_search(ask, items, l, elem)
else:
items= range(elem, h)
return random_search(ask, items, elem, h)