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Print multiple lines without space between lines

I have a list of lines (from a text file) to be printed in terminal. This is the format I like (without empty lines between printed lines):
>>> print("line \n" * 5)
line
line
line
line
line
This is how it looks (a line with text, an empty line, etc.):
>>> for x in range(0, 5): print "line \n"
...
line
line
line
line
line
Any idea why it's working in this way and how to print my list of lines without empty lines between them?
UPDATE (this is where I want to get rid of empty lines):
with open(FILE, 'r') as f:
lines = f.readlines()
for line in lines:
print line

This is actually due to the way you're reading the file. If you've done something like
with open(FILE) as f:
data = f.readlines()
Then the data will be a list of lines which retain the end of line character. If you don't want the end of line character, use this instead:
with open(FILE) as f:
data = f.read().splitlines()
If you don't want to change the way that you read the data into a list, then concatenate and print the lines like this instead:
print ''.join(data)
To answer the literal question, if you have a string with a newline, and you want to suppress the newline generated by the print statement, the way to do that in Python 2 is by using a trailing comma on the print statement:
with open(FILE) as f:
for line in f:
print line,
But note, that's not really necessary to iterate line by line like that. You may as well just print the data directly:
with open(FILE) as f:
print f.read()

When using a for loop you can remove "\n" as follows
for x in range(0, 5): print "line"

The print command implicitly adds a new line feed \n in the output display. Remove the \n to avoid printing blank lines in the looping structure.

print adds a trailing newline by default. You can disable it as follows:
from __future__ import print_function # only needed for python 2
print("string", end="")

By default print adds a newline, and your strings also have it; you have two possible solutions.
Either override this behaviour, setting the string to be put to empty:
# python 3.*
for x in range(0, 5): print("line \n", end="")
And
# python 2.*
from __future__ import print_function # to use py3 print in py2
for x in range(0, 5): print("line \n", end="")
Alternatively, if you don't have full control over the lines - some may have the newlines, other - not, trim any newline endings and leave the default behaviour:
for x in range(0, 5): print("line \n".rstrip("\n").rstrip("\r")) # takes care of also Windows line ending, just in case

A standard call to the print function will add a newline automatically so you can either remove the \n from your existing line(s), if the lines come from an external file use line.strip(), or tell print not to add the newline with: print(line, end='')
This will work for Python3 or for 2.7 with from __future__ import print_function as the first code line.

Send keylogger log files to e-mail [duplicate]

I have a text file that looks like:
ABC
DEF
How can I read the file into a single-line string without newlines, in this case creating a string 'ABCDEF'?
For reading the file into a list of lines, but removing the trailing newline character from each line, see How to read a file without newlines?.

You could use:
with open('data.txt', 'r') as file:
data = file.read().replace('\n', '')
Or if the file content is guaranteed to be one-line
with open('data.txt', 'r') as file:
data = file.read().rstrip()

In Python 3.5 or later, using pathlib you can copy text file contents into a variable and close the file in one line:
from pathlib import Path
txt = Path('data.txt').read_text()
and then you can use str.replace to remove the newlines:
txt = txt.replace('\n', '')

You can read from a file in one line:
str = open('very_Important.txt', 'r').read()
Please note that this does not close the file explicitly.
CPython will close the file when it exits as part of the garbage collection.
But other python implementations won't. To write portable code, it is better to use with or close the file explicitly. Short is not always better. See https://stackoverflow.com/a/7396043/362951

To join all lines into a string and remove new lines, I normally use :
with open('t.txt') as f:
s = " ".join([l.rstrip("\n") for l in f])

with open("data.txt") as myfile:
data="".join(line.rstrip() for line in myfile)
join() will join a list of strings, and rstrip() with no arguments will trim whitespace, including newlines, from the end of strings.

This can be done using the read() method :
text_as_string = open('Your_Text_File.txt', 'r').read()
Or as the default mode itself is 'r' (read) so simply use,
text_as_string = open('Your_Text_File.txt').read()

I'm surprised nobody mentioned splitlines() yet.
with open ("data.txt", "r") as myfile:
data = myfile.read().splitlines()
Variable data is now a list that looks like this when printed:
['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']
Note there are no newlines (\n).
At that point, it sounds like you want to print back the lines to console, which you can achieve with a for loop:
for line in data:
print(line)

It's hard to tell exactly what you're after, but something like this should get you started:
with open ("data.txt", "r") as myfile:
data = ' '.join([line.replace('\n', '') for line in myfile.readlines()])

I have fiddled around with this for a while and have prefer to use use read in combination with rstrip. Without rstrip("\n"), Python adds a newline to the end of the string, which in most cases is not very useful.
with open("myfile.txt") as f:
file_content = f.read().rstrip("\n")
print(file_content)

Here are four codes for you to choose one:
with open("my_text_file.txt", "r") as file:
data = file.read().replace("\n", "")
or
with open("my_text_file.txt", "r") as file:
data = "".join(file.read().split("\n"))
or
with open("my_text_file.txt", "r") as file:
data = "".join(file.read().splitlines())
or
with open("my_text_file.txt", "r") as file:
data = "".join([line for line in file])

you can compress this into one into two lines of code!!!
content = open('filepath','r').read().replace('\n',' ')
print(content)
if your file reads:
hello how are you?
who are you?
blank blank
python output
hello how are you? who are you? blank blank

You can also strip each line and concatenate into a final string.
myfile = open("data.txt","r")
data = ""
lines = myfile.readlines()
for line in lines:
data = data + line.strip();
This would also work out just fine.

This is a one line, copy-pasteable solution that also closes the file object:
_ = open('data.txt', 'r'); data = _.read(); _.close()

f = open('data.txt','r')
string = ""
while 1:
line = f.readline()
if not line:break
string += line
f.close()
print(string)

python3: Google "list comprehension" if the square bracket syntax is new to you.
with open('data.txt') as f:
lines = [ line.strip('\n') for line in list(f) ]

Oneliner:
List: "".join([line.rstrip('\n') for line in open('file.txt')])
Generator: "".join((line.rstrip('\n') for line in open('file.txt')))
List is faster than generator but heavier on memory. Generators are slower than lists and is lighter for memory like iterating over lines. In case of "".join(), I think both should work well. .join() function should be removed to get list or generator respectively.
Note: close() / closing of file descriptor probably not needed

Have you tried this?
x = "yourfilename.txt"
y = open(x, 'r').read()
print(y)

To remove line breaks using Python you can use replace function of a string.
This example removes all 3 types of line breaks:
my_string = open('lala.json').read()
print(my_string)
my_string = my_string.replace("\r","").replace("\n","")
print(my_string)
Example file is:
{
"lala": "lulu",
"foo": "bar"
}
You can try it using this replay scenario:
https://repl.it/repls/AnnualJointHardware

I don't feel that anyone addressed the [ ] part of your question. When you read each line into your variable, because there were multiple lines before you replaced the \n with '' you ended up creating a list. If you have a variable of x and print it out just by
x
or print(x)
or str(x)
You will see the entire list with the brackets. If you call each element of the (array of sorts)
x[0]
then it omits the brackets. If you use the str() function you will see just the data and not the '' either.
str(x[0])

Maybe you could try this? I use this in my programs.
Data= open ('data.txt', 'r')
data = Data.readlines()
for i in range(len(data)):
data[i] = data[i].strip()+ ' '
data = ''.join(data).strip()

Regular expression works too:
import re
with open("depression.txt") as f:
l = re.split(' ', re.sub('\n',' ', f.read()))[:-1]
print (l)
['I', 'feel', 'empty', 'and', 'dead', 'inside']

with open('data.txt', 'r') as file:
data = [line.strip('\n') for line in file.readlines()]
data = ''.join(data)

from pathlib import Path
line_lst = Path("to/the/file.txt").read_text().splitlines()
Is the best way to get all the lines of a file, the '\n' are already stripped by the splitlines() (which smartly recognize win/mac/unix lines types).
But if nonetheless you want to strip each lines:
line_lst = [line.strip() for line in txt = Path("to/the/file.txt").read_text().splitlines()]
strip() was just a useful exemple, but you can process your line as you please.
At the end, you just want concatenated text ?
txt = ''.join(Path("to/the/file.txt").read_text().splitlines())

This works:
Change your file to:
LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE
Then:
file = open("file.txt")
line = file.read()
words = line.split()
This creates a list named words that equals:
['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']
That got rid of the "\n". To answer the part about the brackets getting in your way, just do this:
for word in words: # Assuming words is the list above
print word # Prints each word in file on a different line
Or:
print words[0] + ",", words[1] # Note that the "+" symbol indicates no spaces
#The comma not in parentheses indicates a space
This returns:
LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN, GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE

with open(player_name, 'r') as myfile:
data=myfile.readline()
list=data.split(" ")
word=list[0]
This code will help you to read the first line and then using the list and split option you can convert the first line word separated by space to be stored in a list.
Than you can easily access any word, or even store it in a string.
You can also do the same thing with using a for loop.

file = open("myfile.txt", "r")
lines = file.readlines()
str = '' #string declaration
for i in range(len(lines)):
str += lines[i].rstrip('\n') + ' '
print str

Try the following:
with open('data.txt', 'r') as myfile:
data = myfile.read()
sentences = data.split('\\n')
for sentence in sentences:
print(sentence)
Caution: It does not remove the \n. It is just for viewing the text as if there were no \n

reading in file python says its a string [duplicate]

I have a text file that looks like:
ABC
DEF
How can I read the file into a single-line string without newlines, in this case creating a string 'ABCDEF'?
For reading the file into a list of lines, but removing the trailing newline character from each line, see How to read a file without newlines?.

You could use:
with open('data.txt', 'r') as file:
data = file.read().replace('\n', '')
Or if the file content is guaranteed to be one-line
with open('data.txt', 'r') as file:
data = file.read().rstrip()

In Python 3.5 or later, using pathlib you can copy text file contents into a variable and close the file in one line:
from pathlib import Path
txt = Path('data.txt').read_text()
and then you can use str.replace to remove the newlines:
txt = txt.replace('\n', '')

You can read from a file in one line:
str = open('very_Important.txt', 'r').read()
Please note that this does not close the file explicitly.
CPython will close the file when it exits as part of the garbage collection.
But other python implementations won't. To write portable code, it is better to use with or close the file explicitly. Short is not always better. See https://stackoverflow.com/a/7396043/362951

To join all lines into a string and remove new lines, I normally use :
with open('t.txt') as f:
s = " ".join([l.rstrip("\n") for l in f])

with open("data.txt") as myfile:
data="".join(line.rstrip() for line in myfile)
join() will join a list of strings, and rstrip() with no arguments will trim whitespace, including newlines, from the end of strings.

This can be done using the read() method :
text_as_string = open('Your_Text_File.txt', 'r').read()
Or as the default mode itself is 'r' (read) so simply use,
text_as_string = open('Your_Text_File.txt').read()

I'm surprised nobody mentioned splitlines() yet.
with open ("data.txt", "r") as myfile:
data = myfile.read().splitlines()
Variable data is now a list that looks like this when printed:
['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']
Note there are no newlines (\n).
At that point, it sounds like you want to print back the lines to console, which you can achieve with a for loop:
for line in data:
print(line)

It's hard to tell exactly what you're after, but something like this should get you started:
with open ("data.txt", "r") as myfile:
data = ' '.join([line.replace('\n', '') for line in myfile.readlines()])

I have fiddled around with this for a while and have prefer to use use read in combination with rstrip. Without rstrip("\n"), Python adds a newline to the end of the string, which in most cases is not very useful.
with open("myfile.txt") as f:
file_content = f.read().rstrip("\n")
print(file_content)

Here are four codes for you to choose one:
with open("my_text_file.txt", "r") as file:
data = file.read().replace("\n", "")
or
with open("my_text_file.txt", "r") as file:
data = "".join(file.read().split("\n"))
or
with open("my_text_file.txt", "r") as file:
data = "".join(file.read().splitlines())
or
with open("my_text_file.txt", "r") as file:
data = "".join([line for line in file])

you can compress this into one into two lines of code!!!
content = open('filepath','r').read().replace('\n',' ')
print(content)
if your file reads:
hello how are you?
who are you?
blank blank
python output
hello how are you? who are you? blank blank

You can also strip each line and concatenate into a final string.
myfile = open("data.txt","r")
data = ""
lines = myfile.readlines()
for line in lines:
data = data + line.strip();
This would also work out just fine.

This is a one line, copy-pasteable solution that also closes the file object:
_ = open('data.txt', 'r'); data = _.read(); _.close()

f = open('data.txt','r')
string = ""
while 1:
line = f.readline()
if not line:break
string += line
f.close()
print(string)

python3: Google "list comprehension" if the square bracket syntax is new to you.
with open('data.txt') as f:
lines = [ line.strip('\n') for line in list(f) ]

Oneliner:
List: "".join([line.rstrip('\n') for line in open('file.txt')])
Generator: "".join((line.rstrip('\n') for line in open('file.txt')))
List is faster than generator but heavier on memory. Generators are slower than lists and is lighter for memory like iterating over lines. In case of "".join(), I think both should work well. .join() function should be removed to get list or generator respectively.
Note: close() / closing of file descriptor probably not needed

Have you tried this?
x = "yourfilename.txt"
y = open(x, 'r').read()
print(y)

To remove line breaks using Python you can use replace function of a string.
This example removes all 3 types of line breaks:
my_string = open('lala.json').read()
print(my_string)
my_string = my_string.replace("\r","").replace("\n","")
print(my_string)
Example file is:
{
"lala": "lulu",
"foo": "bar"
}
You can try it using this replay scenario:
https://repl.it/repls/AnnualJointHardware

I don't feel that anyone addressed the [ ] part of your question. When you read each line into your variable, because there were multiple lines before you replaced the \n with '' you ended up creating a list. If you have a variable of x and print it out just by
x
or print(x)
or str(x)
You will see the entire list with the brackets. If you call each element of the (array of sorts)
x[0]
then it omits the brackets. If you use the str() function you will see just the data and not the '' either.
str(x[0])

Maybe you could try this? I use this in my programs.
Data= open ('data.txt', 'r')
data = Data.readlines()
for i in range(len(data)):
data[i] = data[i].strip()+ ' '
data = ''.join(data).strip()

Regular expression works too:
import re
with open("depression.txt") as f:
l = re.split(' ', re.sub('\n',' ', f.read()))[:-1]
print (l)
['I', 'feel', 'empty', 'and', 'dead', 'inside']

with open('data.txt', 'r') as file:
data = [line.strip('\n') for line in file.readlines()]
data = ''.join(data)

from pathlib import Path
line_lst = Path("to/the/file.txt").read_text().splitlines()
Is the best way to get all the lines of a file, the '\n' are already stripped by the splitlines() (which smartly recognize win/mac/unix lines types).
But if nonetheless you want to strip each lines:
line_lst = [line.strip() for line in txt = Path("to/the/file.txt").read_text().splitlines()]
strip() was just a useful exemple, but you can process your line as you please.
At the end, you just want concatenated text ?
txt = ''.join(Path("to/the/file.txt").read_text().splitlines())

This works:
Change your file to:
LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE
Then:
file = open("file.txt")
line = file.read()
words = line.split()
This creates a list named words that equals:
['LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN', 'GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE']
That got rid of the "\n". To answer the part about the brackets getting in your way, just do this:
for word in words: # Assuming words is the list above
print word # Prints each word in file on a different line
Or:
print words[0] + ",", words[1] # Note that the "+" symbol indicates no spaces
#The comma not in parentheses indicates a space
This returns:
LLKKKKKKKKMMMMMMMMNNNNNNNNNNNNN, GGGGGGGGGHHHHHHHHHHHHHHHHHHHHEEEEEEEE

with open(player_name, 'r') as myfile:
data=myfile.readline()
list=data.split(" ")
word=list[0]
This code will help you to read the first line and then using the list and split option you can convert the first line word separated by space to be stored in a list.
Than you can easily access any word, or even store it in a string.
You can also do the same thing with using a for loop.

file = open("myfile.txt", "r")
lines = file.readlines()
str = '' #string declaration
for i in range(len(lines)):
str += lines[i].rstrip('\n') + ' '
print str

Try the following:
with open('data.txt', 'r') as myfile:
data = myfile.read()
sentences = data.split('\\n')
for sentence in sentences:
print(sentence)
Caution: It does not remove the \n. It is just for viewing the text as if there were no \n

How to completely remove "\n" in text file using python

So the text file I have is formatted something like this:
a
b
c
I know how to strip() and rstrip() but I want to get rid of the empty lines.
I want to make it shorter like this:
a
b
c

You could remove all blank lines (lines that contain only whitespace) from stdin and/or files given at the command line using fileinput module:
#!/usr/bin/env python
import sys
import fileinput
for line in fileinput.input(inplace=True):
if line.strip(): # preserve non-blank lines
sys.stdout.write(line)

You can use regular expressions :
import re
txt = """a
b
c"""
print re.sub(r'\n+', '\n', txt) # replace one or more consecutive \n by a single one
However, lines with spaces won't be removed. A better solution is :
re.sub(r'(\n[ \t]*)+', '\n', txt)
This way, wou will also remove leading spaces.

Simply remove any line that only equals "\n":
in_filename = 'in_example.txt'
out_filename = 'out_example.txt'
with open(in_filename) as infile, open(out_filename, "w") as outfile:
for line in infile.readlines():
if line != "\n":
outfile.write(line)
If you want to simply update the same file, close and reopen it to overwrite it with the new data:
filename = 'in_example.txt'
filedata = ""
with open(filename, "r") as infile:
for line in infile.readlines():
if line != "\n":
filedata += line
with open(filename, "w") as outfile:
outfile.write(filedata)

Splitting lines in python based on some character

Input:
!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/1
2/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:14,000.
0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W
55.576,+0013!,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013!,A,56
281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34
:18,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:19,000.0,0,37N22.
Output:
!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:14,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:18,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:19,000.0,0,37N22.
'!' is the starting character and +0013 should be the ending of each line (if present).
Problem which I am getting:
Output is like :
!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/1
2/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:14,000.
0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W
Any help would be highly appreciated...!!!
My code:
file_open= open('sample.txt','r')
file_read= file_open.read()
file_open2= open('output.txt','w+')
counter =0
for i in file_read:
if '!' in i:
if counter == 1:
file_open2.write('\n')
counter= counter -1
counter= counter +1
file_open2.write(i)

You can try something like this:
with open("abc.txt") as f:
data=f.read().replace("\r\n","") #replace the newlines with ""
#the newline can be "\n" in your system instead of "\r\n"
ans=filter(None,data.split("!")) #split the data at '!', then filter out empty lines
for x in ans:
print "!"+x #or write to some other file
.....:
!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:14,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:18,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:19,000.0,0,37N22.

Could you just use str.split?
lines = file_read.split('!')
Now lines is a list which holds the split data. This is almost the lines you want to write -- The only difference is that they don't have trailing newlines and they don't have '!' at the start. We can put those in easily with string formatting -- e.g. '!{0}\n'.format(line). Then we can put that whole thing in a generator expression which we'll pass to file.writelines to put the data in a new file:
file_open2.writelines('!{0}\n'.format(line) for line in lines)
You might need:
file_open2.writelines('!{0}\n'.format(line.replace('\n','')) for line in lines)
if you find that you're getting more newlines than you wanted in the output.
A few other points, when opening files, it's nice to use a context manager -- This makes sure that the file is closed properly:
with open('inputfile') as fin:
lines = fin.read()
with open('outputfile','w') as fout:
fout.writelines('!{0}\n'.format(line.replace('\n','')) for line in lines)

Another option, using replace instead of split, since you know the starting and ending characters of each line:
In [14]: data = """!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/1
2/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:14,000.
0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W
55.576,+0013!,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013!,A,56
281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34
:18,000.0,0,37N22.714,121W55.576,+0013!,A,56281,12/12/19,19:34:19,000.0,0,37N22.""".replace('\n', '')
In [15]: print data.replace('+0013!', "+0013\n!")
!,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:14,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:18,000.0,0,37N22.714,121W55.576,+0013
!,A,56281,12/12/19,19:34:19,000.0,0,37N22.

Just for some variance, here is a regular expression answer:
import re
outputFile = open('output.txt', 'w+')
with open('sample.txt', 'r') as f:
for line in re.findall("!.+?(?=!|$)", f.read(), re.DOTALL):
outputFile.write(line.replace("\n", "") + '\n')
outputFile.close()
It will open the output file, get the contents of the input file, and loop through all the matches using the regular expression !.+?(?=!|$) with the re.DOTALL flag. The regular expression explanation & what it matches can be found here: http://regex101.com/r/aK6aV4
After we have a match, we strip out the new lines from the match, and write it to the file.

Let's try to add a \n before every "!"; then let python splitlines :-) :
file_read.replace("!", "!\n").splitlines()

I will actually implement as a generator so that you can work on the data stream rather than the entire content of the file. This will be quite memory friendly if working with huge files
>>> def split_on_stream(it,sep="!"):
prev = ""
for line in it:
line = (prev + line.strip()).split(sep)
for parts in line[:-1]:
yield parts
prev = line[-1]
yield prev
>>> with open("test.txt") as fin:
for parts in split_on_stream(fin):
print parts
,A,56281,12/12/19,19:34:12,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:13,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:14,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:15,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:16,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:17,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:18,000.0,0,37N22.714,121W55.576,+0013
,A,56281,12/12/19,19:34:19,000.0,0,37N22.