I have a Python script that converts JSON to CSV successfully when run in PyCharm.
When I move that Python script into a Python Transformer in MuleSoft, the script fails with the error:
TypeError: unicode indices must be integers in at line number 10 (javax.script.ScriptException). Message payload is of type: String (org.mule.api.transformer.TransformerMessagingException). Message payload is of type: String
What is the difference between Python and Jython in this context? I don't get it!
Here is the Python:
import csv
import io
data = message.getInvocationProperty("my_JSON")
output = io.BytesIO()
writer = csv.writer(output)
for item in data:
writer.writerow(([item['observationid'], item['fkey_observation'], item['value'], item['participantid'], item['uom'], item['finishtime'], item['starttime'], item['observedproperty'], item['measuretime'], item['measurementid'], item['longitude'], item['identifier'], item['latitude']]))
result = output.getvalue()
"my_JSON" is a variable containing the JSON.
You seem to have forgotten to parse the JSON, like so: data = json.loads(data).
Without that, data is a str, item is a str of length 1, and item['observationid'] raises TypeError.
Related
I'm following the Databricks example for uploading a file to DBFS (in my case .csv):
import json
import requests
import base64
DOMAIN = '<databricks-instance>'
TOKEN = '<your-token>'
BASE_URL = 'https://%s/api/2.0/dbfs/' % (DOMAIN)
def dbfs_rpc(action, body):
""" A helper function to make the DBFS API request, request/response is encoded/decoded as JSON """
response = requests.post(
BASE_URL + action,
headers={'Authorization': 'Bearer %s' % TOKEN },
json=body
)
return response.json()
# Create a handle that will be used to add blocks
handle = dbfs_rpc("create", {"path": "/temp/upload_large_file", "overwrite": "true"})['handle']
with open('/a/local/file') as f:
while True:
# A block can be at most 1MB
block = f.read(1 << 20)
if not block:
break
data = base64.standard_b64encode(block)
dbfs_rpc("add-block", {"handle": handle, "data": data})
# close the handle to finish uploading
dbfs_rpc("close", {"handle": handle})
When using the tutorial as is, I get an error:
Traceback (most recent call last):
File "db_api.py", line 65, in <module>
data = base64.standard_b64encode(block)
File "C:\Miniconda3\envs\dash_p36\lib\base64.py", line 95, in standard_b64encode
return b64encode(s)
File "C:\Miniconda3\envs\dash_p36\lib\base64.py", line 58, in b64encode
encoded = binascii.b2a_base64(s, newline=False)
TypeError: a bytes-like object is required, not 'str'
I tried doing with open('./sample.csv', 'rb') as f: before passing the blocks to base64.standard_b64encode but then getting another error:
TypeError: Object of type 'bytes' is not JSON serializable
This happens when the encoded block data is being sent into the API call.
I tried skipping encoding entirely and just passing the blocks into the post call. In this case the file gets created in the DBFS but has 0 bytes size.
At this point I'm trying to make sense of it all. It doesn't want a string but it doesn't want bytes either. What am I doing wrong? Appreciate any help.
In Python we have strings and bytes, which are two different entities note that there is no implicit conversion between them, so you need to know when to use which and how to convert when necessary. This answer provides nice explanation.
With the code snippet I see two issues:
This you already got - open by default reads the file as text. So your block is a string, while standard_b64encode expects bytes and returns bytes. To read bytes from file it needs to be opened in binary mode:
with open('/a/local/file', 'rb') as f:
Only strings can be encoded as JSON. There's no source code available for dbfs_rpc (or I can't find it), but apparently it expects a string, which it internally encodes. Since your data is bytes, you need to convert it to string explicitly and that's done using decode:
dbfs_rpc("add-block", {"handle": handle, "data": data.decode('utf8')})
i read about 10 to 12 answer but nothing help me.
i wanna print the url shows in picute click to see
this is my code :
> from urllib.request import urlopen
> import json as simplejson
> link = "https://api.instagram.com/v1/users/self/media/recent/?access_token=2290710571.098b867.5cf99a24896b476982c70c47eb0a0413"
> response = urlopen(link)
> data = simplejson.load(response)
> print (data['data']['0']['image']['standard_resolution']['url'])
but i get this error :
TypeError: list indices must be integers or slices, not str
edit1:
i saw someone say put [0] in you code.
if i change
print (data['data']['0']['image']['standard_resolution']['url'])
to this
print (data[0]['data']['0']['image']['standard_resolution']['url'])
i will get new error -> KeyError: 0
edit2:
and if i change
data = simplejson.load(response)
to this
pdata = simplejson.loads(response)
i will get new error ->
aise TypeError(f'the JSON object must be str, bytes or bytearray, '
TypeError: the JSON object must be str, bytes or bytearray, not
HTTPResponse
The advice is to use an integer, not to add an extra two lookups.
print(data['data'][0]['images']['standard_resolution']['url'])
Note, that data has images not image.
(Also, there's no reason to import the json library as simplejson. simplejson was a library that was popular before json was included in the standard library; but that was added in version 2.6 and we're on 3.7 now. Just import json and use it.)
I was following a tutorial that how to use elasticsearch with python (link=
https://tryolabs.com/blog/2015/02/17/python-elasticsearch-first-steps/#contacto) i faced this error.
import json
r = requests.get('http://localhost:9200')
i = 1
while r.status_code == 200:
r = requests.get('http://swapi.co/api/people/'+ str(i))
es.index(index='sw', doc_type='people', id=i, body=json.loads(r.content))
i=i+1
print(i)
TypeError: the JSON object must be str, not 'bytes'
You are using Python 3, and the blog post is aimed at Python 2 instead. The Python 3 json.loads() function expects decoded unicode text, not the raw response bytestring, which is what response.content returns.
Rather than use json.loads(), leave it to requests to decode the JSON correctly for you, by using the response.json() method:
es.index(index='sw', doc_type='people', id=i, body=r.json())
i'm new to programing and I'm trying to accese the webservice provided in http://indicadoreseconomicos.bccr.fi.cr/indicadoreseconomicos/WebServices/wsindicadoreseconomicos.asmx?op=ObtenerIndicadoresEconomicosXML, i've added the parameters I need to acces it but when I try to read the file in python I get
TypeError: 'HTTPResponse' object cannot be interpreted as an integer
this is my code
import urllib
import http.client
import time
HEADERS={"Content-type":"application/x-www-form-urlencoded","Accept":"text/plain"}
HOST = "indicadoreseconomicos.bccr.fi.cr"
POST = "/indicadoreseconomicos/WebServices/wsIndicadoresEconomicos.asmx/ObtenerIndicadoresEconomicos"
data = urllib.parse.urlencode({'tcIndicador': 317,
'tcFechaInicio':str(time.strftime("%d/%m/%Y")),
'tcFechaFinal':str(time.strftime("%d/%m/%Y")),
'tcNombre' : 'TI1400',
'tnSubNiveles' : 'N'})
conn=http.client.HTTPConnection(HOST)
conn.request("POST",POST,data,headers=HEADERS)
response= conn.getresponse()
responseSTR= response.read(response)
print (response)
Any suggestions are apreciated
response.read() takes an optional argument that is the number of bytes to read from the response; an integer, whole number. Now you passed the response object instead.
As you want to read the entire response, you should omit the argument altogether, thus:
response_str = response.read()
print(response_str)
This question already has answers here:
How can I parse (read) and use JSON?
(5 answers)
Closed 29 days ago.
In Python I'm getting an error:
Exception: (<type 'exceptions.AttributeError'>,
AttributeError("'str' object has no attribute 'read'",), <traceback object at 0x1543ab8>)
Given python code:
def getEntries (self, sub):
url = 'http://www.reddit.com/'
if (sub != ''):
url += 'r/' + sub
request = urllib2.Request (url +
'.json', None, {'User-Agent' : 'Reddit desktop client by /user/RobinJ1995/'})
response = urllib2.urlopen (request)
jsonStr = response.read()
return json.load(jsonStr)['data']['children']
What does this error mean and what did I do to cause it?
The problem is that for json.load you should pass a file like object with a read function defined. So either you use json.load(response) or json.loads(response.read()).
Ok, this is an old thread but.
I had a same issue, my problem was I used json.load instead of json.loads
This way, json has no problem with loading any kind of dictionary.
Official documentation
json.load - Deserialize fp (a .read()-supporting text file or binary file containing a JSON document) to a Python object using this conversion table.
json.loads - Deserialize s (a str, bytes or bytearray instance containing a JSON document) to a Python object using this conversion table.
You need to open the file first. This doesn't work:
json_file = json.load('test.json')
But this works:
f = open('test.json')
json_file = json.load(f)
If you get a python error like this:
AttributeError: 'str' object has no attribute 'some_method'
You probably poisoned your object accidentally by overwriting your object with a string.
How to reproduce this error in python with a few lines of code:
#!/usr/bin/env python
import json
def foobar(json):
msg = json.loads(json)
foobar('{"batman": "yes"}')
Run it, which prints:
AttributeError: 'str' object has no attribute 'loads'
But change the name of the variablename, and it works fine:
#!/usr/bin/env python
import json
def foobar(jsonstring):
msg = json.loads(jsonstring)
foobar('{"batman": "yes"}')
This error is caused when you tried to run a method within a string. String has a few methods, but not the one you are invoking. So stop trying to invoke a method which String does not define and start looking for where you poisoned your object.
AttributeError("'str' object has no attribute 'read'",)
This means exactly what it says: something tried to find a .read attribute on the object that you gave it, and you gave it an object of type str (i.e., you gave it a string).
The error occurred here:
json.load(jsonStr)['data']['children']
Well, you aren't looking for read anywhere, so it must happen in the json.load function that you called (as indicated by the full traceback). That is because json.load is trying to .read the thing that you gave it, but you gave it jsonStr, which currently names a string (which you created by calling .read on the response).
Solution: don't call .read yourself; the function will do this, and is expecting you to give it the response directly so that it can do so.
You could also have figured this out by reading the built-in Python documentation for the function (try help(json.load), or for the entire module (try help(json)), or by checking the documentation for those functions on http://docs.python.org .
Instead of json.load() use json.loads() and it would work:
ex:
import json
from json import dumps
strinjJson = '{"event_type": "affected_element_added"}'
data = json.loads(strinjJson)
print(data)
So, don't use json.load(data.read()) use json.loads(data.read()):
def findMailOfDev(fileName):
file=open(fileName,'r')
data=file.read();
data=json.loads(data)
return data['mail']
use json.loads() function , put the s after that ... just a mistake btw i just realized after i searched error
def getEntries (self, sub):
url = 'http://www.reddit.com/'
if (sub != ''):
url += 'r/' + sub
request = urllib2.Request (url +
'.json', None, {'User-Agent' : 'Reddit desktop client by /user/RobinJ1995/'})
response = urllib2.urlopen (request)
jsonStr = response.read()
return json.loads(jsonStr)['data']['children']
try this
Open the file as a text file first
json_data = open("data.json", "r")
Now load it to dict
dict_data = json.load(json_data)
If you need to convert string to json. Then use loads() method instead of load(). load() function uses to load data from a file so used loads() to convert string to json object.
j_obj = json.loads('["label" : "data"]')