Seems like this should be so simple but for the life of me, I can't find the answer. I pull two datetimes/timestamps from the database:
2015-08-10 19:33:27.653
2015-08-10 19:31:28.209
How do I subtract the first from the second, preferably the result being in milliseconds? And yes, I have the date in there, too, because I need it to work at around midnight, as well.
Parse your strings as datetime.datetime objects and subtract them:
from datetime import datetime
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
Gives me:
0:01:59.444000
Also check out timedelta documentation for all possible operations.
you can do subtraction on 2 datetime objects to get the difference
>>> import time
>>> import datetime
>>>
>>> earlier = datetime.datetime.now()
>>> time.sleep(10)
>>> now = datetime.datetime.now()
>>>
>>> diff = now - earlier
>>> diff.seconds
10
convert your strings to datetime objects with time.strptime
datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
timedelta.seconds does not represent the total number of seconds in the timedelta, but the total number of seconds modulus 60.
Call the function timedelta.total_seconds() instead of accessing the timedelta.seconds property.
For python 3.4, first you'd need to convert the strings representing times into datetime objects, then the datetime module has helpful tools work with dates and times.
from datetime import datetime
def to_datetime_object(date_string, date_format):
s = datetime.strptime(date_string, date_format)
return s
time_1 = '2015-08-10 19:33:27'
time_2 = '2015-08-10 19:31:28'
date_format = "%Y-%m-%d %H:%M:%S"
time_1_datetime_object = to_datetime_object(time_1, date_format)
time_2_datetime_object = to_datetime_object(time_2, date_format)
diff_time = time_1_datetime_object - time_2_datetime_object
Related
Kindly help below my query:
I got an estimated time from API server like below:
2019-09-25T20:11:23+08:00
it seems like iso 8601 standard with timezone.
I would like to know how to calculate how many days, hours, minutes and seconds left from above value to the current time.
import datetime
Receved_time_frim_API = "2019-09-25T20:11:23+08:00"
Current_time = datetime.datetime.now()
left_days =
left_hour =
left_min =
left_sec =
Your time string contains timezone info. According to https://stackoverflow.com/a/13182163/12112986 it's easy to convert it to datetime object in python 3.7
import datetime
received = datetime.datetime.fromisoformat(Receved_time_frim_API)
In previous versions there is no easy oneliner to convert string with timezone to datetime object. If you're using earlier python version, you can try something crude, like
>>> date, timezone = Receved_time_frim_API.split("+")
>>> tz_hours, tz_minutes = timezone.split(":")
>>> date = datetime.datetime.strptime(date, "%Y-%m-%dT%H:%M:%S")
>>> date -= datetime.timedelta(hours=int(tz_hours))
>>> date -= datetime.timedelta(minutes=int(tz_minutes))
Note that this will work only in case of positive timezones
To substract two datetime objects use
td = date - Current_time
left_days = td.days
left_hour = td.seconds // 3600
left_min = (td.seconds//60)%60
left_sec = td.seconds % 60
Okay first you need to parse the Receved_time_frim_API into datetime format:
from dateutil import parser
Receved_time_frim_API = parser.parse("2019-09-25T20:11:23+08:00")
But you can't just substract this from your Current_time, because datetime.now() is not aware of a timezone:
from datetime import timezone
Current_time = datetime.datetime.now().replace(tzinfo=timezone.utc)
print (Current_time-Receved_time_frim_API)
The result is a datetime.timedelta
I am able to get the current time as below:
from datetime import datetime
str(datetime.now())[11:19]
Result
'19:43:20'
Now, I am trying to add 9 hours to the above time, how can I add hours to current time in Python?
from datetime import datetime, timedelta
nine_hours_from_now = datetime.now() + timedelta(hours=9)
#datetime.datetime(2012, 12, 3, 23, 24, 31, 774118)
And then use string formatting to get the relevant pieces:
>>> '{:%H:%M:%S}'.format(nine_hours_from_now)
'23:24:31'
If you're only formatting the datetime then you can use:
>>> format(nine_hours_from_now, '%H:%M:%S')
'23:24:31'
Or, as #eumiro has pointed out in comments - strftime
Import datetime and timedelta:
>>> from datetime import datetime, timedelta
>>> str(datetime.now() + timedelta(hours=9))[11:19]
'01:41:44'
But the better way is:
>>> (datetime.now() + timedelta(hours=9)).strftime('%H:%M:%S')
'01:42:05'
You can refer strptime and strftime behavior to better understand how python processes dates and time field
This works for me working with seconds not hours and also using a function to convert back to UTC time.
from datetime import timezone, datetime, timedelta
import datetime
def utc_converter(dt):
dt = datetime.datetime.now(timezone.utc)
utc_time = dt.replace(tzinfo=timezone.utc)
utc_timestamp = utc_time.timestamp()
return utc_timestamp
# create start and end timestamps
_now = datetime.datetime.now()
str_start = str(utc_converter(_now))
_end = _now + timedelta(seconds=10)
str_end = str(utc_converter(_end))
This is an answer which is significant for nowadays (python 3.9 or later).
Use strptime to create a datetime object from the timestring. Add 9 hours with timedelta, and match the time format with the timestring you have.
from datetime import datetime, timedelta
from zoneinfo import ZoneInfo
time_format = "%H:%M:%S"
timestring = datetime.strptime(str(datetime.now() + timedelta(hours=9))[11:19], time_format)
#You can then apply custom time formatting as well as a timezone.
TIMEZONE = [Add a timezone] #https://en.wikipedia.org/wiki/List_of_tz_database_time_zones
custom_time_format = "%H:%M"
time_modification = datetime.fromtimestamp(timestring.timestamp(), ZoneInfo(TIMEZONE)).__format__(custom_time_format)
While I think it's more meaningful to apply a timezone, you don't necessarily need to, so you can also simply do that:
time_format = "%H:%M:%S"
timestring = datetime.strptime(str(datetime.now() + timedelta(hours=9))[11:19], time_format)
time_modification = datetime.fromtimestamp(timestring.timestamp())
datetime
https://docs.python.org/3/library/datetime.html
strftime-and-strptime-format-codes
https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes
timedelta
https://docs.python.org/3/library/datetime.html#datetime.timedelta
zoneinfo
https://docs.python.org/3/library/zoneinfo.html#module-zoneinfo
As an input to an API request I need to get yesterday's date as a string in the format YYYY-MM-DD. I have a working version which is:
yesterday = datetime.date.fromordinal(datetime.date.today().toordinal()-1)
report_date = str(yesterday.year) + \
('-' if len(str(yesterday.month)) == 2 else '-0') + str(yesterday.month) + \
('-' if len(str(yesterday.day)) == 2 else '-0') + str(yesterday.day)
There must be a more elegant way to do this, interested for educational purposes as much as anything else!
You Just need to subtract one day from today's date. In Python datetime.timedelta object lets you create specific spans of time as a timedelta object.
datetime.timedelta(1) gives you the duration of "one day" and is subtractable from a datetime object. After you subtracted the objects you can use datetime.strftime in order to convert the result --which is a date object-- to string format based on your format of choice:
>>> from datetime import datetime, timedelta
>>> yesterday = datetime.now() - timedelta(1)
>>> type(yesterday)
>>> datetime.datetime
>>> datetime.strftime(yesterday, '%Y-%m-%d')
'2015-05-26'
Note that instead of calling the datetime.strftime function, you can also directly use strftime method of datetime objects:
>>> (datetime.now() - timedelta(1)).strftime('%Y-%m-%d')
'2015-05-26'
As a function:
from datetime import datetime, timedelta
def yesterday(frmt='%Y-%m-%d', string=True):
yesterday = datetime.now() - timedelta(1)
if string:
return yesterday.strftime(frmt)
return yesterday
example:
In [10]: yesterday()
Out[10]: '2022-05-13'
In [11]: yesterday(string=False)
Out[11]: datetime.datetime(2022, 5, 13, 12, 34, 31, 701270)
An alternative answer that uses today() method to calculate current date and then subtracts one using timedelta(). Rest of the steps remain the same.
https://docs.python.org/3.7/library/datetime.html#timedelta-objects
from datetime import date, timedelta
today = date.today()
yesterday = today - timedelta(days = 1)
print(today)
print(yesterday)
Output:
2019-06-14
2019-06-13
>>> import datetime
>>> datetime.date.fromordinal(datetime.date.today().toordinal()-1).strftime("%F")
'2015-05-26'
Calling .isoformat() on a date object will give you YYYY-MM-DD
from datetime import date, timedelta
(date.today() - timedelta(1)).isoformat()
I'm trying to use only import datetime based on this answer.
import datetime
oneday = datetime.timedelta(days=1)
yesterday = datetime.date.today() - oneday
I want to compare two date and times with each other and then use that information for other stuff. Like if delta > 23 hours do this, elif delta > 11 hours, do that etc. I thought this would be a reasonable way to write it, but python won't accept it! It says:
ValueError: 'h' is a bad directive in format '%m/%d/%Y%h:%m:%s'
Isn't h the standard way to write hours in Python? :o
My dates are written in this format: "12/28/13 16:49:19", "m/d/y h:m:s" if that's any help!
from datetime import datetime
date_format = "%m/%d/%Y%h:%m:%s"
then=(dictionary["date"])
now= time.strftime("%c")
a = datetime.strptime(str(then), date_format)
b = datetime.strptime(str(now), date_format)
delta = b - a
print(delta.hour)
The 24 hour format is %H, a capital H, not a lowercase. The same for the minutes and seconds. You'll need a space as well, and you have a year format without the century, so use lower-case y:
date_format = "%m/%d/%y %H:%M:%S"
See the strftime() and strptime() behaviour documentation. %h doesn't exist as a format character.
And instead of using time.strftime('%c') to represent now, then parse that again, use:
b = datetime.now()
datetime.timedelta objects do not have an hours attribute; calculate the hours from the total seconds in the delta:
delta = b - a
print(delta.total_seconds() // 60)
or compare the delta object against another timedelta():
if delta > timedelta(hours=23):
Demo:
>>> from datetime import datetime
>>> date_format = "%m/%d/%y %H:%M:%S"
>>> datetime.strptime('12/28/13 16:49:19', date_format)
datetime.datetime(2013, 12, 28, 16, 49, 19)
I am able to get the current time as below:
from datetime import datetime
str(datetime.now())[11:19]
Result
'19:43:20'
Now, I am trying to add 9 hours to the above time, how can I add hours to current time in Python?
from datetime import datetime, timedelta
nine_hours_from_now = datetime.now() + timedelta(hours=9)
#datetime.datetime(2012, 12, 3, 23, 24, 31, 774118)
And then use string formatting to get the relevant pieces:
>>> '{:%H:%M:%S}'.format(nine_hours_from_now)
'23:24:31'
If you're only formatting the datetime then you can use:
>>> format(nine_hours_from_now, '%H:%M:%S')
'23:24:31'
Or, as #eumiro has pointed out in comments - strftime
Import datetime and timedelta:
>>> from datetime import datetime, timedelta
>>> str(datetime.now() + timedelta(hours=9))[11:19]
'01:41:44'
But the better way is:
>>> (datetime.now() + timedelta(hours=9)).strftime('%H:%M:%S')
'01:42:05'
You can refer strptime and strftime behavior to better understand how python processes dates and time field
This works for me working with seconds not hours and also using a function to convert back to UTC time.
from datetime import timezone, datetime, timedelta
import datetime
def utc_converter(dt):
dt = datetime.datetime.now(timezone.utc)
utc_time = dt.replace(tzinfo=timezone.utc)
utc_timestamp = utc_time.timestamp()
return utc_timestamp
# create start and end timestamps
_now = datetime.datetime.now()
str_start = str(utc_converter(_now))
_end = _now + timedelta(seconds=10)
str_end = str(utc_converter(_end))
This is an answer which is significant for nowadays (python 3.9 or later).
Use strptime to create a datetime object from the timestring. Add 9 hours with timedelta, and match the time format with the timestring you have.
from datetime import datetime, timedelta
from zoneinfo import ZoneInfo
time_format = "%H:%M:%S"
timestring = datetime.strptime(str(datetime.now() + timedelta(hours=9))[11:19], time_format)
#You can then apply custom time formatting as well as a timezone.
TIMEZONE = [Add a timezone] #https://en.wikipedia.org/wiki/List_of_tz_database_time_zones
custom_time_format = "%H:%M"
time_modification = datetime.fromtimestamp(timestring.timestamp(), ZoneInfo(TIMEZONE)).__format__(custom_time_format)
While I think it's more meaningful to apply a timezone, you don't necessarily need to, so you can also simply do that:
time_format = "%H:%M:%S"
timestring = datetime.strptime(str(datetime.now() + timedelta(hours=9))[11:19], time_format)
time_modification = datetime.fromtimestamp(timestring.timestamp())
datetime
https://docs.python.org/3/library/datetime.html
strftime-and-strptime-format-codes
https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes
timedelta
https://docs.python.org/3/library/datetime.html#datetime.timedelta
zoneinfo
https://docs.python.org/3/library/zoneinfo.html#module-zoneinfo