I got a probem I am not able to solve for quiet some time and maybe someone of you can help me.
Because it is a more easy code and it's clear what it is good for, I would like to start wit the code:
#Create empty dictionary
lit_dict = {}
#List with different material names
mat_category_list = ['X', 'Y', 'Z', 'Default']
#Fill lit_dict with lists called e.g "lit_names_X" for every material
for mat in mat_category_list:
lit_dict['lit_name_%s'%mat.lower()] = [('Choose Manually','Choose Manually','Choose the value using the button below')]
So far the code is working fine. I get a dictionary (lit_dict) with a key called lit_name_A for every material A stored in the list mat_category_list. Furthermore, every key has the value ('Choose Manually','Choose Manually','Choose the value using the button below'). That's exactly what I want. Every value has to be a tuple.
Now we are getting to the problem. I have a dictionary called mat_properties_A for every material A. These dictionaries look like that e.g.:
mat_properties_A= {'A.Geramy,2000':Material_Property(13700.0,0.38,reference='A.Geramy,2000',mat='Bone')
I now want a loop which adds for every material A the names of every key of the mat_properties_A dictionary as a tuple to my lit_dict to the right list lit_name_A
The loop should look like that:
for mat in mat_category_list:
for lit in mat_properties_A.keys():
lit_dict['lit_value_%s'%mat.lower()] += [tuple([lit]*3)]
My problem is now that the A in the second row above has to be dynamic that means it has to change with the mat loop. I tried to solve that probelm with a setattr() or so but it does not work.
Does anyone has an idea how to solve that problem?
Edit1:
To clearify more what I want to achieve:
I am working with Blender. There I have 2 Dropdown menus. One where I can choose the material I want (e.g. X) and then a second Dorpdown menu where then (based on the choosen material in the first drowpdon) I can choose the corresponding names of literature.
So for example:
Dropdown 1: "X"
Dropdown 2: Shows all Names stored in the list lit_name_x
Tha is why I need a lit_name_x for every material in the mat_category_list. The mat_category_list contains all materials which can be selected in Dropdown Menu 1. And because the user is able to create own materials, with own literature, the whole code has to be independent of the names of the materials.
I hope it is more clear what I want as a "Outcome"
for mat in mat_category_list:
keys = eval("mat_properties_%s.keys()" % A)#here, A is the name from mat
for lit in keys:
lit_dict['lit_value_%s'%mat.lower()] += [tuple([lit]*3)]
Related
I have a list of dictionaries in which keys are "group_names" and values are gene_lists.
I want to update each dictionary with a new list of genes by looping through a species_list.
Here is my pseudocode:
groups=["group1", "group2"]
species_list=["spA", "spB"]
def get_genes(group,sp)
return gene_list
for sp in species_list:
for group in groups:
gene_list[group]=get_genes(group,sp)
gene_list.update(get_genes(group,sp))
The problem with this code is that new genes are replaced/overwritten by the previous ones instead of being added to the dictionary. My question is where should I put the following line. Although, I'm not sure if this is the only problem.
gene_list.update(get_genes(group,sp))
The data I have looks like this dataframe:
data={"group1":["geneA1", "geneA2"],
"group2":[ "geneB1","geneB2"]}
pd.DataFrame.from_dict(data).T
The data I want to create should look like this:
data={"group1":["geneA1", "geneA2", "geneX"],
"group2":[ "geneB1","geneB2", "geneX"]}
pd.DataFrame.from_dict(data).T
So in this case, "gene_x" refers to the new genes obtained by the get_genes function for each species and finally updated to the existing dictionary.
Any help would be much appreciated!!
You need to append to the list in the dictionary entry, not assign it.
Use setdefault() to provide a default empty list if the dictionary key doesn't exist yet.
for sp in species_list:
for group in groups:
gene_list.setdefault(group, []).extend(get_genes(group, sp))
From what I understand, you want to append new gene to each key, in order to do that:
new_gene = "gene_x"
data={"group1":["geneA1", "geneA2"], "group2":[ "geneB1","geneB2"]}
for value in data.values():
value.append(new_gene)
print(data)
You can also use defaultdict where you can append directly (read the docs for that).
I ask the user of my program to input the number of datasets he/she wants to investigate, e.g. three datasets. Accordingly, I should then create three dictionaries (dataset_1, dataset_2, and dataset_3) to hold the values for the various parameters. Since I do not know beforehand the number of datasets the user wants to investigate, I have to create and name the dictionaries within the program.
Apparently, Python does not let me do that. I could not rename the dictionary once it has been created.
I have tried using os.rename("oldname", "newname"), but that only works if I have a file stored on my computer hard disk. I could not get it to work with an object that lives only within my program.
number_sets = input('Input the number of datasets to investigate:')
for dataset in range(number_sets):
init_dict = {}
# create dictionary name for the particular dataset
dict_name = ''.join(['dataset_', str(dataset+1)])
# change the dictionary´s name
# HOW CAN I CHANGE THE DICTIONARY´S NAME FROM "INIT_DICT"
# TO "DATASET_1", WHICH IS THE STRING RESULT FOR DICT_NAME?
I would like to have in the end
dataset_1 = {}
dataset_2 = {}
and so on.
You don't (need to). Keep a list of data sets.
datasets = []
for i in range(number_sets):
init_dict = {}
...
datasets.append(init_dict)
Then you have datasets[0], datasets[1], etc., rather than dataset_1, dataset_2, etc.
Inside the loop, init_dict is set to a brand new empty directory at the top of each iteration, without affecting the dicts added to datasets on previous iterations.
If you want to create variables like that you could use the globals
number_sets = 2
for dataset in range(number_sets):
dict_name = ''.join(['dataset_', str(dataset+1)])
globals() [dict_name] = {}
print(dataset_1)
print(dataset_2)
However this is not a good practice, and it should be avoided, if you need to keep several variables that are similar the best thing to do is to create a list.
You can use a single dict and then add all the data sets into it as a dictionary:
all_datasets = {}
for i in range(number_sets):
all_datasets['dataset'+str(i+1)] = {}
And then you can access the data by using:
all_datasets['dataset_1']
This question gets asked many times in many different variants (this is one of the more prominent ones, for example). The answer is always the same:
It is not easily possible and most of the time not a good idea to create python variable names from strings.
The more easy, approachable, safe and usable way is to just use another dictionary. One of the cool things about dictionaries: any object can become a key / value. So the possibilities are nearly endless. In your code, this can be done easily with a dict comprehension:
number_sets = int(input('Input the number of datasets to investigate:')) # also notice that you have to add int() here
data = {''.join(['dataset_', str(dataset + 1)]): {} for dataset in range(number_sets)}
print(data)
>>> 5
{'dataset_1': {}, 'dataset_2': {}, 'dataset_3': {}, 'dataset_4': {}, 'dataset_5': {}}
Afterwards, these dictionaries can be easily accessed via data[name_of_dataset]. Thats how it should be done.
I'm trying to extract data from a JSON file with Python.
Mainly, I want to pull out the date and time from the "Technicals" section, to put that in one column of a dataframe, as well as pulling the "AKG" number and putting that in the 2nd col of the dataframe. Yes, I've looked at similar questions, but this issue is different. Thanks for your help.
A downNdirty example of the JSON file is below:
{ 'Meta Data': { '1: etc'
'2: etc'},
'Technicals': { '2017-05-04 12:00': { 'AKG': '64.8645'},
'2017-05-04 12:30': { 'AKG': '65.7834'},
'2017-05-04 13:00': { 'AKG': '63.2348'}}}
As you can see, and what's stumping me, is while the date stays the same the time advances. 'AKG' never changes, but the number does. Some of the relevant code I've been using is below. I can extract the date and time, but I can't seem to reach the AKG numbers. Note, I don't need the "AKG", just the number.
I'll mention: I'm creating a DataFrame because this will be easier to work with when creating plots with the data...right? I'm open to an array of lists et al, or anything easier, if that will ultimately help me with the plots.
akg_time = []
akg_akg = []
technicals = akg_data['Technicals'] #akg_data is the entire json file
for item in technicals: #this works
akg_time.append(item)
for item in technicals: #this not so much
symbol = item.get('AKG')
akg_akg.append(symbol)
pp.pprint(akg_akg)
error: 'str' object has no attribute 'get'
You've almost got it. You don't even need the second loop. You can append the akg value in the first one itself:
for key in technicals: # renaming to key because that is a clearer name
akg_time.append(key)
akg_akg.append(technicals[key]['AKG'])
Your error is because you believe item (or key) is a dict. It is not. It is just a string, one of the keys of the technicals dictionary, so you'd actually need to use symbols = technicals[key].get('AKG').
Although Coldspeed answer is right: when you have a dictionary you loop through keys and values like this:
Python 3
for key,value in technicals.items():
akg_time.append(key)
akg_akg.append(value["akg"])
Python 2
for key,value in technicals.iteritems():
akg_time.append(key)
akg_akg.append(value["akg"])
import collections
header_dict = {'account number':'ACCOUNT_name','accountID':'ACCOUNT_name','name':'client','first name':'client','tax id':'tin'}
#header_dict = collections.defaultdict(lambda: 'tin') # attempted use of defaultdict...destroys my dictionary
given_header = ['account number','name','tax id']#,'tax identification number']#,'social security number'
#given_header = ['account number','name','tax identification number']...non working header layout
fileLayout = [header_dict[ting] for ting in given_header if ting] #create if else..if ting exists, add to list...else if not in list, add to dictionary
def getLayout(ting):
global given_header
global fileLayout
return given_header[fileLayout.index(ting)]
print getLayout('ACCOUNT_name')
print getLayout('client')
print getLayout('tin')
rows = zip((getLayout('ACCOUNT_name'),getLayout('client'),getLayout('tin')))
print rows
I am working with many files of random, mixed up layouts/column orders. I have a set template for my db table of 'ACCOUNT_name','client','tin' that I want the files to be ordered in. I have created a dictionary of the possible header/column names I might find in other files as keys and my set header names as values. So, for example, if I wanted to see where to put the column 'account number' from one of my given files, I would type header_dict['account number'].
This would give me the corresponding column from my template, 'ACCOUNT_name'. This works great...I also added another feature. Instead of having to type 'account number'..I made a list comprehension that looks up each value by key.
This list I just created with the 'fileLayout' list comprehension essentially transforms my given file's header into my desired names: ['ACCOUNT_name','client']
That makes life a lot easier...I know that I want to look up 'ACCOUNT_name', or 'client'. Next I run a function 'getLayout' that returns the index of the desired columns I am searching...So if I want to see where my desired column 'ACCOUNT_name' is in the file, I just run the function which is called like this...
getLayout('ACCOUNT_name')
Now at this point, I can easily print the columns to my order...with:
rows = zip((getLayout('ACCOUNT_name'),getLayout('client'),getLayout('tin')))
print rows
The above code gives me [('account number'),('name'),('tax id')], which is exactly what I want...
But what if there is a new header I am not used to ?? Lets use the same example code above but change the list 'given_header' to this:
given_header = ['account number','name','tax identification number']
I most certainly get the key error, KeyError: 'tax identification number' I know I can use defaultdict but when I try to use it with the set value 'tin', I end up overwriting my entire dictionary... What I would ultimately like to end up doing is this...
I would like to create an else within my list comprehension that allows me to standard input dictionary entries if they don't exist. In other words, since 'tax identification number' does not exists as a key, add it as one to my dict and give it the value 'tin' via raw_input. Has anyone ever done or tried anything like this? Any ideas? If you have and have any suggestions, I am all ears. I'm struggling on this issue...
The way I would want to go about this is in the list comprehension..
fileLayout = [header_dict[ting] for ting in given_header if ting else raw_input('add missing key value pair to dictionary')] # or do something of the sort.
In my code, I've created a QTableWidget with 50 columns and 2 rows.
By executing a function, Python put in cells list's elements that I've created before. But, I don't know how to modify these cells.
For example, I want to get the current data of a cell at (x,y) and add an integer. So I've tried :
content = int(self.ui.table.item(X, Y).text()) #I've just strings in my cells
self.ui.table.item(X, Y).setText(str(content + 1)
But that part of code, don't work.
I've tried too :
a=self.ui.table.item(X,Y)
print(a.data(0).toString())
But Python return me :
'NoneType' object has no attribute 'data'
Try this,hope this will work:
val = 21 # integer value
row = X # this is your row number
self.ui.table.insertRow(row) # here you decide in which row
item = QTableWidgetItem(str(val)) # create a new Item
self.ui.table.setItem(row,Y, item)
This will override the value at X,Y index of QTableWidget cell.
if you used QtDesigner to create the user interface, particularly the tables, is probably that you have a instances problem, Qtdesigner create the table (QTablewiget) but does not create cells (QTableWidgetItem) inside the table, these is the reason that when you try to get the item X, Y you got a "noneType" object, I know its sound crazy there is 3 ways to solve these:
1st : you can create the individual items as #zeb show it
2do : fill the cell on QtDesigner with a value, with this Qtdesigner create the tables items
3th : you can crare each element you need to use on the setupUi funciton as :
item = self.table.item(X,Y)
item.setText(_translate("MainWindow", " "))