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importing filename and using regex to change the filename and save back

I have files with filenames as "lsud-ifgufib-1234568789.png" I want to rename this file as digits only which are followed by last "-" and then save them back in the folder.
Basically I want the final filename to be the digits that are followed by "-".
~ path = 'C:/Users/abc/downloads'
for filename in os.listdir(path):
r = re.compile("(\d+)")
newlist = filter(r.match, filename)
print(newlist)
~
How do I proceed further?

Assumptions:
You want to rename files if the file has a hyphen before the number.
The file may or may not have an extention.
If the file has an extention, preserve it.
Then would you please try the following:
import re, os
path = 'C:/Users/abc/downloads'
for filename in os.listdir(path):
m = re.search(r'.*-(\d+.*)', filename)
if m:
os.rename(os.path.join(path, filename), os.path.join(path, m.group(1)))

You could try a regex search followed by a path join:
import re
import os
path = 'C:/Users/abc/downloads'
for filename in os.listdir(path):
os.rename(filename, os.path.join(path, re.search("\d+(?=\D+?$)", filename).group()))

import re
import pathlib
fileName = "lsud-ifgufib-1234568789.png"
_extn = pathlib.Path(fileName).suffix
_digObj = re.compile(r'\d+')
digFileName = ''.join(_digObj.findall(fileName))
replFileName = digFileName + _extn

separate filename after underlining _ os.path

In my path /volume1/xx/ are several files with this character A_test1.pdf, B_test2.pdf, ...I want to seperate the test1 part without path and .pdf.
Im newbie so I tried first with full name
but I got only the "*.pdf" as a text.
What is wrong with the path oder placeholder * ?
splitname = os.path.basename('/volume1/xx/*.pdf')
Edit
I got 2019-01-18_RG-Telekom[] from orign ReT_march - I want 2019-01-18_RG-Telekom_march (text after underlining) xx is a folder
here is the whole code:
#!/usr/bin/env python3
import datetime
import glob
import os
import os.path
SOURCE_PATH = '/volume1/xx'
TARGET_PATH = os.path.join(SOURCE_PATH, 'DMS')
def main():
today = datetime.date.today()
splitnames = [os.path.basename(fpath) for fpath in glob.glob("./xx/*.pdf")]
for prefix, name_part in [
('ReA', 'RG-Amazon'),
('GsA', 'GS-Amazon'),
('ReT', 'RG-Telekom'),
('NoE', 'Notiz-EDV'),
]:
filenames = glob.iglob(os.path.join(SOURCE_PATH, prefix + '*.pdf'))
for old_filename in filenames:
new_filename = os.path.join(TARGET_PATH, '{}_{}_{}.pdf'.format(today, name_part, splitnames))
os.rename(old_filename, new_filename)
if __name__ == '__main__':
main()

Use glob, os.path don't know how to process masks, but glob.glob works:
splitnames = [os.path.basename(fpath) for fpath in glob.glob("./**/*.txt")]
splitnames
Out:
['A_test1.pdf', 'B_test2.pdf']
Output of the glob:
glob.glob("./**/*.txt")
Out:
['./some_folder/A_test1.pdf', './another_folder/B_test2.pdf']
Apply os.path.basename to this list and extract basenames, as it shown above.
Edit
If xx in the path volume1/xx/ is just a folder name, not a mask, you should use following expression:
splitnames = [os.path.basename(fpath) for fpath in glob.glob("./xx/*.txt")]
because ./**/ is expression which masks a folder name and it's unnecessary that case.

How to rename a file to a substring within the filename?

I'm trying to rename the files in a directory that have the substring "Episode.26" by truncating the words before and after the substring
e.g. 'The.Vision.of.Escaflowne.Episode.26.Eternal.Love.1080p.Dual.Audio.Bluray [BC6DDF99].mkv'
The value to be found will always be Episode.## (## two digits)
Desired result: Episode.26.mkv
Current result: Episode.26.Eternal.Love.1080p.Dual.Audio.Bluray [BC6DDF99].mkv'
I removed the first n characters using python; but, I don't know how to isolate 'Episode.26' efficiently
import os
key = "Episode."
for filename in os.listdir("."):
if(key in filename):
index = filename.index(key)
os.rename(filename, filename[index:])

If your filename is always separated by periods then split() might be sufficient:
import os
ext = ".mkv"
ndl = "Episode"
for filename in os.listdir("."):
if ext in filename and ndl in filename:
num = filename.split(ndl, 1)[1].split(" ")[0].split(".")[1]
epi = "{}.{}{}".format(ndl, num, ext)
os.rename(filename, epi)
This should split the name after your needle ("ndl") grab the episode number and rename the file; it should also handle filenames that include spaces in addition to periods or if "Episode.26" is at the end of the string (eg. Some.Movie.Episode.26 [BC6DDF99].mkv).
Result:
Episode.26.mkv

If u'r sure there's two digits after "Episode.", then u can code like this. Otherwise, i'm afraid u should use re or split to get what u want.
import os
key = 'Episode'
for filename in os.listdir("."):
try:
index = filename.index(key)
_, file_extension = os.path.splitext(filename)
new_name = filename[index:index+len(key)+3] + file_extension
os.rename(filename, new_name)
except ValueError:
pass

You could use regular expressions, capture the episode number and file extension and create the new name using such data:
Code
import re
import os
key = "Episode"
regexp = re.compile('.*%s\.(\d\d).*\.(.+)' % key)
for filename in os.listdir("."):
match = regexp.match(filename)
if match:
episode, file_ext = match.group(1), match.group(2)
new_name = key + episode + '.' + file_ext
os.rename(filename, new_name)
This way is more cleaner and flexible. REs are very powerfull. Let me know if this worked for you.

in your code, you can use search instead of match and remove .* at the beginning of re
import re
import os
key = "Episode"
regexp = re.compile('%s\.(\d\d).*\.(.+)' % key)
for filename in os.listdir("."):
match = regexp.search(filename)
if match:
episode, file_ext = match.group(1), match.group(2)
new_name = key + episode + '.' + file_ext
os.rename(filename, new_name)

How to remove all numbers from a file name or a string - Python3

I have a Python script that will walk through all of the directories within the Test Folder(in this case) and will remove all numbers at the beginning of each of the file names. So my question is how would I modify my script in order to remove numbers from the whole file name? Not just the beginning or the end of it.
Thanks,
Alex
import os
for root, dirs, files in os.walk("Test Folder", topdown=True):
for name in files:
if (name.startswith("01") or name.startswith("02") or name.startswith("03") or name.startswith("04") or name.startswith("04") or name.startswith("05") or name.startswith("06") or name.startswith("07") or name.startswith("08") or name.startswith("09") or name[0].isdigit()):
old_filepath = (os.path.join(root, name))
_, new_filename = name.split(" ", maxsplit=1)
new_filepath = (os.path.join(root, new_filename))
os.rename(old_filepath, new_filepath)

Use regular expression, particularly re.sub:
>>> import re
>>> filename = '12name34with56numbers78in9it.txt'
>>> re.sub(r'\d', '', filename)
'namewithnumbersinit.txt'
This replaces everything that matches the \d pattern, i.e. that is a number, with '', i.e. nothing.
If you want to protect the extension, it get's more messy. You have to split the extension from the string, replace numbers in the first part, then join the extension back on. os.path.splitext can help you with that:
>>> filename = '12name34with56numbers78in9it.mp3'
>>> name, ext = os.path.splitext(filename)
>>> re.sub(r'\d+', '', name) + ext
'namewithnumbersinit.mp3'

You can do this:
filename = "this2has8numbers323in5it"
filename = "".join(char for char in filename if not char.isdigit())
No imports necessary.

import os
def rename_files():
# Get files names from the directory
files_names = os.listdir(" file r directory path")
saved_dir = os.chdir(files_name)
# To get cutrrent working directiry name
print os.getcwd() # This is to verify whether you are in correct path
for file_name in files_names:
os.rename(file_name,file_name.translate(None,'0123456789'))
# Above translate function remove all the number from file name
rename_files()

Renaming multiple images with .rename and .endswith

I've been trying to get this to work, but I feel like I'm missing something. There is a large collection of images in a folder that I need to rename just part of the filename. For example, I'm trying to rename the "RJ_200", "RJ_600", and "RJ_60"1 all to the same "RJ_500", while keeping the rest of the filename intact.
Image01.Food.RJ_200.jpg
Image02.Food.RJ_200.jpg
Image03.Basket.RJ_600.jpg
Image04.Basket.RJ_600.jpg
Image05.Cup.RJ_601.jpg
Image06.Cup.RJ_602.jpg
This is what I have so far, but it keeps just giving me the "else" instead of actually renaming any of them:
import os
import fnmatch
import sys
user_profile = os.environ['USERPROFILE']
dir = user_profile + "\Desktop" + "\Working"
print (os.listdir(dir))
for images in dir:
if images.endswith("RJ_***.jpg"):
os.rename("RJ_***.jpg", "RJ_500.jpg")
else:
print ("Arg!")

The Python string method endswith does not do pattern-matching with *, so you're looking for filenames which explicitly include the asterisk character and not finding any.
Try using regular expressions to match your filenames and then building your target filename explicitly:
import os
import re
patt = r'RJ_\d\d\d'
user_profile = os.environ['USERPROFILE']
path = os.path.join(user_profile, "Desktop", "Working")
image_files = os.listdir(path)
for filename in image_files:
flds = filename.split('.')
try:
frag = flds[2]
except IndexError:
continue
if re.match(patt, flds[2]):
from_name = os.path.join(path, filename)
to_name = '.'.join([flds[0], flds[1], 'RJ_500', 'jpg'])
os.rename(from_name, os.path.join(path, to_name))
Note that you need to do your matching with the file's basename and join on the rest of the path later.

You don't need to use .endswith. You can split the image file name up using .split and check the results. Since there are several suffix strings involved, I've put them all into a set for fast membership testing.
import os
import re
import sys
suffixes = {"RJ_200", "RJ_600", "RJ_601"}
new_suffix = "RJ_500"
user_profile = os.environ["USERPROFILE"]
dir = os.path.join(user_profile, "Desktop", "Working")
for image_name in os.listdir(dir):
pieces = image_name.split(".")
if pieces[2] in suffixes:
from_path = os.path.join(dir, image_name)
new_name = ".".join([pieces[0], pieces[1], new_suffix, pieces[3]])
to_path = os.path.join(dir, new_name)
print("renaming {} to {}".format(from_path, to_path))
os.rename(from_path, to_path)