I am trying to click a button that brings up a dialogue box to select a file. inspecting the element it looks like its an input rather than a button. Either way I cannot click it with:
element = browser.find_element_by_id("fileupload")
element.click()
and
browser.find_element_by_id("fileupload").send_keys("\n")
Neither of which seem to work.
Here is what I see when I inspect that element on the page:
<span class="btn btn-success fileinput-button">
<span class="glyphicon glyphicon-upload"></span>
Select and Upload...
<input id="fileupload" name="upfile" accept=".xml" type="file">
</span>
Any assistance help or pointers would be appreciated!
Clicking on a file input usually triggers a file upload dialog. Since you cannot control it with selenium, you need to avoid the dialog being opened by sending keys to the input instead:
browser.find_element_by_id("fileupload").send_keys("path_to_the_file")
See also:
How to deal with file uploading in test automation using selenium or webdriver
How to upload file using Selenium WebDriver in Java
How to upload file ( picture ) with selenium, python
Related
I am trying to upload a file from a specific path in Python.
video_path = 'C:\\Users\\x\\Desktop\\s.mp4'
self.driver.find_element_by_xpath(file_upload).send_keys(video_path)
This works, but it opens this:
I have tried several xpaths, including ones with the word 'input' or other. I tried using this: https://www.tutorialspoint.com/how-to-upload-file-with-selenium-python
Here is screenshot of all the xpaths:
<input type="file" name="Filedata"
button id="select-files-button" type=" (This is the button that press that opens the select file option.)
I'm having an issue clicking on an image using the Chromedriver with Selenium for the following HTML:
<div class="modal_buttons">
<input type="image" name="GoButton" id="GoButton" tabindex=14 title="Continue" alt="Continue" onfocus="SetLastFocus(this.id)" src="https://t4.ftcdn.net/jpg/00/81/83/05/240_F_81830511_aJbF2vH9yufF0UAUFQ83JDnbp0jE5mNV.jpg"
I tried using the following code:
element = driver.find_element_by_css_selector("//div[img/#src='https://t4.ftcdn.net/jpg/00/81/83/05/240_F_81830511_aJbF2vH9yufF0UAUFQ83JDnbp0jE5mNV.jpg']").click()
Selenium is failing everytime, and giving the same list of errors that it can't locate the button. Any ideas how to fix?
Thanks
Try:
driver.find_element_by_xpath("//input[#id='GoButton'][#name='GoButton']").click()
or
driver.find_element_by_xpath("//input[#id='GoButton'][#title='Continue']").click()
or
driver.find_element_by_xpath("//input[#name='GoButton'][#title='Continue']").click()
or
driver.find_element_by_xpath("//input[contains(#src,'240_F_81830511_aJbF2vH9yufF0UAUFQ83JDnbp0jE5mNV.jpg')]")
How can I click file upload page options with python selenium? I mean, I click this <input type="file" id="uploadfile"> with this code: driver.find_element_by_id("uploadfile").click()
then, a small window opens, this window's title is 'File Upload' and I want write on location input in this window. How can I do this? Thanks !
If the file upload option is an input tag and its type is file then you can directly upload the file using send_keys() method in Selenium
e.g.
driver.find_element_by_id("uploadfile").send_keys("D:\test\filename.extension")
Note :enter absolute location of your file
I am testing a textbox and button - the user types in some information to the textbox and then hits the button - the button changes text from "Update" to "Updating" and then back to "Update" once the operation is complete.
I want Selenium to wait until the button returns back to "Update" before continuing.
I have tried various solutions using xpath here is where I am now:
self.wait.until(EC.element_to_be_clickable(By.XPATH, '//button[#id="send_data"][text()="Update"]'))
The HTML of the button is as follows:
<button id="send_data" type="button" class="btn btn-success" onclick="ChangeParam(this,'radio','freq'; return false;">Update</button>
and
<button id="send_data" type="button" class="btn btn-default" onclick="ChangeParam(this,'radio','freq'; return false;">Updating</button>
Where am I going wrong?
This is quite common issue: you should send type_of_locator, "locator_string" as tuple of arguments ((By.XPATH, "//button")), but not as two separate args (By.XPATH, "//button")
Use following code
self.wait.until(EC.element_to_be_clickable((By.XPATH,'//button[#id="send_data"][text()="Update"]')))
Another solution that should work is using EC.invisibility_of_element_located. After clicking Update button, you can wait invisibility of Element which represented of "Updating" state button.
self.wait.until(EC.invisibility_of_element_located((By.CSS_SELECTOR,'button#send_data .btn-default')))
I am very new to Web UI automation, my queries might be very basic.
My UI automation requirement,I have to click on 'Allow' Pop up message. Could you please help me that How I can do this will work, I have given following try, However, unfortunately, these try did not work.
Following things could not worked. :
driver.find_element_by_css_selector('p.instructions.ALLOW').click();
##
#driver.find_element_by_css_selector('p.instructions').click()
document = 'ALLOW'
#driver.find_element_by_xpath("//*[normalize-space()='"+document+"']").click();
#driver.findElement_by_xpath("//span[contains(., \"" + document + "\")]").click();
#driver.find_element_by_xpath("//p[contains(text(),'ALLOW')]/span").click(); ##2
#driver.find_element_by_xpath("//span[contains(text(),'ALLOW')]").click(); ##2
#driver.find_element_by_xpath("//span[contains(text(),'ALLOW')]").click()
#driver.find_element_by_xpath("//span[contains(text(),'Allow')]").click()
#//a[contains(text(), 'Created By Me')]/span
#section.hidden.MouseAllowCameraView
#content = driver.find_element_by_css_selector('section.MouseAllowCameraView').click()
=========HTML Code ===========
<section class="MouseAllowCameraView hidden"><div class="background"></div>
<div class="page">
<div class="content">
<p class="instructions"><bdo dir="ltr">Activate your webcam by clicking <span>**ALLOW**</span><br>at the top of your browser window.</bdo></p>
</div>
<div class="webcam-arrow"></div>
</div>
</section>
===================End HTML Code
After checking the site, your question became more clear to me and its answer too.
Your Site has to be open only in Google Chrome, Once we click on Start Button it pops-up a browser pop-up which request a user to click on 'Allow' to proceed further,
Now here is the actual problem.
Selenium so far is not capable of automating the controls of the Browsers(Favorite bar, Address bar,Menu options) and the window which we get on clicking on 'Start'button is a part of the controls of our chrome browser.
To handle this situation you can use Some third part tools like Sikuli,AutoIT or ROBOT.
I'll suggest to go with Sikuli, with the help of this you will be able to click on Allow button.
Here is the complete Sikuli Link1 and Link2 tutorial.
Please let me know if any questions.