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How to open multiple text files from an array?

I want to open and read several text files. The plan is to find a string in the text files and print the whole line from the string. The thing is, I can´t open the paths from the array.
I hope it is unterstandable what I want to try.
import os
from os import listdir
from os.path import join
from config import cred
path = (r"E:\Utorrent\Leaked_txt")
for filename in os.listdir(path):
list = [os.path.join(path, filename)]
print(list)
for i in range(len(list)-1):
with open(str(list[i], "r")) as f:
for line in f:
if cred in line:
print(line)
Thanks :D

I prefer to use glob when reading several files in a directory
import glob
files = glob.glob(r"E:\Utorrent\Leaked_txt\*.txt") # read all txt files in folder
for file in files: # iterate over files
with open(file, 'r') as f: # read file
for line in f.read(): # iterate over lines in each file
if cred in line: # if some string is in line
print(line) # print the line

With os, you can do something like this:
import os
from config import cred
path = "E:/Utorrent/Leaked_txt"
files = [os.path.join(path, file) for file in os.listdir(path) if file.endswith(".txt")]
for file in files:
with open(file, "r") as f:
for line in f.readlines():
if cred in line:
print(line)
Edit
os.listdir only includes files from the parent directory (specified by path). To get the .txt files from all sub-directories, use the following:
files = list()
for root, _, f in os.walk(path):
files += [os.path.join(root, file) for file in f if file.endswith(".txt")]

Python - loop through subfolders and files in a directory without ignoring the subfolder

I have read all the stack exchange help files on looping through subfolders, as as well as the os documentation, but I am still stuck. I am trying to loop over files in subfolders, open each file, extract the first number in the first line, copy the file to a different subfolder(with the same name but in the output directory) and rename the file copy with the number as a suffix.
import os
import re
outputpath = "C:/Users/Heather/Dropbox/T_Files/Raw_FRUS_Data/Wisconsin_Copies_With_PageNumbers"
inputpath = "C:/Users/Heather/Dropbox/T_Files/Raw_FRUS_Data/FRUS_Wisconsin"
suffix=".txt"
for root, dirs, files in os.walk(inputpath):
for file in files:
file_path = os.path.join(root, file)
foldername=os.path.split(os.path.dirname(file_path))[1]
filebname=os.path.splitext(file)[0]
filename=filebname + "_"
f=open(os.path.join(root,file),'r')
data=f.readlines()
if data is None:
f.close()
else:
with open(os.path.join(root,file),'r') as f:
for line in f:
s=re.search(r'\d+',line)
if s:
pagenum=(s.group())
break
with open(os.path.join(outputpath, foldername,filename+pagenum+suffix), 'w') as f1:
with open(os.path.join(root,file),'r') as f:
for line in f:
f1.write(line)
I expect the result to be copies of the files in the input directory placed in the corresponding subfolder in the output directory, renamed with a suffix, such as "005_2", where 005 is the original file name, and 2 is the number the python code extracted from it.
The error I get seems to indicates that I am not looping through files correctly. I know the code for extracting the first number and renaming the file works because I tested it on a single file. But using os.walk to loop through multiple subfolders is not working, and I can't figure out what I am doing wrong. Here is the error:
File "<ipython-input-1-614e2851f16a>", line 23, in <module>
with open(os.path.join(outputpath, foldername,filename+pagenum+suffix), 'w') as f1:
IOError: [Errno 2] No such file or directory: 'C:/Users/Heather/Dropbox/T_Files/Raw_FRUS_Data/Wisconsin_Copies_With_PageNumbers\\FRUS_Wisconsin\\.dropbox_1473986809.txt'

Well, this isn't eloquent, but it worked
from glob import glob
folderlist=glob("C:\\...FRUS_Wisconsin*\\")
outputpath = "C:\\..\Wisconsin_Copies_With_PageNumbers"
for folder in folderlist:
foldername = str(folder.split('\\')[7])
for root, dirs, files in os.walk(folder):
for file in files:
filebname=os.path.splitext(file)[0]
filename=filebname + "_"
if not filename.startswith('._'):
with open(os.path.join(root,file),'r') as f:
for line in f:
s=re.search(r'\d+',line)
if s:
pagenum=(s.group())
break
with open(os.path.join(outputpath, foldername,filename+pagenum+suffix), 'w') as f1:
with open(os.path.join(root,file),'r') as f:
for line in f:
f1.write(line)

read contents of a file from a list of file with os.listdir() (python)

I need to read the contents of a file from the list of files from a directory with os.listdir. My working scriptlet is as follows:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
with open(filename, 'rU') as f:
t = f.read()
t = t.split()
print(t)
print(t) gives me all the contents from all the files at once present in the directory (path).
But I like to print the contents on first file, then contents of the second and so on, until all the files are read from in dir.
Please guide ! Thanks.

You can print the file name.
Print the content after the file name.
import os
path = "/home/vpraveen/uni_tmp/temp"
for filename in os.listdir(path):
with open(filename, 'rU') as f:
t = f.read()
print filename + " Content : "
print(t)

First, you should find the path of each file using os.path.join(path, filename). Otherwise you'll loop wrong files if you change the variable path. Second, your script already provides the contents of all files starting with the first one. I added a few lines to the script to print the file path and an empty line to see where the contents end and begin:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
filepath = os.path.join(path, filename)
with open(filepath, 'rU') as f:
content = f.read()
print(filepath)
print(content)
print()

os.listdir returns the name of the files only. you need to os.path.join that name with the path the files live in - otherwise python will look for them in your current working directory (os.getcwd()) and if that happens not to be the same as path python will not find the files:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
print(filename)
file_path = os.path.join(path, filename)
print(file_path)
..
if you have pathlib at your disposal you can also:
from pathlib import Path
path = "/Users/Desktop/test/"
p = Path(path)
for file in p.iterdir():
if not file.is_file():
continue
print(file)
print(file.read_text())

How to Save file names and their directories path in a text file using Python

I am trying to find a string that is contained in files under a directory. Then make it to store it's file names and directories under a new text file or something.
I got upto where it is going through a directory and finding a string, then printing a result. But not sure of the next step.
Please help, I'm completely new to coding and python.
import glob, os
#Open a source as a file and assign it as source
source = open('target.txt').read()
filedirectories = []
#locating the source file and printing the directories.
os.chdir("/Users/a1003584/desktop")
for root, dirs, files in os.walk(".", topdown=True):
for name in files:
print(os.path.join(root, name))
if source in open(os.path.join(root, name)).read():
print 'treasure found.'

Don't do a string comparison if your looking for a dictionary. Instead use the json module. Like this.
import json
import os
filesFound = []
def searchDir(dirName):
for name in os.listdir(dirName):
# If it is a file.
if os.isfile(dirName+name):
try:
fileCon = json.load(dirName+name)
except:
print("None json file.")
if "KeySearchedFor" in fileCon:
filesFound.append(dirName+name)
# If it is a directory.
else:
searchDir(dirName+name+'/')
# Change this to the directory your looking in.
searchDir("~/Desktop")
open("~/Desktop/OutFile.txt",'w').write(filesFound)

This should write the output to a csv file
import csv
import os
with open('target.txt') as infile: source = infile.read()
with open("output.csv", 'w') as fout:
outfile = csv.writer(fout)
outfile.writerow("Directory FileName FilePath".split())
for root, dirnames, fnames in os.walk("/Users/a1003584/desktop", topdown=True):
for fname in fnames:
with open(os.path.join(root, fname)) as infile:
if source not in infile.read(): continue
outfile.writerow(root, fname, os.path.join(root, fname))

Python file-IO and zipfile. Trying to loop through all the files in a folder and then loop through the texts in respective file using Python

Trying to extract all the zip files and giving the same name to the folder where all the files are gonna be.
Looping through all the files in the folder and then looping through the lines within those files to write on a different text file.
This is my code so far:
#!usr/bin/env python3
import glob
import os
import zipfile
zip_files = glob.glob('*.zip')
for zip_filename in zip_files:
dir_name = os.path.splitext(zip_filename)[0]
os.mkdir(dir_name)
zip_handler = zipfile.ZipFile(zip_filename, "r")
zip_handler.extractall(dir_name)
path = dir_name
fOut = open("Output.txt", "w")
for filename in os.listdir(path):
for line in filename.read().splitlines():
print(line)
fOut.write(line + "\n")
fOut.close()
This is the error that I encounter:
for line in filename.read().splitlines():
AttributeError: 'str' object has no attribute 'read'

You need to open the file and also join the path to the file, also using splitlines and then adding a newline to each line is a bit redundant:
path = dir_name
with open("Output.txt", "w") as fOut:
for filename in os.listdir(path):
# join filename to path to avoid file not being found
with open(os.path.join(path, filename)):
for line in filename:
fOut.write(line)
You should always use with to open your files as it will close them automatically. If the files are not large you can simply fOut.write(f.read()) and remove the loop.
You also set path = dir_name which means path will be set to whatever the last value of dir_name was in your first loop which may or may not be what you want. You can also use iglob to avoid creating a full list zip_files = glob.iglob('*.zip').