I have a directory that contains a thousand or so txt files. I've read and explored these files with glob (searching for specific strings within the file) and I've appended the filenames of the files of interest to a list in Python, like so:
list_of_chosen_files = ['file2.txt', 'file10.txt', 'file17.txt', ...]
I'll be using this list for other things as well, but now I'm trying to figure out how to use the OS module to cross-reference the filenames in the directory against the list above and, if the filename is in that list, to add "1-" to the beginning of the filename. I've saved "1-" in a variable for reuse as well. Here's what I have so far: -
var = "1-"
import os
for filename in os.listdir("."):
if filename == list_of_chosen_files[:]:
os.rename(filename, var+filename)
print filename
It's running without any errors in anaconda, but nothing's printing and none of the files are getting renamed. I feel like it should be such an easy fix, but I'm concerned about poking around directories with the OS module if I don't really know what I'm doing yet.
Any help would be greatly appreciated! Thanks!
Your issue is this line:
if filename == list_of_chosen_files[:]:
You're comparing a single string (filename) to an entire list (list_of_chosen_files[:] just gives you back the whole list). If you want to check if the filename is in the list, use this:
if filename in list_of_chosen_files:
This will check to see if list_of_chosen_files contains filename.
Error : if filename == list_of_chosen_files[:]:
os.listdir(".")is only giving you back the basename results. Not full path. They don't exist in your current working directory. You would need to join them back with the root:
root = 'full Path of your directory'
for item in os.listdir(root):
fullpath = os.path.join(root, item)
os.rename(fullpath, fullpath.replace('filename', 'var+filename'))
Related
I've got 2 folders, each with a different CSV file inside (both have the same format):
I've written some python code to search within the "C:/Users/Documents" directory for CSV files which begin with the word "File"
import glob, os
inputfile = []
for root, dirs, files in os.walk("C:/Users/Documents/"):
for datafile in files:
if datafile.startswith("File") and datafile.endswith(".csv"):
inputfile.append([os.path.join(root, datafile)])
print(inputfile)
That almost worked as it returns:
[['C:/Users/Documents/Test A\\File 1.csv'], ['C:/Users/Documents/Test B\\File 2.csv']]
Is there any way I can get it to return this instead (no sub list and shows / instead of \):
['C:/Users/Documents/Test A/File 1.csv', 'C:/Users/Documents/Test B/File 2.csv']
The idea is so I can then read both CSV files at once later, but I believe I need to get the list in the format above first.
okay, I will paste an option here.
I made use of os.path.abspath to get the the path before join.
Have a look and see if it works.
import os
filelist = []
for folder, subfolders, files in os.walk("C:/Users/Documents/"):
for datafile in files:
if datafile.startswith("File") and datafile.endswith(".csv"):
filePath = os.path.abspath(os.path.join(folder, datafile))
filelist.append(filePath)
filelist
Result:
['C:/Users/Documents/Test A/File 1.csv','C:/Users/Documents/Test B/File 2.csv']
The problem is to get all the file names in a list that are under a particular directory and in a particular condition.
We have a directory named "test_dir".
There, we have sub directory "sub_dir_1", "sub_dir_2", "sub_dir_3"
and inside of each sub dir, we have some files.
sub_dir_1 has files ['test.txt', 'test.wav']
sub_dir_2 has files ['test_2.txt', 'test.wav']
sub_dir_2 has files ['test_3.txt', 'test_3.tsv']
What I want to get at the end of the day is a list of of the "test.wav" that exist under the "directory" ['sub_dir_1/test.wav', 'sub_dir_2/test.wav']. As you can see the condition is to get every path of 'test.wav' under the mother directory.
mother_dir_name = "directory"
get_test_wav(mother_dir_name)
returns --> ['sub_dir_1/test.wav', 'sub_dir_2/test.wav']
EDITED
I have changed the direction of the problem.
We first have this list of file names
["sub_dir_1/test.wav","sub_dir_2/test.wav","abc.csv","abc.json","sub_dir_3/test.json"]
from this list I would like to get a list that does not contain any path that contains "test.wav" like below
["abc.csv","abc.json","sub_dir_3/test.json"]
You can use glob patterns for this. Using pathlib,
from pathlib import Path
mother_dir = Path("directory")
list(mother_dir.glob("sub_dir_*/*.wav"))
Notice that I was fairly specific about which subdirectories to check - anything starting with "sub_dir_". You can change that pattern as needed to fit your environment.
Use os.walk():
import os
def get_test_wav(folder):
found = []
for root, folders, files in os.walk(folder):
for file in files:
if file == "test.wav":
found.append(os.path.join(root, file))
return found
Or a list comprehension approach:
import os
def get_test_wav(folder):
found = [f"{arr[0]}\\test.wav" for arr in os.walk(folder) if "test.wav" in arr[2]]
return found
I think this might help you How can I search sub-folders using glob.glob module?
The main way to make a list of files in a folder (to make it callable later) is:
file_path = os.path.join(motherdirectopry, 'subdirectory')
list_files = glob.glob(file_path + "/*.wav")
just check that link to see how you can join all sub-directories in a folder.
This will also give you all the file in sub directories that only has .wav at the end:
os.chdir(motherdirectory)
glob.glob('**/*.wav', recursive=True)
I have a list
fileslist=[1.jpg,2.xml,3.png]
I want to search files in list in current working directory
I have tried
listingdir=os.getcwd()
for rootpath,directories,files in os.walk(listingdir):
for file in fileslist:
if file in files:
print("file:{} found".format(file))
I also tried
list=(set(files).intersection(fileslist))
but not worked because of not only one type extentions in files
when I used set it creates a list like following and i don't get the results
f=set(files)
print(f)
#result is
[[1.jpg,2.jpg,....],[1.png,2.png,...],[1.xml,2.xml,.......]]
If you only want to search through the current dir, you can do something like:
files = [f for f in os.listdir() if os.path.isfile(f)]
fileslist = ['1.jpg','2.xml','3.png']
list = (set(files).intersection(fileslist))
Output:
{'1.png'} # it wont always be this, just an example.
You may use os.path.isfile(...). It will check if a certain file exists. It may accept a full path or a filename only (then it will check if the file exists in the current working directory).
import os.path
fileslist=['1.jpg','2.xml','3.png'] # no, it won't work without the quotes!
for f in fileslist:
if os.path.isfile(f):
print("file:{} found".format(f))
I am trying to write a program in python that loops through data from various csv files within a folder. Right now I just want to see that the program can identify the files in a folder but I am unable to have my code print the file names in my folder. This is what I have so far, and I'm not sure what my problem is. Could it be the periods in the folder names in the file path?
import glob
path = "Users/Sarah/Documents/College/Lab/SEM EDS/1.28.20 CZTS hexane/*.csv"
for fname in glob.glob(path):
print fname
No error messages are popping up but nothing will print. Does anyone know what I'm doing wrong?
Are you on a Linux-base system ? If you're not, switch the / for \\.
Is the directory you're giving the full path, from the root folder ? You might need to
specify a FULL path (drive included).
If that still fails, silly but check there actually are files in there, as your code otherwise seems fine.
This code below worked for me, and listed csv files appropriately (see the C:\\ part, could be what you're missing).
import glob
path = "C:\\Users\\xhattam\\Downloads\\TEST_FOLDER\\*.csv"
for fname in glob.glob(path):
print(fname)
The following code gets a list of files in a folder and if they have csv in them it will print the file name.
import os
path = r"C:\temp"
filesfolders = os.listdir(path)
for file in filesfolders:
if ".csv" in file:
print (file)
Note the indentation in my code. You need to be careful not to mix tabs and spaces as theses are not the same to python.
Alternatively you could use os
import os
files_list = os.listdir(path)
out_list = []
for item in files_list:
if item[-4:] == ".csv":
out_list.append(item)
print(out_list)
Are you sure you are using the correct path?
Try moving the python script in the folder when the CSV files are, and then change it to this:
import glob
path = "./*.csv"
for fname in glob.glob(path):
print fname
I'm trying to delete the last several characters of multiple files in a specific directory using the rename function. The code I have written using suggestions on this site looks like it should work, but it returns the error message:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'test1.txt' -> 'test'
And here is my code:
import os
list = os.listdir("C:\\Users\\Jonathan\\Desktop")
for file in list:
if file.startswith("test"):
os.rename(file, file[0:4])
My code shows that for all files beginning with the word "test", delete all characters after it. As I said, to me it looks like it should work, but I am new at Python, and I don't even understand what the error message means.
Are you actually in the folder where you're renaming? If not, the problem is likely that you're looking in the local folder (where you launched the program). Prepend that path to each file name:
import os
cwd = "C:\\Users\\Jonathan\\Desktop"
list = os.listdir(cwd)
for file in list:
if file.startswith("test"):
os.rename(cwd+file, cwd+"test")
As you didn't specify the complete path to your file, it is likely that your program was saving the in your root directory. Also, you should not use list or file as variable names since they shadow two of Python's types.
import os
files_path = "C:\\Users\\Jonathan\\Desktop\\"
lst = os.listdir(files_path)
for file_name in lst:
if file_name.startswith("test"):
os.rename(files_path + file_name, files_path + file_name[:-4])
Try this:
import os
list = os.listdir("C:\\Users\\Jonathan\\Desktop\\")
for file in list:
if file[:4] == "test":
os.renames(list+file, list+file[:4])
And by the way, if you need find the files and rename them recursively(That means will find all directories in that directory). You can use os.walk() like this:
for root, dirs, files in os.walk("C:\\Users\\Jonathan\\Desktop\\"):
for name in files:
if name[:4] == "test":
os.renames(os.path.join(root, name), os.path.join(root, name)[:4])
you need to use os.rename() with existing paths. if your working directory is not the directory containing the file your script will fail. this should work independently of your working directory:
files_path = "C:\\Users\\Jonathan\\Desktop\\"
lst = os.listdir(files_path)
for fle in lst:
if fle.startswith("test"):
os.rename(os.path.join(files_path, fle),
os.path.join(files_path, fle[:4]) )
and avoid using list as a varaible name.