I try to display all the tasks names in the path
C:\WINDOWS\System32\Tasks
This is my code:
path = 'C:\Windows\System32\Tasks'
for file in os.listdir(path):
print file
This is the output:
C:\WINDOWS\System32\Tasks\Microsoft
Can someone see why is this the only output that presented ?
I'm only guessing here, but i'm placing it as the solution:
Your computer has a 64 bit Windows version, but your Python installation is 32 bit.
Due to Microsoft WOW64 redirection, when accessing the C:\WINDOWS\System32\Tasks folder, it is actually accessing C:\WINDOWS\SysWOW64\Tasks, and therefore you can only "see" the Microsoft folder inside.
try use
x = os.popen("tree C:\WINDOWS\System32\Tasks")
x.read()
that should give you some output
Related
Even though there are a handful of threads on this issue, no solutions have helped me, here is the problematic lines of code:
AudioSegment.converter = r'C:/users/user_/appdata/local/packages/pythonsoftwarefoundation.python.3.8_qbz5n2kfra8p0/localcache/local-packages/python38/site-packages/ffmpeg.exe'
AudioSegment.ffprobe = r'C:/users/user_/appdata/local/packages/pythonsoftwarefoundation.python.3.8_qbz5n2kfra8p0/localcache/local-packages/python38/site-packages/ffprobe.exe'
final_voice = AudioSegment.from_mp3(file_path) + AudioSegment.silent(duration=silence_duration)
I have tried different methods to solve this issue, such as adding the paths to ffmpeg.exe and ffprobe.exe but nothing changed after that, other solutions do not make much sense as I am not using the modules they have had issues with and I did not do things they have done.
If you have any ideas please share as I have not found how to do the things AudioSegment does with other modules (by the way this issue has come up in every line of code containing AudioSegment.from_mp3(file_path))
Thanks
The solution is quite simple, you have to add ffmpeg.exe, ffprobe.exe and ffplay.exe into your script directory. Download these exe files from the FFMPEG download page and take them from the bin folder
Adding the ffmpeg files was not an option for me so I dug a little deeper. Short answer:
Change the else clause of get_prober_name() in your local ...\site-packages\pydub\utils.py (line 199 in my current version) to return the absolute path of your ffprobe.exe. After that the following code worked for me:
from pydub import AudioSegment
AudioSegment.converter = 'D:/Stuff/Software/ffmpeg/bin/ffmpeg.exe'
AudioSegment.ffprobe = 'D:/Stuff/Software/ffmpeg/bin/ffprobe.exe' # this does nothing!
mp3_fol = "D:/mp3/"
mp3_file = AudioSegment.from_mp3(mp3_fol + "my.mp3")
I'm using Windows with a unzipped version of ffmpeg (so no installation, Path entry or similar). While the converter method seemed to acutally set a value, the ffprobe method didn't do anything.
The subprocess the script is calling simply calls 'ffprobe' as a program. Which of course will not work if this is not a registered program. So the easiest (and hopefully safest) way to circumvent this behaviour is to set the default prober name to the correct full path (as done above).
I'm trying to get someone else's Python script to run on my computer and part of the script finds a file in the USERPROFILE. Here is that code:
for w in os.walk(os.getenv('USERPROFILE')):
if 'FilenName' in w[1]:
path = str(w[0]) + r'\FilenName\UsrData\Directory\Data'
However, in the above code, the program tries to search in the following directory:
C:\Users\User\AppData\Roaming\
When, in fact, the program should be looking in
C:\Users\User\AppData\Local\
If I replace the problem code with the following, it works, but I need it to run for all USERPROFILEs, not just mine:
path = r'C:\Users\Bill\AppData\Local\FilenName\UsrData\Directory\Data'
What is the solution to this?
Thanks.
I'm not on a windows machine, so this is a bit tricky, but could you find all user profiles using the env var ALLUSERSPROFILE?
Another option may be to replace "Roaming" with "Local" in the string. It's a bit hacky, but can be done:
for w in os.walk(os.getenv('USERPROFILE')):
if 'FilenName' in w[1]:
path = (str(w[0]) + r'\FilenName\UsrData\Directory\Data').replace('Roaming', 'Local')
Good morning, I can indicate how to enter a path of internal hard disk in python, currently use the statement:
file = GETfile() or 'http://**********'
I would like to put a path to a local file, but it does not work, where am I wrong?
file = GETfile() or 'D:\xxx\xxxx\playlist\playlist.m3u'
\ is a escape character. You have three options.
1) use /. This, as a bonus works for linux as well:
'D:/xxx/xxxx/playlist/playlist.m3u'
2) escape the backslash
'D:\\xxx\\xxxx\\playlist\\playlist.m3u'
3) use raw strings:
r'D:\xxx\xxxx\playlist\playlist.m3u'
A correct answer is already given, but some additional information when working with local drive paths on Windows operating system.
Personally I would go with the r'D:\dir\subdir\filename.ext' format, however the other two methods already mentioned are valid as well.
Furthermore, file operations on Windows are limited by Explorer to a 256 character limit. Longer path names will usually result in an OS error.
However there is a workaround, by pre fixing "\\?\" to a long path.
Example of a path which does not work:
D:\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\filename.ext
Same file path which does work:
\\?\D:\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\reallyreallyreallyreallyreallylonglonglonglongdir\filename.ext
so the following code I use to change filenames to include the "\\?\":
import os
import platform
def full_path_windows(filepath):
if platform.system() == 'Windows':
if filepath[1:3] == ':\\':
return u'\\\\?\\' + os.path.normcase(filepath)
return os.path.normcase(filepath)
I use this for every path to file (or directories), it will return the path with a prefix. The path does not need to exist; so you can use this also before you create a file or directory, to ensure you are not running into the Windows Explorer limitations.
HTH
I feel like I am taking crazy pills. So for security on an api at work I am using, I have to read 2 things from the registry, that I then pass to suds. The problem is with reading the registry values. No matter what I do, I get "Error2 the system cannot find the file specified". I know that the registry file is there, yet it won't let me read it. I have tried the code below on 2 different 2008 r2 servers. On one windows 7 box, I am able to read the values...but only on one machine. Below is the code, with the actual directory I need changed(to protect anonymity)
from _winreg import *
key = OpenKey(HKEY_LOCAL_MACHINE, r"Software\a\b", 0, KEY_ALL_ACCESS)
devguid = QueryValueEx(key, "DeviceID")
devid = QueryValueEx(key, "DeviceGUID")
devnm = socket.gethostname()
If I change the directory to something other than \a\b, it works fine. I have verified that the permissions on these directories are the exact same as directories I can read from.
Also, I can run the following command from cmd and get the output I need:
reg query HKLM\software\a\b /v DeviceGUID
But when I run it from a python script, it says cannot find file specified.
import os
cmd = "reg query HKEY_LOCAL_MACHINE\software\a\b /v DeviceGUID"
a = os.system(cmd)
print a
Running my script as admin or anything doesn't help. For some reason, python is unable to try and ready registry....
First of all you do need to make sure that your backslashes are suitably escaped, or use raw strings as per the first code sample. I'm going to assume that you've done that.
The most likely explanation is that you use 32 bit Python on a 64 bit system. And so are subject to the registry redirector serving up the 32 bit view of the registry.
Either use 64 bit Python, or specifically open they key with a 64 bit view. Do the latter by specifying the KEY_WOW64_64KEY flag.
In my script I want to be able, in the end, to be able to download all files in a directory and all sub-directories... So I am trying FTPLIB. I'm trying to call dir of my ftp server and put it into a variable, but I get NONETYPE?! I can connect to the server and when I call directory = session.dir() It displays a kind of matrix style output in the console with files, read/write perms, dates, etc.... But when I then try to print Directory all I seem to get is "None". My initial idea was to for each item in the directory download them to my computer, but I can't seem to get a list of the directory!
directory = session.dir()
print(str(directory))
Sorry for the long and probably trivial explanation, but I have become a little bit too frustrated.
Any help would be very much appreciated!
-Clem
First, read this. http://docs.python.org/library/ftplib.html#ftplib.FTP.nlst
Then, try this:
directory = session.nlst()
print(directory)
Note.
You don't need to do print(str(...)). The print function gets the string representation for you.
In the official docs, the very first example shows how to do what you need: use .retrlines('LIST') to read the output of LIST command.
Another way is to use .nlst().