I would like to add a fourth dimension to the scatter plot by defining the ellipticity of the markers depending on a variable. Is that possible somehow ?
EDIT:
I would like to avoid a 3D-plot. In my opinion these plots are usually not very informative.
You can place Ellipse patches directly onto your axes, as demonstrated in this matplotlib example. To adapt it to use eccentricity as your "third dimension") keeping the marker area constant:
from pylab import figure, show, rand
from matplotlib.patches import Ellipse
import numpy as np
import matplotlib.pyplot as plt
N = 25
# ellipse centers
xy = np.random.rand(N, 2)*10
# ellipse eccentrities
eccs = np.random.rand(N) * 0.8 + 0.1
fig = plt.figure()
ax = fig.add_subplot(111, aspect='equal')
A = 0.1
for pos, e in zip(xy, eccs):
# semi-minor, semi-major axes, b and a:
b = np.sqrt(A/np.pi * np.sqrt(1-e**2))
a = A / np.pi / b
ellipse = Ellipse(xy=pos, width=2*a, height=2*b)
ax.add_artist(ellipse)
ax.set_xlim(0, 10)
ax.set_ylim(0, 10)
show()
Of course, you need to scale your marker area to your x-, y- values in this case.
You can use colorbar as the 4th dimension to your 3D plot. One example is as shown below:
import matplotlib.cm as cmx
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import matplotlib
import numpy as np
def scatter3d(x,y,z, cs, colorsMap='jet'):
cm = plt.get_cmap(colorsMap)
cNorm = matplotlib.colors.Normalize(vmin=min(cs), vmax=max(cs))
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=cm)
fig = plt.figure()
ax = Axes3D(fig)
ax.scatter(x, y, z, c=scalarMap.to_rgba(cs))
scalarMap.set_array(cs)
fig.colorbar(scalarMap,label='Test')
plt.show()
x = np.random.uniform(0,1,50)
y = np.random.uniform(0,1,50)
z = np.random.uniform(0,1,50)
so scatter3D(x,y,z,x+y) produces:
with x+y being the 4th dimension shown in color. You can add your calculated ellipticity depending on your specific variable instead of x+y to get what you want.
To change the ellipticity of the markers you will have to create them manually as such a feature is not implemented yet. However, I believe you can show 4 dimensions with a 2D scatter plot by using color and size as additional dimensions. You will have to take care of the scaling from data to marker size yourself. I added a simple function to handle that in the example below:
import matplotlib.pyplot as plt
import numpy as np
data = np.random.rand(60,4)
def scale_size(data, data_min=None, data_max=None, size_min=10, size_max=60):
# if the data limits are set to None we will just infer them from the data
if data_min is None:
data_min = data.min()
if data_max is None:
data_max = data.max()
size_range = size_max - size_min
data_range = data_max - data_min
return ((data - data_min) * size_range / data_range) + size_min
plt.scatter(data[:,0], data[:,1], c=data[:,2], s=scale_size(data[:,3]))
plt.colorbar()
plt.show()
Result:
Related
I have a problem very similar to this question. The answer works very well for plotting the voxels. However, I need to find a way to colour the voxels according to a colormap (of type 'jet') which is based on the 5x1 array called "variable". I also need to associate a logarithmic colorbar with that 3D plot.
Thanks in advance!
I found a solution myself. I will post the code here in case somebody has the same problem.
I added two changes to the problem conditions:
The voxels are rectangular prisms of custom dimensions (a,b,c) instead of simple cubes.
Instead of "variable", i defined an array called "Ivec", which has more suitable values for displaying the logarithmic colormap.
If one wants to display a linear colormap, he/she can simply uncomment the line commented as "linear scale colormap" and comment/delete the line commented as "log scale colormap"
import numpy as np
import matplotlib
import matplotlib.cm as cmx
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import pandas as pd
df = pd.DataFrame({"x": [14630, 14630, 14360, 14360, 14360], "y" : [21750, 21770, 21790, 21930, 21950], "z" : [4690, 4690, 4690, 5290, 5270]})
Ivec = np.array([1, 10, 100, 1000, 10000])
def get_cube():
phi = np.arange(1,10,2)*np.pi/4
Phi, Theta = np.meshgrid(phi, phi)
x = np.cos(Phi)*np.sin(Theta)
y = np.sin(Phi)*np.sin(Theta)
z = np.cos(Theta)/np.sqrt(2)
return x,y,z
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
a = 25
b = 8
c = 14
ax.view_init(azim=0, elev=0)
cm = plt.get_cmap('jet')
#cNorm = matplotlib.colors.Normalize(vmin=min(Ivec), vmax=max(Ivec))#linear scale colormap
cNorm = matplotlib.colors.LogNorm(vmin=min(Ivec), vmax=max(Ivec)) #log scale colormap
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=cm)
scalarMap.set_array(Ivec)
fig.colorbar(scalarMap)
cmapRgba=scalarMap.to_rgba(Ivec)
for i in df.index:
x,y,z = get_cube()
# Change the centroid of the cube from zero to values in data frame
x = x*a + df.x[i]
y = y*b + df.y[i]
z = z*c + df.z[i]
ax.plot_surface(x, y, z, color = cmapRgba[i])
ax.set_zlabel("z")
plt.xlabel("x")
plt.ylabel("y")
plt.show()
I have a sequence of line plots for two variables (x,y) for a number of different values of a variable z. I would normally add the line plots with legends like this:
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number.
legns = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = (z,0,0))
legns.append("z = %f"%(z))
ax.legends(legns)
plt.show()
But I have too many graphs and the legends will cover the graph. I'd rather have a colorbar indicating the value of z corresponding to the color. I can't find anything like that in the galery and all my attempts do deal with the colorbar failed. Apparently I must create a collection of plots before trying to add a colorbar.
Is there an easy way to do this? Thanks.
EDIT (clarification):
I wanted to do something like this:
import matplotlib.pyplot as plt
import matplotlib.cm as cm
fig = plt.figure()
ax = fig.add_subplot(111)
mycmap = cm.hot
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number between 0 and 1
plots = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = mycmap(z))
plots.append(pl)
fig.colorbar(plots)
plt.show()
But this won't work according to the Matplotlib reference because a list of plots is not a "mappable", whatever this means.
I've created an alternative plot function using LineCollection:
def myplot(ax,xs,ys,zs, cmap):
plot = lc([zip(x,y) for (x,y) in zip(xs,ys)], cmap = cmap)
plot.set_array(array(zs))
x0,x1 = amin(xs),amax(xs)
y0,y1 = amin(ys),amax(ys)
ax.add_collection(plot)
ax.set_xlim(x0,x1)
ax.set_ylim(y0,y1)
return plot
xs and ys are lists of lists of x and y coordinates and zs is a list of the different conditions to colorize each line. It feels a bit like a cludge though... I thought that there would be a more neat way to do this. I like the flexibility of the plt.plot() function.
(I know this is an old question but...) Colorbars require a matplotlib.cm.ScalarMappable, plt.plot produces lines which are not scalar mappable, therefore, in order to make a colorbar, we are going to need to make a scalar mappable.
Ok. So the constructor of a ScalarMappable takes a cmap and a norm instance. (norms scale data to the range 0-1, cmaps you have already worked with and take a number between 0-1 and returns a color). So in your case:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(min=0, max=1))
plt.colorbar(sm)
Because your data is in the range 0-1 already, you can simplify the sm creation to:
sm = plt.cm.ScalarMappable(cmap=my_cmap)
EDIT: For matplotlib v1.2 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v1.3 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v3.1 or greater simplifies to:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
plt.colorbar(sm)
Here's one way to do it while still using plt.plot(). Basically, you make a throw-away plot and get the colorbar from there.
import matplotlib as mpl
import matplotlib.pyplot as plt
min, max = (-40, 30)
step = 10
# Setting up a colormap that's a simple transtion
mymap = mpl.colors.LinearSegmentedColormap.from_list('mycolors',['blue','red'])
# Using contourf to provide my colorbar info, then clearing the figure
Z = [[0,0],[0,0]]
levels = range(min,max+step,step)
CS3 = plt.contourf(Z, levels, cmap=mymap)
plt.clf()
# Plotting what I actually want
X=[[1,2],[1,2],[1,2],[1,2]]
Y=[[1,2],[1,3],[1,4],[1,5]]
Z=[-40,-20,0,30]
for x,y,z in zip(X,Y,Z):
# setting rgb color based on z normalized to my range
r = (float(z)-min)/(max-min)
g = 0
b = 1-r
plt.plot(x,y,color=(r,g,b))
plt.colorbar(CS3) # using the colorbar info I got from contourf
plt.show()
It's a little wasteful, but convenient. It's also not very wasteful if you make multiple plots as you can call plt.colorbar() without regenerating the info for it.
Here is a slightly simplied example inspired by the top answer given by Boris and Hooked (Thanks for the great idea!):
1. Discrete colorbar
Discrete colorbar is more involved, because colormap generated by mpl.cm.get_cmap() is not a mappable image needed as a colorbar() argument. A dummie mappable needs to generated as shown below:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
cmap = mpl.cm.get_cmap('jet', n_lines)
fig, ax = plt.subplots(dpi=100)
# Make dummie mappable
dummie_cax = ax.scatter(c, c, c=c, cmap=cmap)
# Clear axis
ax.cla()
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(dummie_cax, ticks=c)
plt.show();
This will produce a plot with a discrete colorbar:
2. Continuous colorbar
Continuous colorbar is less involved, as mpl.cm.ScalarMappable() allows us to obtain an "image" for colorbar().
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
norm = mpl.colors.Normalize(vmin=c.min(), vmax=c.max())
cmap = mpl.cm.ScalarMappable(norm=norm, cmap=mpl.cm.jet)
cmap.set_array([])
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap.to_rgba(i + 1))
fig.colorbar(cmap, ticks=c)
plt.show();
This will produce a plot with a continuous colorbar:
[Side note] In this example, I personally don't know why cmap.set_array([]) is necessary (otherwise we'd get error messages). If someone understand the principles under the hood, please comment :)
As other answers here do try to use dummy plots, which is not really good style, here is a generic code for a
Discrete colorbar
A discrete colorbar is produced in the same way a continuous colorbar is created, just with a different Normalization. In this case a BoundaryNorm should be used.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1., n_lines + 1)
cmap = plt.get_cmap("jet", len(c))
norm = matplotlib.colors.BoundaryNorm(np.arange(len(c)+1)+0.5,len(c))
sm = plt.cm.ScalarMappable(norm=norm, cmap=cmap)
sm.set_array([]) # this line may be ommitted for matplotlib >= 3.1
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(sm, ticks=c)
plt.show()
How can I set the colormap in relation to the radius of the figure?
And how can I close the ends of the cylinder (on the element, not the top and bottom bases)?
My script:
import numpy as np
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from math import sin, cos, pi
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
h, w = 60,30
znew = np.random.randint(low=90, high=110, size=(60,30))
theta = np.linspace(0,2*pi, h)
Z = np.linspace(0,1,w)
Z,theta = np.meshgrid(Z, theta)
R = 1
X = (R*np.cos(theta))*znew
Y = (R*np.sin(theta))*znew
ax1 = ax.plot_surface(X,Y,Z,linewidth = 0, cmap="coolwarm",
vmin= 80,vmax=130, shade = True, alpha = 0.75)
fig.colorbar(ax1, shrink=0.9, aspect=5)
plt.show()
First you need to use the facecolors keyword argument of plot_surface to draw your surface with arbitrary (non-Z-based) colours. You have to pass an explicit RGBA colour four each point, which means we need to sample a colormap object with the keys given by the radius at every point. Finally, this will break the mappable property of the resulting surface, so we will have to construct the colorbar by manually telling it to use our radii for colours:
import numpy as np
from matplotlib import pyplot as plt
import matplotlib.cm as cm
from matplotlib.colors import Normalize
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
h, w = 60,30
#znew = np.random.randint(low=90, high=110, size=(h,w))
theta = np.linspace(0,2*np.pi, h)
Z = np.linspace(0,1,w)
Z,theta = np.meshgrid(Z, theta)
znew = 100 + 10*np.cos(theta/2)*np.cos(2*Z*np.pi)
R = 1
X = (R*np.cos(theta))*znew
Y = (R*np.sin(theta))*znew
true_radius = np.sqrt(X**2 + Y**2)
norm = Normalize()
colors = norm(true_radius) # auto-adjust true radius into [0,1] for color mapping
cmap = cm.get_cmap("coolwarm")
ax.plot_surface(X, Y, Z, linewidth=0, facecolors=cmap(colors), shade=True, alpha=0.75)
# the surface is not mappable, we need to handle the colorbar manually
mappable = cm.ScalarMappable(cmap=cmap)
mappable.set_array(colors)
fig.colorbar(mappable, shrink=0.9, aspect=5)
plt.show()
Note that I changed the radii to something smooth for a less chaotic-looking result. The true_radius arary contains the actual radii in data units, which after normalization becomes colors (essentially colors = (true_radius - true_radius.min())/true_radius.ptp()).
The result:
Finally, note that I generated the radii such that the cylinder doesn't close seamlessly. This mimicks your random example input. There's nothing you can do about this as long as the radii are not 2π-periodic in theta. This has nothing to do with visualization, this is geometry.
I have a 3d plot made using matplotlib. I now want to fill the vertical space between the drawn line and the x,y axis to highlight the height of the line on the z axis. On a 2d plot this would be done with fill_between but there does not seem to be anything similar for a 3d plot. Can anyone help?
here is my current code
from stravalib import Client
import matplotlib as mpl
import numpy as np
import matplotlib.pyplot as plt
... code to get the data ....
mpl.rcParams['legend.fontsize'] = 10
fig = plt.figure()
ax = fig.gca(projection='3d')
zi = alt
x = df['x'].tolist()
y = df['y'].tolist()
ax.plot(x, y, zi, label='line')
ax.legend()
plt.show()
and the current plot
just to be clear I want a vertical fill to the x,y axis intersection NOT this...
You're right. It seems that there is no equivalent in 3D plot for the 2D plot function fill_between. The solution I propose is to convert your data in 3D polygons. Here is the corresponding code:
import math as mt
import matplotlib.pyplot as pl
import numpy as np
import random as rd
from mpl_toolkits.mplot3d import Axes3D
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
# Parameter (reference height)
h = 0.0
# Code to generate the data
n = 200
alpha = 0.75 * mt.pi
theta = [alpha + 2.0 * mt.pi * (float(k) / float(n)) for k in range(0, n + 1)]
xs = [1.0 * mt.cos(k) for k in theta]
ys = [1.0 * mt.sin(k) for k in theta]
zs = [abs(k - alpha - mt.pi) * rd.random() for k in theta]
# Code to convert data in 3D polygons
v = []
for k in range(0, len(xs) - 1):
x = [xs[k], xs[k+1], xs[k+1], xs[k]]
y = [ys[k], ys[k+1], ys[k+1], ys[k]]
z = [zs[k], zs[k+1], h, h]
#list is necessary in python 3/remove for python 2
v.append(list(zip(x, y, z)))
poly3dCollection = Poly3DCollection(v)
# Code to plot the 3D polygons
fig = pl.figure()
ax = Axes3D(fig)
ax.add_collection3d(poly3dCollection)
ax.set_xlim([min(xs), max(xs)])
ax.set_ylim([min(ys), max(ys)])
ax.set_zlim([min(zs), max(zs)])
ax.set_xlabel("x")
ax.set_ylabel("y")
ax.set_zlabel("z")
pl.show()
It produces the following figure:
I hope this will help you.
I have a sequence of line plots for two variables (x,y) for a number of different values of a variable z. I would normally add the line plots with legends like this:
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number.
legns = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = (z,0,0))
legns.append("z = %f"%(z))
ax.legends(legns)
plt.show()
But I have too many graphs and the legends will cover the graph. I'd rather have a colorbar indicating the value of z corresponding to the color. I can't find anything like that in the galery and all my attempts do deal with the colorbar failed. Apparently I must create a collection of plots before trying to add a colorbar.
Is there an easy way to do this? Thanks.
EDIT (clarification):
I wanted to do something like this:
import matplotlib.pyplot as plt
import matplotlib.cm as cm
fig = plt.figure()
ax = fig.add_subplot(111)
mycmap = cm.hot
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number between 0 and 1
plots = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = mycmap(z))
plots.append(pl)
fig.colorbar(plots)
plt.show()
But this won't work according to the Matplotlib reference because a list of plots is not a "mappable", whatever this means.
I've created an alternative plot function using LineCollection:
def myplot(ax,xs,ys,zs, cmap):
plot = lc([zip(x,y) for (x,y) in zip(xs,ys)], cmap = cmap)
plot.set_array(array(zs))
x0,x1 = amin(xs),amax(xs)
y0,y1 = amin(ys),amax(ys)
ax.add_collection(plot)
ax.set_xlim(x0,x1)
ax.set_ylim(y0,y1)
return plot
xs and ys are lists of lists of x and y coordinates and zs is a list of the different conditions to colorize each line. It feels a bit like a cludge though... I thought that there would be a more neat way to do this. I like the flexibility of the plt.plot() function.
(I know this is an old question but...) Colorbars require a matplotlib.cm.ScalarMappable, plt.plot produces lines which are not scalar mappable, therefore, in order to make a colorbar, we are going to need to make a scalar mappable.
Ok. So the constructor of a ScalarMappable takes a cmap and a norm instance. (norms scale data to the range 0-1, cmaps you have already worked with and take a number between 0-1 and returns a color). So in your case:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(min=0, max=1))
plt.colorbar(sm)
Because your data is in the range 0-1 already, you can simplify the sm creation to:
sm = plt.cm.ScalarMappable(cmap=my_cmap)
EDIT: For matplotlib v1.2 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v1.3 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v3.1 or greater simplifies to:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
plt.colorbar(sm)
Here's one way to do it while still using plt.plot(). Basically, you make a throw-away plot and get the colorbar from there.
import matplotlib as mpl
import matplotlib.pyplot as plt
min, max = (-40, 30)
step = 10
# Setting up a colormap that's a simple transtion
mymap = mpl.colors.LinearSegmentedColormap.from_list('mycolors',['blue','red'])
# Using contourf to provide my colorbar info, then clearing the figure
Z = [[0,0],[0,0]]
levels = range(min,max+step,step)
CS3 = plt.contourf(Z, levels, cmap=mymap)
plt.clf()
# Plotting what I actually want
X=[[1,2],[1,2],[1,2],[1,2]]
Y=[[1,2],[1,3],[1,4],[1,5]]
Z=[-40,-20,0,30]
for x,y,z in zip(X,Y,Z):
# setting rgb color based on z normalized to my range
r = (float(z)-min)/(max-min)
g = 0
b = 1-r
plt.plot(x,y,color=(r,g,b))
plt.colorbar(CS3) # using the colorbar info I got from contourf
plt.show()
It's a little wasteful, but convenient. It's also not very wasteful if you make multiple plots as you can call plt.colorbar() without regenerating the info for it.
Here is a slightly simplied example inspired by the top answer given by Boris and Hooked (Thanks for the great idea!):
1. Discrete colorbar
Discrete colorbar is more involved, because colormap generated by mpl.cm.get_cmap() is not a mappable image needed as a colorbar() argument. A dummie mappable needs to generated as shown below:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
cmap = mpl.cm.get_cmap('jet', n_lines)
fig, ax = plt.subplots(dpi=100)
# Make dummie mappable
dummie_cax = ax.scatter(c, c, c=c, cmap=cmap)
# Clear axis
ax.cla()
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(dummie_cax, ticks=c)
plt.show();
This will produce a plot with a discrete colorbar:
2. Continuous colorbar
Continuous colorbar is less involved, as mpl.cm.ScalarMappable() allows us to obtain an "image" for colorbar().
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
norm = mpl.colors.Normalize(vmin=c.min(), vmax=c.max())
cmap = mpl.cm.ScalarMappable(norm=norm, cmap=mpl.cm.jet)
cmap.set_array([])
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap.to_rgba(i + 1))
fig.colorbar(cmap, ticks=c)
plt.show();
This will produce a plot with a continuous colorbar:
[Side note] In this example, I personally don't know why cmap.set_array([]) is necessary (otherwise we'd get error messages). If someone understand the principles under the hood, please comment :)
As other answers here do try to use dummy plots, which is not really good style, here is a generic code for a
Discrete colorbar
A discrete colorbar is produced in the same way a continuous colorbar is created, just with a different Normalization. In this case a BoundaryNorm should be used.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1., n_lines + 1)
cmap = plt.get_cmap("jet", len(c))
norm = matplotlib.colors.BoundaryNorm(np.arange(len(c)+1)+0.5,len(c))
sm = plt.cm.ScalarMappable(norm=norm, cmap=cmap)
sm.set_array([]) # this line may be ommitted for matplotlib >= 3.1
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(sm, ticks=c)
plt.show()