I'm using openpyxl for the first time. I have to read excel file, then after manipulation, populate the result on three different excel sheets -> sheet_T, sheet_D and sheet_U. I created three sheets using openpyxl as follows-
sheet_T = filename2.create_sheet(0)
sheet_T.title = "Target First"
sheet_D = filename2.create_sheet(1)
sheet_D.title = "Distractor First"
sheet_U = filename2.create_sheet(2)
sheet_U.title = "Unclassified"
I used xlwt to do it but there is a constraint of 256 columns. Hence, I used openpyxl. The below code is written by using xlwt-
sheet_T.write(row_first, col_target, Name_Target)
sheet_D.write(row_first, col_target, Name_Target)
sheet_U.write(row_first, col_target, Name_Target)
How do I write the same thing by using openpyxl? All the documentation I read is how to write on a specific cell not sheet.
Many thanks for the help!
You need to create another sheet:
from openpyxl.workbook import Workbook
from openpyxl.writer.excel import ExcelWriter
wb = Workbook()
ws0 = wb.worksheets[0]
ws0.title = 'My Sheet 1'
ws1 = wb.create_sheet()
ws1.title = 'My Sheet 2'
ws2 = wb.create_sheet()
ws2.title = 'My Sheet 3'
Now you can write to the different sheets:
cell_ws0_a1 = ws0.cell('A1')
cell_ws0_a1.value = 'Wrote to cell in 1st sheet.'
cell_ws1_a1 = ws1.cell('A1')
cell_ws1_a1.value = 'Wrote to cell in 2nd sheet.'
cell_ws2_a1 = ws2.cell('A1')
cell_ws2_a1.value = 'Wrote to cell in 3rd sheet.'
writer = ExcelWriter(workbook=wb)
writer.save('example.xlsx')
There is only one sheet in a workbook by default. wb.create_sheet() creates a second sheet.
I would like to make a correction in the code for smooth running-
from openpyxl.workbook import Workbook
from openpyxl.writer.excel import ExcelWriter
wb = Workbook()
ws0 = wb.worksheets[0]
ws0.title = 'My Sheet 1'
ws1 = wb.create_sheet()
ws1.title = 'My Sheet 2'
ws2 = wb.create_sheet()
ws2.title = 'My Sheet 3
v1 = ws1.cell(row=1, column=1)
v1.value = "Hello"
(Basically insert values in this manner instead)
And then end with-
writer = ExcelWriter(wb, 'file.xlsx')
wb.save('file.xlsx')
Hope this helps :)
Related
Code :
wb = Workbook()
sdwbb = load_workbook(sdpath)
filename = os.path.basename(sdpath)
bulan = "September"
try:
sdp = sdwbb[bulan]
except:
sdwbb.create_sheet(bulan)
wb.save(filename)
time.sleep(0.5)
sdp = sdwbb[bulan]
cell_one = sdp['F1']
cell_one.value = 'test'
sdwbb.save(filename)
for your information I doesn't get any error but its doesn't write anything cell f1 sheet September
what I trying to do is to write on specific workbook ,sheet ,and cell
This is my code to write "test" in cel F1 (in the current sheet) in the file test.xlxs in the same folder:
from openpyxl import Workbook, load_workbook
wb = load_workbook("test.xlsx")
ws = wb.active
ws["F1"] = "test"
wb.save("test.xlsx")
print("done")
It's as easy as that :).
Also, you should devenitly check out the documentation of openpyxl: https://openpyxl.readthedocs.io/en/stable/tutorial.html#create-a-workbook
wb_cover = xw.Book()
wb_table = xw.Book()
wb1 = xw.Book(path1)
ws1 = wb1.sheets("Table")
ws2 = wb1.sheets("Cover")
ws1.api.Copy(Before=wb_table.sheets(1).api)
ws2.api.Copy(Before=wb_cover.sheets(1).api)
When the sheet gets copied it keeps the same name also on the new file. Is there the possibility to rename the sheets?
I can see all the sheet names when i use
wb.get_sheet_names()
now i would like to rename all the sheets one after the other to numbers i.e first sheet to 1, second sheet to 2 and so on.
Loop through each sheet and set the title to whatever you want.
from openpyxl import load_workbook
wb = load_workbook('test.xlsx')
sheets = wb.get_sheet_names()
counter = 0
for sheet in sheets:
ss_sheet = wb.get_sheet_by_name(sheet)
ss_sheet.title = str(counter)
wb.save("file.xlsx")
counter+= 1
from openpyxl import load_workbook
work_book = load_workbook('test.xlsx')
sheets = work_book.get_sheet_names()
name = ['Name1', 'Name2', 'Name3']
index = 0
for sheet in sheets:
sheetname = work_book.get_sheet_by_name(sheet)
sheetname.title = str(name[index])
work_book.save("renamed.xlsx")
index += 1
I generate an xlsx file with lots of sheets and I want to take me at specific position when I open it manually with Excel. This function does the job but for one sheet only. How can I apply it to all of the sheets in workbook?
import win32com.client
def select_cell():
xl = win32com.client.gencache.EnsureDispatch('Excel.Application')
wb = xl.Workbooks.Open(r'H:\Files\1.xlsx')
ws = xl.ActiveSheet
ws.Range('B100').Select()
wb.Close(True)
xl.Quit()
select_cell()
I want to make something like this:
import win32com.client
def select_cell():
xl = win32com.client.gencache.EnsureDispatch('Excel.Application')
wb = xl.Workbooks.Open(r'H:\Files\1.xlsx')
for ws in wb.Worksheets():
ws.Range('B100').Select()
wb.Close(True)
xl.Quit()
select_cell()
In order to be taken to specific cell in newly generated document it is necessary to have both of these expressions executed:
ws.Range('k100').Value = 1
ws.Range('k100').Select()
To do it in every sheet of the workbook:
def select_cell():
xl = win32com.client.gencache.EnsureDispatch('Excel.Application')
wb = xl.Workbooks.Open(r'H:\Files1.xlsx')
for sh in wb.Sheets:
xl.Worksheets(sh.Name).Activate()
ws = xl.ActiveSheet
ws.Range('k100').Value = 1
ws.Range('k100').Select()
wb.Close(True)
xl.Quit()
The code above will take you to K100 on every worksheet in the book.
Your script did nothing at all when I tested it.
The script below worked fine, based on my test.
import xlsxwriter
# Create an new Excel file and add a worksheet.
workbook = xlsxwriter.Workbook('C:\\Users\\Excel\\Desktop\\book1.xlsx')
worksheet = workbook.add_worksheet()
# Widen the first column to make the text clearer.
worksheet.set_column('A:A', 20)
# Add a bold format to use to highlight cells.
bold = workbook.add_format({'bold': True})
# Write some simple text.
worksheet.write('A1', 'Hello')
# Text with formatting.
worksheet.write('A2', 'World', bold)
# Write some numbers, with row/column notation.
worksheet.write(2, 0, 123)
worksheet.write(3, 0, 123.456)
workbook.close()
I am trying to activate multiple excel worksheets and write to both multiple sheets within both workbook(s) using python and openpyxl. I am able to load the second workbook f but I am unable to append cell G2 of my second workbook with the string Recon
from openpyxl import Workbook, load_workbook
filename = 'sda_2015.xlsx'
wb = Workbook()
ws = wb.active
ws['G1'] = 'Path'
ws.title = 'Main'
adf = "Dirty Securities 04222015.xlsx"
f = "F:\\ana\\xlmacro\\" + adf
wb2 = load_workbook(f)
"""
wb22 = Workbook(wb2)
ws = wb22.active
ws['G1'] = "Recon2"
ws.title = 'Main2'
"""
print wb2.get_sheet_names()
wb.save(filename)
I commented out the code which is broken
Update
I adjusted my code with the below answer. The value in cell H1 is written onto wb2 in column H, but for some reason the column is hidden. I have adjusted the column to other columns but still I have seen the code hide multiple columns. There are also occurences when the code executes and titles ws2 as Main21 but the encoded value is Main2
from openpyxl import Workbook, load_workbook
filename = 'sda_2015.xlsx'
wb1 = Workbook()
ws1 = wb1.active
ws1['G1'] = 'Path'
ws1.title = 'Main'
adf = "Dirty Securities 04222015.xlsx"
f = "F:\\ana\\xlmacro\\" + adf
wb2 = load_workbook(f)
ws2 = wb2.active
ws2['H1'] = 'Recon2'
ws2.title = 'Main2'
print wb2.get_sheet_names()
wb1.save(filename)
wb2.save(f)
If you have two workbooks open, wb1 and wb2, you'll also need different names for the various worksheets: ws1 = wb1.active and ws2 = wb2.active.
If you're working with a file with macros, you'll need to set the keep_vba flag to True when opening it in order to preserve the macros.
I had experienced the same thing with hidden cells. Eventually, I unpacked the Excel file and looked at the raw XML to find out that not all of the columns had a dimension for width. Those without a width were being by Excel.
A quick fix is to do something like this...
for col in 'ABCDEFG':
if not worksheet.column_dimensions[col].width:
worksheet.column_dimensions[col].width = 10