Quitting processes in PySide Dialog Window - python

Ok, let's say that I have a theoretical application written in PySide and I want to integrate video tutorials on how to use certain functions and tools all within a dialog window that loads an instance of webview.
E.g.:
class TutorialWindow(QtGui.QDialog)
(Some code)
....
....
(Some code)
video = QtWebKit.QWebView()
video.load(QUrl(youtube.com/video)
Well, the issue that I'm running into is that the video continues to play even after the dialog window has been closed. I know this is because the audio continues to play until I close the parent application.
I'm looking into the documentation for the dialog window close event but, I feel I'm missing something.
*I apologize for any incoherent-ness, I have been machining some components on a CNC for the past 8 hours at 4:00AM.

Related

Tkinter-based app keeps running in the background if the window is closed abruptly

I've created a tkinter app designed to let users create and take quizzes locally. Unfortunately, if a user closes the window by hitting the 'x' in the corner instead of hitting the "quit" button on the main menu, the window is destroyed but the process remains in the background. It isn't a huge deal as it stops using any CPU and only holds on to about 40mb of memory per instance, but this just seems pretty sloppy for an app that I'd like to deploy.
I have no idea what specifically is refusing to exit when the window is closed, and as it could be coming from almost anywhere in my 1700 lines of code, I'm instead looking for some more general tips for identifying what's still running or for killing any remaining processes when the window is closed. I'm happy to provide my code if anyone thinks it would help, though I reiterate that it's quite long given that I can't identify the source of the particular problem.
You can use state() from Tk to check if the window is open or not. When the window is open it should return 'normal' and if the window isn't open it will return something else.
What I would do is add something that checks the state of the window and exit the app when it's closed.
while app_is_running:
if root.state() != 'normal':
sys.exit(0)

Tracking focus changes

I'm trying to track the window focus changes (what application is in the foreground) with python 3.7 in a windows 10 (64b) machine because I'd like to log how much time I spend using each application (I hope chrome is a different app for each tab XD)
I tried to search in the web about how to do it but didn't find it (odd). For now I learnt that I have to install win32api (pypiwin32) and that with this code I can get the name of the window
from win32gui import GetWindowText, GetForegroundWindow
print(GetWindowText(GetForegroundWindow()))
That works fine but I don't want to make a loop with that every second, I'd like to have a callback that when the event 'onWindowFocusChange' or something like that is called run that.
EDIT: As David Heffeman pointed out, I was using wrong terminology. What I meant is the piece of software that I'm interacting with at each point. (None if the screen is blocked, If I'm playing a game and listening to music, the game, if I'm reading a web or a pdf that browser or reader, etc... hope this clarifies the matter.
This example code here logs all focus changes: https://gist.github.com/keturn/6695625

Python - How to make a daemon out of GUI Application on Mac OS X?

On Windows it is easy. Just run your program with pythonw instead with python and code will be executed in the background.
So, the thing I wish to achieve is easily arranged.
I have an application which is really a service doing underground stuff. But this service needs a control panel.
So, on Windows I use wxPython to create a GUI, even some wx stuff to provide needed service, and when user is done with adjustments she/he clicks Hide and Show(False) is called on main window.
Thus the GUI disappears and the service continues its work in the background. User can always bring it back using a hotkey.
The trouble is that on Mac OS X this strategy works only to some degree.
When wx.Frame.Show(False) is called, the window disappears along with its menu bar and service works fine, but the Application is still visible there.
You can switch to it regardless the fact that you cannot do anything with it. It is still present in the Dock etc. etc.
This happens when program is using python or pythonw or when it is bundled with Py2App.
No matter what I do, the icon stays there.
There must be some trick that allows a programmer to remove this naughty icon and thus stop bothering poor little user when she/he doesn't want to be bothered.
Hiding window is obviously not enough. Anyone knows the trick?
N.B.: I would really like to do it the way I described above and not mess with two separate processes and IPC.
Edit:
After much digging I found these:
How to hide application icon from Mac OS X dock
http://codesorcery.net/2008/02/06/feature-requests-versus-the-right-way-to-do-it
How to hide the Dock icon
According to last link the proper way to do it is to use:
[NSApp setActivationPolicy: NSApplicationActivationPolicyAccessory];
or
[NSApp setActivationPolicy: NSApplicationActivationPolicyProhibited];
So what I want (runtime switching from background to foreground and back) is possible.
But how to do it from Python???
Constants: NSApplicationActivationPolicyProhibited and NSApplicationActivationPolicyAccessory are present in AppKit, but I cannot find setApplicationActivationPolicy function anywhere.
NSApp() doesn't have it.
I know there is a way of doing it by loading objc dylib with ctypes, delegating to NSApp and sending "setApplicationActivationPolicy: <constant_value>", but I don't know how much will this mess with wx.App(). And it is a bit much work for something that should be available already.
In my experience, NSApp() and wx.App() active at the same time dislike eachother pretty much.
Perhaps we can get the NSApp() instance that wx is using somehow and use wx's delegate???
Remember please, already suggested solutions with starting as agent and switching to foreground or running multiple processes and doing IPC is very undesirable in my case.
So, ideally, using setApplicationActivationPolicy is my goal, but how? (Simple and easy and no messup to wx.App() please.)
Any ideas???
OK people, there is a good, nice and correct solution without any messing around.
Firstly, I want to explain why Windows GUI process goes to background when wx.Frame.Show(MyFrame, False) is called.
Very short explanation and skipping over details is that Windows consider the Window and an application the same thing.
I.e. The main element of the MS Windows application is your main GUI window.
So, when this window is hidden, an application has no more GUI and continues to run in background.
Mac OS X considers the application to be your application and any windows you choose to put into it are its children so to speak.
This allows you to have an application running while presenting no windows but a menu bar, from which you may choose an action which would then generate a needed window.
Very handy for editors where you may have more than one file opened at once, each in its own window and when you close the last one, you can still open a new one or create a blank one, etc. etc.
Therefore a main element of Mac OS X application is the application itself, and that is why it stays opened after last window is hidden, logically. Destroying its menu bar also will not help. The name of the app will stay present in Dock and in application switcher and in Force Quit. You will be able to switch to it and do nothing. :D
But, luckily, Mac provides us with function to put it to background though. And this function is already mentioned setApplicationActivationPolicy() from NSApp object.
The trouble was its naming in Python's AppKit, which is NSApp.setActivationPolicy_(). To complicate matters further, it is not available directly from Python's interactive shell but it has to be called at least from an imported module.
Why? I have no idea. Anyway here is a complete example for throwing an application into background that will work on Mac and Windows.
I didn't try it on Linux, which combines behaviour of Mac and Windows in matter of presenting an app, so, whether only hiding a window would be enough remains to be seen.
Feel free to try and submit an edit to make the example more cross-platform.
Example:
"""
This app will show you small window with the randomly generated code that will confirm that reopened window is still the same app returned from background,
and the button allowing you to send it to background.
After you send it to background, wait 8 seconds and application will return to foreground again.
Too prove that the application is continuing its work in the background, the app will call wx.Bell() every second.
You should hear the sound while app is in the foreground and when it is in background too.
Merry Christmas and a happy New Year!
"""
import wx
import random, sys
if sys.platform=="darwin":
from AppKit import NSBundle, NSApp, NSAutoreleasePool, NSApplicationActivationPolicyRegular, NSApplicationActivationPolicyProhibited
# Use Info.plist values to know whether our process started as daemon
# Also, change this dict in case anyone is later checking it (e.g. some module)
# Note: Changing this dict doesn't change Info.plist file
info = NSBundle.mainBundle().infoDictionary()
def SendToBackground ():
# Change info, just in case someone checks it later
info["LSUIElement"] = "1"
NSApp.setActivationPolicy_(NSApplicationActivationPolicyProhibited)
def ReturnToForeground ():
# Change info, just in case someone checks it later
info["LSUIElement"] = "0"
NSApp.setActivationPolicy_(NSApplicationActivationPolicyRegular)
else:
# Simulate Mac OS X App - Info.plist
info = {"LSUIElement": "0"} # Assume non background at startup
# If programmer chose not to display GUI at startup then she/he should change this before calling ReturnToForeground()
# To preserve consistency and allow correct IsDaemon() answer
def SendToBackground ():
info["LSUIElement"] = "1"
def ReturnToForeground ():
info["LSUIElement"] = "0"
def IsDaemon ():
return info["LSUIElement"]=="1"
class Interface (wx.Frame):
def __init__ (self):
wx.Frame.__init__(self, None, -1, "Test", pos=(100, 100), size=(100, 100))
wx.StaticText(self, -1, "Test code: "+str(random.randint(1000, 10000)), pos=(10, 10), size=(80, 20))
b = wx.Button(self, -1, "DAEMONIZE ME", size=(80, 20), pos=(10, 50))
wx.EVT_BUTTON(self, b.GetId(), self.OnDaemonize)
self.belltimer = wx.Timer(self)
wx.EVT_TIMER(self, self.belltimer.GetId(), self.OnBellTimer)
self.belltimer.Start(1000)
# On Mac OS X, you wouldn't be able to quit the app without the menu bar:
if sys.platform=="darwin":
self.SetMenuBar(wx.MenuBar())
self.Show()
def OnBellTimer (self, e):
wx.Bell()
def OnDaemonize (self, e):
self.Show(False)
SendToBackground()
self.timer = wx.Timer(self)
wx.EVT_TIMER(self, self.timer.GetId(), self.OnExorcize)
self.timer.Start(8000)
def OnExorcize (self, e):
self.timer.Stop()
ReturnToForeground()
self.Show()
self.Raise()
app = wx.App()
i = Interface()
app.MainLoop()
Of course, this example may be started from terminal or with CLI window. In this case the terminal control over your program will stay opened while app only will appear and disappear.
To complete your GUI daemon, you should start it with pythonw (on Windows) or launch it from daemontest.pyw file,
and on Mac you should use:
% nohup python daemontest.py &
or bundle it with py2app or use Python launcher that comes with python.org Python version to start daemontest.py without terminal.
Note: This example suffers from the same flaw on Mac OS X that is mentioned on links I supplied in my question. I refer to the problem of wrong focusing and menu bar not instantly appearing when app comes from background. User has to switch around and come back to newly returned app for it to work properly. I hope somebody will solve this too. And soon. It is quite annoying.
One more note: If you have threads running in your program, pause them while daemonizing and exorcizing. Especially if they are communicating with another app using Apple events. To be frank, something about wx.Timers should be done too. If you are not careful you may get leaking problems around non-existing NSAutoreleasePool and/or SegmentationFault upon program termination.
Ok. Here is the code to do what you want to do:
import AppKit
info = AppKit.NSBundle.mainBundle().infoDictionary()
info["LSUIElement"] = "1"
This the messier answer you do not want to do, but I will list it anyway. In the info.plist file add in this key:
<key>LSUIElement</key>
<string>1</string>
Another more daemonish solution but means it can't have a GUI, you add in this key to the info.plist file:
<key>LSBackgroundOnly</key>
<string>1</string>
Source

Tkinter activate window on Windows XP

I have a small GUI application that listens for network messages so a user can update some info and accept it. This is in a production factory environment and used for interacting with a specific piece of physical hardware (over serial in some cases). The workflow looks like this:
User is interacting with another program (5250 Green Screen)
They enter a certain keybinding that sends a UDP message to a Tkinter GUI
The Tkinter GUI does a deiconify()
User edits data, accepts (Enter) and it does an iconify()
My issue is that on windows XP, the GUI does not become active when I do the deiconify and conversely does not fall back to the prior window on iconify. I have tried some things I found in other questions such as:
Setting the Tk GUI as top.. self.wm_attributes("-topmost", 1)
Trying to set/force focus... self.focus_set() and self.focus_force()
Although the window is visible with the first, I can not seem to get it to be the active window so that the user can type in it without "clicking" on it to activate. The same is true for releasing the "focus" so that the active window becomes the one they were previously on (5250).
It seems like an issue that others also have had but I have not been able to find anything that works. Is there a programmatic way to get the window activated and release it when done?
Unfortunately, after a week there have been no answers and I was not able to find a direct way to do this with Tkinter. I did find a way to solve the problem though and it appears to work consistently. Here are the steps I took to make the screens activate:
Install pywin32.
Create a function that activates the tk app.
Create a function that activates the 5250.
Then each time I do a iconify/deiconify I also run the function to activate the appropriate screen. The code that activates the tk window looks like this:
def activate_self(self):
""" Activate this window. """
shell = win32com.client.Dispatch('WScript.Shell')
shell.AppActivate(str(self.title))
shell = None
The code that activates the caller is a little ugly since it has to guess the title but is the same basic concept.

Progress Bar over getOpenFileName

In my application I have the following line which opens a file dialog window. Once I get the file name, I do a bunch of processing which takes quite some time, and once this is done the workspace is ready for the user.
filename, _ = QtGui.QFileDialog.getOpenFileName(self, 'Open file', os.curdir, "*.cws")
The file dialog is a modal window (by default), which is great, because it's preventing the user from doing stupid stuff while the workspace is not ready for use yet. I want to put a progress bar somewhere to give a sense of how much has be processed. I made another dialog window which displays a progress bar and some other information.
Now, since the file dialog window is modal, it just sits there frozen while my workspace is processing, and the progress dialog only pops up after everything is done.
I've looked into setting the file dialog window to not modal, but I don't think that is possible. I was thinking to maybe force it to close, and immediately have my progress dialog window pop up and take over the modality. How can I close the file dialog window programmatically? I don't know how to get a reference for the form.
Or perhaps you have a better suggestion on how to address this?
As thuga mentioned, your application event loop is stuck by your heavy processing.
So events (and especialy paint events) are not processed while your processing is running causing the GUI to freeze.
In my opinion, you have 2 options:
Force events to be processesed (not very classy but may work):
It depends on how your "heavy processing" is done.
Assuming the code hanging the loop is "under your hands" (not in a third party lib).
You can add as much call to QApplication.processEvents as you can in it.
If the processing is loop based, it can look like:
for item in itemList:
...processitem...
QtGui.QApplication.processEvents()
This as the main drawback of adding dependencies to GUI in parts of code that should not be aware of.
If your code is not loop based then you'll have to add several calls to processEvents that will pollute the processing code.
Stop hanging the event loop (more complicated but more maintainable)
That means you will have to deal with Threads and/or subprocesses as thuga suggested.
This solution assumes that GUI code and business code are separated well enough.
You can have a look at this article from Qt Quarterly that gives some highlights on this issue.
Because of python Global Interpreter Lock (GIL) you may not see better results with threads.
Consider using the multiprocessing library.

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