My code looks like this:
Right now my code outputs two text file named absorbance.txt and energy.txt separately. I need to modify it so that it outputs only one file named combined.txt such that every line of combined.txt has two values separated by comma. The first value must be from absorbance.txt and second must be from energy.txt. ( I apologize if anyone is confused by my writting, Please comment if you need more clarification)
g = open("absorbance.txt", "w")
h = open("Energy.txt", "w")
ask = easygui.fileopenbox()
f = open( ask, "r")
a = f.readlines()
bg = []
wavelength = []
for string in a:
index_j = 0
comma_count = 0
for j in string:
index_j += 1
if j == ',':
comma_count += 1
if comma_count == 1:
slicing_point = index_j
t = string[slicing_point:]
new_str = string[:(slicing_point- 1)]
new_energ = (float(1239.842 / int (float(new_str))) * 8065.54)
print >>h, new_energ
import math
list = []
for i in range(len(ref)):
try:
ans = ((float (ref[i]) - float (bg[i])) / (float(sample[i]) - float(bg[i])))
print ans
base= 10
final_ans = (math.log(ans, base))
except:
ans = -1 * ((float (ref[i]) - float (bg[i])) / (float(sample[i]) - float(bg[i])))
print ans
base= 10
final_ans = (math.log(ans, base))
print >>g, final_ans
Similar to Robert's approach, but aiming to keep control flow as simple as possible.
absorbance.txt:
Hello
How are you
I am fine
Does anybody want a peanut?
energy.txt:
123
456
789
Code:
input_a = open("absorbance.txt")
input_b = open("energy.txt")
output = open("combined.txt", "w")
for left, right in zip(input_a, input_b):
#use rstrip to remove the newline character from the left string
output.write(left.rstrip() + ", " + right)
input_a.close()
input_b.close()
output.close()
combined.txt:
Hello, 123
How are you, 456
I am fine, 789
Note that the fourth line of absorbance.txt was not included in the result, because energy.txt does not have a fourth line to go with it.
You can open both text files and append them to the new text file as shown below. This is what I gave based on your question, not necessarily the code your provided.
combined = open("Combined.txt","w")
with open(r'Engery.txt', "rU") as EnergyLine:
with open(r'Absorbance.txt', "rU") as AbsorbanceLine:
for line in EnergyLine:
Eng = line[:-1]
for line2 in AbsorbanceLine:
Abs = line2[:-1]
combined.write("%s,%s\n" %(Eng,Abs))
break
combined.close()
Related
I have to write a Python function which records temperatures for different days. The temperature for the same day is stored on the same line.The first day is considered to be day 1, and each subsequent line of the file records the following days in sequential order (e.g. the 3rd line of data is collected from the 3rd day). If there was no data collected for a given day then the entire line will be blank. For example, The text file contains the following inputs for 6 days:
23 24.5
25
22.25 22.5
23.4
25.2 20.0
This file contains data collected for 6 days.
I am to define a function temp_record which takes a filename as a parameter. It reads the data from the parameter file and analyses the temperatures. The function should return a list of average temperatures per day. For example, the function returns the following list for the above text file:
[23.75, 25.0, 22.375, 0, 23.4, 22.6]
I wrote a code but it doesn't seem to work for all case types and I'm not sure what went wrong. Can someone help?
Here is the code I wrote:
def temp_record(filename):
input_file = open(filename,'r')
contents = input_file.read().split("\n")
sum_val = 0
lis = []
for string in contents:
split_str = string.split(" ")
for i in range(len(split_str)):
if split_str[i] == '':
split_str[i] = 0
else:
split_str[i] = float(split_str[i])
ans = (sum(split_str)/len(split_str))
if ans == 0.0:
ans = 0
lis.append(ans)
return lis
When you do contents = input_file.read().split("\n") you get an additional element in contents list that gets computed to 0.
You can fix this like this:
def temp_record(filename):
input_file = open(filename, 'r')
# read all lines
contents = input_file.readlines()
sum_val = 0
lis = []
for string in contents:
# lines end in \n use rstrip to remove it
split_str = string.rstrip().split(" ")
for i in range(len(split_str)):
if split_str[i] == '':
split_str[i] = 0
else:
split_str[i] = float(split_str[i])
ans = (sum(split_str) / len(split_str))
if ans == 0.0:
ans = 0
lis.append(ans)
return lis
but this can be much shorter:
def temp_record(filename):
result = []
with open(filename, 'r') as fp:
for line in fp:
temps = line.split()
avg_temp = sum(map(float, temps)) / len(temps) if temps else 0
result.append(avg_temp if avg_temp > 0 else 0)
return result
or even shorter if you want to play golfcode:
def temp_record2(filename):
with open(filename, 'r') as fp:
return list(map(lambda x: x if x > 0 else int(x), [sum(map(float, line.split())) / len(line.split()) if line.split() else 0 for line in fp]))
Perhaps the hidden test that fails is with an input like:
-1 1
0
30
The first two days do have recorded temperatures, but their average is 0. Following the format of using floats for all other averages, the average should be 0.0, not 0 (as that would imply no temperature was collected for the day, when in fact one was).
If this is the issue, this could be fixed:
def temp_record(filename):
input_file = open(filename,'r')
contents = input_file.read().split("\n")
sum_val = 0
lis = []
for string in contents:
split_str = string.split(" ")
for i in range(len(split_str)):
if split_str[i] == '':
split_str[i] = 0
else:
split_str[i] = float(split_str[i])
ans = (sum(split_str)/len(split_str))
if string == '':
ans = 0
lis.append(ans)
return lis
I've been trying to figure this out for about a year now and I'm really burnt out on it so please excuse me if this explanation is a bit rough.
I cannot include job data, but it would be accurate to imagine 2 csv files both with the first column populated with values (Serial numbers/phone numbers/names, doesn't matter - just values). Between both csv files, some values would match while other values would only be contained in one or the other (Timmy is in both files and is a match, Robert is only in file 1 and does not match any name in file 2).
I can successfully output a csv value ONCE that exists in the both csv files (I.e. both files contain "Value78", output file will contain "Value78" only once).
When I try to tack on an else statement to my if condition, to handle non-matching items, the program will output 1 entry for every item it does not match with (makes 100% sense, matches happen once but every other comparison result besides the match is a non-match).
I cannot envision a structure or method to hold the fields that don't match back so that they can be output once and not overrun my terminal or output file.
My goal is to output two csv files, matches and non-matches, with the non-matches having only one entry per value.
Anyways, onto the code:
import csv
MYUNITS = 'MyUnits.csv'
VENDORUNITS = 'VendorUnits.csv'
MATCHES = 'Matches.csv'
NONMATCHES = 'NonMatches.csv'
with open(MYUNITS,mode='r') as MFile,
open(VENDORUNITS,mode='r') as VFile,
open(MATCHES,mode='w') as OFile,
open(NONMATCHES,mode'w') as NFile:
MyReader = csv.reader(MFile,delimiter=',',quotechar='"')
MyList = list(MyReader)
VendorReader = csv.reader(VFile,delimiter=',',quotechar='"')
VList = list(VendorReader)
for x in range(len(MyList)):
for y in range(len(VList)):
if str(MyList[x][0]) == str(VList[y][0]):
OFile.write(MyList[x][0] + '\n')
else:
pass
The "else: pass" is where the logic of filtering out non-matches is escaping me. Outputting from this else statement will write the non-matching value (len(VList) - 1) times for an iteration that DOES produce 1 match, the entire len(VList) for an iteration with no match. I've tried using a counter and only outputting if the counter equals the len(VList), (incrementing in the else statement, writing output under the scope of the second for loop), but received the same output as if I tried outputting non-matches.
Below is one way you might go about deduplicating and then writing to a file:
import csv
MYUNITS = 'MyUnits.csv'
VENDORUNITS = 'VendorUnits.csv'
MATCHES = 'Matches.csv'
NONMATCHES = 'NonMatches.csv'
list_of_non_matches = []
with open(MYUNITS,mode='r') as MFile,
open(VENDORUNITS,mode='r') as VFile,
open(MATCHES,mode='w') as OFile,
open(NONMATCHES,mode'w') as NFile:
MyReader = csv.reader(MFile,delimiter=',',quotechar='"')
MyList = list(MyReader)
VendorReader = csv.reader(VFile,delimiter=',',quotechar='"')
VList = list(VendorReader)
for x in range(len(MyList)):
for y in range(len(VList)):
if str(MyList[x][0]) == str(VList[y][0]):
OFile.write(MyList[x][0] + '\n')
else:
list_of_non_matches.append(MyList[x][0])
# Remove duplicates from the non matches
new_list = []
[new_list.append(x) for x in list_of_non_matches if x not in new_list]
# Write the new list to a file
for i in new_list:
NFile.write(i + '\n')
Does this work?
import csv
MYUNITS = 'MyUnits.csv'
VENDORUNITS = 'VendorUnits.csv'
MATCHES = 'Matches.csv'
NONMATCHES = 'NonMatches.csv'
with open(MYUNITS,'r') as MFile,
(VENDORUNITS,'r') as VFile,
(MATCHES,'w') as OFile,
(NONMATCHES,mode,'w') as NFile:
MyReader = csv.reader(MFile,delimiter=',',quotechar='"')
MyList = list(MyReader)
MyVals = [x for x in MyList]
MyVals = [x[0] for x in MyVals]
VendorReader = csv.reader(VFile,delimiter=',',quotechar='"')
VList = list(VendorReader)
vVals = [x for x in VList]
vVals = [x[0] for x in vVals]
for val in MyVals:
if val in vVals:
OFile.write(Val + '\n')
else:
NFile.write(Val + '\n')
#for x in range(len(MyList)):
# for y in range(len(VList)):
# if str(MyList[x][0]) == str(VList[y][0]):
# OFile.write(MyList[x][0] + '\n')
# else:
# pass
Sorry, I had some issues with my PC. I was able to solve my own question the night I posted. The solution I used is so simple I'm kicking myself for not figuring it out way sooner:
import csv
MYUNITS = 'MyUnits.csv'
VENDORUNITS = 'VendorUnits.csv'
MATCHES = 'Matches.csv'
NONMATCHES = 'NonMatches.csv'
with open(MYUNITS,mode='r') as MFile,
open(VENDORUNITS,mode='r') as VFile,
open(MATCHES,mode='w') as OFile,
open(NONMATCHES,mode'w') as NFile:
MyReader = csv.reader(MFile,delimiter=',',quotechar='"')
MyList = list(MyReader)
VendorReader = csv.reader(VFile,delimiter=',',quotechar='"')
VList = list(VendorReader)
for x in range(len(MyList)):
tmpStr = ''
for y in range(len(VList)):
if str(MyList[x][0]) == str(VList[y][0]):
tmpStr = '' #Sets to blank so comparison fails, works because break
OFile.write(MyList[x][0] + '\n')
break
else:
tmp = str(MyList[x][0])
if tmp != '':
NFile.write(tmp + '\n')
so -----2-----3----5----2----3----- would become -----4-----5----7----4----5-----
if the constant was 2 and etc. for every individual line in the text file.
This would involve splitting recognising numbers in between strings and adding a constant to them e.g ---15--- becomes ---17--- not ---35---.
(basically getting a guitar tab and adding a constant to every fret number)
Thanks. Realised this started out vague and confusing so sorry about that.
lets say the file is:
-2--3--5---7--1/n-6---3--5-1---5
and im adding 2, it should become:
-4--5--7---9--3/n-8---5--7-3---7
Change the filename to something relevant and this code will work. Anything below new_string needs to be change for what you need, eg writing to a file.
def addXToAllNum(int: delta, str: line):
values = [x for x in s.split('-') if x.isdigit()]
values = [str(int(x) + delta) for x in values]
return '--'.join(values)
new_string = '' # change this section to save to new file
for line in open('tabfile.txt', 'r'):
new_string += addXToAllNum(delta, line) + '\n'
## general principle
s = '-4--5--7---9--3 -8---5--7-3---7'
addXToAllNum(2, s) #6--7--9--11--10--7--9--5--9
This takes all numbers and increments by the shift regardless of the type of separating characters.
import re
shift = 2
numStr = "---1----9---15---"
print("Input: " + numStr)
resStr = ""
m = re.search("[0-9]+", numStr)
while (m):
resStr += numStr[:m.start(0)]
resStr += str(int(m.group(0)) + shift)
numStr = numStr[m.end(0):]
m = re.search("[0-9]+", numStr)
resStr += numStr
print("Result:" + resStr)
Hi You Can use that to betwine every line in text file add -
rt = ''
f = open('a.txt','r')
app = f.readlines()
for i in app:
rt+=str(i)+'-'
print " ".join(rt.split())
import re
c = 2 # in this example, the increment constant value is 2
with open ('<your file path here>', 'r+') as file:
new_content = re.sub (r'\d+', lambda m : str (int (m.group (0)) + c), file.read ())
file.seek (0)
file.write (new_content)
I have 2 text files I wants to compare column 3 and 4 t only if column 1 and 2 is the same in the files .
Text 1 :
12345,67890,4.6,5.7
89736,62828,5.1,4.2
63793,38392,5.4,7.3
Text 2:
12345,67890,4.6,5.7
63793,38392,5.4,7.3
My code :
pre = open ("g.txt","r")
post = open ("g2.utm","r")
line = pre.readlines()
if not line:
break
if line.startswith("L"):
print ("\n") #to avoid the header
else :
v = line[0:5]
l = line[6:11]
i = line[12:14]
k = line[15:17]
line2 = post.readlines()
if not line2:
break
if line2.startswith("L"):
print ("\n") #to avoid the header
else :
v2 = line[0:5]
l2 = line[6:11]
i2 = line[12:14]
k2 = line[15:17]
if v == v2 and l == l2 :
d = (i - i2)
h = (k - k2)
if d >= 6.25 and h >=6.25:
print (v2,l2,"not ok")
print ("Done")
Your code is too much repetitive and messy. Let me suggest you some modification in your code. First read the file line by line. How could you do that?
with open("g.txt","r") as f:
for line in f:
a_line_of_the_file = line
Next, instead of accessing the values with index, you can split them with commas and save them to a list.
valuelist = a_line_of_the_file.split(',')
# contains ["12345","67890","4.6","5.7"] at first iteration.
When you have two list from each row of two files, you can always compare them by index like:
if valuelist1[0]== valueList2[0]:
do_something
Cast the value first if you need another datatype.
You should now solve your problem yourselves. If you still got error, plz inform.
I have a question concerning some python code that I have written:
def read_graph_from_file(filename):
txtfile = open(filename, "rU")
node_memory = 0
neighbour_list = 0
for entry in txtfile:
entry_without_newline = entry.replace('\n',"")
columns = entry_without_newline.replace(','," ")
columns = columns.split(" ")
number_of_columns = len(columns)
if number_of_columns == 2:
neighbour_list = columns
neighbour_list.sort()
if node_memory == float(neighbour_list[0]):
y = neighbour_list[1]
print y
The output I want from this is a list, i.e. [1,4]. Instead I am receiving the characters across multiple lines, i.e:
1
4
I was wondering how I might rectify this?
If you want them in a list, you will have to create a list variable and just append your results to it. You should return this list once your function is done.
def read_graph_from_file(filename):
txtfile = open(filename, "rU")
node_memory = 0
neighbour_list = 0
lst = []
for entry in txtfile:
entry_without_newline = entry.replace('\n',"")
columns = entry_without_newline.replace(','," ")
columns = columns.split(" ")
number_of_columns = len(columns)
if number_of_columns == 2:
neighbour_list = columns
neighbour_list.sort()
if node_memory == float(neighbour_list[0]):
y = neighbour_list[1]
lst.append(y)
return lst
Then if you run your function like this:
print read_graph_from_file(<fileName>)
You will get the desired result:
[1,4]
Alternatively, you can print the resulting list directly at the end of your function. Then you won't have to call the function with print.