Root logger doesn't log when (I think) it should:
import logging
# NOTE: I make sure to set the root logger level to logging.DEBUG
logging.basicConfig(format='%(levelname)s:%(message)s', level=logging.DEBUG)
logging.debug('This is a debugging test.')
From my understanding this should log something but it does nothing.
Quick Google searches didn't help me to figure this issue out, neither did the official documentation.
In the other hand, if I use logging.warning instead of logging.debug, it does work.
What am I doing wrong?
EDIT:
Checking the current level with logging.getLogger().getEffectiveLevel() indicates me that the level is still at 30, like before the call of logging.basicConfig.
Checking logging.getLogger().isEnabledFor(logging.DEBUG) effectively tells me that the root logger level isn't enabled for logging.DEBUG.
EDIT: Turned out OP's (me) trouble was due to already calling logging.debug before logging.basicConfig, thus settings the config to defaults and the call to logging.basicConfig was ignored as pointed out by #SmCaterpillar.
Although, this alternative solution allows you to "force" root logger level after a basicConfig has already been set, could still be useful!
Found a "solution":
# […] Previous code
# Sets the root logger level
logging.getLogger().setLevel(logging.DEBUG)
logging.debug('Test') # Displays 'DEBUG:root:Test'
But it doesn't carry out the format I gave in in logging.basicConfig.
That said I'm already satisfied: It is already some kind of progress. Logging even with not exactly the format I expected is always better than no logging at all.
Related
it seems that in python setting the logging level for loggers (including the root logger) is not applied, until you use one of the logging module's logging functions. Here's some code to show what I mean (I used python 3.7):
import logging
if __name__ == "__main__":
# Create a test logger and set its logging level to DEBUG
test_logger = logging.getLogger("test")
test_logger.setLevel(logging.DEBUG)
# Log some debug messages
# THESE ARE NOT PRINTED
test_logger.debug("test debug 1")
# Now use the logging module directly to log something
logging.debug("whatever, you won't see this anyway")
# Apparently the line above "fixed" the logging for the custom logger
# and you should be able to see the message below
test_logger.debug("test debug 2")
Output:
DEBUG:test:test debug 2
Maybe there's something I misunderstood about the configuration of the loggers, in that case I'd appreciate to know the correct way of doing it.
You didn't (explicitly) call logging.basicConfig, so the handler isn't configured correctly.
test_logger initially has no handler, because you didn't add one and the root logger doesn't have one yet. So although the message is "logged", nothing defines what that actually means.
When you call logging.debug, logging.basicConfig is called for you, because the root logger has no handler. At this time, a StreamHandler is created, but the root logger remains at the default level of INFO, and so nothing is sent to the new handler.
Now when you call test_logger.debug again, it has the inherited StreamHandler to actually output the long message to standard error.
I've seen some very odd behaviour with the logger module. It started with a relatively complex project, but now I've seen it with the following script:
import logging
import os
# Uncomment the following line to remove handlers
# logging.getLogger().handlers = []
filePath = os.environ['userprofile'] + r'\Documents\log.txt'
logging.basicConfig(filename=filePath)
logging.debug('Gleep')
logging.shutdown()
This should simply write 'Gleep' to the log.txt file to your documents. Currently it is writing the file but not writing anything to it, however, I've inconsistently seen the following behaviour:
List item
No log file being written at all.
Log file created, but nothing written to it.
Everything working fine.
The only way I've got it working before is to remove existing handlers (commented out in the example above).
This is on several machines in different locations.
So...am I doing something grotesquely wrong here? Why is the logging module acting this way?
I'm not sure how to prove/disprove/debug your 'other' situations, but maybe the following can help clarify what is happening in the code from your question:
First, setting logging.getLogger().handlers = [] should not be necessary, since logging.getLogger() is the root logger by default and has no handlers. Here is a fresh Python 3.7 shell:
>>> import logging
>>> logging.getLogger()
<RootLogger root (WARNING)>
>>> logging.getLogger().handlers
[]
(Note that in the absence of any handlers, a logger will fall back to lastResort, but that should be irrelevant here since you add a handler implicitly via basicConfig().)
Which brings you to logging.basicConfig(filename=filePath): this adds a FileHandler handler to the root logger. It does not touch the level of the root logger, which is WARNING by default, so your message won't pass the 'level test' and won't be emitted as a result.
>>> logging.root.getEffectiveLevel()
30
(This uses .getEffectiveLevel() rather than just the plain attribute because a logger will walk its hierarchy until it finds a level if its level is NOTSET.)
All that is to say: as you currently have it, you are logging from the root logger (level WARNING) a message object that has level DEBUG, so the message will go nowhere.
I can't understand why the following code does not produce my debug message even though effective level is appropriate (output is just 10)
import logging
l = logging.getLogger()
l.setLevel(logging.DEBUG)
l.debug("Debug Mess!")
l.error(l.getEffectiveLevel())
while when I add this line after the import: logging.debug("Start...")
import logging
logging.debug("Start...")
l = logging.getLogger()
l.setLevel(logging.DEBUG)
l.debug("Debug Mess!")
l.error(l.getEffectiveLevel())
it produces following output:
DEBUG:root:Debug Mess!
ERROR:root:10
so even though "Start..." is not shown, it starts to log. Why?
It's on Python 3.5. Thanks
The top-level logging.debug(..) call calls the logging.basicConfig() function for you if no handlers have been configured yet on the root logger.
Because using a call to logging.getLogger().debug() does not trigger that call, you don't see any output because there are no handlers to show the output on.
The Python 3 version of logger does have a logging.lastResort handler, used for when no logging configuration exists, but this handler is configured to only show messages of level WARNING and up, which is why you see your ERROR level message (10) printed to STDERR, but not your DEBUG level message. In Python 2 you would get the message No handlers could be found for logger "root" printed instead, just once for the first attempt to log anything. I'd not rely on the lastResort handler however; instead properly configure your logging hierarchy with a decent handler configured for your own needs.
Either call logging.basicConfig() yourself, or manually add a handler on the root logger:
l = logging.getLogger()
l.addHandler(logging.StreamHandler())
The above basically does the same thing as a logging.basicConfig() call with no further arguments. The StreamHandler() created this way logs to STDERR and does not further filter on the message level. Note that a logging.basicConfig() call can also set the logging level for you.
The root logger(default logger, top level) and all other logger's default log level is warning(order 3) in all 5 log levels: debug < info < warning < error < fatal in order.
So at your first logging.debug('starting...'), you haven't set the root log level to debug as following code and you can't get the starting...output.
import logging
logging.basicConfig(level=logging.DEBUG)
logging.debug('starting...')
see python logging HOW TO for detail
At my current project there are thousand of code lines which looks like this:
logging.info("bla-bla-bla")
I don't want to change all these lines, but I would change log behavior. My idea is changing root logger to other Experimental logger, which is configured by ini-file:
[loggers]
keys = Experimental
[formatter_detailed]
format = %(asctime)s:%(name)s:%(levelname)s %(module)s:%(lineno)d: %(message)s
[handler_logfile]
class = FileHandler
args = ('experimental.log', 'a')
formatter = detailed
[logger_Experimental]
level = DEBUG
qualname = Experimental
handlers = logfile
propagate = 0
Now setting the new root logger is done by this piece of code:
logging.config.fileConfig(path_to_logger_config)
logging.root = logging.getLogger('Experimental')
Is redefining of root logger safe? Maybe there is more convenient way?
I've tried to use google and looked through stackoverflow questions, but I didn't find the answer.
You're advised not to redefine the root logger in the way you describe. In general you should only use the root logger directly for small scripts - for larger applications, best practice is to use
logger = logging.getLogger(__name__)
in each module where you use logging, and then make calls to logger.info() etc.
If all you want to do is to log to a file, why not just add a file handler to the root logger? You can do using e.g.
if __name__ == '__main__':
logging.basicConfig(filename='experimental.log', filemode='w')
main() # or whatever your main entry point is called
or via a configuration file.
Update: When I say "you're advised", I mean by me, here in this answer ;-) While you may not run into any problems in your scenario, it's not good practice to overwrite a module attribute which hasn't been designed to be overwritten. For example, the root logger is an instance of a different class (which is not part of the public API), and there are other references to it in the logging machinery which would still point to the old value. Either of these facts could lead to hard-to-debug problems. Since the logging package allows a number of ways of achieving what you seem to want (seemingly, logging to a file rather than the console), then you should use those mechanisms that have been provided.
logger = logging.getLogger()
Leaving the name empty will return you the root logger.
logger = logging.getLogger('name'）
Gives you another logger.
It appears that if you invoke logging.info() BEFORE you run logging.basicConfig, the logging.basicConfig call doesn't have any effect. In fact, no logging occurs.
Where is this behavior documented? I don't really understand.
You can remove the default handlers and reconfigure logging like this:
# if someone tried to log something before basicConfig is called, Python creates a default handler that
# goes to the console and will ignore further basicConfig calls. Remove the handler if there is one.
root = logging.getLogger()
if root.handlers:
for handler in root.handlers:
root.removeHandler(handler)
logging.basicConfig(format='%(asctime)s %(message)s',level=logging.DEBUG)
Yes.
You've asked to log something. Logging must, therefore, fabricate a default configuration. Once logging is configured... well... it's configured.
"With the logger object configured,
the following methods create log
messages:"
Further, you can read about creating handlers to prevent spurious logging. But that's more a hack for bad implementation than a useful technique.
There's a trick to this.
No module can do anything except logging.getlogger() requests at a global level.
Only the if __name__ == "__main__": can do a logging configuration.
If you do logging at a global level in a module, then you may force logging to fabricate it's default configuration.
Don't do logging.info globally in any module. If you absolutely think that you must have logging.info at a global level in a module, then you have to configure logging before doing imports. This leads to unpleasant-looking scripts.
This answer from Carlos A. Ibarra is in principle right, however that implementation might break since you are iterating over a list that might be changed by calling removeHandler(). This is unsafe.
Two alternatives are:
while len(logging.root.handlers) > 0:
logging.root.removeHandler(logging.root.handlers[-1])
logging.basicConfig(format='%(asctime)s %(message)s',level=logging.DEBUG)
or:
logging.root.handlers = []
logging.basicConfig(format='%(asctime)s %(message)s',level=logging.DEBUG)
where the first of these two using the loop is the safest (since any destruction code for the handler can be called explicitly inside the logging framework). Still, this is a hack, since we rely on logging.root.handlers to be a list.
Here's the one piece of the puzzle that the above answers didn't mention... and then it will all make sense: the "root" logger -- which is used if you call, say, logging.info() before logging.basicConfig(level=logging.DEBUG) -- has a default logging level of WARNING.
That's why logging.info() and logging.debug() don't do anything: because you've configured them not to, by... um... not configuring them.
Possibly related (this one bit me): when NOT calling basicConfig, I didn't seem to be getting my debug messages, even though I set my handlers to DEBUG level. After a bit of hair-pulling, I found you have to set the level of the custom logger to be DEBUG as well. If your logger is set to WARNING, then setting a handler to DEBUG (by itself) won't get you any output on logger.info() and logger.debug().
Ran into this same issue today and, as an alternative to the answers above, here's my solution.
import logging
import sys
logging.debug('foo') # IRL, this call is from an imported module
if __name__ == '__main__':
logging.basicConfig(level=logging.INFO, force=True)
logging.info('bar') # without force=True, this is not printed to the console
Here's what the docs say about the force argument.
If this keyword argument is specified as true, any existing handlers
attached to the root logger are removed and closed, before carrying
out the configuration as specified by the other arguments.
A cleaner version of the answer given by #paul-kremer is:
while len(logging.root.handlers):
logging.root.removeHandler(logging.root.handlers[-1])
Note: it is generally safe to assume logging.root.handlers will always be a list (see: https://github.com/python/cpython/blob/cebe9ee988837b292f2c571e194ed11e7cd4abbb/Lib/logging/init.py#L1253)
Here is what I did.
I wanted to log to a file which has a name configured in a config-file and also get the debug-logs of the config-parsing.
TL;DR; This logs into a buffer until everything to configure the logger is available
# Log everything into a MemoryHandler until the real logger is ready.
# The MemoryHandler never flushes (flushLevel 100 is above CRITICAL) automatically but only on close.
# If the configuration was loaded successfully, the real logger is configured and set as target of the MemoryHandler
# before it gets flushed by closing.
# This means, that if the log gets to stdout, it is unfiltered by level
root_logger = logging.getLogger()
root_logger.setLevel(logging.NOTSET)
stdout_logging_handler = logging.StreamHandler(sys.stderr)
tmp_logging_handler = logging.handlers.MemoryHandler(1024 * 1024, 100, stdout_logging_handler)
root_logger.addHandler(tmp_logging_handler)
config: ApplicationConfig = ApplicationConfig.from_filename('config.ini')
# because the records are already logged, unwanted ones need to be removed
filtered_buffer = filter(lambda record: record.levelno >= config.main_config.log_level, tmp_logging_handler.buffer)
tmp_logging_handler.buffer = filtered_buffer
root_logger.removeHandler(tmp_logging_handler)
logging.basicConfig(filename=config.main_config.log_filename, level=config.main_config.log_level, filemode='wt')
logging_handler = root_logger.handlers[0]
tmp_logging_handler.setTarget(logging_handler)
tmp_logging_handler.close()
stdout_logging_handler.close()