I am trying yo load an excel file using Openpyxl in Python.
from openpyxl import load_workbook
wb2 = load_workbook('Book1.xlsx')
print wb2.get_sheet_names()
It just these three lines. and it throws the following error:
Traceback (most recent call last):
File "C:/Python27/excel1.py", line 5, in <module>
wb2 = load_workbook('Book1.xlsx')
File "C:\Python27\Lib\site-packages\openpyxl\reader\excel.py", line 141, in load_workbook
archive = ZipFile(f, 'r', ZIP_DEFLATED)
File "C:\Python27\Lib\zipfile.py", line 793, in __init__
self._RealGetContents()
File "C:\Python27\Lib\zipfile.py", line 835, in _RealGetContents
raise BadZipfile, "File is not a zip file"
BadZipfile: File is not a zip file
This is exactly like their Documentation. https://openpyxl.readthedocs.org/en/latest/tutorial.html
Is their any better package to do this.
If this file does not exist at the desired location, try:
from openpyxl import load_workbook
from openpyxl import Workbook
# 1) create a workbook
wb = Workbook()
wb.save('my.xlsx')
del wb
# 2) build connection with the just created excel
book = load_workbook('my.xlsx')
It is an issue with the file. When we saved the file externally it was prompting this error. easy fix is to make a try catch and if the it gives the error create a new file in the same name and save on the same place. But for appending with old data wont work in this case.
try:
# this statement shall raise error for Badzip file
wb_obj = openpyxl.load_workbook(filename=path)
except:
# try to create a new file and save at same path
wb_obj = openpyxl.Workbook()
wb_obj.save(path)
wb_obj = openpyxl.load_workbook(filename=path)
xlsx files are zip archives. It looks like the file you're trying to open isn't. If you think this isn't the case please submit a but with a sample file.
Related
Here is my code to import an excel sheet and edit it:
import openpyxl as xl
wb = xl.load_workbook('transactions.xlxs')
sheet = wb['Sheet1']
cell = sheet['a1']
cell = sheet.cell(1, 1)
print(cell.value)
However I get the following error message:
C:\Users\mirco\PycharmProjects\pythonProject14\venv\Scripts\python.exe C:/Users/mirco/PycharmProjects/pythonProject14/main.py
Traceback (most recent call last):
File "C:\Users\mirco\PycharmProjects\pythonProject14\main.py", line 2, in <module>
wb = xl.load_workbook('transactions.xlxs')
File "C:\Users\mirco\PycharmProjects\pythonProject14\venv\lib\site-packages\openpyxl\reader\excel.py", line 315, in load_workbook
reader = ExcelReader(filename, read_only, keep_vba,
File "C:\Users\mirco\PycharmProjects\pythonProject14\venv\lib\site-packages\openpyxl\reader\excel.py", line 124, in __init__
self.archive = _validate_archive(fn)
File "C:\Users\mirco\PycharmProjects\pythonProject14\venv\lib\site-packages\openpyxl\reader\excel.py", line 94, in _validate_archive
raise InvalidFileException(msg)
openpyxl.utils.exceptions.InvalidFileException: openpyxl does not support .xlxs file format, please check you can open it with Excel first. Supported formats are: .xlsx,.xlsm,.xltx,.xltm
Process finished with exit code 1
How can I fix this?
wb = xl.load_workbook('transactions.xlxs')
was supposed to be
wb = xl.load_workbook('transactions.xlsx')
a little dyslexic mistake
also had to move excel file to the right location
the code as below
from openpyxl import *
wb = load_workbook(r'./test.xlsx')
ws = wb.active
ws1 = wb.create_sheet("Mysheet")
ws.delete_cols(2)
wb.save('./test.xlsx')
tagui_output = open('C:/Downloads/TagUI_Windows/tagui/src/tagui_py/tagui_py.txt','w')
tagui_output.write(temp_result)
tagui_output.close()
the output of code as below
C:\Downloads\TagUI_Windows\tagui\flows\samples> python .\excel2.py
fn of load_workbook = ./test.xlsx
fn of load_workbook = C:/Downloads/TagUI_Windows/tagui/src/tagui_py/tagui_py.txt
Traceback (most recent call last):
File "C:\Downloads\TagUI_Windows\tagui\flows\samples\excel2.py", line 7, in <module>
tagui_output = open('C:/Downloads/TagUI_Windows/tagui/src/tagui_py/tagui_py.txt','w')
File "C:\Users\xxx\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 316, in load_workbook
reader = ExcelReader(filename, read_only, keep_vba,
File "C:\Users\xxx\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 124, in __init__
self.archive = _validate_archive(fn)
File "C:\Users\xxx\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 94, in _validate_archive
raise InvalidFileException(msg)
openpyxl.utils.exceptions.InvalidFileException: filename=C:/Downloads/TagUI_Windows/tagui/src/tagui_py/tagui_py.txt openpyxl does not support .txt file format, please check you can open it with Excel first. Supported formats are: .xlsx,.xlsm,.xltx,.xltm
It seems the load_workbook function was automatically called when the open('C:/Downloads/TagUI_Windows/tagui/src/tagui_py/tagui_py.txt','w') function run,why this happened ?
You've conflict for python io function open() with openpyxl.open.
from openpyxl import * is importing all functions which shadows built-in open(). Restrict from openpyxl imports to limited function calls which you use.
Also, use with open("path/tagui_py.txt", "w") as tagui_output: for better file-handling.
i have been trying to append some data on my excel sheet using openpyxl and after that append some data in my text file...for some reason it gives me error whenever i try to open my text file
import openpyxl
from openpyxl import*
path = "students.xlsx"
To open the workbook
wb = openpyxl.load_workbook(path)
Get workbook active sheet object
sheet = wb.active
data to later append
data = (
(1, "john", 1/5/2022)
)
appending data
sheet.append(data)
saving and closing xlsx file
wb.save("students.xlsx")
wb.close()
problem lies here
with open("students.txt", "a") as f:
f.write(data[0]+data[1] + data[2])
here's my error
Traceback (most recent call last):
File "D:\taha\tools\attendance\quiz.py", line 32, in <module>
with open("students.txt", "a") as f:
File "C:\Users\FLH\AppData\Local\Programs\Python\Python310\lib\site-packages\openpyxl\reader\excel.py", line 315, in load_workbook
reader = ExcelReader(filename, read_only, keep_vba,
File "C:\Users\FLH\AppData\Local\Programs\Python\Python310\lib\site-packages\openpyxl\reader\excel.py", line 124, in __init__
self.archive = _validate_archive(fn)
File "C:\Users\FLH\AppData\Local\Programs\Python\Python310\lib\site-packages\openpyxl\reader\excel.py", line 94, in _validate_archive
raise InvalidFileException(msg)
openpyxl.utils.exceptions.InvalidFileException: openpyxl does not support .txt file format, please check you can open it with Excel first. Supported formats are: .xlsx,.xlsm,.xltx,.xltm
In a quick view, you defined data as a tuple that contains a tuple with three elements.
As a first step to solve should use a list instead a tuple of tuples:
data = [1, "john", 1/5/2022]
Could you try this and let me know if it solves or you need more help.
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Beginner here.
I've tried making new excel files, running the python code while the excel file is open, tried renaming the excel file, but nothing works. I was just following this youtube tutorial: https://www.youtube.com/watch?v=7YS6YDQKFh0&t=14s
from openpyxl import Workbook, load_workbook
workbook = load_workbook("Test2.xlsx")
The error:
Traceback (most recent call last):
File "c:\Users\Name\Desktop\Python Projects\Excel Manipulation\Excel_Test.py", line 3, in <module>
workbook = load_workbook("Test2.xlsx")
File "C:\Users\Name\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 315, in load_workbook
reader = ExcelReader(filename, read_only, keep_vba,
File "C:\Users\Name\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 124, in __init__
self.archive = _validate_archive(fn)
File "C:\Users\Name\AppData\Local\Programs\Python\Python39\lib\site-packages\openpyxl\reader\excel.py", line 96, in _validate_archive
archive = ZipFile(filename, 'r')
File "C:\Users\Name\AppData\Local\Programs\Python\Python39\lib\zipfile.py", line 1239, in __init__
self.fp = io.open(file, filemode)
**FileNotFoundError: [Errno 2] No such file or directory: 'Test2.xlsx'
PS C:\Users\Name>**
I found a solution. Turns out you just need to copy the file location, convert it to raw string, and add \ExcelFile to the end:
from openpyxl import Workbook, load_workbook
location = r'C:\Users\Name\Desktop\Python Projects\Excel Manipulation\Test2.xlsx'
workbook = load_workbook(location)
Derp.
I try to open a file with openpyxl but only get the error:
raise BadZipFile("File is not a zip file") zipfile.BadZipFile: File is not a zip file
A simple code example:
from openpyxl import load_workbook
wb = load_workbook('path.xlsx')
Context: I am trying to open an existing excel file, edit the file and then save it. Until now I am able to only read the file with pandas.read_excel(path.xlsx).
The excel files were in read-only mode. I saved the file as a new file and load_workbook worked.