When I draw a plot with pyplot, it automatically generates nice widely space tick marks and labels. Is there a simple way to adjust the spacing between the automatically generated marks? For example, in a plot where default tick positions are [2,4,6], have ticks at positions [2,3,4,5,6].
I know I can set the mark positions and labels with xticks() and yticks(), but I need to know the range of values first, and with different data, I'd need to adjust them manually.
There are a whole bunch of tick locators and formatters, depending on what you want to standardize. Here's an example of linearly spacing ticks, set up for comparison with the default:
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
df = pd.DataFrame((np.random.random((2,30)).T),columns=['A','B'])
fig, axs = plt.subplots(1,2)
axs[0].scatter(df.A, df.B)
axs[0].set_title('Default y-locator')
from matplotlib.ticker import LinearLocator
axs[1].get_yaxis().set_major_locator(LinearLocator(numticks=12))
axs[1].set_title('12 evenly spaced y-ticks')
axs[1].scatter(df.A, df.B)
See, generally, http://matplotlib.org/api/ticker_api.html?highlight=fixedlocator#module-matplotlib.ticker and the example gallery.
Related
I'm experimenting with seaborn and have a question about specifying axes properties. In my code below, I've taken two approaches to creating a heatmap of a matrix and placing the results on two sets of axes in a figure.
import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns
A=np.random.randn(4,4)
labels=['a','b','c','d']
fig, ax = plt.subplots(2)
sns.heatmap(ax =ax[0], data = A)
ax[0].set_xticks(range(len(labels)))
ax[0].set_xticklabels(labels,fontsize=10,rotation=45)
ax[0].set_yticks(range(len(labels)))
ax[0].set_yticklabels(labels,fontsize=10,rotation=45)
ax[1].set_xticks(range(len(labels)))
ax[1].set_xticklabels(labels,fontsize=10,rotation=45)
ax[1].set_yticks(range(len(labels)))
ax[1].set_yticklabels(labels,fontsize=10,rotation=45)
sns.heatmap(ax =ax[1], data = A,xticklabels=labels, yticklabels=labels)
plt.show()
The resulting figure looks like this:
Normally, I would always take the first approach of creating the heatmap and then specifying axis properties. However, when creating an animation (to be embedded on a tkinter canvas), which is what I'm ultimately interested in doing, I found such an ordering in my update function leads to "flickering" of axis labels. The second approach will eliminate this effect, and it also centers the tickmarks within squares along the axes.
However, the second approach does not rotate the y-axis tickmark labels as desired. Is there a simple fix to this?
I'm not sure this is what you're looking for. It looks like you create your figure after you change the yticklabels. so the figure is overwriting your yticklabels.
Below would fix your issue.
import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns
A=np.random.randn(4,4)
labels=['a','b','c','d']
fig, ax = plt.subplots(2)
sns.heatmap(ax =ax[0], data = A)
ax[0].set_xticks(range(len(labels)))
ax[0].set_xticklabels(labels,fontsize=10,rotation=45)
ax[0].set_yticks(range(len(labels)))
ax[0].set_yticklabels(labels,fontsize=10,rotation=45)
ax[1].set_xticks(range(len(labels)))
ax[1].set_xticklabels(labels,fontsize=10,rotation=45)
ax[1].set_yticks(range(len(labels)))
sns.heatmap(ax =ax[1], data = A,xticklabels=labels, yticklabels=labels)
ax[1].set_yticklabels(labels,fontsize=10,rotation=45)
plt.show()
I'm using matplotlib to draw a bar chart with 3 bars. I want to add some extra space along the x-axis (so that the x-axis line is drawn longer).
Below is what I have:
import numpy as np
import matplotlib.pyplot as plt
%matplotlib inline
dt = [1,3,2]
plt.figure()
xvals = range(len(dt))
plt.bar(xvals, dt, width=0.5)
plt.tick_params(bottom=False)
plt.xticks(xvals, ['a','b','c'])
plt.yticks(range(0,4), [0,1,2,3])
plt.gca().spines['top'].set_visible(False)
plt.gca().spines['right'].set_visible(False)
plt.show()
This code produces:
I simply want (note the elongated x-axis):
Change the limits of the x-axis using xlim()
for ex:
plt.xlim(-0.5,3.5) # adjust as necessary
Just add the following limits. Yo can use None as the left hand limit to let the plot choose the limit as the default value. Since the x-values are 0, 1, 2 and now you add the right hand side limit as 3, you will have an extended axis. Replace 3 by whatever value you want.
plt.xlim(None, 3)
I have a line chart based on a simple list of numbers. By default the x-axis is just the an increment of 1 for each value plotted. I would like to be a percentage instead but can't figure out how. So instead of having an x-axis from 0 to 5, it would go from 0% to 100% (but keeping reasonably spaced tick marks. Code below. Thanks!
from matplotlib import pyplot as plt
from mpl_toolkits.axes_grid.axislines import Subplot
data=[8,12,15,17,18,18.5]
fig=plt.figure(1,(7,4))
ax=Subplot(fig,111)
fig.add_subplot(ax)
plt.plot(data)
The code below will give you a simplified x-axis which is percentage based, it assumes that each of your values are spaces equally between 0% and 100%.
It creates a perc array which holds evenly-spaced percentages that can be used to plot with. It then adjusts the formatting for the x-axis so it includes a percentage sign using matplotlib.ticker.FormatStrFormatter. Unfortunately this uses the old-style string formatting, as opposed to the new style, the old style docs can be found here.
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.ticker as mtick
data = [8,12,15,17,18,18.5]
perc = np.linspace(0,100,len(data))
fig = plt.figure(1, (7,4))
ax = fig.add_subplot(1,1,1)
ax.plot(perc, data)
fmt = '%.0f%%' # Format you want the ticks, e.g. '40%'
xticks = mtick.FormatStrFormatter(fmt)
ax.xaxis.set_major_formatter(xticks)
plt.show()
This is a few months late, but I have created PR#6251 with matplotlib to add a new PercentFormatter class. With this class you can do as follows to set the axis:
import matplotlib.ticker as mtick
# Actual plotting code omitted
ax.xaxis.set_major_formatter(mtick.PercentFormatter(5.0))
This will display values from 0 to 5 on a scale of 0% to 100%. The formatter is similar in concept to what #Ffisegydd suggests doing except that it can take any arbitrary existing ticks into account.
PercentFormatter() accepts three arguments, max, decimals, and symbol. max allows you to set the value that corresponds to 100% on the axis (in your example, 5).
The other two parameters allow you to set the number of digits after the decimal point and the symbol. They default to None and '%', respectively. decimals=None will automatically set the number of decimal points based on how much of the axes you are showing.
Note that this formatter will use whatever ticks would normally be generated if you just plotted your data. It does not modify anything besides the strings that are output to the tick marks.
Update
PercentFormatter was accepted into Matplotlib in version 2.1.0.
Totally late in the day, but I wrote this and thought it could be of use:
def transformColToPercents(x, rnd, navalue):
# Returns a pandas series that can be put in a new dataframe column, where all values are scaled from 0-100%
# rnd = round(x)
# navalue = Nan== this
hv = x.max(axis=0)
lv = x.min(axis=0)
pp = pd.Series(((x-lv)*100)/(hv-lv)).round(rnd)
return pp.fillna(navalue)
df['new column'] = transformColToPercents(df['a'], 2, 0)
I'm facing issues in scaling axes 3d in matplotlib. I have found another questions but somehow the answer it does not seems to work. Here is a sample code:
import matplotlib as mpl
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
data=np.array([[0,0,0],[10,1,1],[2,2,2]])
fig=plt.figure()
ax=Axes3D(fig)
ax.set_xlim3d(0,15)
ax.set_ylim3d(0,15)
ax.set_zlim3d(0,15)
ax.scatter(data[:,0],data[:,1],data[:,2])
plt.show()
It seems it just ignore the ax.set commands...
In my experience, you have to set your axis limits after plotting the data, otherwise it will look at your data and adjust whatever axes settings you entered before to fit it all in-frame out to the next convenient increment along the axes in question. If, for instance, you set your x-axis limits to +/-400 but your data go out to about +/-1700 and matplotlib decides to label the x-axis in increments of 500, it's going to display the data relative to an x-axis that goes out to +/-2000.
So in your case, you just want to rearrange that last block of text as:
fig=plt.figure()
ax=Axes3D(fig)
ax.scatter(data[:,0],data[:,1],data[:,2])
ax.set_xlim3d(0,15)
ax.set_ylim3d(0,15)
ax.set_zlim3d(0,15)
plt.show()
The way of ColorOutOfSpace is good. But if you want to automate the scaling you have to search for the maximum and minimum number in the data and scale with those values.
min = np.amin(data) # lowest number in the array
max = np.amax(data) # highest number in the array
ax.set_xlim3d(min, max)
ax.set_ylim3d(min, max)
ax.set_zlim3d(min, max)
When no axes limits are specified, matplotlib chooses default values as nice, round numbers below and above the minimum and maximum values in the list to be plotted.
Sometimes I have outliers in my data and I don't want them included when the axes are selected. I can detect the outliers, but I don't want to actually delete them, just have them be beyond the area of the plot. I have tried setting the axes to be the minimum and maximum value in the list not including the outliers, but that means that those values lie exactly on the axes, and the bounds of the plot do not line up with ticker points.
Is there a way to specify that the axes limits should be in a certain range, but let matplotlib choose an appropriate point?
For example, the following code produces a nice plot with the y-axis limits automatically set to (0.140,0.165):
from matplotlib import pyplot as plt
plt.plot([0.144490353418, 0.142921640661, 0.144511781706, 0.143587888773, 0.146009766101, 0.147241517391, 0.147224266382, 0.151530932135, 0.158778411784, 0.160337332636])
plt.show()
After introducing an outlier in the data and setting the limits manually, the y-axis limits are set to slightly below 0.145 and slightly above 0.160 - not nearly as neat and tidy.
from matplotlib import pyplot as plt
plt.plot([0.144490353418, 0.142921640661, 0.144511781706, 0.143587888773, 500000, 0.146009766101, 0.147241517391, 0.147224266382, 0.151530932135, 0.158778411784, 0.160337332636])
plt.ylim(0.142921640661, 0.160337332636)
plt.show()
Is there any way to tell matplotlib to either ignore the outlier value when setting the limits, or set the axes to 'below 0.142921640661' and 'above 0.160337332636', but let it decide an appropriate location? I can't simply round the numbers up and down, as all my datasets occur on a different scale of magnitude.
You could make your data a masked array:
from matplotlib import pyplot as plt
import numpy as np
data = [0.144490353418, 0.142921640661, 0.144511781706, 0.143587888773, 500000, 0.146009766101, 0.147241517391, 0.147224266382, 0.151530932135, 0.158778411784, 0.160337332636]
data = np.ma.array(data, mask=False)
data.mask = data>0.16
plt.plot(data)
plt.show()
unutbu actually gave me an idea that solves the problem. It's not the most efficient solution, so if anyone has any other ideas, I'm all ears.
EDIT: I was originally masking the data like unutbu said, but that doesn't actually set the axes right. I have to remove the outliers from the data.
After removing the outliers from the data, the remaining values can be plotted and the y-axis limits obtained. Then the data with the outliers can be plotted again, but setting the limits from the first plot.
from matplotlib import pyplot as plt
data = [0.144490353418, 0.142921640661, 0.144511781706, 0.143587888773, 500000, 0.146009766101, 0.147241517391, 0.147224266382, 0.151530932135, 0.158778411784, 0.160337332636]
cleanedData = remove_outliers(data) #Function defined by me elsewhere.
plt.plot(cleanedData)
ymin, ymax = plt.ylim()
plt.clf()
plt.plot(data)
plt.ylim(ymin,ymax)
plt.show()