How to get stream from Google+ REST API using python? [closed] - python

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I have been browsing the Google Plus APIs and I can't seem to figure out if its possible to get the stream of posts(feed) of all those people who I have circled.
I have read through the Google+ API documentation and even tried Google's API explorer, but couldn't seem to figure out how to do it.
It's a very important feature of any API, which really shouldn't be missing to stream automatically on my page.

Check out https://developers.google.com/+/api/latest/people/list.
GET https://www.googleapis.com/plus/v1/people/me/people/connected
import requests
import json
r = requests.get('https://www.googleapis.com/plus/v1/people/me/people/connected')
input_log = json.loads(r.text)

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How to fetch live videos from a stream? [closed]

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I have been trying to fetch live video streams from the twitch website with requests, but it does not consider me as a viewer as it does with people watching streams on the browser. What i want to know is that do we have to send periodic requests to twitch database to make it consider us as a viewer. If yes then how can i send periodic requests what would be format of each request and what headers and payload/data would i have to send. I am very new to this so plz help me out.
I tried sending sync periodic requests but it didn't work with it.

Is there any way to search tweet by url? [closed]

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https://twitter.com/metakongz_G/status/1502223321009913857?t=PVLQS03E87nARHxbOMBjDQ&s=19
I have this target url. I want to get this tweet's retweets and comments using tweepy.
However it seems to be like tweepy does not support searching with url. How can I?
There are several ways:
Try to use automated browsers: There is an interesting manual that can help with Selenium and Python
Use official or unofficial Twitter APIs, example from RapidAPI
Get tweet id from url (numbers between "/status/" and "?") and use tweepy by id like here:
url = "https://twitter.com/metakongz_G/status/1502223321009913857?t=PVLQS03E87nARHxbOMBjDQ&s=19"
id = url.split("/status/")[1].split("?")[0]
print(id)

it possible to generate the rss feed from a website that didnt provide rss [closed]

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I want to know if it's possible to use Python or any other way to generate an RSS feed for a website, if the site does not provide RSS feeds.
Are there any examples?
Yes, if I would build something like that I would design it like this.
Write a Flask server which would handle request.
On every request download data from the target website with bs4.
Transform the data to XML output according to RSS format.
It's a bit more than just short code, but nothing very hard.

How can I get Youtube videos after searching through the Youtube api [closed]

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I want to make a python program that uses Youtube's api. The thing that I want to do is searching Youtube videos and showing the results in my program. Program gonna run like this: There is gonna be a textbox you write something and hit enter then you'll see the Youtube results below . What should I do for doing this in python or is this impossible?
Youtube has a Data API with very helpful example snippets. I would suggest reading through the official documentation before proceeding.
Relevant section: https://developers.google.com/youtube/v3/docs/search/list
Snippet tool instructions: https://google-developers.appspot.com/youtube/v3/code_samples/code_snippet_instructions

Discussion comments from Coursera [closed]

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I would like to do a simple machine learning project where I want to analyse comments from discussion forums on Coursera courses.
However, I am not sure if it is possible to do so programatically. So, providing a course page address, user name, password and getting all the discussion forums comments.
Being able to use Python for this would be awesome but I am language agnostic.
You can access web pages with python using urllib:
https://docs.python.org/2/library/urllib.html
or the higher lever interface requests:
http://requests.readthedocs.org/en/latest/
Then you still have to parse the content of the page and extract the comments.

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