First off, apologies for a commonly asked question. I've looked through all the earlier examples but none of the answers seem to work in my situation.
I'm trying to locate the username and password fields from this website: http://epaper.bt.com.bn/
I've had no problems locating the "myprofile" element and clicking on it. It then loads a page into an iframe. Here's my problem. I've tried all the various methods like find_element_by_id('input_username'), find_element_by_name('username') etc and they all do not work. Would appreciate if someone could point me down the right path.
Try first: (you should switch to iframe)
driver.switch_to.frame("iframe_login")
then you can find your elements. For example:
driver.find_element_by_id("input_username").send_keys("username")
for moving out of iframe:
driver.switch_to.default_content()
Related
Hi :) This is my first time here and I am new to programming.
I am currently trying to automate some work-steps, using Selenium.
There was no problem, mainly using the find_element(By.ID,'') function and clicking stuff.
But now I cannot find any element that comes after the second "html" tag on the site (see screenshot)
I tried to google this "multiple html" problem, but all I found was people saying it is not possible to have multiple html tags. I basically don't know anything about html, but this site seems to have more than one - there are actually three. And anything after the first one cannot be subject to the find_element function. Please help me with this confusion.
These "multiple html" are due to the i frames in the html code. Each iframe has its own html code. If the selector you are using is meant to find something inside one of these iframes you have to "move" your driver inside the iframe. You can find an example in this other question
I've been researching this for two days now. There seems to be no simple way of doing this. I can find an element on a page by downloading the html with Selenium and passing it to BeautifulSoup, followed by a search via classes and strings. I want to click on this element after finding it, so I want to pass its Xpath to Selenium. I have no minimal working example, only pseudo code for what I'm hoping to do.
Why is there no function/library that lets me search through the html of a webpage, find an element, and then request it's Xpath? I can do this manually by inspecting the webpage and clicking 'copy Xpath'. I can't find any solutions to this on stackoverflow, so please don't tell me I haven't looked hard enough.
Pseudo-Code:
*parser is BeautifulSoup HTML object*
for box in parser.find_all('span', class_="icon-type-2"): # find all elements with particular icon
xpath = box.get_xpath()
I'm willing to change my code entirely, as long as I can locate a particular element, and extract it's Xpath. So any other ideas on entirely different libraries are welcome.
I've been working on automations for a few months now, and for a recent project, I came across a Javascript link with href format as "javascript:srcUp" and no "htm" at the end. I've tried multiple ways of identifying this element, including css_selector, xpath, link_text, execute_script, etc. But none of the methods seem to work. With the link_text method, I was able to identify the element, but the click command didn't really do anything. Was wondering if anyone here has faced this issue, and if someone has, it would be great if you could share a possible solution.
Thanks
url:https://www.zhihu.com/question/305744720/answer/557418746
use selenium can not reply answer,only human
options.add_experimental_option("debuggerAddress", "127.0.0.1:9222")
browser = webdriver.Chrome(executable_path='.\chromedriver.exe',chrome_options=options)
button_li = self.browser.find_elements_by_class_name('Button--blue')
if len(button_li) > 2:
print(len(button_li))
button_ele = button_li[4]
button_ele.click()
time.sleep(random.uniform(0.5, 3))
browser.find_element_by_css_selector('div.AnswerForm-editor').click()
time.sleep(random.uniform(0.5, 2))
js="""
var div=document.getElementsByClassName('public-DraftStyleDefault-block')
var text =document.createTextNode("君");
div[0].firstChild.appendChild(text)
"""
self.browser.execute_script(js)
browser.find_element_by_css_selector('Button.Button.AnswerForm-submit').click()
Summary of problem:
My problem is that I wrote the content to the answer box successfully, but I was identified as a machine. After that, my actions on the page seemed to stop working. How can I avoid being identified as a machine so that I can still use selenium to select my element?
I'm not sure where you are trying to select the submit button, but the following selector worked for me:
browser.find_element_by_css_selector('Button.Button.AnswerForm-submit').click()
With respect to being detected as a 'machine', it's not easy to avoid that.
There are several different ways they can detect you.
That said, here's one thing I found that can avoid some of the Selenium detection attempts. One thing they look for document variables called $cdc_ and $wdc_ that selenium uses, and for Chrome it would be $cdc_. Here is what I suggest you try:
Download a hex editor if you don't already have one. I used one from here.
open your chromedriver.exe in the hex editor.
Use the Search functionality to find any instance of $cdc_ or $wdc_ and replace basically any other string ending in an underscore. Myself, I found just one instance of $cdc_, and it looked like this:
'$cdc_asdjflasutopfhvcZLmcfl_'
I simply replaced it with 'Random_'
Hopefully this works and now you can traverse the site unimpeded. If not, try some of the following; the only problem with this is that it might break your chromedriver file so that the tests no longer work. But it could be worth a try, and if it does break you can easily download a fresh one.
Search the document for any usage of the words 'selenium', 'webdriver', or 'chromedriver' and delete them. These is another way that a site can tell you are using selenium.
Let me know if any of this helps or you have any questions. It's hard for me to come up with a concrete answer because I don't know how exactly the site is detecting selenium.
How do I get a link from Google? I tried the following ways, but none of them worked:
find_elements_by_xpath("//*[#class='r']/#href")
driver.find_element_by_xpath("//a").get_attribute("href")
driver.find_element_by_xpath("//a").get_attribute(("href")[2])
I am receiving "none"
I need to get google link, not link to the site (e.g. not www.stackoverflow.com). It's highlighted on this image:
You maye have multiple issues here:
First and third options are a not a valid xpath. Second options may find more than one matches, so it will return the first that fits, which is not necessarily the one you want. So I suggest:
Make find specific enough to locate a proper element. I'd suggest find_element_by_link_text if you know the name of the link you are going to choose:
link = driver.find_element_by_link_text('Stack Overflow')
Given you chose the right link, you should be able to get the attribute:
href = link.get_attribute('href')
If the first statement throws an exception (most likely element not found), you may need to wait for the element to appear on the page, as described here