I am trying to write a simple server that will listen for one set of messages on UDP and another set of messages on TCP. I have written the following code:
from threading import Thread
import time
import socket
#define UDP listening function
def UDPListen():
Listening_UDP_Port = 300
Listening_IP = "127.0.0.1"
BUFFER_SIZE = 64
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # IPv4, UDP
sock.bind((Listening_IP, Listening_UDP_Port))
while True:
data, address = sock.recvfrom(BUFFER_SIZE)
print "UDP Messsage from address: ", address
print "Message: ", data
# END UPDListen() FUCNTION
#define a TCP listening function
def TCPListen():
Listening_TCP_Port = 300
Listening_IP = "127.0.0.1"
BUFFER_SIZE = 64
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) # IPv4, TCP
sock.bind((Listening_IP, Listening_TCP_Port))
while True:
sock.listen(1)
conn, address = sock.accept()
print "TCP connection from", address
data = conn.recv(BUFFER_SIZE)
print "Mesage: ", data
conn.close()
# END TCPListen() FUCNTION
# main function
def main():
ThreadUDP = Thread(target=UDPListen)
ThreadTCP = Thread(target=TCPListen)
print "Starting Server..."
ThreadUDP.start()
ThreadTCP.start()
print "Server Started!"
#END main() FUNCTION
if __name__ == "__main__":
main()
However when I run it in Python 2.7 it throws a wobbly, any ideas where I am going wrong?
For me on Windows it launches fine as it is.
For linux you'll have to run it as root or use sudo
e.g.
sudo python ./yourserver.py
Or else change your port number to 1024 or above.
It's ok that they have the same port number. If it were 2 tcp service though it wouldn't be ok. See here.
Edit:
Given the OP's clarification of the real issue the solution is to use.
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
After creating the sockets. Where sock is your socket name.
Related
I am testing out p2p connections and roughly followed this tutorial.
The script runs without any errors but sent messages aren't received.
This runs for both clients
import socket
import sys
import threading
dport = 50000
ip = # ip of other pc
sport = 50001
sock1 = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock1.bind(("0.0.0.0", sport))
sock1.sendto(b"0", (ip, dport))
print("ready")
def listen():
global sock1
# sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
# sock.bind(("0.0.0.0", sport))
while True:
data = sock1.recv(1024)
print(f"recv: {data.decode()}", end="")
listener = threading.Thread(target=listen, daemon=True)
listener.start()
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind(("0.0.0.0", dport))
while True:
msg = input(" >>> ")
sock.sendto(msg.encode(), (ip, sport))
Both clients are Macs. One runs on LAN, one on a Hotspot (to test between different networks).
I think the hotspot could be the problem but I can't test it right now as I don't have access to another network. I tried running both on the same network but that didn't work.
In the tutorial he creates another socket in listen() which gave me the error
OSError: [Errno 48] Address already in use
so I just reused the socket from before in line 14.
I am trying a little client server project to get me into network programming but I seem to have got stuck at the first hurdle. I cant seem to get past getting the first line of data only even if its a new connection.
#!/usr/bin/python
import socket
s = socket.socket()
host = '192.168.0.233' # Test Server
port = 7777
s.bind((host, port))
s.listen(5)
while True:
c, addr = s.accept()
print 'Got connection from', addr
data = c.recv(2048)
print(data)
If I telnet to the host running the server, the connection opens fine and I see on the server Got connection from addr, but I also only see the first line of data when I sent 4 lines of data,
I thought because its in a loop it should now always be looking for data?
I know im doing something wrong but unsure what.
Im using Python 2.6.6
recv needs to be in a loop too, at the moment your code is receiving some data and then waiting for a new connection.
https://docs.python.org/2/library/socket.html#example has an example of socket.recv in a loop.
Try this:
#!/usr/bin/python
import socket
import threading
def listenForClients(sock):
while True:
client, address = sock.accept()
client.settimeout(5)
threading.Thread( target = listenToClient, args = (client,address) ).start()
def listenToClient(client, address):
size = 2048
while True:
try:
data = client.recv(size)
if data:
response = "Got connection"
client.send(response)
else:
raise error('Client disconnected')
except:
client.close()
return False
def main(host, port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
sock.bind((host, port))
sock.listen(5)
listenForClients(sock)
if __name__ == "__main__":
main('192.168.0.233',7777)
Here I use a thread for each client. The problem that you have with having Socket.accept() in the loop is that it blocks meaning that concurrent access won't work and you'll only be able to talk to one client at a time.
Try running it in the background and sending it messages with:
#!/usr/bin/python
import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.connect(('192.168.0.233',7777))
vwhile True:
data = raw_input("enter a message: ")
sock.send(data)
print sock.recv(2048)
I have two scripts, Server.py and Client.py.
I have two objectives in mind:
To be able to send data again and again to server from client.
To be able to send data from Server to client.
here is my Server.py :
import socket
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "192.168.1.3"
port = 8000
print (host)
print (port)
serversocket.bind((host, port))
serversocket.listen(5)
print ('server started and listening')
while 1:
(clientsocket, address) = serversocket.accept()
print ("connection found!")
data = clientsocket.recv(1024).decode()
print (data)
r='REceieve'
clientsocket.send(r.encode())
and here is my client :
#! /usr/bin/python3
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host ="192.168.1.3"
port =8000
s.connect((host,port))
def ts(str):
s.send('e'.encode())
data = ''
data = s.recv(1024).decode()
print (data)
while 2:
r = input('enter')
ts(s)
s.close ()
The function works for the first time ('e' goes to the server and I get return message back), but how do I make it happen over and over again (something like a chat application) ?
The problem starts after the first time. The messages don't go after the first time.
what am I doing wrong?
I am new with python, so please be a little elaborate, and if you can, please give the source code of the whole thing.
import socket
from threading import *
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "192.168.1.3"
port = 8000
print (host)
print (port)
serversocket.bind((host, port))
class client(Thread):
def __init__(self, socket, address):
Thread.__init__(self)
self.sock = socket
self.addr = address
self.start()
def run(self):
while 1:
print('Client sent:', self.sock.recv(1024).decode())
self.sock.send(b'Oi you sent something to me')
serversocket.listen(5)
print ('server started and listening')
while 1:
clientsocket, address = serversocket.accept()
client(clientsocket, address)
This is a very VERY simple design for how you could solve it.
First of all, you need to either accept the client (server side) before going into your while 1 loop because in every loop you accept a new client, or you do as i describe, you toss the client into a separate thread which you handle on his own from now on.
client.py
import socket
s = socket.socket()
s.connect(('127.0.0.1',12345))
while True:
str = raw_input("S: ")
s.send(str.encode());
if(str == "Bye" or str == "bye"):
break
print "N:",s.recv(1024).decode()
s.close()
server.py
import socket
s = socket.socket()
port = 12345
s.bind(('', port))
s.listen(5)
c, addr = s.accept()
print "Socket Up and running with a connection from",addr
while True:
rcvdData = c.recv(1024).decode()
print "S:",rcvdData
sendData = raw_input("N: ")
c.send(sendData.encode())
if(sendData == "Bye" or sendData == "bye"):
break
c.close()
This should be the code for a small prototype for the chatting app you wanted.
Run both of them in separate terminals but then just check for the ports.
This piece of code is incorrect.
while 1:
(clientsocket, address) = serversocket.accept()
print ("connection found!")
data = clientsocket.recv(1024).decode()
print (data)
r='REceieve'
clientsocket.send(r.encode())
The call on accept() on the serversocket blocks until there's a client connection. When you first connect to the server from the client, it accepts the connection and receives data. However, when it enters the loop again, it is waiting for another connection and thus blocks as there are no other clients that are trying to connect.
That's the reason the recv works correct only the first time. What you should do is find out how you can handle the communication with a client that has been accepted - maybe by creating a new Thread to handle communication with that client and continue accepting new clients in the loop, handling them in the same way.
Tip: If you want to work on creating your own chat application, you should look at a networking engine like Twisted. It will help you understand the whole concept better too.
I'm trying the following client and server chat program. Although I get an error whenever I try to run the server program, when the client program runs it stays on a blank screen not allowing me to type anything. I've tried running server first and running client first and I get the same results. I can't read the error from the server program because it flashes the error and closes the window. Here is my code:
server:
#server
import socket
import time
HOST = ''
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((HOST,PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()
client:
#client
import socket
import time
HOST = "localhost"
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect((HOST,PORT))
s.sendall('Helloworld')
data = s.recv(1024)
s.close()
print 'Recieved', repr(data)
Im not an expert but I was able to make your examples work by changing the socket from datagram to stream connection, and then encoding message being sent because strings aren't supported (although this might not effect you since I think that change was made in Python 3...I'm not 100% sure).
I believe the main issue is that you're trying to listen() but SOCK_DGRAM (UDP) doesn't support listen(), you just bind and go from there, whereas SOCK_STREAM (TCP) uses connections.
If you're just trying to get the program going, use the below code, unless there is a specific reason you'd like to use SOCK_DGRAM.
The code is below:
client
#client
import socket
import time
HOST = "localhost"
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST,PORT))
test = 'Helloworld'
s.sendall(test.encode())
data = s.recv(1024)
s.close()
print 'Recieved', repr(data)
server
#server
import socket
import time
HOST = ''
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST,PORT))
s.listen(1)
conn, addr = s.accept()
print ('Connected by', addr)
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()
I have a server written in python 2.7 that executes an infinite loop and process information from port 5000. Is it possible to change this connection port without restarting the server?
For example: the server is running in port 5000 and receives a 'change_port' option, the server module has to stop listening in port 5000 to start listening in port 7000. I don't know if i can manipulate sockets like that... Thanks
Once you have bound a socket to an address (interface, port) it cannot be changed. However, you can create a new socket (or many, depending on your needs) and bind it to your address (interface, port).
The code will differ based on the transport layer protocol you're using:
TCP:
# 1) Create first socket
s1 = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s1.bind(('0.0.0.0',5000))
# 2) Create second socket
s2 = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s2.bind(('0.0.0.0',7000))
# 3) Wait for a connection on the first socket
s1.listen(5)
sc, address = s1.accept()
# 4) Once a connection has been established...
# send, recv, process data
# until you need the next socket
# 5) Open connection on second socket
s2.listen(1)
sc2, address2 = s2.accept()
# now it probably a good time to tell the client (via s1) that s2 is ready
# client connects to s2
There you go
UDP (almost the same):
s1 = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s1.bind(('0.0.0.0',5000))
s2 = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s2.bind(('0.0.0.0',7000))
data, addr = s1.recvfrom(256)
s1.sendto("s2 ready",addr)
data2, addr2 = s2.recvfrom(256)
Simplified, but that's all there really is to it.
You might consider verifying that the address of the client from s1 is the same as the client connecting to s2.
No, it seems that you cannot run the socket.bind() method when its already bound. However, I have a solution you can use with the Asyncore module.
Heres my server:
import asyncore
import socket
class EchoHandler(asyncore.dispatcher_with_send):
def handle_read(self):
data = self.recv(8192)
if data:
print "Recieved Data: ", data, ". This server address:", self.getsockname()
class EchoServer(asyncore.dispatcher):
def __init__(self, host, port):
asyncore.dispatcher.__init__(self)
self.create_socket(socket.AF_INET, socket.SOCK_STREAM)
self.set_reuse_addr()
self.bind((host, port))
self.listen(5)
def handle_accept(self):
pair = self.accept()
if pair is not None:
sock, addr = pair
print 'Incoming connection from %s' % repr(addr)
handler = EchoHandler(sock)
server = EchoServer('localhost', 56787)
server = EchoServer('localhost', 56788)
asyncore.loop()
Here are my clients:
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(('localhost', 56787))
data = ""
while data.upper() != "Q":
data = raw_input("Enter something to send to the server")
s.send(data)
s.close()
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(('localhost', 56788))
data = ""
while data.upper() != "Q":
data = raw_input("Enter something to send to the server")
s.send(data)
s.close()
This worked well, the python handled both ports. You should also be able to define seperate server classes for each of your ports.