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How to check for a running shell in windows?

I try to write a programm in python that notifies me, when a shell like cmd gets opened.
Until now I did the following in python.
Check for new starting processes, get the name of the process and check if its name is cmd.exe.
This works if I start a cmd process manually myself.
But it Turns out if i open a shell with subprocess.getoutput(command) from the subprocess library in python there is no shell listed in the prosesses and I also cant see it in taskmanager.
So I assumed its a childprocess of the pythonscripts process running?
My next Idea was to list all the modules a process is using and check for cmd.exe in the modules.
It turns out the pythonscript with subprocess.getoutput(command) does not use cmd.exe in the modules. Strange.
So right now I am not sure how I could detect the shell or if I am even on the right way.
Maybe I need to find the childprocesses of a the pythonprocess? Or is it possible to get a shell without calling cmd.exe I honestly dont know enough about it.
Maybe its better to check for chertain dlls in the used methods by a process?
I also tried to look in the subprocess.py library but it is difficult for me to understand and it seems to atleast pass over cmd as a parameter for subprocess.getoutput() method.
Can somebody help?
Thank you.
UPDATE:
I use this code to detect the process:
import wmi
c = wmi.WMI()
process_watcher = c.Win32_Process.watch_for("creation")
while True:
new_process = process_watcher()
print(new_process.Caption, new_process.ProcessId)
if new_process.Caption =="cmd.exe":
pid = new_process.ProcessID
break
But if I run this code
import subprocess
output = subprocess.getoutput("ipconfig")
print(output)
The only process detected is pythonw.exe
But if I run
import subprocess
while True:
output = subprocess.getoutput("ipconfig")
print(output)
At some point it find cmd.exe.
So I assume that wmi takes to long to detect the process. So cmd is already closed and does not get found.
Any Ideas how to do this a better way?

I didnt know practic version of solution.But you can use pyautogui for it if you want.You can write a program with pyautogui that notifies you when it find cmd logo at task bar.Example:
import pyautogui
cmdlogo = pyautogui.locateOnScreen('get screenshot of cmd logo and write file name here example:'cmd.png'')
While True:
if cmdlogo:
print('write here what yo want to say when it finds cmd')
else:
pyautogui.sleep(5)

Playing audio continuously in Python [duplicate]

How can I play audio (it would be like a 1 second sound) from a Python script?
It would be best if it was platform independent, but firstly it needs to work on a Mac.
I know I could just execute the afplay file.mp3 command from within Python, but is it possible to do it in raw Python? I would also be better if it didn't rely on external libraries.

Your best bet is probably to use pygame/SDL. It's an external library, but it has great support across platforms.
pygame.mixer.init()
pygame.mixer.music.load("file.mp3")
pygame.mixer.music.play()
You can find more specific documentation about the audio mixer support in the pygame.mixer.music documentation

Try playsound which is a Pure Python, cross platform, single function module with no dependencies for playing sounds.
Install via pip:
$ pip install playsound
Once you've installed, you can use it like this:
from playsound import playsound
playsound('/path/to/a/sound/file/you/want/to/play.mp3')

Take a look at Simpleaudio, which is a relatively recent and lightweight library for this purpose:
> pip install simpleaudio
Then:
import simpleaudio as sa
wave_obj = sa.WaveObject.from_wave_file("path/to/file.wav")
play_obj = wave_obj.play()
play_obj.wait_done()
Make sure to use uncompressed 16 bit PCM files.

You can find information about Python audio here: http://wiki.python.org/moin/Audio/
It doesn't look like it can play .mp3 files without external libraries. You could either convert your .mp3 file to a .wav or other format, or use a library like PyMedia.

In pydub we've recently opted to use ffplay (via subprocess) from the ffmpeg suite of tools, which internally uses SDL.
It works for our purposes – mainly just making it easier to test the results of pydub code in interactive mode – but it has it's downsides, like causing a new program to appear in the dock on mac.
I've linked the implementation above, but a simplified version follows:
import subprocess
def play(audio_file_path):
subprocess.call(["ffplay", "-nodisp", "-autoexit", audio_file_path])
The -nodisp flag stops ffplay from showing a new window, and the -autoexit flag causes ffplay to exit and return a status code when the audio file is done playing.
edit: pydub now uses pyaudio for playback when it's installed and falls back to ffplay to avoid the downsides I mentioned. The link above shows that implementation as well.

Sorry for the late reply, but I think this is a good place to advertise my library ...
AFAIK, the standard library has only one module for playing audio: ossaudiodev.
Sadly, this only works on Linux and FreeBSD.
UPDATE: There is also winsound, but obviously this is also platform-specific.
For something more platform-independent, you'll need to use an external library.
My recommendation is the sounddevice module (but beware, I'm the author).
The package includes the pre-compiled PortAudio library for Mac OS X and Windows, and can be easily installed with:
pip install sounddevice --user
It can play back sound from NumPy arrays, but it can also use plain Python buffers (if NumPy is not available).
To play back a NumPy array, that's all you need (assuming that the audio data has a sampling frequency of 44100 Hz):
import sounddevice as sd
sd.play(myarray, 44100)
For more details, have a look at the documentation.
It cannot read/write sound files, you'll need a separate library for that.

Aaron's answer appears to be about 10x more complicated than necessary. Just do this if you only need an answer that works on OS X:
from AppKit import NSSound
sound = NSSound.alloc()
sound.initWithContentsOfFile_byReference_('/path/to/file.wav', True)
sound.play()
One thing... this returns immediately. So you might want to also do this, if you want the call to block until the sound finishes playing.
from time import sleep
sleep(sound.duration())
Edit: I took this function and combined it with variants for Windows and Linux. The result is a pure python, cross platform module with no dependencies called playsound. I've uploaded it to pypi.
pip install playsound
Then run it like this:
from playsound import playsound
playsound('/path/to/file.wav', block = False)
MP3 files also work on OS X. WAV should work on all platforms. I don't know what other combinations of platform/file format do or don't work - I haven't tried them yet.

You can see this: http://www.speech.kth.se/snack/
s = Sound()
s.read('sound.wav')
s.play()

It is possible to play audio in OS X without any 3rd party libraries using an analogue of the following code. The raw audio data can be input with wave_wave.writeframes. This code extracts 4 seconds of audio from the input file.
import wave
import io
from AppKit import NSSound
wave_output = io.BytesIO()
wave_shell = wave.open(wave_output, mode="wb")
file_path = 'SINE.WAV'
input_audio = wave.open(file_path)
input_audio_frames = input_audio.readframes(input_audio.getnframes())
wave_shell.setnchannels(input_audio.getnchannels())
wave_shell.setsampwidth(input_audio.getsampwidth())
wave_shell.setframerate(input_audio.getframerate())
seconds_multiplier = input_audio.getnchannels() * input_audio.getsampwidth() * input_audio.getframerate()
wave_shell.writeframes(input_audio_frames[second_multiplier:second_multiplier*5])
wave_shell.close()
wave_output.seek(0)
wave_data = wave_output.read()
audio_stream = NSSound.alloc()
audio_stream.initWithData_(wave_data)
audio_stream.play()

This is the easiest & best iv'e found. It supports Linux/pulseaudio, Mac/coreaudio, and Windows/WASAPI.
import soundfile as sf
import soundcard as sc
default_speaker = sc.default_speaker()
samples, samplerate = sf.read('bell.wav')
default_speaker.play(samples, samplerate=samplerate)
See https://github.com/bastibe/PySoundFile and https://github.com/bastibe/SoundCard for tons of other super-useful features.

Also on OSX - from SO, using OSX's afplay command:
import subprocess
subprocess.call(["afplay", "path/to/audio/file"])
UPDATE: All this does is specify how to do what the OP wanted to avoid doing in the first place. I guess I posted this here because what OP wanted to avoid was the info I was looking for. Whoops.

Install playsound package using :
pip install playsound
Usage:
from playsound import playsound
playsound("file location\audio.p3")

Try PySoundCard which uses PortAudio for playback which is available on many platforms.
In addition, it recognizes "professional" sound devices with lots of channels.
Here a small example from the Readme:
from pysoundcard import Stream
"""Loop back five seconds of audio data."""
fs = 44100
blocksize = 16
s = Stream(samplerate=fs, blocksize=blocksize)
s.start()
for n in range(int(fs*5/blocksize)):
s.write(s.read(blocksize))
s.stop()

Mac OS I tried a lot of codes but just this works on me
import pygame
import time
pygame.mixer.init()
pygame.init()
pygame.mixer.music.load('fire alarm sound.mp3') *On my project folder*
i = 0
while i<10:
pygame.mixer.music.play(loops=10, start=0.0)
time.sleep(10)*to protect from closing*
pygame.mixer.music.set_volume(10)
i = i + 1

It's Simple. I did it this way.
For a wav file
from IPython.display import Audio
from scipy.io.wavfile import read
fs, data = read('StarWars60.wav', mmap=True) # fs - sampling frequency
data = data.reshape(-1, 1)
Audio(data = data[:, 0], rate = fs)
For mp3 file
import IPython.display import Audio
Audio('audio_file_name.mp3')

Pypi has a list of modules for python in music. My favorite would be jython because it has more resources and libraries for music. As example of of code to play a single note from the textbook:
# playNote.py
# Demonstrates how to play a single note.
from music import * # import music library
note = Note(C4, HN) # create a middle C half note
Play.midi(note) # and play it!

To play a notification sound using python, call a music player, such as vlc. VLC prompted me to use its commandline version, cvlc, instead.
from subprocess import call
call(["cvlc", "--play-and-exit", "myNotificationTone.mp3"])
It requires vlc to be preinstalled on the device. Tested on Linux(Ubuntu 16.04 LTS); Running Python 3.5.

Try sounddevice
If you don't have the module enter
pip install sounddevice in your terminal.
Then in your preferred Python script (I use Juypter), enter
import sounddevice as sd
sd.play(audio, sr) will play what you want through Python
The best way to get the audio and samplerate you want is with the librosa module. Enter this in terminal if you don't have the librosa module.
pip install librosa
audio, sr = librosa.load('wave_file.wav')
Whatever wav file you want to play, just make sure it's in the same directory as your Python script. This should allow you to play your desired wav file through Python
Cheers,
Charlie
P.S.
Once audio is a "librosa" data object, Python sees it as a numpy array. As an experiment, try playing a long (try 20,000 data points) thing of a random numpy array. Python should play it as white noise. The sounddevice module plays numpy arrays and lists as well.

In a Colab notebook you can do:
from IPython.display import Audio
Audio(waveform, Rate=16000)

This library aims to be simple, cross-platform and have many features: https://github.com/libwinmedia/libwinmedia-py
It requires a libwinmedia shared library, which you can download in Releases tab.
You can install it using pip install libwinmedia
Example:
import libwinmedia
player = libwinmedia.Player(True)
player.set_position_callback(lambda position: print(f"{position} ms."))
media = libwinmedia.Media("test.mp3")
player.open(media)

This should work on Linux, Mac or Windows:
from preferredsoundplayer import *
soundplay("audio.wav")
Should work for mp3 also.
In Linux it will try up to 4 different methods. In Windows it uses winmm.dll. In Mac it uses afplay.
I wrote it because:
I kept having issues with cross-compatibility for playing sounds.
It also manually garbage collects calls to the winmm.dll player in Windows and appropriate closes finished sounds.
It has no dependencies, other than what comes with Windows 10, the standard Linux kernel, MacOS 10.5 or later, and the Python Standard Library.
You can install using pip install preferredsoundplayer (see project) or just utilize the source code which is a single file (source code) .

Put this at the top of your python script you are writing:
import subprocess
If the wav file IS in the directory of the python script:
f = './mySound.wav'
subprocess.Popen(['aplay','-q',f)
If the wav file IS NOT in the directory of the python script:
f = 'mySound.wav'
subprocess.Popen(['aplay','-q', 'wav/' + f)
If you want to learn more about aplay:
man aplay

I recently made my Music Player support all audio files locally. I did this by figuring out a way to use the vlc python module and also the VLC dll files.
You can check it out:
https://github.com/elibroftw/music-caster/blob/master/audio_player.py

For those who use Linux and the other packages haven't worked on MP3 files, audioplayer worked fine for me:
https://pypi.org/project/audioplayer/
from audioplayer import AudioPlayer
AudioPlayer("path/to/somemusic.mp3").play(block=True)

If you're on OSX, you can use the "os" module or "subprocess" etc. to call the OSX "play" command. From the OSX shell, it looks like
play "bah.wav"
It starts to play in about a half-second on my machine.

Simply You can do it with the help of cvlc-
I did it in this way:
import os
os.popen2("cvlc /home/maulo/selfProject/task.mp3 --play-and-exit")
/home/maulo/selfProject/task.mp3. This is the location of my mp3 file.
with the help of "--play-and-exit" you will be able to play again the sound without ending the vlc process.

Run .bat file using Python

I have a batch file, which I use to load some pre-build binaries to control my device.
It's command is:
cd build
java -classpath .;..\Library\mfz-rxtx-2.2-20081207-win-x86\RXTXcomm.jar -
Djava.library.path=..\Library\mfz-rxtx-2.2-20081207-win-x86 tabotSample/Good1
pause
Now, I want to run the batch file using Python, and I tried os.system(batch,bat), and I tried using Popen
import os
from subprocess import Popen
os.popen("cd TAbot")
r=os.popen("hello.bat")
However, the python console(Anaconda python 2.7) seems like executed the code, but returns nothing, and nothing happens.
I want to run this batch file from python, please help me.
by the way, I tried popen for another batch file like,
echo Hello but nothing happens.

Here is the simple solution.
from subprocess import Popen
import subprocess
def run_batch_file(file_path):
Popen(file_path,creationflags=subprocess.CREATE_NEW_CONSOLE)
run_batch_file('file_name.bat')
file_name.bat
echo .bat file running from python
pause

You can also use this
import subprocess
subprocess.call(["C:\\temp\\test.bat"], shell=False)
test.bat
copy "C:\temp\test.txt" "C:\temp\test2.txt"

I think this should work like this:
batch.py
from subprocess import Popen
p = Popen("test.bat", cwd=r"C:\path\to\batch\folder")
stdout, stderr = p.communicate()
test.bat
echo Hello World!
pause

Here many guys suggested very useful solutions, but I want to point the importance of where is the program located.
(Bat file is usually made for automation task to reduce time and this has high probability to work some task related path)
import subprocess
os.chdir("YOUR TARGET PATH")
exit_code = subprocess.call(FILEPATH)# FILEPATH is from the standpoint on YOUR TARGET PATH

Python- Error in playing mp3 audio using vlc-command line

Objective
I wanted to use the os module to play an audio file using VLC player at a faster rate.
os.system("vlc 'C:\Users\user\Desktop\file1.mp3' --rate=1.5")
What should have happened
A VLC player window should have popped open and the music should have started playing at a speed 1.5 times that of the default speed.
What happened instead
File reading failed:
VLC could not open the file "C:\Program Files\VideoLAN\VLC\'C:\Users\user\Desktop\file1.mp3'". (%m)
Your input can't be opened:
VLC is unable to open the MRL 'file:///C:/Program%20Files/VideoLAN/VLC/%27C%3A/Users/user/Desktop/file1.mp3%27'. Check the log for details.
Code
import os
os.chdir("C:\Program Files\VideoLAN\VLC")
os.system("vlc 'C:\Users\user\Desktop\file1.mp3' --rate=1.5")
Where did I go wrong?
How can I resolve the error?

This might be because of the extra quoting required in Windows paths
If you are using Python >=3.5 you can use subprocess.run instead of os.system which could help with the quoting issues as well.
import subprocess
subprocess.run(['vlc', r'C:\Users\user\Desktop\file1.mp3',
'--play-and-exit', '--rate=1.5'])

If you are using python 2.7 you may also use the following.
import subprocess
subprocess.Popen(r'vlc --rate 5 C:\Users\user\Desktop\file1.mp3',shell = True)
AFAIK, the rate switch should be given immediately after vlc. This worked for me
Please let me know if it solved your purpose.

Why does the terminal search the working directory for files that an executing file is searching for?

If the title isn't clear enough the directory has Developer/Pythonfiles/Pong has Pong.py and hit.wav in it.
When i run ~ $python Developer/Pythonfiles/Pong/Pong.py
The sound hit.wav won't play, A weird popping noise plays instead.
But when I run ~/Developer/Pythonfiles/Pong $python Pong.py the sound from hit.wav plays as expected.
Why doesn't the program Pong.py search the directory its in rather than my working directory for Hit.wav? I try to access hit.wav with hit = pygame.mixer.Sound("hit.wav") and play it with hit.play()

Because it has no way of automagically knowing that's what you wanted. So specify the desired behaviour yourself:
import os
hit = pygame.mixer.Sound(os.path.join(os.path.dirname(__file__), "hit.wav"))